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Answer the followingHow would you find the normal approximation t.pdf

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Answer the following: How would you find the normal approximation to the binominal probability P(x=4) where n=12 and P= 0.40. (show all work) Solution n=12 p=0.4 q= 1-p =1-0.4 =0.6 P(x=4) = 12 c 4 0.4^4 0.6^12-4 = 12 c 4 0.4^4 0.6^8 = 495 0.4^4 0.6^8 = 0.21284093952.

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Answer the following: How would you find the normal approximation to the binominal probability P(x=4) where n=12 and P= 0.40. (show all work) Solution n=12 p=0.4 q= 1-p =1-0.4 =0.6 P(x=4) = 12 c 4 0.4^4 0.6^12-4 = 12 c 4 0.4^4 0.6^8 = 495 0.4^4 0.6^8 = 0.21284093952

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  • 1. Answer the following: How would you find the normal approximation to the binominal probability P(x=4) where n=12 and P= 0.40. (show all work) Solution n=12 p=0.4 q= 1-p =1-0.4 =0.6 P(x=4) = 12 c 4 0.4^4 0.6^12-4 = 12 c 4 0.4^4 0.6^8 = 495 0.4^4 0.6^8 = 0.21284093952