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x+5
4
+
3x−2
3
−
2x+5
2
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5x−1
6
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µx+1+
x+2
2
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x+3
3
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x+4
4
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µ(x−3)(x+2)+
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3
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−(2x+5)ËÓкx=6
µ8(2x+1)−3(5x+1)=7ËÓкx=2
µ2(x+3)−4(x−3)=16ËÓкx=1
µx−(3+2(6−2x))=2(2x−5)ËÓкx=5
µ
1
4
−
1
x
=
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12
+
1
9
ËÓкx=18
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x
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x
3
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x
2
ËÓкx=15
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20
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12x−3
4
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ËÓкx=35/19
µ
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6
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x+2
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8
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1
4
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µ
2x
15
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3x−5
20
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x
5
−3ËÓкx=15
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µ1−
x+1
6
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x
2
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3
ËÓкx=7/6
µ
x
6
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2x−1
6
−
1
3
2
5
−
x
3
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µ
x+5
3
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x−3
2
=
x+5
5
−
3x
15
ËÓкx=1
µ3x2
−75=0ËÓкx=5Ýx=−5
µ7x2
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µ7x2
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µ2x2
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µ
x2
3
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x2
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6
ËÓкx=0Ýx=18
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x2
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3
−
x2
+1
4
=1−
x+7
12
ËÓкx=0Ýx=−1
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x2
−1
3
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=
x2
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2
ËÓкx=4Ýx=4/5
Òµ
1
2
x−1
1
2
x+1=(x+1)2
−9ËÓкx=2Ýx=−14/3
µ
1
2
(x−1)2
−
1
4
(x+1)2
=4−xËÓкx=5Ýx=−3
Óµ(x+4)2
−(2x−1)2
=8xËÓкx=3Ýx=−5/3
Ôµ2(2−x)(3x+1)−(1−2x)(x+3)+24=0ËÓкx=5Ýx=−5/4
Õµ
(3x−1)2
4
−
(2x+1)2
9
=
125
36
ËÓкx=2Ýx=−12/13
Öµ
2x−1
3
=
2(2x+1)
5
ËÓкx=−11/2
×µ
x−2
6
−
2(x+1)
6
−
x−1
2
=
−5
2
ËÓкx=7/2
ص
3(x+1)
24
−
x−1
6
−
x+3
5
=−2ËÓкx=7
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