Pre-Test
Give what isasked
1. Write in words 30 501 047.
2. Write in standard form: 5 x 105 + 6 x 104 +
3 x 103 + 5 x 102 + 2 x 10 + 9 .
3. The following are prime numbers except,
2, 3, 5, 7, 9, 11, 13, 17, 19
4. 800 is how many times lesser than 80 000?
5. What is the standard form of 23 x 32 x 5?
4.
Pre-Test
6.What is theGCF of 12 and 18?
7. The LCM of 8 and 12.
8. The prime factors of 180.
9. Which of the following is greater?
34 or 43 ?
10. Which of the following is not correct?
22 x 3 x 5 = 60
24 x 33 = 133
22 x 32 x 52 = 900
Answers
1. Thirty million,five hundred one thousand,
forty-seven
2. 563 529
3. 9
4. 100 times
5. 360
6. 6
7. 24
8. 2x2x3x3x5 or 22 x 32 x 5
9. 34
10. 24 x 33 = 133
7.
Introduction
Place Value ofWhole Numbers
Our numeration system is called the decimal number
system (“deci” means 10)because it makes use of ten
symbols to form numbers.
The decimal number system makes use of Hindu-
Arabic numerals that the value of a number depends
on the place values the digits use in a number.
Each place or position that a digit holds in a number has
a value ten times the value of the place at its right
8.
Place Value Chart
BillionsMillions Thousands Units
Hundreds
Tens Ones
Hundreds
Tens Ones
Hundreds
Tens Ones
Hundreds
Tens Ones
P E R I O D S
P L A C E V A L U E S
D I G I T P L A C E M E N T
9.
Place Value Chart
I.Writing numbers in words
1. Thirteen thousand, one hundred ninety five
2. Two hundred seven thousand, six hundred thirty
3. Eight million, one hundred thirty –seven thousand,
five hundred thirty-nine
4. seventy-six million, one hundred four thousand, two
hundred sixty-five
5. Six hundred thirty-nine million, eight hundred
seventy-one thousand, two hundred twenty-three
10.
Place Value Chart
I.Writing numbers in words
5. Five billion, ninety-two million, four hundred forty-
one thousand, seven hundred thirty-six
11.
Place Value Chart
II.Writing numbers in standard form
1. 8 475
2. 30 656 213
3. 40 823
4. 756 345
5. 5 016 899
12.
Writing Expanded notationin standard form
4 628
4 000 = 4 x 103
600 = 6 x 102
20 = 2 x 101
8
Thus:
4 628 = 4 x 103 + 6 x 102 + 2 x 101 + 8 (place-value
expanded form) or
= 4 000 + 600 + 20 + 8 ( value-expanded form)
13.
Writing Expanded notationin standard form
850 609
800 000 = 8 x 105
50 000 = 5 x 104
600 = 6 x 102
9
Thus:
850 609 = 8 x 105 + 5 x 104 + 6 x 102 + 9 or
= 800 000 + 50 000 + 600 + 9
14.
II. B. WritingExpanded notation in standard
form
1. 40 925
2. 863
3. 287 927
4. 35 569
5. 7 895 738
15.
Expressing Exponential Formin
Standard Form
Base – is the number used as a factor
Exponent – indicates how many times the
base is multiplied to itself
Product is the standard form of an
exponential expression
Ex. 23 = 2 x 2 x 2 = 8
112 = 11 x 11= 121
105 = 10 x 10 x 10 x 10 x 10=100 000
16.
Identifying how manytimes a number is
lower or greater than on its place value
900 900
= 900 000 is 100 times greater than 900
= 900 is 100 times lesser than 900 000
2 020
= 2 000 is 100 times greater than 20
= 20 is 100 times lesser than 2 000
17.
III. Identifying howmany times a number is
lower or greater than on its place value
1. 1oox greater
2. 10 000x greater
3. 1 000x lesser
4. 10 000x lesser
5. 10x lesser
6. 10x greater
18.
Odd , Evenand Prime Numbers
ODD numbers are NOT divisible by 2
EVEN numbers are divisible by 2
Prime Number
Is a number which has only 2 factors; 1 and
itself
Prime numbers below 100:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41,
43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97
19.
IV. Expressing anumber as a sum of
two prime numbers
Choose from the following list of prime numbers:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43,
47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97
1. 35
= 5+7+23
2. 21
= 19 + 2
= 2+2+17
20.
Factor
A number thatevenly divides
another number
An amount by which another
amount is multiplied or divided
Any of the numbers or symbols in
mathematics that when
multiplied together form a
product
Finding prime factorsby
continuous division method
2 36
2 18
3 9
3
36 = 2 x 2 x 3 x 3 or
22 x 32
25.
Finding prime factorsby factor-
tree method
48
2 x 24
2 x 12
2 x 6
2 x 3
48 = 2 x 2 x 2 x 2 x 3 or
24 x 3
26.
V. Work byPair: Give the Prime Factors
B. 1. 96
2. 42
3. 81
4. 56
5. 144
6. 108
7. 420
8. 1260
= 2 x 2 x 2 x 2 x 2 x 3 or 25 x 3
= 2 x 3 x 7
= 3 x 3 x 3 x 3 or 34
= 2 x 2 x 2 x 7 or 23 x 7
= 2 x 2 x 3 x 3 x 3 or 22 x 33
= 2 x 2 x 3 x 5 x 7 or 22 x 3 x 5x7
= 22 x 32 5 x 7
= 2 x 2 x 2 x 2 x 3 x 3 or 24 x 32
27.
Finding GCF andLCM
Greatest Common Factor (GCF)
- is the largest divisor of the
numbers in a set
Least Common Multiple (LCM)
- is the smallest number that can be
divided by each number in a set
28.
Finding GCF bycontinuous division
method
24 and 36
24 ÷ =
36 ÷ =
Common factors = 2 x 2 x3
GCF = 2 x 2 x 3 = 12
12
18
÷
÷
2
2
=6
=9
÷
÷
3
3
=2
=3
2
2
29.
Finding LCM bycontinuous division
method
24 and 36
24 ÷ =
36 ÷ =
Common factors = 2 x 2 x 3
Uncommon Factors (end part)= 2 x 3
LCM (common x uncommon factors)
= 2 x 2 x 3 x 2 x 3
= 72
12
18
÷
÷
2
2
=6
=9
÷
÷
3
3
=2
=3
2
2
30.
VI. Give theGCF of each set of numbers
1. 20 & 36
2 20 36
2 10 18
5 9
GCF = 2 x 2 = 4
LCM = 2 x 2 x 5 x 9 = 180
VI. Give the GCF of each set of numbers
31.
VI. Give theGCF of each set of numbers
2. 18 & 54
3. 32 & 56
4. 44 & 88
5. 63 & 84
6. 150 & 225
GCF= 22 x 3 x 3= 18
GCF= 2 x 2 x 2 = 8
GCF= 2 x 2 x 11 = 44
GCF= 3 x 7 = 21
GCF= 3 x 5 x 5= 75
32.
VII. Give theLCM of each set of numbers
1. 12 & 15
3 12 15
2 4 5
2 5
GCF = 3= 3
LCM = 3 x 2 x 2 x 5 = 60
33.
VI. Give theLCM of each set of numbers
2. 14 & 18
3. 32 & 56
4. 36 & 48
5. 27 & 63
6. 48 & 54
LCM = 2 x 3 x 3 x 7= 126
LCM = 2 x 2 x 2 x 2 x 2 x 3= 96
LCM = 2 x 2 x 2 x 2 x 3x 3= 144
LCM = 3 x 3 x 3 x 7= 189
LCM = 2 x 2 x 2 x 2 x 3 x 3 = 432
34.
Expressing a numberas a sum of two
prime numbers
Choose from the following list of prime numbers:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43,
47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97
ex. 32
= 13 + 19 or 29 + 3
64
= 3 + 61 or 47 + 17