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7 At 20 °c (293 K) the vapor pressure of water is 0.0231 atm. What is the vapor pressure
produced by vaporization of seawater if the total concentration of sea-salt is 1.15 m? 8 Molar
mass from boiling point elevation: A solution is prepared by dissolving 0.300 g of an unknown
solute (nonvolatile) in 30.0 g of carbon tetrachloride (CCl4) which has a boiling point 0.392 °C
higher than pure CCl4. What is the molecular weight of the unknown solute? Kb for CCls is
5.020 °C/m. 9 How many grams of Na2SO4 should be used to be added to 250 mL of water to
preparea 0.750 m solution of Na2S04? [MW of Na2SO4 is 142.04 g/mol]
Solution
8.
Elevation in boiling point = 1000 * Kb * w / ( W * m )
0.392 = 1000 * 5.020 * 0.300 / ( 30.0 * m)
m = molecular weight of unknown solute = 128. g / mol
9.
molality = ( mass / molar mass ) * ( 1000 / weight of solvent in g. )
0.750 = ( mass / 142.04 ) * ( 1000 / 250 )
mass of Na 2 SO 4 needed = 0.750 * 142.04 * 250 / 1000 = 26.6 g.
7 At 20 c (293 K) the vapor pressure of water is 0-0231 atm- What is t.docx

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7 At 20 c (293 K) the vapor pressure of water is 0-0231 atm- What is t.docx

  • 1. 7 At 20 °c (293 K) the vapor pressure of water is 0.0231 atm. What is the vapor pressure produced by vaporization of seawater if the total concentration of sea-salt is 1.15 m? 8 Molar mass from boiling point elevation: A solution is prepared by dissolving 0.300 g of an unknown solute (nonvolatile) in 30.0 g of carbon tetrachloride (CCl4) which has a boiling point 0.392 °C higher than pure CCl4. What is the molecular weight of the unknown solute? Kb for CCls is 5.020 °C/m. 9 How many grams of Na2SO4 should be used to be added to 250 mL of water to preparea 0.750 m solution of Na2S04? [MW of Na2SO4 is 142.04 g/mol] Solution 8. Elevation in boiling point = 1000 * Kb * w / ( W * m ) 0.392 = 1000 * 5.020 * 0.300 / ( 30.0 * m) m = molecular weight of unknown solute = 128. g / mol 9. molality = ( mass / molar mass ) * ( 1000 / weight of solvent in g. ) 0.750 = ( mass / 142.04 ) * ( 1000 / 250 ) mass of Na 2 SO 4 needed = 0.750 * 142.04 * 250 / 1000 = 26.6 g.