The area of a triangle must be at least 42. The base is twice the height. Which of the following is an inequality that can be used to solve for the shortest possible base? Select one. A.14 b2 = 42 B.14 b2 = 42 C.12 bh = 42 D.12 b•2h = 4 Solution A= 1/2bh=42 b=2h h=b/2 A= 1/2 b *b/2= 42 1/4 b^2 = 42 (B).

1. The area of a triangle must be at least 42. The base is twice the height.
Which of the following is an inequality that can be used to solve for the shortest possible base?
Select one.
A.14 b2 = 42
B.14 b2 = 42
C.12 bh = 42
D.12 b•2h = 4
Solution
A= 1/2bh=42 b=2h h=b/2 A= 1/2 b *b/2= 42 1/4 b^2 = 42 (B)