Basic Geometry Unit 11.4 – Surface Area of Prisms and Cylinders
Surface Area The amount of material it would take to cover a geometric solid is called the  surface area . If you “unfold” a geometric figure, the result is a  net .
Surface Area of a Prism:  SA = Ph + 2B B is the Area of the Polygon Base h is the height of the prism P is the perimeter of the polygon h B B B h P
Surface of a Cylinder: SA = 2 π rh + 2 π r 2 π r 2  is the area of the  Circle Base h B B B h C h is the height of the cylinder 2π r  is the circumference of the Circle Base
Find the surface area of each solid. 16 cm 8 cm 25 cm 14 ft. 7 ft.
Questions? Homework 11.4 pg 576 #3-19

11.4 notes

  • 1.
    Basic Geometry Unit11.4 – Surface Area of Prisms and Cylinders
  • 2.
    Surface Area Theamount of material it would take to cover a geometric solid is called the surface area . If you “unfold” a geometric figure, the result is a net .
  • 3.
    Surface Area ofa Prism: SA = Ph + 2B B is the Area of the Polygon Base h is the height of the prism P is the perimeter of the polygon h B B B h P
  • 4.
    Surface of aCylinder: SA = 2 π rh + 2 π r 2 π r 2 is the area of the Circle Base h B B B h C h is the height of the cylinder 2π r is the circumference of the Circle Base
  • 5.
    Find the surfacearea of each solid. 16 cm 8 cm 25 cm 14 ft. 7 ft.
  • 6.