Experiment# Kinetics of an Iodine Clock Reaction 1- A color change wil.docxtodd401
Experiment# Kinetics of an Iodine Clock Reaction
1: A color change will occur in Kinetics of an Iodine Clock Reaction that signifies the end of a trial. What chemical change occurs that causes the color change?
2: The same amount of thiosulfate ion is added to each trail to delay the onset of the color change. Calculate the initial molarity of S2O3 2- in each trail given that each trail has 1.00mL of 0.010M Na2S2O3 and the total volume of 7.00mL.
Solution
In Iodine clock reaction, all the colourless reactants react to form iodine which is identified by starch indicatin by the formation of a blue-black colour after a some period of time.
The reactant are hydrogen peroxide which is identified using dilute sulphuric acid, small quantities of starch and sodium thiosulphate.
Hydrogen peroxide reacts with potassium iodide to form iodine.
H 2 O 2(aq) + 2I - (aq) + 2H + (aq) ------------> 2H 2 O (l) + I 2(aq)
The iodine formed reacts with sodium thiosulphate to form iodide ion
I 2 (aq) + Na 2 S 2 O 3(aq) ---------> 2NaI (aq) + S 4 O 6 2- (aq)
When all the sodium thioulphate is consumed then the left over iodine reacts with iodide to form triodide ion which reacts with starch indicator to form a blue-black colour complex.
I 2 + I - ----> I 3 - + starch -------> blue-black colour
The only source of thiosulphate ions is sodium thiosulphate so,
number of moles of thiosulphate = number of moles of sodium thiosulphate
Vol of Na 2 S 2 O 3 in lts = 0.001 lt
Molarity of Na 2 S 2 O 3 = 0.01 M
No. of moles of sodium thiosulphate = Molarity (mol/lt) of Na 2 S 2 O 3 X Vol of Na 2 S 2 O 3 in lts =
= 0.01 M x 0.001 lts = 10 -5 moles of Na 2 S 2 O 3 = 10 -5 moles of S 2 O 3 2- .
Total volume in lts = 0.007 lts
Molarity of thiosulphate initially = No. of moles of S 2 O 3 2- ./ total Vol in lts
= 10 -5 moles of S 2 O 3 2- ./ 0.007 lts = 1.428 x 10 -3 moles/lt or M of S 2 O 3 2- .
Initial molarity of S 2 O 3 2- .= 1.43 x 10 -3 M
.
Experiment# Kinetics of an Iodine Clock Reaction 1- A color change wil.docxtodd401
Experiment# Kinetics of an Iodine Clock Reaction
1: A color change will occur in Kinetics of an Iodine Clock Reaction that signifies the end of a trial. What chemical change occurs that causes the color change?
2: The same amount of thiosulfate ion is added to each trail to delay the onset of the color change. Calculate the initial molarity of S2O3 2- in each trail given that each trail has 1.00mL of 0.010M Na2S2O3 and the total volume of 7.00mL.
Solution
In Iodine clock reaction, all the colourless reactants react to form iodine which is identified by starch indicatin by the formation of a blue-black colour after a some period of time.
The reactant are hydrogen peroxide which is identified using dilute sulphuric acid, small quantities of starch and sodium thiosulphate.
Hydrogen peroxide reacts with potassium iodide to form iodine.
H 2 O 2(aq) + 2I - (aq) + 2H + (aq) ------------> 2H 2 O (l) + I 2(aq)
The iodine formed reacts with sodium thiosulphate to form iodide ion
I 2 (aq) + Na 2 S 2 O 3(aq) ---------> 2NaI (aq) + S 4 O 6 2- (aq)
When all the sodium thioulphate is consumed then the left over iodine reacts with iodide to form triodide ion which reacts with starch indicator to form a blue-black colour complex.
I 2 + I - ----> I 3 - + starch -------> blue-black colour
The only source of thiosulphate ions is sodium thiosulphate so,
number of moles of thiosulphate = number of moles of sodium thiosulphate
Vol of Na 2 S 2 O 3 in lts = 0.001 lt
Molarity of Na 2 S 2 O 3 = 0.01 M
No. of moles of sodium thiosulphate = Molarity (mol/lt) of Na 2 S 2 O 3 X Vol of Na 2 S 2 O 3 in lts =
= 0.01 M x 0.001 lts = 10 -5 moles of Na 2 S 2 O 3 = 10 -5 moles of S 2 O 3 2- .
Total volume in lts = 0.007 lts
Molarity of thiosulphate initially = No. of moles of S 2 O 3 2- ./ total Vol in lts
= 10 -5 moles of S 2 O 3 2- ./ 0.007 lts = 1.428 x 10 -3 moles/lt or M of S 2 O 3 2- .
Initial molarity of S 2 O 3 2- .= 1.43 x 10 -3 M
.
Worksheet for working out the number of moles of compounds. Pupils will need a data sheet or a list of relative atomic masses to be able to complete the questions.
1. Copper is above silver in the activity series. Thus Cu metal will.pdfvichu19891
1. Copper is above silver in the activity series. Thus Cu metal will displace Ag+ ions from
solution, forming Cu2+ ions and metallic Ag.
Observation: The reddish brown copper metal dissolves and silver metal precipitates out. The
colorless Ag+ solution turns blue due to Cu2+ ions formed.
2. Molecular equation:
Cu(s) + 2 AgNO3(aq) => 2 Ag(s) + Cu(NO3)2(aq)
3. Complete ionic equation (obtained by expanding soluble ions in molecular equation):
Cu(s) + 2 Ag+(aq) + 2 NO3-(aq) => 2 Ag(s) + Cu2+(aq) + 2 NO3-(aq)
4. Net ionic equation (obtained by cancelling common ions in complete ionic equation):
Cu(s) + 2 Ag+(aq) => 2 Ag(s) + Cu2+(aq)
Solution
1. Copper is above silver in the activity series. Thus Cu metal will displace Ag+ ions from
solution, forming Cu2+ ions and metallic Ag.
Observation: The reddish brown copper metal dissolves and silver metal precipitates out. The
colorless Ag+ solution turns blue due to Cu2+ ions formed.
2. Molecular equation:
Cu(s) + 2 AgNO3(aq) => 2 Ag(s) + Cu(NO3)2(aq)
3. Complete ionic equation (obtained by expanding soluble ions in molecular equation):
Cu(s) + 2 Ag+(aq) + 2 NO3-(aq) => 2 Ag(s) + Cu2+(aq) + 2 NO3-(aq)
4. Net ionic equation (obtained by cancelling common ions in complete ionic equation):
Cu(s) + 2 Ag+(aq) => 2 Ag(s) + Cu2+(aq).
Above 70 °C, sodium bicarbonate gradually decomposes into sodium car.pdfsanjeevtandonsre
Above 70 °C, sodium bicarbonate gradually decomposes into sodium carbonate, water and
carbon dioxide. The conversion is fast at 200 °C 2 NaHCO3 ? Na2CO3 + H2O + CO2
Solution
Above 70 °C, sodium bicarbonate gradually decomposes into sodium carbonate, water and
carbon dioxide. The conversion is fast at 200 °C 2 NaHCO3 ? Na2CO3 + H2O + CO2.
You need to put your electrons in the first one .pdfsanjeevtandonsre
You need to put your electrons in the first one: ClO2 + e- => ClO2- In the second
one, you have done nothing with the hydrogen. H2O2 => O2 + 2H+ + 2e- Now you must
multiply the first one by 2 to get the same number of electrons on both sides: 2ClO2 + 2e- =>
2ClO2- Now add the equations and eliminate the electrons: H2O2 + 2ClO2 => 2ClO2- + O2 +
2H+ This is now balanced. The charges are the same on both sides and the number of atoms of
each element is the same on both sides. The oxidizing agent is the one which gains electrons and
is itself reduced. So, yes, it is the ClO2. The reducing agent is the H2O2. This is itself oxidized
because it loses electrons to form H+.
Solution
You need to put your electrons in the first one: ClO2 + e- => ClO2- In the second
one, you have done nothing with the hydrogen. H2O2 => O2 + 2H+ + 2e- Now you must
multiply the first one by 2 to get the same number of electrons on both sides: 2ClO2 + 2e- =>
2ClO2- Now add the equations and eliminate the electrons: H2O2 + 2ClO2 => 2ClO2- + O2 +
2H+ This is now balanced. The charges are the same on both sides and the number of atoms of
each element is the same on both sides. The oxidizing agent is the one which gains electrons and
is itself reduced. So, yes, it is the ClO2. The reducing agent is the H2O2. This is itself oxidized
because it loses electrons to form H+..
More Related Content
Similar to 1) 0.1 M NaClIon expected to hydrolyze = Nil Sp.pdf
Worksheet for working out the number of moles of compounds. Pupils will need a data sheet or a list of relative atomic masses to be able to complete the questions.
1. Copper is above silver in the activity series. Thus Cu metal will.pdfvichu19891
1. Copper is above silver in the activity series. Thus Cu metal will displace Ag+ ions from
solution, forming Cu2+ ions and metallic Ag.
Observation: The reddish brown copper metal dissolves and silver metal precipitates out. The
colorless Ag+ solution turns blue due to Cu2+ ions formed.
2. Molecular equation:
Cu(s) + 2 AgNO3(aq) => 2 Ag(s) + Cu(NO3)2(aq)
3. Complete ionic equation (obtained by expanding soluble ions in molecular equation):
Cu(s) + 2 Ag+(aq) + 2 NO3-(aq) => 2 Ag(s) + Cu2+(aq) + 2 NO3-(aq)
4. Net ionic equation (obtained by cancelling common ions in complete ionic equation):
Cu(s) + 2 Ag+(aq) => 2 Ag(s) + Cu2+(aq)
Solution
1. Copper is above silver in the activity series. Thus Cu metal will displace Ag+ ions from
solution, forming Cu2+ ions and metallic Ag.
Observation: The reddish brown copper metal dissolves and silver metal precipitates out. The
colorless Ag+ solution turns blue due to Cu2+ ions formed.
2. Molecular equation:
Cu(s) + 2 AgNO3(aq) => 2 Ag(s) + Cu(NO3)2(aq)
3. Complete ionic equation (obtained by expanding soluble ions in molecular equation):
Cu(s) + 2 Ag+(aq) + 2 NO3-(aq) => 2 Ag(s) + Cu2+(aq) + 2 NO3-(aq)
4. Net ionic equation (obtained by cancelling common ions in complete ionic equation):
Cu(s) + 2 Ag+(aq) => 2 Ag(s) + Cu2+(aq).
Above 70 °C, sodium bicarbonate gradually decomposes into sodium car.pdfsanjeevtandonsre
Above 70 °C, sodium bicarbonate gradually decomposes into sodium carbonate, water and
carbon dioxide. The conversion is fast at 200 °C 2 NaHCO3 ? Na2CO3 + H2O + CO2
Solution
Above 70 °C, sodium bicarbonate gradually decomposes into sodium carbonate, water and
carbon dioxide. The conversion is fast at 200 °C 2 NaHCO3 ? Na2CO3 + H2O + CO2.
You need to put your electrons in the first one .pdfsanjeevtandonsre
You need to put your electrons in the first one: ClO2 + e- => ClO2- In the second
one, you have done nothing with the hydrogen. H2O2 => O2 + 2H+ + 2e- Now you must
multiply the first one by 2 to get the same number of electrons on both sides: 2ClO2 + 2e- =>
2ClO2- Now add the equations and eliminate the electrons: H2O2 + 2ClO2 => 2ClO2- + O2 +
2H+ This is now balanced. The charges are the same on both sides and the number of atoms of
each element is the same on both sides. The oxidizing agent is the one which gains electrons and
is itself reduced. So, yes, it is the ClO2. The reducing agent is the H2O2. This is itself oxidized
because it loses electrons to form H+.
Solution
You need to put your electrons in the first one: ClO2 + e- => ClO2- In the second
one, you have done nothing with the hydrogen. H2O2 => O2 + 2H+ + 2e- Now you must
multiply the first one by 2 to get the same number of electrons on both sides: 2ClO2 + 2e- =>
2ClO2- Now add the equations and eliminate the electrons: H2O2 + 2ClO2 => 2ClO2- + O2 +
2H+ This is now balanced. The charges are the same on both sides and the number of atoms of
each element is the same on both sides. The oxidizing agent is the one which gains electrons and
is itself reduced. So, yes, it is the ClO2. The reducing agent is the H2O2. This is itself oxidized
because it loses electrons to form H+..
PbSO4 is not generally soluble in water. It will .pdfsanjeevtandonsre
PbSO4 is not generally soluble in water. It will form aprecipicate Pb(OH)2 is
generally not soluble in water, athough morethan PbSO4. I hope this helps, Steve
Solution
PbSO4 is not generally soluble in water. It will form aprecipicate Pb(OH)2 is
generally not soluble in water, athough morethan PbSO4. I hope this helps, Steve.
pH is proportional to the cell potential and it i.pdfsanjeevtandonsre
pH is proportional to the cell potential and it is indicated by the Nernst equation
According to Nernst equation -if the reaction occurs in preence of acidic media - Ecell = E0(cell)
- 0.0592/n log 1/[H+] [because all other species are at standard conditions] Therefore - Ecell =
0.42 V - (0.0592/n) log 1/[H+] Let n = 1, then - 0 V = 0.42 V - 0.592 pH 0.0592 pH = 0.42
Therefore - pH = 0.42/0.0592 = 6.75
Solution
pH is proportional to the cell potential and it is indicated by the Nernst equation
According to Nernst equation -if the reaction occurs in preence of acidic media - Ecell = E0(cell)
- 0.0592/n log 1/[H+] [because all other species are at standard conditions] Therefore - Ecell =
0.42 V - (0.0592/n) log 1/[H+] Let n = 1, then - 0 V = 0.42 V - 0.592 pH 0.0592 pH = 0.42
Therefore - pH = 0.42/0.0592 = 6.75.
Nitration occurs through electrophilic addition o.pdfsanjeevtandonsre
Nitration occurs through electrophilic addition of aromatic rings by breaking one of
its aromatic bonds in order to attack the nitogen. The ring with more electron density will be
more likely to add NO2 groups in its meta position (the only position if another group is already
attached). When electrophillic addition occurs, the benzene ring would have to unfavorably
break its stable aromaticity to attack. However, the phenyl oxygen can donate its electrons to the
benzene ring, thus enriching it with electron density and stabilizing the positive charge. The
carbonyl group does nothing to stabilize the other benzene ring during its electrophilic addition.
In fact, the carbonyl group may as well have the opposite effect: the resonance structure of a
single bonded carbon to its oxygen pulls electrons away from the benzene ring through inductive
effect.
Solution
Nitration occurs through electrophilic addition of aromatic rings by breaking one of
its aromatic bonds in order to attack the nitogen. The ring with more electron density will be
more likely to add NO2 groups in its meta position (the only position if another group is already
attached). When electrophillic addition occurs, the benzene ring would have to unfavorably
break its stable aromaticity to attack. However, the phenyl oxygen can donate its electrons to the
benzene ring, thus enriching it with electron density and stabilizing the positive charge. The
carbonyl group does nothing to stabilize the other benzene ring during its electrophilic addition.
In fact, the carbonyl group may as well have the opposite effect: the resonance structure of a
single bonded carbon to its oxygen pulls electrons away from the benzene ring through inductive
effect..
I Hope some more information required to solve th.pdfsanjeevtandonsre
I Hope some more information required to solve the problem once verify the
question
Solution
I Hope some more information required to solve the problem once verify the
question.
Uses of HRIS SystemsThe principle motivation behind keeping up HR.pdfsanjeevtandonsre
Uses of HRIS Systems:
The principle motivation behind keeping up HRIS framework is to assemble, arrange, process,
record and disperses the data required for productive and successful administration of HR in the
association.The various uses of HRIS in an organisation can be listed as follows:
1. Work force Administration:
It envelops individual data of a worker. These may incorporate name, address, date of birth,
conjugal status, and the date of joining the association. It additionally contains the name and
address of next kinfolk of the worker concern. These data depict the representative.
2. Compensation Administration:
One of the elements of HRIS is to give a report containing data like present compensation,
advantages, last boost in salary and proposed increment in future.
3. Leave/Absence Increase:
HRIS is likewise used to control leave/nonattendance of representatives. This is finished by
keeping up a leave history of every worker. Each worker can be issued a character card
composing each representative\'s token number coded on it. Worker\'s entrance and exit from the
association ought to be recorded on the personality card. This diminishes chances for
misbehavior or oversight in computing compensation for every worker.
4. Aptitude Inventory:
Recording representative aptitudes and checking an expertise information base is yet another
utilization of the HRIS. Such an aptitude record recognizes representatives with the fundamental
expertise for specific positions or occupations in an association.
5. Labor Planning:
HRIS is utilized for labor arranging too. It keeps data of hierarchical necessities as far as
positions. HRIS associates workers to the required positions in the association. It is additionally
used to recognize opening and build up workers consequently. HRIS can likewise distinguish a
legitimate movement way and the progressions to be taken for worker progress/headway.
6. Enlistment:
Enlistment shapes the most crucial capacity of HRM. HRIS helps in the enlistment procedure
bigly by recording the points of interest of exercises required in worker enrollment. These may
incorporate expense and strategy for enlistment and time taken to fill the positions level astute,
for instance.
7. Profession Planning:
By giving important data, for example, which representatives have been reserved for which
positions, HRIS encourages positional headway of workers. At the end of the day, HRIS helps in
making arrangements for progression.
8. Aggregate Bargaining:
HRIS through a work station can give a la mode pertinent and required data, statistical data
points and, in this manner, can encourage aggregate bartering. It would he be able to p aggregate
bartering as \"consider the possibility that investigation\" rather as sentiments and fictions. In the
same way, HRIS can likewise keep up better human relations in the association.
Solution
Uses of HRIS Systems:
The principle motivation behind keeping up HRIS framework is to assemble, arrange, proces.
The moving force behind IT decisions are variable as to what context.pdfsanjeevtandonsre
The moving force behind IT decisions are variable as to what context can it profit an
organisation or a business. Some of it are as follows-
1) Displacement of labour and capital(ex-ATM)
2)Data repositories, ERP, business intelligence and high-end analytics help decision-makers
discover operational flaws and successes which augments future strategic initiatives.
3)Maintaining the customer relationshio management(CRM) [by providing goods and services
that customers value].
4) Maintaining the supply chain management(SCM).[ex- increase productivity through the most
efficient manufacturing processes available. In the computer industry, Dell Computer has
consistently been a market leader as they have achieved efficiencies through implementing both
CRM and SCM with success.]
General Recommendations
• Develop a three-tiered set of business case methodologies that are scaled to
the size and complexity of an initiative. These methodologies should be
Web-supported. Specific tools should include:
Tier 1 (least complex/cost): Total Cost of Ownership;
Tier 2 (middle/cost): Total Cost of Ownership, Payback Period,
Benefit/Cost Ratio, Internal Rate of Return, and Return on Investment;
Tier 3 (most complex/cost): Applied Information Economics.
• The tier requirements are phased to the initiative’s life cycle, requiring that
business case metrics be completed during the planning phase and refined
as the initiative moves through the various stages of its remaining life
cycle.
• Convene a task group to develop accounting reports/tools to more easily track the
financial metrics identified by the business case methodologies.
• Develop an in-depth training program and technical assistance program for
agency program, business, IT, and legislative staff on the adopted business
case methodologies.
• Develop a training/orientation program for senior department and line/staff
managers that include essential legal, financial/budgetary, IT architectural,
and IT project management issues. This orientation should be offered (possibly required) for all
agencies contemplating an initiative involving an information technology
investment.
Solution
The moving force behind IT decisions are variable as to what context can it profit an
organisation or a business. Some of it are as follows-
1) Displacement of labour and capital(ex-ATM)
2)Data repositories, ERP, business intelligence and high-end analytics help decision-makers
discover operational flaws and successes which augments future strategic initiatives.
3)Maintaining the customer relationshio management(CRM) [by providing goods and services
that customers value].
4) Maintaining the supply chain management(SCM).[ex- increase productivity through the most
efficient manufacturing processes available. In the computer industry, Dell Computer has
consistently been a market leader as they have achieved efficiencies through implementing both
CRM and SCM with success.]
General Recommendations
• Develop a three-tiered set of business .
Solution Millennials referred to as narcissistic referred to as n.pdfsanjeevtandonsre
Solution
:
Millennials referred to as narcissistic referred to as narcissistic because people born between
19th and 20th century are consider as more self centred than any other generation.But this
statement is not valid due to the fact that when we compare many generation then it is found that
some previous generation are more narcissistic than Millennials.Self esteem is common factor
for all the generation but there is difference in degree it exist.So,it is not right to blame one
generation as narcissistic..
SolutionThe SELECT DISTINCT stamen will returns distinct values. .pdfsanjeevtandonsre
Solution
:
The SELECT DISTINCT stamen will returns distinct values. SELECT DISTINCT statement
will eliminates the duplicates from the result. DISTINCT can be used for single column, it does
not support the multiple columns. Using this we can get the unique record from the table instead
of duplicate records..
Rheumatic fever shows various symptoms and signs, out of which sore .pdfsanjeevtandonsre
Rheumatic fever shows various symptoms and signs, out of which sore throat is one of the
symptoms.
Only 35-60% of patients show the symptom of upper respiratory sore throat several weeks
preceeding rheumatic fever. Many symptomatic individuals do not seek medical attention, go
undiagnosed, or do not take the prescribed antibiotic for acute rheumatic fever prevention.
Treatment with penicillin will reduce 80% of rheumatic fever risk.
Solution
Rheumatic fever shows various symptoms and signs, out of which sore throat is one of the
symptoms.
Only 35-60% of patients show the symptom of upper respiratory sore throat several weeks
preceeding rheumatic fever. Many symptomatic individuals do not seek medical attention, go
undiagnosed, or do not take the prescribed antibiotic for acute rheumatic fever prevention.
Treatment with penicillin will reduce 80% of rheumatic fever risk..
Physiological responce are those in which the functions of the body .pdfsanjeevtandonsre
Physiological responce are those in which the functions of the body parts changes or affected. so
examples include
1) excessive heat causes the blood vessel to dilate
2) a mammal shivers to generate heat when it is cold
Anatomical response are those in which internal body tissue or organs affects.So examples
include
1) A rabbit grows thicker fur during winter
2) A plant grows deeper root in draught.
Behavioral response are those in which behavior of an organism affects So example includes
1) During cold weather honey bee huddle together to keep warm
2) Monarch butterfly migrate to warmer region during winter
3) A reptile migrate to shaded area to lower its body temperature.
Solution
Physiological responce are those in which the functions of the body parts changes or affected. so
examples include
1) excessive heat causes the blood vessel to dilate
2) a mammal shivers to generate heat when it is cold
Anatomical response are those in which internal body tissue or organs affects.So examples
include
1) A rabbit grows thicker fur during winter
2) A plant grows deeper root in draught.
Behavioral response are those in which behavior of an organism affects So example includes
1) During cold weather honey bee huddle together to keep warm
2) Monarch butterfly migrate to warmer region during winter
3) A reptile migrate to shaded area to lower its body temperature..
Honest Reviews of Tim Han LMA Course Program.pptxtimhan337
Personal development courses are widely available today, with each one promising life-changing outcomes. Tim Han’s Life Mastery Achievers (LMA) Course has drawn a lot of interest. In addition to offering my frank assessment of Success Insider’s LMA Course, this piece examines the course’s effects via a variety of Tim Han LMA course reviews and Success Insider comments.
How to Make a Field invisible in Odoo 17Celine George
It is possible to hide or invisible some fields in odoo. Commonly using “invisible” attribute in the field definition to invisible the fields. This slide will show how to make a field invisible in odoo 17.
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
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The people of Punjab felt alienated from main stream due to denial of their just demands during a long democratic struggle since independence. As it happen all over the word, it led to militant struggle with great loss of lives of military, police and civilian personnel. Killing of Indira Gandhi and massacre of innocent Sikhs in Delhi and other India cities was also associated with this movement.
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This Gasta posits a strategic approach to integrating AI into HEIs to prepare staff, students and the curriculum for an evolving world and workplace. We will highlight the advantages of working with these technologies beyond the realm of teaching, learning and assessment by considering prompt engineering skills, industry impact, curriculum changes, and the need for staff upskilling. In contrast, not engaging strategically with Generative AI poses risks, including falling behind peers, missed opportunities and failing to ensure our graduates remain employable. The rapid evolution of AI technologies necessitates a proactive and strategic approach if we are to remain relevant.
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http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
