1. Exercice 11
2x − 3
(a) f (x) = → x+8=0 → x = −8
x+8
ED : x∈ − {−8}
x+1
(b) f (x) = → 2x 2 + 3x = 0 ou x(2x + 3) = 0
2x 2 + 3x
x=0 et
2x + 3 = 0 → x = −3/2
ED : x∈ − {−3/2; 0}
ax + b d
(c) f (x) = → cx + d = 0 → x=−
cx + d c
d
ED : x∈ − −
c