An air-filled parallel-plate capacitor has capacitance Co. If two identically sized dielectric slabs of dielectric constants K_1 and K_2 are inserted as shown in the following figure, what is the new capacitance? (Hnt: treat this as two capacitor in combinations) Solution it would act as capacitors in parallel. C= K0A/d. Non C1= A/(d/2)*K1=2C/k1 Simlarly C2= 2C/K2 Since it can be treated as capacitor is parallel so Cfinal= 2C/K1 + 2c/k2 = 2C(K1+K2/K1*K2).