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Electrical Circuits
1- Phase AC Circuits
Prof. Poonam Sarawgi
EED, GGITS
Prof. Poonam Sarawgi, EED, GGITS
AC Fundamentals
Previously you learned that DC sources have fixed polarities and constant
magnitudes and thus produce currents with constant value and unchanging
direction
In contrast, the voltages of ac sources alternate in polarity and vary in
magnitude and thus produce currents that vary in magnitude and alternate in
direction.
2
Prof. Poonam Sarawgi, EED, GGITS
Chapter (15): AC Fundamentals
Sinusoidal ac Voltage
One complete variation is referred to as a cycle.
Starting at zero,
the voltage increases to a positive peak amplitude,
decreases to zero,
changes polarity,
increases to a negative peak amplitude,
then returns again to zero.
Since the waveform repeats itself at regular intervals, it is called a periodic signal.
Symbol for an ac Voltage Source
Lowercase letter e is used
to indicate that the voltage varies with time.
3
Prof. Poonam Sarawgi, EED, GGITS
Sinusoidal ac Current
During the first half-cycle, the
source voltage is positive
Therefore, the current is in the
clockwise direction.
During the second half-cycle, the
voltage polarity reverses
Therefore, the current is in the
counterclockwise direction.
Since current is proportional to voltage, its
shape is also sinusoidal
4
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 5
Sinusoidal Alternating Quantity
Alternating quantity that varies
according to sin of angle .
The instantaneous value of a sine-wave voltage for any
angle of rotation is expressed in the formula:
V= Vm sin
is the angle
Vm = the maximum voltage value
V = the instantaneous value of voltage at angle .
5
Prof. Poonam Sarawgi, EED, GGITS
Generating ac Voltages (Method A)
One way to generate an ac voltage is to rotate a coil of wire at constant
angular velocity in a fixed magnetic field
The magnitude of the resulting voltage is proportional to the rate at which flux
lines are cut
its polarity is dependent on the direction the coil sides move through the field.
6
Prof. Poonam Sarawgi, EED, GGITS
Generating ac Voltages
Since the coil rotates continuously, the voltage produced will be a repetitive,
Time Scales Often we need to scale the output voltage in time.
The length of time required to generate one cycle depends on the
velocity of rotation.
600 revolutions in 1 minute = 600 rev / 60 s
= 10 revolutions in 1 second.
The time for 1 revolution = one-tenth of a second
= 100 ms
7
Prof. Poonam Sarawgi, EED, GGITS
AC waveforms may also be created electronically using function (or signal)
generators.
With function generators, you are not limited to sinusoidal ac. gear.
Generating ac Voltages (Method B)
The unit of Figure can produce a variety of variable-frequency waveforms,
including sinusoidal, square wave, triangular, and so on.
Waveforms such as these are commonly used to test electronic
8
Prof. Poonam Sarawgi, EED, GGITS
Instantaneous Value
As the coil voltage changes from instant to instant. The value of voltage at any
point on the waveform is referred to as its instantaneous value.
The voltage has a peak value of 40 volts
The cycle time of 6 ms.
✔ at t = 0 ms, the voltage is zero.
✔ at t=0.5 ms, the voltage is 20V.
9
Prof. Poonam Sarawgi, EED, GGITS
Voltage and Current Conventions for ac
First, we assign reference polarities for the source and a reference direction for
the current.
For current, we use the convention that
when i has a positive value, its actual
direction is the same as the reference
arrow,
and when i has a negative value, its actual
direction is opposite to that of the
reference.
We then use the convention that, when e has a positive value, its actual polarity is the
same as the reference polarity, and when e has a negative value, its actual polarity is
opposite to that of the reference.
10
Prof. Poonam Sarawgi, EED, GGITS
Voltage and Current Conventions for ac
11
‫ﻗﻧﺎوي‬ ‫أﺳﺎﻣﺔ‬ .‫–د‬ ‫اﻟﺗﺄﯾﯾد‬ ‫وﻛﺳب‬ ‫اﻟدﻋوة‬
12
Prof. Poonam Sarawgi, EED, GGITS
Attributes of Periodic Waveforms
Periodic waveforms (i.e., waveforms that repeat at regular intervals), regardless
of their wave shape, may be described by a group of attributes such as:
✔ Frequency, Period, Amplitude, Peak value.
Frequency: The number of cycles per second of a waveform is defined
Frequency is denoted by the lower-case letter f.
In the SI system, its unit is the hertz (Hz, named in honor of pioneer researcher Heinrich
Hertz, 1857–1894).
12
Prof. Poonam Sarawgi, EED, GGITS
Attributes of Periodic Waveforms
Frequency Ranges:
The range of frequencies is huge.
✔ Power line frequencies, for example, are 60 Hz in North America and 50 Hz in
India, many other parts of the world.
✔ Audible sound frequencies range from about 20 Hz to about 20 kHz.
✔ The standard AM radio band occupies from 550 kHz to 1.6 MHz
✔ The FM band extends from 88 MHz to 108 MHz.
✔ TV transmissions occupy several bands in the 54-MHz to 890-MHz range.
✔ Above 300 GHz are optical and X-ray frequencies.
13
Prof. Poonam Sarawgi, EED, GGITS
Attributes of Periodic Waveforms
Period:
It is the inverse of frequency.
The period, T, of a waveform, is the duration of one cycle.
The period of a waveform can be measured between any two corresponding
points ( Often it is measured between zero points because they are easy to
establish on an oscilloscope trace).
14
Prof. Poonam Sarawgi, EED, GGITS
Attributes of Periodic Waveforms
Amplitude , Peak-Value, and Peak-to-Peak Value
The amplitude of a sine wave is the distance
from its average to its peak.
Amplitude (Em):
It is measured between minimum and maximum peaks.
Peak-to-Peak Value (Ep-p):
Peak Value
The peak value of a voltage or current is its maximum
value with respect to zero.
In this figure : Peak voltage = E + Em
15
Prof. Poonam Sarawgi, EED, GGITS
16
Prof. Poonam Sarawgi, EED, GGITS
The Basic Sine Wave Equation
The voltage produced by the previously described generator is:
• Em: the maximum coil voltage and
• α : the instantaneous angular position of the coil.
For a given generator and rotational velocity, Em is constant.)
Note that a 0° represents the horizontal position of the coil and that one
complete cycle corresponds to 360°.
17
Prof. Poonam Sarawgi, EED, GGITS
Angular Velocity (ω)
The rate at which the generator coil rotates is called its angular velocity
When you know the angular velocity of a coil and the length of time that it has
rotated, you can compute the angle through which it has turned using:
If the coil rotates through an angle of 30° in one second, its
angular velocity is 30° per second.
18
Prof. Poonam Sarawgi, EED, GGITS
Radian Measure
In practice, q is usually expressed in radians per second,
Radians and degrees are related by :
For Conversion:
19
Prof. Poonam Sarawgi, EED, GGITS
Relationship between ω, T, and f
Earlier you learned that one cycle of sine wave may be represented as either:
Substituting these into:
Sinusoidal Voltages and Currents as Functions of Time:
We could replace the angle α as:
20
Prof. Poonam Sarawgi, EED, GGITS
21
Prof. Poonam Sarawgi, EED, GGITS
22
Prof. Poonam Sarawgi, EED, GGITS
23
Prof. Poonam Sarawgi, EED, GGITS
24
Prof. Poonam Sarawgi, EED, GGITS
Voltages and Currents with Phase Shifts
If a sine wave does not pass through zero at t =0 s, it has a phase shift.
Waveforms may be shifted to the left or to the right
25
Prof. Poonam Sarawgi, EED, GGITS
26
Prof. Poonam Sarawgi, EED, GGITS
Introduction to Phasors
A phasor is a rotating line whose projection on a vertical axis can be used
to represent sinusoidally varying quantities.
To get at the idea, consider the red line of length Vm shown in Figure :
The vertical projection of this line (indicated in dotted red) is :
v =
By assuming that the phasor rotates at angular velocity of ω rad/s in the
counterclockwise direction
27
Prof. Poonam Sarawgi, EED, GGITS
Introduction to Phasors
28
Prof. Poonam Sarawgi, EED, GGITS
Introduction to Phasors
29
Prof. Poonam Sarawgi, EED, GGITS
Shifted Sine Waves Phasor Representation
30
Prof. Poonam Sarawgi, EED, GGITS
Phasor Difference
Phase difference refers to the angular displacement between different
waveforms of the same frequency.
The terms lead and lag can be understood in terms of phasors. If you observe
phasors rotating as in Figure, the one that you see passing first is leading and the
other is lagging.
31
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 32
Expressing Alternating Quantaties
• In AC system, alternating current and voltage varies
from instant to instant.
• Three ways to express
– Peak Value
– Average Value
– RMS value
32
Prof. Poonam Sarawgi, EED, GGITS
AC Waveforms and Average Value
Since ac quantities constantly change its value, we need one single numerical
value that truly represents a waveform over its complete cycle.
Average Values:
For waveforms, the process is conceptually the same. You
can sum the instantaneous values over a full cycle, then
divide by the number of points used.
The trouble with this approach is that waveforms do not
consist of discrete values.
To find the average of a set of marks for example, you add
them, then divide by the number of items summed.
Average in Terms of the Area Under a Curve:
Or use area
33
Prof. Poonam Sarawgi, EED, GGITS
To find the average value of a waveform, divide the area under the waveform by
the length of its base.
Areas above the axis are counted as positive, while areas below the axis are
counted as negative.
This approach is valid regardless of waveshape.
AC Waveforms and Average Value
Average values are also called dc values, because dc meters indicate average
values rather than instantaneous values.
34
Average Value
Prof. Poonam Sarawgi, EED, GGITS
35
The Effective (rms) Value
Prof. Poonam Sarawgi, EED, GGITS
36
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 37
R.M.S. Value
Root mean square value is effective value of
varying voltage or current.
It is equivalent steady DC value that gives the same effect.
Two methods of finding RMS value
Graphical Method
Analytical Method
37
R.M.S. Value
Prof. Poonam Sarawgi, EED, GGITS
38
Prof. Poonam Sarawgi, EED, GGITS
39
Note:
Three processes are done on the AC current in the above derivation to find its effective
value, these are:
1. The AC current is squared.
2. The average value of the squared current is adopted.
3. The effective current determined by finding the square root of the mean of the
squared current.
Hence, the effective value of the AC sinusoidal current is “the root of the mean of its
square value, so it is known as the rms value”.
Prof. Poonam Sarawgi, EED, GGITS
40
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 41
Peak Factor
Ratio of the Maximum value to the R.M.S. value of an alternating quantity§
It is denoted
by
Where K = 1.4
§Peak factor is also called the crest
factor or amplitude factor.
41
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 42
Form Factor
Form Factor is ratio of R.M.S. value to the average value
of an alternating quantity. It is denoted by Kf
Where Kf =
1.11
42
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 43
A.C. Circuit
§ Circuits in which currents and voltages vary
sinusoidally, ie vary with time are called A.C. circuits.
§All A.C. circuits are made up of combination of resistance R
, inductance L and capacitance C.
§The circuit elements R,L and C are called circuit
parameters.
§ To study a general A.C. circuit it is necessary to
consider the effect of each separately.
43
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 44
Purely Resistive Circuit
§ In purely resistive circuits, all the power is
dissipated by resistors.
– Voltage and current in same phase.
For purely resistive circuits, the voltage and current are in
phase
with each other .
44
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 45
Phasor and Wave Diagram of
Purely Resistive Circuit
Average power consumed
over a complete cycle
P= Vrms I
rms
P= VI
45
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 46
Purely Inductive Circuit
§ In purely inductive circuits, current lags the voltage by an
angle of 90
– No power consumed in pure inductive circuit
46
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 47
Phasor and Wave Diagram of
Purely Inductive Circuit
Average power consumed
over
a complete cycle
P= zero
47
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 48
Purely Capacitive Circuit
§ In purely capacitive circuits, current leads the voltage
by an
angle of 90
– No power consumed in pure capactive circuit
48
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 49
Phasor and Wave Diagram of
Purely Capacitive Circuit
Average power consumed
over a complete cycle
P= zero
49
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 50
A.C. Series
Circuit
• In actual practice, A.C. circuit contain two or
more than two components (R,L,C) connected
in series or parallel.
– Three types of A.C. series circuits
• R-L series circuit
• R-C series circuit
• R-L-C series circuit
50
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 51
R-L Series
Circuit
This circuit contains a resistance R and an inductance L
in series Let V = supply voltage
I = circuit current
VR= voltage drop across R = IR
VL = voltage drop across L = IXL= 2πfLI
ΦL = phase angle between I and V
Since I is common to both elements R and L, this is used
as
reference phasor.
The voltage VR is in phase with I and VL leads I by 90
.
The voltage V is the phasor sum of VR and VL
51
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 52
Phasor Diagram of R-L
Series Circuit
The triangle having VR
,VL
and V as its sides is called voltage triangle for a series R-L
circuit.
The phase angle ΦL
between the supply voltage V and the circuit
current I is the angle between the hypotenuse and the side VR
.
Itis seen that the current I is lagging behind the voltage V in an R-L circuit.
V2
= V2R
+ V2L
V2
=(RI)2
+
(XL
I)2
V2
/I2
=R2
+ X2L
V/I = √
(R2
+X2L
) Z = √
(R2
+ X2
)
L L 52
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 53
Impedance Triangle For
R-L Series Circuit
§ If the length of each side of the voltage triangle is divided by current
I,
the impedance triangle is obtained .
§ The following results may be found from an impedance triangle for a
series R
-L circuit:
Z = √(R2
+X2
)
L L
R= ZL
cosΦL
XL
=ZL
sinΦ
L
tanΦL
=X
/R
L
53
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 54
Phasor and Wave Diagram of
R-L Series Circuit
Average power consumed
over a
complete cycle
P= Vrms Irms
Cos P= V I
Cos
54
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 55
R-C Series
Circuit
This circuit contains a resistance R and a capacitance C in
series
Let V = supply voltage
I = circuit current
V
R
= voltage drop across R = IR
VC
= voltage drop across C =IXC= I/2πfC
ΦC = phase angle between I and V
The voltage VR is in phase with I and VC lags I by
90° . The voltage sum is V = VR + VC
55
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 56
Phasor Diagram of R-C
Series Circuit
The triangle having VR
,VC
and V as its sides is called voltage triangle for a series R-C circuit.
The phase angle ΦC
between the supply voltage V and the circuit
current I is the angle between the hypotenuse and the side VR
.
Itis seen that the current I is leading behind the voltage V in an R-C circuit.
V2
= V2R
+ V2C
V2
=(RI)2
+(XC
I)2
V2
/I2
=R2
+ X2C
V/I = √
(R2
+X2C
)
Z = √(R2
+ X2
)
C C
Z is called the impedance of a series R-C circuit
56
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 57
Impedance Triangle For
R-C Series Circuit
•
§
If the length of each side of the voltage
triangle
is divided by current I , the
impedance triangle
. is obtained
•
§
The following results may be found from an impedance triangle for a
.series R-C circuit
•
Z = √(R2
+X2
)
•
c
c
•
R= Zc
cosΦc
•
Xc
=Zc
sinΦ
c
tanΦc
=X
/R
c
57
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 58
Phasor and Wave Diagram of
R-C Series Circuit
Average power consumed
over a
complete cycle
P= Vrms Irms
Cos P= V I
Cos
58
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 59
R-L-C Series
Circuit
§ A circuit having R, L and C in series is called a R-L-Cseries
circuit
.
§ Current is used as reference phasor in series circuit since it is
common to all
the elements of circuit.
§ There are four voltages
VR
in phase with I
VL
leading Iby
900
VC
lagging
Iby 900
Totalvoltage V =V R
+V L
+V 59
Phasor Diagram of
R-L-C Series Circuit
Prof. Poonam Sarawgi, EED, GGITS
60
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 61
When XL> XC, the circuit is predominantly
. Inductive
Inductive circuits cause the current ‘lag’ the
.voltage
V=I √[R2
+ ( XL
- XC
)2
]
Z = √[R2
+( XL
- XC
)2
]
When XL < XC the circuit is predominately
Capacitive.
Capacitive circuits cause the current to ‘lead’ the
voltage.
V=I √[R2
+ ( Xc
- XL
)2
]
Z = √[R2
+( Xc
- XL
)2
]
61
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 62
Impedance Triangle For
R-L-C Series Circuit
If the length of each side of a voltage triangle isdivided by
current I, the impedance triangle is obtained. The impedence
triangle for series R-L-C circuit.
XC>
XL
XL>
XC
62
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 63
Question For Practice
Q: A coil resistance 10 ohms and inductance 114.7mH is connected in
series with capacitor of 159.16 microFarads across a 200V, 50 Hz
supply.
Calculate
(i) Inductive reactance
(ii) Capacitive reactance
(iii) Impedance
(iv) Current
(v) Voltage across coil and capacitor
63
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 64
Resonance
• Resonance is a condition in an RLC circuit in which the
capacitive and inductive reactance are equal in
magnitude, thereby resulting in a purely resistive
impedance.
• At resonance, the impedance consists only
resistive component R.
• The value of current will be maximum since the total
impedance is minimum.
• The voltage and current are in phase.
• Maximum power occurs at resonance since the power
factor is unity
• Resonance circuits are useful for constructing
filters and used in many application.
64
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 65
Resonance Frequency
§ Resonance frequency is the frequency where the
condition of resonance occur.
§Also known as center frequency.
65
‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 66
Resonance
Curve
•The curve obtained by plotting a graph
between current and frequency is
known as resonance curve or response
curve .
•The current has a maximum
value at resonance given by
Imax = V/R.
•The value of I decreases on either sides
of the resonance
66

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1- Phase AC CIRCUITS.pdf for electrical circuits

  • 1. Electrical Circuits 1- Phase AC Circuits Prof. Poonam Sarawgi EED, GGITS
  • 2. Prof. Poonam Sarawgi, EED, GGITS AC Fundamentals Previously you learned that DC sources have fixed polarities and constant magnitudes and thus produce currents with constant value and unchanging direction In contrast, the voltages of ac sources alternate in polarity and vary in magnitude and thus produce currents that vary in magnitude and alternate in direction. 2
  • 3. Prof. Poonam Sarawgi, EED, GGITS Chapter (15): AC Fundamentals Sinusoidal ac Voltage One complete variation is referred to as a cycle. Starting at zero, the voltage increases to a positive peak amplitude, decreases to zero, changes polarity, increases to a negative peak amplitude, then returns again to zero. Since the waveform repeats itself at regular intervals, it is called a periodic signal. Symbol for an ac Voltage Source Lowercase letter e is used to indicate that the voltage varies with time. 3
  • 4. Prof. Poonam Sarawgi, EED, GGITS Sinusoidal ac Current During the first half-cycle, the source voltage is positive Therefore, the current is in the clockwise direction. During the second half-cycle, the voltage polarity reverses Therefore, the current is in the counterclockwise direction. Since current is proportional to voltage, its shape is also sinusoidal 4
  • 5. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 5 Sinusoidal Alternating Quantity Alternating quantity that varies according to sin of angle . The instantaneous value of a sine-wave voltage for any angle of rotation is expressed in the formula: V= Vm sin is the angle Vm = the maximum voltage value V = the instantaneous value of voltage at angle . 5
  • 6. Prof. Poonam Sarawgi, EED, GGITS Generating ac Voltages (Method A) One way to generate an ac voltage is to rotate a coil of wire at constant angular velocity in a fixed magnetic field The magnitude of the resulting voltage is proportional to the rate at which flux lines are cut its polarity is dependent on the direction the coil sides move through the field. 6
  • 7. Prof. Poonam Sarawgi, EED, GGITS Generating ac Voltages Since the coil rotates continuously, the voltage produced will be a repetitive, Time Scales Often we need to scale the output voltage in time. The length of time required to generate one cycle depends on the velocity of rotation. 600 revolutions in 1 minute = 600 rev / 60 s = 10 revolutions in 1 second. The time for 1 revolution = one-tenth of a second = 100 ms 7
  • 8. Prof. Poonam Sarawgi, EED, GGITS AC waveforms may also be created electronically using function (or signal) generators. With function generators, you are not limited to sinusoidal ac. gear. Generating ac Voltages (Method B) The unit of Figure can produce a variety of variable-frequency waveforms, including sinusoidal, square wave, triangular, and so on. Waveforms such as these are commonly used to test electronic 8
  • 9. Prof. Poonam Sarawgi, EED, GGITS Instantaneous Value As the coil voltage changes from instant to instant. The value of voltage at any point on the waveform is referred to as its instantaneous value. The voltage has a peak value of 40 volts The cycle time of 6 ms. ✔ at t = 0 ms, the voltage is zero. ✔ at t=0.5 ms, the voltage is 20V. 9
  • 10. Prof. Poonam Sarawgi, EED, GGITS Voltage and Current Conventions for ac First, we assign reference polarities for the source and a reference direction for the current. For current, we use the convention that when i has a positive value, its actual direction is the same as the reference arrow, and when i has a negative value, its actual direction is opposite to that of the reference. We then use the convention that, when e has a positive value, its actual polarity is the same as the reference polarity, and when e has a negative value, its actual polarity is opposite to that of the reference. 10
  • 11. Prof. Poonam Sarawgi, EED, GGITS Voltage and Current Conventions for ac 11
  • 12. ‫ﻗﻧﺎوي‬ ‫أﺳﺎﻣﺔ‬ .‫–د‬ ‫اﻟﺗﺄﯾﯾد‬ ‫وﻛﺳب‬ ‫اﻟدﻋوة‬ 12 Prof. Poonam Sarawgi, EED, GGITS Attributes of Periodic Waveforms Periodic waveforms (i.e., waveforms that repeat at regular intervals), regardless of their wave shape, may be described by a group of attributes such as: ✔ Frequency, Period, Amplitude, Peak value. Frequency: The number of cycles per second of a waveform is defined Frequency is denoted by the lower-case letter f. In the SI system, its unit is the hertz (Hz, named in honor of pioneer researcher Heinrich Hertz, 1857–1894). 12
  • 13. Prof. Poonam Sarawgi, EED, GGITS Attributes of Periodic Waveforms Frequency Ranges: The range of frequencies is huge. ✔ Power line frequencies, for example, are 60 Hz in North America and 50 Hz in India, many other parts of the world. ✔ Audible sound frequencies range from about 20 Hz to about 20 kHz. ✔ The standard AM radio band occupies from 550 kHz to 1.6 MHz ✔ The FM band extends from 88 MHz to 108 MHz. ✔ TV transmissions occupy several bands in the 54-MHz to 890-MHz range. ✔ Above 300 GHz are optical and X-ray frequencies. 13
  • 14. Prof. Poonam Sarawgi, EED, GGITS Attributes of Periodic Waveforms Period: It is the inverse of frequency. The period, T, of a waveform, is the duration of one cycle. The period of a waveform can be measured between any two corresponding points ( Often it is measured between zero points because they are easy to establish on an oscilloscope trace). 14
  • 15. Prof. Poonam Sarawgi, EED, GGITS Attributes of Periodic Waveforms Amplitude , Peak-Value, and Peak-to-Peak Value The amplitude of a sine wave is the distance from its average to its peak. Amplitude (Em): It is measured between minimum and maximum peaks. Peak-to-Peak Value (Ep-p): Peak Value The peak value of a voltage or current is its maximum value with respect to zero. In this figure : Peak voltage = E + Em 15
  • 16. Prof. Poonam Sarawgi, EED, GGITS 16
  • 17. Prof. Poonam Sarawgi, EED, GGITS The Basic Sine Wave Equation The voltage produced by the previously described generator is: • Em: the maximum coil voltage and • α : the instantaneous angular position of the coil. For a given generator and rotational velocity, Em is constant.) Note that a 0° represents the horizontal position of the coil and that one complete cycle corresponds to 360°. 17
  • 18. Prof. Poonam Sarawgi, EED, GGITS Angular Velocity (ω) The rate at which the generator coil rotates is called its angular velocity When you know the angular velocity of a coil and the length of time that it has rotated, you can compute the angle through which it has turned using: If the coil rotates through an angle of 30° in one second, its angular velocity is 30° per second. 18
  • 19. Prof. Poonam Sarawgi, EED, GGITS Radian Measure In practice, q is usually expressed in radians per second, Radians and degrees are related by : For Conversion: 19
  • 20. Prof. Poonam Sarawgi, EED, GGITS Relationship between ω, T, and f Earlier you learned that one cycle of sine wave may be represented as either: Substituting these into: Sinusoidal Voltages and Currents as Functions of Time: We could replace the angle α as: 20
  • 21. Prof. Poonam Sarawgi, EED, GGITS 21
  • 22. Prof. Poonam Sarawgi, EED, GGITS 22
  • 23. Prof. Poonam Sarawgi, EED, GGITS 23
  • 24. Prof. Poonam Sarawgi, EED, GGITS 24
  • 25. Prof. Poonam Sarawgi, EED, GGITS Voltages and Currents with Phase Shifts If a sine wave does not pass through zero at t =0 s, it has a phase shift. Waveforms may be shifted to the left or to the right 25
  • 26. Prof. Poonam Sarawgi, EED, GGITS 26
  • 27. Prof. Poonam Sarawgi, EED, GGITS Introduction to Phasors A phasor is a rotating line whose projection on a vertical axis can be used to represent sinusoidally varying quantities. To get at the idea, consider the red line of length Vm shown in Figure : The vertical projection of this line (indicated in dotted red) is : v = By assuming that the phasor rotates at angular velocity of ω rad/s in the counterclockwise direction 27
  • 28. Prof. Poonam Sarawgi, EED, GGITS Introduction to Phasors 28
  • 29. Prof. Poonam Sarawgi, EED, GGITS Introduction to Phasors 29
  • 30. Prof. Poonam Sarawgi, EED, GGITS Shifted Sine Waves Phasor Representation 30
  • 31. Prof. Poonam Sarawgi, EED, GGITS Phasor Difference Phase difference refers to the angular displacement between different waveforms of the same frequency. The terms lead and lag can be understood in terms of phasors. If you observe phasors rotating as in Figure, the one that you see passing first is leading and the other is lagging. 31
  • 32. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 32 Expressing Alternating Quantaties • In AC system, alternating current and voltage varies from instant to instant. • Three ways to express – Peak Value – Average Value – RMS value 32
  • 33. Prof. Poonam Sarawgi, EED, GGITS AC Waveforms and Average Value Since ac quantities constantly change its value, we need one single numerical value that truly represents a waveform over its complete cycle. Average Values: For waveforms, the process is conceptually the same. You can sum the instantaneous values over a full cycle, then divide by the number of points used. The trouble with this approach is that waveforms do not consist of discrete values. To find the average of a set of marks for example, you add them, then divide by the number of items summed. Average in Terms of the Area Under a Curve: Or use area 33
  • 34. Prof. Poonam Sarawgi, EED, GGITS To find the average value of a waveform, divide the area under the waveform by the length of its base. Areas above the axis are counted as positive, while areas below the axis are counted as negative. This approach is valid regardless of waveshape. AC Waveforms and Average Value Average values are also called dc values, because dc meters indicate average values rather than instantaneous values. 34
  • 35. Average Value Prof. Poonam Sarawgi, EED, GGITS 35
  • 36. The Effective (rms) Value Prof. Poonam Sarawgi, EED, GGITS 36
  • 37. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 37 R.M.S. Value Root mean square value is effective value of varying voltage or current. It is equivalent steady DC value that gives the same effect. Two methods of finding RMS value Graphical Method Analytical Method 37
  • 38. R.M.S. Value Prof. Poonam Sarawgi, EED, GGITS 38
  • 39. Prof. Poonam Sarawgi, EED, GGITS 39
  • 40. Note: Three processes are done on the AC current in the above derivation to find its effective value, these are: 1. The AC current is squared. 2. The average value of the squared current is adopted. 3. The effective current determined by finding the square root of the mean of the squared current. Hence, the effective value of the AC sinusoidal current is “the root of the mean of its square value, so it is known as the rms value”. Prof. Poonam Sarawgi, EED, GGITS 40
  • 41. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 41 Peak Factor Ratio of the Maximum value to the R.M.S. value of an alternating quantity§ It is denoted by Where K = 1.4 §Peak factor is also called the crest factor or amplitude factor. 41
  • 42. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 42 Form Factor Form Factor is ratio of R.M.S. value to the average value of an alternating quantity. It is denoted by Kf Where Kf = 1.11 42
  • 43. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 43 A.C. Circuit § Circuits in which currents and voltages vary sinusoidally, ie vary with time are called A.C. circuits. §All A.C. circuits are made up of combination of resistance R , inductance L and capacitance C. §The circuit elements R,L and C are called circuit parameters. § To study a general A.C. circuit it is necessary to consider the effect of each separately. 43
  • 44. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 44 Purely Resistive Circuit § In purely resistive circuits, all the power is dissipated by resistors. – Voltage and current in same phase. For purely resistive circuits, the voltage and current are in phase with each other . 44
  • 45. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 45 Phasor and Wave Diagram of Purely Resistive Circuit Average power consumed over a complete cycle P= Vrms I rms P= VI 45
  • 46. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 46 Purely Inductive Circuit § In purely inductive circuits, current lags the voltage by an angle of 90 – No power consumed in pure inductive circuit 46
  • 47. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 47 Phasor and Wave Diagram of Purely Inductive Circuit Average power consumed over a complete cycle P= zero 47
  • 48. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 48 Purely Capacitive Circuit § In purely capacitive circuits, current leads the voltage by an angle of 90 – No power consumed in pure capactive circuit 48
  • 49. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 49 Phasor and Wave Diagram of Purely Capacitive Circuit Average power consumed over a complete cycle P= zero 49
  • 50. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 50 A.C. Series Circuit • In actual practice, A.C. circuit contain two or more than two components (R,L,C) connected in series or parallel. – Three types of A.C. series circuits • R-L series circuit • R-C series circuit • R-L-C series circuit 50
  • 51. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 51 R-L Series Circuit This circuit contains a resistance R and an inductance L in series Let V = supply voltage I = circuit current VR= voltage drop across R = IR VL = voltage drop across L = IXL= 2πfLI ΦL = phase angle between I and V Since I is common to both elements R and L, this is used as reference phasor. The voltage VR is in phase with I and VL leads I by 90 . The voltage V is the phasor sum of VR and VL 51
  • 52. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 52 Phasor Diagram of R-L Series Circuit The triangle having VR ,VL and V as its sides is called voltage triangle for a series R-L circuit. The phase angle ΦL between the supply voltage V and the circuit current I is the angle between the hypotenuse and the side VR . Itis seen that the current I is lagging behind the voltage V in an R-L circuit. V2 = V2R + V2L V2 =(RI)2 + (XL I)2 V2 /I2 =R2 + X2L V/I = √ (R2 +X2L ) Z = √ (R2 + X2 ) L L 52
  • 53. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 53 Impedance Triangle For R-L Series Circuit § If the length of each side of the voltage triangle is divided by current I, the impedance triangle is obtained . § The following results may be found from an impedance triangle for a series R -L circuit: Z = √(R2 +X2 ) L L R= ZL cosΦL XL =ZL sinΦ L tanΦL =X /R L 53
  • 54. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 54 Phasor and Wave Diagram of R-L Series Circuit Average power consumed over a complete cycle P= Vrms Irms Cos P= V I Cos 54
  • 55. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 55 R-C Series Circuit This circuit contains a resistance R and a capacitance C in series Let V = supply voltage I = circuit current V R = voltage drop across R = IR VC = voltage drop across C =IXC= I/2πfC ΦC = phase angle between I and V The voltage VR is in phase with I and VC lags I by 90° . The voltage sum is V = VR + VC 55
  • 56. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 56 Phasor Diagram of R-C Series Circuit The triangle having VR ,VC and V as its sides is called voltage triangle for a series R-C circuit. The phase angle ΦC between the supply voltage V and the circuit current I is the angle between the hypotenuse and the side VR . Itis seen that the current I is leading behind the voltage V in an R-C circuit. V2 = V2R + V2C V2 =(RI)2 +(XC I)2 V2 /I2 =R2 + X2C V/I = √ (R2 +X2C ) Z = √(R2 + X2 ) C C Z is called the impedance of a series R-C circuit 56
  • 57. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 57 Impedance Triangle For R-C Series Circuit • § If the length of each side of the voltage triangle is divided by current I , the impedance triangle . is obtained • § The following results may be found from an impedance triangle for a .series R-C circuit • Z = √(R2 +X2 ) • c c • R= Zc cosΦc • Xc =Zc sinΦ c tanΦc =X /R c 57
  • 58. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 58 Phasor and Wave Diagram of R-C Series Circuit Average power consumed over a complete cycle P= Vrms Irms Cos P= V I Cos 58
  • 59. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 59 R-L-C Series Circuit § A circuit having R, L and C in series is called a R-L-Cseries circuit . § Current is used as reference phasor in series circuit since it is common to all the elements of circuit. § There are four voltages VR in phase with I VL leading Iby 900 VC lagging Iby 900 Totalvoltage V =V R +V L +V 59
  • 60. Phasor Diagram of R-L-C Series Circuit Prof. Poonam Sarawgi, EED, GGITS 60
  • 61. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 61 When XL> XC, the circuit is predominantly . Inductive Inductive circuits cause the current ‘lag’ the .voltage V=I √[R2 + ( XL - XC )2 ] Z = √[R2 +( XL - XC )2 ] When XL < XC the circuit is predominately Capacitive. Capacitive circuits cause the current to ‘lead’ the voltage. V=I √[R2 + ( Xc - XL )2 ] Z = √[R2 +( Xc - XL )2 ] 61
  • 62. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 62 Impedance Triangle For R-L-C Series Circuit If the length of each side of a voltage triangle isdivided by current I, the impedance triangle is obtained. The impedence triangle for series R-L-C circuit. XC> XL XL> XC 62
  • 63. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 63 Question For Practice Q: A coil resistance 10 ohms and inductance 114.7mH is connected in series with capacitor of 159.16 microFarads across a 200V, 50 Hz supply. Calculate (i) Inductive reactance (ii) Capacitive reactance (iii) Impedance (iv) Current (v) Voltage across coil and capacitor 63
  • 64. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 64 Resonance • Resonance is a condition in an RLC circuit in which the capacitive and inductive reactance are equal in magnitude, thereby resulting in a purely resistive impedance. • At resonance, the impedance consists only resistive component R. • The value of current will be maximum since the total impedance is minimum. • The voltage and current are in phase. • Maximum power occurs at resonance since the power factor is unity • Resonance circuits are useful for constructing filters and used in many application. 64
  • 65. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 65 Resonance Frequency § Resonance frequency is the frequency where the condition of resonance occur. §Also known as center frequency. 65
  • 66. ‫اﻟﺣﻠواﻧﻰ‬ ‫ﺑﺎﺳم‬.‫د‬ – ‫اﻟﻣﺷروﻋﺎت‬ ‫إدارة‬ 66 Resonance Curve •The curve obtained by plotting a graph between current and frequency is known as resonance curve or response curve . •The current has a maximum value at resonance given by Imax = V/R. •The value of I decreases on either sides of the resonance 66