9702_s22_ms_all.pdf

This document consists of 3 printed pages.
© UCLES 2022 [Turn over
Cambridge International AS & A Level
PHYSICS 9702/11
Paper 1 Multiple Choice May/June 2022
MARK SCHEME
Maximum Mark: 40
Published
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the
examination.
Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for
Teachers.
Cambridge International will not enter into discussions about these mark schemes.
Cambridge International is publishing the mark schemes for the May/June 2022 series for most
Cambridge IGCSE, Cambridge International A and AS Level and Cambridge Pre-U components, and some
Cambridge O Level components.

9702/11 Cambridge International AS & A Level – Mark Scheme
PUBLISHED
May/June 2022
© UCLES 2022 Page 2 of 3
Question Answer Marks
1 D 1
2 B 1
3 A 1
4 C 1
5 C 1
6 C 1
7 D 1
8 D 1
9 B 1
10 D 1
11 C 1
12 B 1
13 A 1
14 B 1
15 A 1
16 A 1
17 C 1
18 A 1
19 A 1
20 D 1
21 A 1
22 D 1
23 C 1
24 D 1
25 A 1
26 B 1
27 B 1
28 A 1

PUBLISHED
May/June 2022
29 B 1
30 D 1
31 C 1
32 B 1
33 D 1
34 D 1
35 D 1
36 A 1
37 D 1
38 D 1
39 C 1
40 C 1

PHYSICS 9702/12
MARK SCHEME
Maximum Mark: 40
Published
examination.
Teachers.

PUBLISHED
May/June 2022
1 C 1
2 B 1
3 C 1
4 B 1
5 A 1
6 D 1
7 C 1
8 A 1
9 B 1
10 B 1
11 C 1
12 D 1
13 C 1
14 B 1
15 C 1
16 B 1
17 A 1
18 C 1
19 B 1
20 A 1
21 D 1
22 C 1
23 D 1
24 A 1
25 A 1
26 B 1
27 B 1
28 D 1

PUBLISHED
May/June 2022
29 D 1
30 C 1
31 B 1
32 A 1
33 D 1
34 A 1
35 B 1
36 A 1
37 D 1
38 C 1
39 C 1
40 B 1

PHYSICS 9702/13
MARK SCHEME
Maximum Mark: 40
Published
examination.
Teachers.

PUBLISHED
May/June 2022
1 D 1
2 D 1
3 B 1
4 C 1
5 A 1
6 C 1
7 D 1
8 C 1
9 D 1
10 B 1
11 A 1
12 C 1
13 D 1
14 B 1
15 A 1
16 A 1
17 C 1
18 C 1
19 B 1
20 C 1
21 B 1
22 B 1
23 B 1
24 D 1
25 A 1
26 A 1
27 B 1
28 C 1

PUBLISHED
May/June 2022
29 B 1
30 B 1
31 D 1
32 D 1
33 D 1
34 B 1
35 D 1
36 A 1
37 A 1
38 B 1
39 B 1
40 A 1

PHYSICS 9702/21
Paper 2 AS Level Structured Questions May/June 2022
MARK SCHEME
Maximum Mark: 60
Published
examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the
details of the discussions that took place at an Examiners’ meeting before marking began, which would have
considered the acceptability of alternative answers.
Teachers.

PUBLISHED
May/June 2022
Generic Marking Principles
These general marking principles must be applied by all examiners when marking candidate answers. They should be applied alongside the
specific content of the mark scheme or generic level descriptors for a question. Each question paper and mark scheme will also comply with these
marking principles.
GENERIC MARKING PRINCIPLE 1:
Marks must be awarded in line with:
 the specific content of the mark scheme or the generic level descriptors for the question
 the specific skills defined in the mark scheme or in the generic level descriptors for the question
 the standard of response required by a candidate as exemplified by the standardisation scripts.
Marks awarded are always whole marks (not half marks, or other fractions).
Marks must be awarded positively:
 marks are awarded for correct/valid answers, as defined in the mark scheme. However, credit is given for valid answers which go beyond the
scope of the syllabus and mark scheme, referring to your Team Leader as appropriate
 marks are awarded when candidates clearly demonstrate what they know and can do
 marks are not deducted for errors
 marks are not deducted for omissions
 answers should only be judged on the quality of spelling, punctuation and grammar when these features are specifically assessed by the
question as indicated by the mark scheme. The meaning, however, should be unambiguous.
Rules must be applied consistently, e.g. in situations where candidates have not followed instructions or in the application of generic level
descriptors.

PUBLISHED
May/June 2022
Marks should be awarded using the full range of marks defined in the mark scheme for the question (however; the use of the full mark range may
be limited according to the quality of the candidate responses seen).
Marks awarded are based solely on the requirements as defined in the mark scheme. Marks should not be awarded with grade thresholds or
grade descriptors in mind.
Science-Specific Marking Principles
1 Examiners should consider the context and scientific use of any keywords when awarding marks. Although keywords may be present, marks
should not be awarded if the keywords are used incorrectly.
2 The examiner should not choose between contradictory statements given in the same question part, and credit should not be awarded for any
correct statement that is contradicted within the same question part. Wrong science that is irrelevant to the question should be ignored.
3 Although spellings do not have to be correct, spellings of syllabus terms must allow for clear and unambiguous separation from other syllabus
terms with which they may be confused (e.g. ethane / ethene, glucagon / glycogen, refraction / reflection).
4 The error carried forward (ecf) principle should be applied, where appropriate. If an incorrect answer is subsequently used in a scientifically
correct way, the candidate should be awarded these subsequent marking points. Further guidance will be included in the mark scheme where
necessary and any exceptions to this general principle will be noted.
5 ‘List rule’ guidance
For questions that require n responses (e.g. State two reasons …):
 The response should be read as continuous prose, even when numbered answer spaces are provided.
 Any response marked ignore in the mark scheme should not count towards n.
 Incorrect responses should not be awarded credit but will still count towards n.
 Read the entire response to check for any responses that contradict those that would otherwise be credited. Credit should not be
awarded for any responses that are contradicted within the rest of the response. Where two responses contradict one another, this
should be treated as a single incorrect response.
 Non-contradictory responses after the first n responses may be ignored even if they include incorrect science.

PUBLISHED
May/June 2022
6 Calculation specific guidance
Correct answers to calculations should be given full credit even if there is no working or incorrect working, unless the question states ‘show
your working’.
For questions in which the number of significant figures required is not stated, credit should be awarded for correct answers when rounded by
the examiner to the number of significant figures given in the mark scheme. This may not apply to measured values.
For answers given in standard form (e.g. a  10n) in which the convention of restricting the value of the coefficient (a) to a value between 1
and 10 is not followed, credit may still be awarded if the answer can be converted to the answer given in the mark scheme.
Unless a separate mark is given for a unit, a missing or incorrect unit will normally mean that the final calculation mark is not awarded.
Exceptions to this general principle will be noted in the mark scheme.
7 Guidance for chemical equations
Multiples / fractions of coefficients used in chemical equations are acceptable unless stated otherwise in the mark scheme.
State symbols given in an equation should be ignored unless asked for in the question or stated otherwise in the mark scheme.

PUBLISHED
May/June 2022
Abbreviations
/ Alternative and acceptable answers for the same marking point.
( ) Bracketed content indicates words which do not need to be explicitly seen to gain credit but which indicate the context for an
answer. The context does not need to be seen but if a context is given that is incorrect then the mark should not be awarded.
___ Underlined content must be present in answer to award the mark. This means either the exact word or another word that has the
same technical meaning.
Mark categories
B marks These are independent marks, which do not depend on other marks. For a B mark to be awarded, the point to which it refers must be
seen specifically in the candidate’s answer.
M marks These are method marks upon which A marks later depend. For an M mark to be awarded, the point to which it refers must be seen
specifically in the candidate’s answer. If a candidate is not awarded an M mark, then the later A mark cannot be awarded either.
C marks These are compensatory marks which can be awarded even if the points to which they refer are not written down by the candidate,
providing subsequent working gives evidence that they must have known them. For example, if an equation carries a C mark and the
candidate does not write down the actual equation but does correct working which shows the candidate knew the equation, then the
C mark is awarded.
If a correct answer is given to a numerical question, all of the preceding C marks are awarded automatically. It is only necessary to
consider each of the C marks in turn when the numerical answer is not correct.
A marks These are answer marks. They may depend on an M mark or allow a C mark to be awarded by implication.
Annotations
 Indicates the point at which a mark has been awarded.
X Indicates an incorrect answer or a point at which a decision is made not to award a mark.
XP Indicates a physically incorrect equation (‘incorrect physics’). No credit is given for substitution, or subsequent arithmetic, in a
physically incorrect equation.

PUBLISHED
May/June 2022
ECF Indicates ‘error carried forward’. Answers to later numerical questions can always be awarded up to full credit provided they are
consistent with earlier incorrect answers. Within a section of a numerical question, ECF can be given after AE, TE and POT errors,
but not after XP.
AE Indicates an arithmetic error. Do not allow the mark where the error occurs. Then follow through the working/calculation giving full
subsequent ECF if there are no further errors.
POT Indicates a power of ten error. Do not allow the mark where the error occurs. Then follow through the working/calculation giving full
TE Indicates incorrect transcription of the correct data from the question, a graph, data sheet or a previous answer. For example, the
value of 1.6  10–19 has been written down as 6.1  10–19 or 1.6  1019.
Do not allow the mark where the error occurs. Then follow through the working/calculation giving full subsequent ECF if there are no
further errors.
SF Indicates that the correct answer is seen in the working but the final answer is incorrect as it is expressed to too few significant
figures.
BOD Indicates that a mark is awarded where the candidate provides an answer that is not totally satisfactory, but the examiner feels that
sufficient work has been done (‘benefit of doubt’).
CON Indicates that a response is contradictory.
I Indicates parts of a response that have been seen but disregarded as irrelevant.
M0 Indicates where an A category mark has not been awarded due to the M category mark upon which it depends not having
previously been awarded.
^ Indicates where more is needed for a mark to be awarded (what is written is not wrong, but not enough). May also be used to
annotate a response space that has been left completely blank.
SEEN Indicates that a page has been seen.

PUBLISHED
May/June 2022
1(a) change in displacement / time (taken) B1
1(b)(i) (displacement =) area under graph C1
(at t = 4.0 s) v = (–) 2.4 C1
height = ½  2.5  4.0 – ½  1.5  2.4
= 3.2 m
A1
1(b)(ii) change in momentum = 7.5 (–4.0 – 2.4) C1
= (–) 48 N s A1
1(b)(iii) W = ∆p / (∆)t or ∆mv / (∆)t C1
= 48 / 4.0
= 12 N
A1
or
W = ma or mg or m(v – u) / t (C1)
= 7.5  1.6 or 7.5  (4 + 2.4) / 4.0
= 12 N
(A1)
1(c) speed/velocity decreases so viscous force decreases B1
viscous force decreases (and weight constant) so resultant force decreases B1

PUBLISHED
May/June 2022
2(a) point where (all) the weight (of the object) is taken to act B1
2(b)(i) moments about P are: (F  1.10), (44.0  0.60) and (3.0  2.90)
1 mark for any one correct moment and 2 marks for two correct moments
C2
(F  1.10) = (44.0  0.60) + (3.0  2.90)
F = 32 N
A1
2(b)(ii) force = 32 + 44 + 3
= 79 N
A1
2(c)(i) (F = gV)
V = 2.5 / (1100  9.81) (= 2.32  10–4)
C1
V = (4 / 3)r3 C1
r = [(3  2.32  10–4) / 4]1/3
r = 0.038 m
A1
2(c)(ii) resultant moment = 2.5  2.9
= 7.3 N m
or
resultant moment = F  1.1  (44  0.6 + 0.5  2.9)
= 7.3 Nm (allow 7.2 Nm or 7.4 Nm from rounded values of F)
A1
direction: anticlockwise A1

PUBLISHED
May/June 2022
3(a)(i) work (done) / time (taken) B1
3(a)(ii) W = Fx or E = Fx B1
(P =) Fx / t = Fv or P = Fvt / t = Fv B1
3(b)(i) T = 430 sin 11° or 430 cos 79° C1
= 82 N A1
3(b)(ii) speed = 56 / 82
= 0.68 m s–1
A1
3(b)(iii) no change in kinetic energy (of block) B1
3(b)(iv) (input power) = 56 / 0.80
( = 70 W)
C1
time taken = 1.2  103 / 70
= 17 s
A1
or
(useful energy) = 1200  80 / 100
( = 960 J)
(C1)
time taken = 960 / 56
= 17 s
(A1)

PUBLISHED
May/June 2022
4(a) k = F / ∆L or F / x or gradient C1
= e.g. 30 / (0.60 – 0.20)
= 75 N m–1
A1
4(b)
E = 
1
2
F L or
1
2
Fx or  

2
1
2
k L or 2
1
2
kx or area under graph
C1
=
1
2
 15  0.20 or
1
2
 75  0.202
C1
= 1.5 J A1

PUBLISHED
May/June 2022
5(a) wave(s) (travel along string and) reflect at fixed point / A / B / end B1
incident and reflected waves superpose / interfere
or
two waves travelling / with speed in opposite directions superpose / interfere
B1
5(b) line has an approximate sinusoidal shape with maximum downward displacement at P and zero displacement at each node B1
5(c) v =  / T
or
v = f and f = 1 / T
C1
 = 35  0.040 or 35 / 25
( = 1.4 m)
C1
distance = 1.4  2.5
= 3.5 m
A1
5(d) (number of periods / cycles) (= t / T) = 0.060 / 0.040
(= 1.5)
C1
amplitude = 72 / 6
= 12 mm
A1

PUBLISHED
May/June 2022
6(a) sum of current(s) into junction = sum of current(s) out of junction
or
(algebraic) sum of current(s) at a junction is zero
B1
6(b)(i) same potential difference (across X and Y as in parallel) B1
power = V2 / R (and RX  RY)
or
power = VI and IX  IY
M1
(so) Y (dissipates more power) A1
6(b)(ii) R = L / A (and RX  RY) M1
(so) Y (has the larger (cross-sectional) area) A1
6(c)(i) current = 5.4 / 1800
= 3.0  10–3 A
A1
6(c)(ii) 5.4 / 9.0 = 1800 / (1800 + RL)
or
RL = (9.0 – 5.4) / 3.0  10–3
C1
RL = 1200  A1
6(c)(iii) resistance of LDR / RL decreases B1
current (in the circuit) increases (so) voltmeter reading increases B1

PUBLISHED
May/June 2022
7(a)(i) change in A = 0 A1
change in Z = (+)1 A1
7(a)(ii) (electron) antineutrino B1
7(b)(i)
up / u (charge) =  

2
3
e or antidown / d
ത =  

1
3
e
or
(q )= 
2 1
3 3
e e
M1
q = (+)1e A1
7(b)(ii) hadron(s) B1
meson(s) B1

PHYSICS 9702/22
MARK SCHEME
Maximum Mark: 60
Published
Teachers.

PUBLISHED
May/June 2022
marking principles.
descriptors.

PUBLISHED
May/June 2022

PUBLISHED
May/June 2022
your working’.

PUBLISHED
May/June 2022
Abbreviations
( ) Bracketed content indicates words which do not need to be explicitly seen to gain credit but which indicate the context for an
answer. The context does not need to be seen but if a context is given that is incorrect then the mark should not be awarded.
___ Underlined content must be present in answer to award the mark. This means either the exact word or another word that has the
same technical meaning.
Mark categories
candidate does not write down the actual equation but does correct working which shows the candidate knew the equation, then the
C mark is awarded.
Annotations
XP Indicates a physically incorrect equation (‘incorrect physics’). No credit is given for substitution, or subsequent arithmetic, in a
physically incorrect equation.

PUBLISHED
May/June 2022
consistent with earlier incorrect answers. Within a section of a numerical question, ECF can be given after AE, TE and POT errors,
but not after XP.
AE Indicates an arithmetic error. Do not allow the mark where the error occurs. Then follow through the working/calculation giving full
POT Indicates a power of ten error. Do not allow the mark where the error occurs. Then follow through the working/calculation giving full
TE Indicates incorrect transcription of the correct data from the question, a graph, data sheet or a previous answer. For example, the
value of 1.6  10–19 has been written down as 6.1  10–19 or 1.6  1019.
Do not allow the mark where the error occurs. Then follow through the working / calculation giving full subsequent ECF if there are
no further errors.
SF Indicates that the correct answer is seen in the working but the final answer is incorrect as it is expressed to too few significant
figures.
M0 Indicates where an A category mark has not been awarded due to the M category mark upon which it depends not having
previously been awarded.
^ Indicates where more is needed for a mark to be awarded (what is written is not wrong, but not enough). May also be used to
annotate a response space that has been left completely blank.

PUBLISHED
May/June 2022
1(a) only ampere and kilogram underlined B1
1(b)(i) percentage uncertainty = 2.1 + 0.6 + (1.5  2) C1
= 5.7% A1
1(b)(ii) absolute uncertainty = (5.7 / 100)  8.245  109
( = 4.7  108 Pa or 0.47  109 Pa)
C1
E = (8.2 ± 0.5)  109 Pa A1
2(a) T sin 68° + 32 = 280 C1
T = 270 N A1
2(b)(i) F = gV
V = 280 / (1.0  103  9.81)
= 0.029 m3
A1
2(b)(ii)  = (32 / 9.81) / 0.029 C1
= 110 kg m–3 A1

PUBLISHED
May/June 2022
2(c) (∆)E = mg(∆)h or (∆)E = W(∆)h C1
(∆)h = (–) 77 / 32 C1
(∆)h = (–) 2.4
final height = 6.2 – 2.4
= 3.8 m
A1
2(d)(i) T = kx where k is a constant
or
T = (EA / L)x where A is (cross-sectional) area, E is Young modulus, L is (original/unstretched) length
B1
2(d)(ii)
 2
1
2
E kx
or

1
2
E Fx and F = kx
C1
E = 0.65  22
= 2.6 J
A1
or

1
2
E Fx
  
1
0.65 270
2
x and so x = 4.8  10–3 m
k = F / x = 270 / 4.8  10–3
= 5.6  104
(C1)

PUBLISHED
May/June 2022
2(d)(ii)
final 
    3
1
540 9.6 10
2
E
or
E =    

    
3
1
270 2 4.8 10 2
2
or
E =  

   
2
4 3
1
5.6 10 9.6 10
2
= 2.6 J
(A1)

PUBLISHED
May/June 2022
3(a) v2 = u2 + 2as
s = 5.62 / (2  9.81)
C1
(max height =) 3.1 + 5.62 / (2  9.81) = 4.7 (m) A1
3(b)
  2
1
2
s ut at
   2
1
4.7 9.81
2
t
C1
t = 0.98 s A1
3(c) line drawn from a non-zero speed at t = 0 to a greater speed at t = T B1
a single sloping straight line drawn from t = 0 to t = T B1
line starts with a positive non-zero value of v and ends with a negative non-zero value of v B1
3(d) acceleration (of the ball) B1
3(e)(i) (magnitudes of accelerations are) equal / same B1
3(e)(ii) (speeds are) equal / same B1

PUBLISHED
May/June 2022
4(a) sum/total momentum before = sum/total momentum after
or
sum/total momentum (of a system of objects) is constant
M1
if no (resultant) external force/for a closed system A1
4(b)(i) (3.0  4.0  cos) or (2.5  4.8  cos) or (5.5  3.7) C1
(3.0  4.0  cos) + (2.5  4.8  cos) = (5.5  3.7) C1
 = 32° A1
4(b)(ii)
(initial EK =
1
2
 3.0  4.02 +
1
2
 2.5  4.82 =) 53 (J)
or
(final EK =
1
2
 5.5  3.72 =) 38 (J)
C1
values of initial EK and final EK both correct and inelastic stated A1

PUBLISHED
May/June 2022
5(a) constant phase difference (between the waves) B1
5(b)(i) path difference = 1.5  660
= 990 nm
A1
5(b)(ii) phase difference = 360°  1.5
= 540°
A1
5(c)  = ax / D C1
x = (660  10–9  1.8) / 0.44  10–3 C1
= 2.7  10–3 m A1
5(d) bright fringes are brighter B1
no change to dark fringes B1
no change to (fringe) separation / (fringe) spacing B1
5(e) (blue light has) shorter wavelength M1
(so) decrease (slit) separation A1

PUBLISHED
May/June 2022
6(a) V = V1 + V2 + V3 B1
IR = IR1 + IR2 + IR3 or (V / I) = (V1 / I) + (V2 / I) + (V3 / I)
and
R = R1 + R2 + R3
B1
6(b)(i) V / 8.0 = 6.0  103 / (4.0  103 + 6.0  103)
or
I = 8.0 / (4.0  103 + 6.0  103) = 8.0  10–4
V = 8.0  10–4  6.0  103
C1
V = 4.8 V A1
6(b)(ii) total resistance in parallel = 3.0  103 () or 3.0 (k) C1
current = 8.0 / (3.0  103 + 6.0  103)
= 8.9  10–4 A
A1
6(c) thermistor resistance increases B1
(thermistor resistance increases so total resistance increases so) current decreases (in battery) M1
(P = EI and E constant so) power decreases A1

PUBLISHED
May/June 2022
7(a)(i) P = 0 and Q = 137 A1
R = –1 and S = 56 A1
7(a)(ii) lepton(s) B1
7(b)(i)
(charge of ddd / Y =)  

1
3
e  

1
3
e  

1
3
e = –1(e)
B1
(charge of ud / Z =)  

1
3
e  

2
3
e = –1(e)
B1
7(b)(ii) meson: Z / u d because consists of a quark and an antiquark B1
baryon: Y / ddd because consists of three quarks B1

PHYSICS 9702/23
MARK SCHEME
Maximum Mark: 60
Published
Teachers.

PUBLISHED
May/June 2022
These general marking principles must be applied by all examiners when marking candidate answers. They should be applied alongside the specific
content of the mark scheme or generic level descriptors for a question. Each question paper and mark scheme will also comply with these marking
principles.
 marks are awarded for correct / valid answers, as defined in the mark scheme. However, credit is given for valid answers which go beyond the
descriptors.

PUBLISHED
May/June 2022

PUBLISHED
May/June 2022
your working’.

PUBLISHED
May/June 2022
Abbreviations
( ) Bracketed content indicates words which do not need to be explicitly seen to gain credit but which indicate the context for an answer. The
context does not need to be seen but if a context is given that is incorrect then the mark should not be awarded.
___ Underlined content must be present in answer to award the mark. This means either the exact word or another word that has the same
technical meaning.
Mark categories
candidate does not write down the actual equation but does correct working which shows the candidate knew the equation, then the C
mark is awarded.
Annotations

PUBLISHED
May/June 2022
XP Indicates a physically incorrect equation (‘incorrect physics’). No credit is given for substitution, or subsequent arithmetic, in a physically
incorrect equation.
consistent with earlier incorrect answers. Within a section of a numerical question, ECF can be given after AE, TE and POT errors, but
not after XP.
AE Indicates an arithmetic error. Do not allow the mark where the error occurs. Then follow through the working / calculation giving full
POT Indicates a power of ten error. Do not allow the mark where the error occurs. Then follow through the working / calculation giving full
TE Indicates incorrect transcription of the correct data from the question, a graph, data sheet or a previous answer. For example, the value of
1.6  10–19 has been written down as 6.1  10–19 or 1.6  1019.
Do not allow the mark where the error occurs. Then follow through the working / calculation giving full subsequent ECF if there are no
further errors.
SF Indicates that the correct answer is seen in the working but the final answer is incorrect as it is expressed to too few significant figures.
M0 Indicates where an A category mark has not been awarded due to the M category mark upon which it depends not having previously
been awarded.
^ Indicates where more is needed for a mark to be awarded (what is written is not wrong, but not enough). May also be used to annotate a
response space that has been left completely blank.

PUBLISHED
May/June 2022
1(a)  = m / V C1
V = (4 / 3)    r3
= (4 / 3)    (3.42 / 2)3
( = 20.9 cm3)
C1
 = 67 / 20.9
= 3.2 g cm−3
A1
1(b) % = %m + 3  %d
= [(2 / 67)  100] + [3  (0.02 / 3.42)  100]
C1
= 3.0% + 3  0.58%
= 4.7% or 5%
A1

PUBLISHED
May/June 2022
2(a) (time =) displacement / velocity C1
(time =) 70.0 / 65.0 cos 4.30° = 1.08 (s) A1
2(b) s = ut + ½at2
= (65  sin 4.30°  1.08) – (0.5  9.81  1.082)
C1
s = −0.46 (m) C1
height above ground = 1.66 − 0.46
= 1.2 m
A1
2(c) GPE has decreased M1
(total energy conserved so) KE has increased A1

PUBLISHED
May/June 2022
3(a) (velocity =) change in displacement / time B1
3(b)(i) a = 2400 / 1200
= 2.0 m s−2
A1
3(b)(ii) straight line from the origin with positive gradient (labelled A) M1
ending at (20, 40) A1
3(c)(i) line starting at origin (with the same gradient as A) and beneath A at all points B1
gradient decreasing to zero B1
straight horizontal line from t = 12 s and ending at t = 20 s (and labelled B) B1
3(c)(ii) the velocity/speed will increase B1
to a new terminal/constant/maximum velocity/speed B1
or
the car has an acceleration (B1)
to a new (higher) terminal/constant/maximum velocity/speed (B1)

PUBLISHED
May/June 2022
4(a) work (done) = force  displacement M1
(force = mg and distance = h)
(so) work (done) = mgh and work = E(P) (so E(P) = mgh)
A1
4(b) gravitational potential (energy) to heat/thermal (energy) B1
4(c)(i) P = mg()h / ()t or Fv C1
P = (0.60  9.81  1.4) / 4.0 or 0.60  9.81  (1.4 / 4.0)
= 2.1 W
A1
4(c)(ii) P = I2R or IV or V2 / R C1
= 0.092  47 or 0.09  4.23 or 4.232 / 47
= 0.38 W
A1
4(c)(iii) efficiency = Pout / Pin ( 100) or Eout / Ein ( 100) C1
= 0.38 / 2.1 ( 100) or 0.38  4.0 / 2.1  4.0 ( 100)
= 0.18 or 18%
A1

PUBLISHED
May/June 2022
5(a)(i) power = intensity  area C1
= 1.3  103  (  0.0552)
= 12 W
A1
5(a)(ii) intensity = power / area
= 12 / (  0.00152)
= 1.7  106 W m−2
A1
5(b)(i) ( =) v / f or c / f C1
( =) 3.0  108 / 3.7  1015 = 8.1  10−8 (m) A1
5(b)(ii) ultraviolet A1

PUBLISHED
May/June 2022
5(b)(iii) d sin  = n or (1 / N)  sin  = n C1
d = 1 / 2400  103 (m)
= 4.2  10–7 (m)
or
N = 2400  103 (m–1)
C1
n = 4.2  10−7  sin 90° / 8.1  10−8 or sin 90° / 2400  103  8.1  10–8
n = 5.2 or 5.1
or
when n = 5,  = 76.4° and when n = 6, sin > 1
(so) n = 5
B1
number of maxima = (2  5) + 1
= 11
A1
5(b)(iv) the wavelength has increased M1
(so) number of maxima decreases A1

PUBLISHED
May/June 2022
6(a)(i) line passes through (0,0) and is in first and third quadrants only M1
gradient of line becoming less steep in both quadrants and roughly symmetrical A1
6(a)(ii) (as I increases) the temperature (of the filament wire/lamp) increases B1
(as I / temperature / V increases) the resistance (of wire/lamp) increases B1
(as I / temperature / V increases the graph curves because) ratio V / I increases or ratio I / V decreases B1
6(b) R = L / A C1
= (5.6  10−8  5.8) / 3.4  10−8
= 9.6 
A1

PUBLISHED
May/June 2022
6(c)
position of switches ammeter readings
S1 S2 X / A Y / A Z / A
open open 0 0 0
open closed 1.0 0 1.0
closed open 2.0 2.0 0
closed closed 3.0 2.0 1.0
second row: both values correct (B1)
third row: all three values correct (B1)
fourth row: X = Y + Z (any values) (B1)
all three values correct (B1)
B4

PUBLISHED
May/June 2022
7(a)(i) 18
9F  18
8O + 0
( )1
 (+) + (0)
(0)
(e)
 or neutrino (B1)
0
( )1
 (+) (B1)
18
8O (B1)
B3
7(a)(ii) up quark to down quark B1
7(b)(i) must be three (anti)quarks as largest (negative) quark charge is (–)2/3 (e)
or
mesons can only have a charge of 0 or 1(e)
M1
(so hadron is) a baryon A1
7(b)(ii) any combination of three from:
antiup (quark) / up antiquark
and/or anticharm (quark) / charm antiquark
and/or antitop (quark) / top antiquark
B1

PHYSICS 9702/31
Paper 3 Advanced Practical Skills 1 May/June 2022
MARK SCHEME
Maximum Mark: 40
Published
Teachers.

PUBLISHED
May/June 2022
marking principles.
descriptors.

PUBLISHED
May/June 2022

PUBLISHED
May/June 2022
your working’.

PUBLISHED
May/June 2022
1(a) Value of T with unit and in the range 0.850–1.300 s. 1
nT measured at least twice with n ⩾ 5. 1
1(b) Total mass (upper mass + m) is 450 g with consistent unit. 1
1(c) Six sets of readings of m and time with correct trend (T increases as m increases) and without help from the Supervisor
scores 4 marks, five sets scores 3 marks etc.
4
Range: mmax – mmin ⩾ 300 g. 1
Column headings:
Each column heading must contain a quantity and a unit where appropriate.
The presentation of quantity and unit must conform to accepted scientific convention e.g. m / g, T / s, T / s½.
1
Consistency:
Raw values of time either all given to the nearest 0.1 s or all given to the nearest 0.01 s.
1
Significant figures:
All values of T must be given to the same number of s.f. as (or one more than) the number of s.f. in raw times.
1
Calculation: Correct calculation of T. 1

PUBLISHED
May/June 2022
1(d)(i) Axes:
Sensible scales must be used, no awkward scales (e.g. 3:10 or fractions).
Scales must be chosen so that the plotted points occupy at least half the graph grid in both the x and y directions.
Axes must be labelled with the quantity that is being plotted.
Scale markings are no more than 2cm (one large square) apart.
1
Plotting of points:
All observations in the table must be plotted on the grid.
Diameter of plotted points must be ⩽ half a small square.
Points must be plotted to an accuracy of half a small square in both x and y directions.
1
Quality:
All points in the table must be plotted (at least 5) on the grid for this mark to be awarded.
Trend of points must be positive.
It must be possible to draw a straight line that is within  25 g ( 0.025 kg) on the m axis of all plotted points.
1
1(d)(ii) Line of best fit:
Judge by the balance of all points on the grid about the candidate’s line (at least 5 points). There must be an even
distribution of points either side of the line along the full length.
Allow one anomalous point only if clearly indicated (i.e. circled or labelled) by the candidate. There must be at least 5
points left after the anomalous point is disregarded.
Lines must not be kinked or thicker than half a small square.
1
1(d)(iii) Gradient:
The hypotenuse of the triangle used must be greater than half the length of the drawn line.
Both read-offs must be accurate to half a small square in both the x and y directions.
Method of calculation must be correct (not x / y).
Gradient sign on answer line matches graph drawn.
1
y-intercept:
Correct read-off from a point on the line and substituted into y = mx + c or an equivalent expression.
Read-off accurate to half a small square in both x and y directions.
or
Intercept read directly from the graph, with read-off at m = 0, accurate to half a small square.
1

PUBLISHED
May/June 2022
1(e) Value of P = candidate’s gradient and value of Q = candidate’s intercept.
The values must not be fractions.
1
Unit for P: s½ kg–1 or s½ g–1
and
unit for Q: s½.
1

PUBLISHED
May/June 2022
2(a)(i) Raw d value(s) to the nearest mm and value of d in the range 0.020–0.030 m. 1
2(a)(ii) Correct calculation of A. 1
2(b)(i) Value of h in the range 0.040–0.060 m. 1
Value of y. 1
2(b)(ii) Percentage uncertainty in h based on an absolute uncertainty in the range 2–5 mm.
If several readings have been taken, then the absolute uncertainty can be half the range (but not zero) provided the
working is clearly shown.
Correct method of calculation to obtain percentage uncertainty.
1
2(b)(iii) Correct calculation of C. 1
2(b)(iv) Justification for significant figures in C linked to significant figures in L, d, h,  and M. 1
2(c) Second value of x. 1
Second value of y. 1
Second value of y > first value of y. 1
2(d) Two values of k calculated correctly. The final k values must not be written as fractions. 1
2(e) Calculation of percentage difference between candidate’s two k values.
Comparison of percentage difference with 10% leading to a consistent conclusion.
1

PUBLISHED
May/June 2022
2(f)(i) A Two readings are not enough to draw a (valid) conclusion (not “not enough for accurate results”, “few readings”).
B Difficulty with measuring d with a reason e.g. tube surface is curved/parallax error/tube not flat on rule.
C Difficulty with measuring h with a reason e.g. measuring outside beaker/tube not vertical/parallax error/refraction
effects/distortion/tray obscures view.
D Difficulty with measuring x with a reason e.g. sand surface not level/tube and rule not parallel/holding rule and tube at
the same time.
E Difficulty with measuring/judging/setting y with a reason e.g. judging centre of rod/balance is achieved over a range of
y/difficult finding balance point/hard to balance/difficult to adjust ruler to horizontal.
1 mark for each point up to a maximum of 4.
4
2(f)(ii) A Take more readings (for different amounts of sand) and plot a graph or take more readings and compare k values (not
“repeat readings” on its own).
B Use calipers/micrometer screw gauge/travelling microscope/blocks either side.
C Improvements to tube e.g. mark tube/place rubber band around tube to mark position/use a graduated tube.
D Improved method for x or h e.g. clamp tube/use rule with pointers/use shallower tray or remove tray.
E Use a triangular pivot.
4

PHYSICS 9702/32
MARK SCHEME
Maximum Mark: 40
Published
Teachers.

PUBLISHED
May/June 2022
marking principles.
descriptors.

PUBLISHED
May/June 2022
2 The examiner should not choose between contradictory statements given in the same question part, and credit should not be awarded for
any correct statement that is contradicted within the same question part. Wrong science that is irrelevant to the question should be ignored.
3 Although spellings do not have to be correct, spellings of syllabus terms must allow for clear and unambiguous separation from other
syllabus terms with which they may be confused (e.g. ethane / ethene, glucagon / glycogen, refraction / reflection).
correct way, the candidate should be awarded these subsequent marking points. Further guidance will be included in the mark scheme
where necessary and any exceptions to this general principle will be noted.

PUBLISHED
May/June 2022
your working’.
For questions in which the number of significant figures required is not stated, credit should be awarded for correct answers when rounded
by the examiner to the number of significant figures given in the mark scheme. This may not apply to measured values.

PUBLISHED
May/June 2022
1(a)(i) Value of raw x to the nearest mm and final value in the range 4.0–8.0 cm. 1
1(a)(ii) Value for R with unit in the range 18.0  ⩽ R ⩽ 30.0 . 1
1(b) Five sets of readings of n and R with correct trend (R decreases as n increases) and without help from the Supervisor
scores 4 marks, four sets scores 3 marks etc.
4
Range: nmin ⩽ 3 and nmax ⩾ 9. 1
Column headings:
The presentation of quantity and unit must conform to accepted scientific convention e.g. R / .
The quantities n and (n – 1 / n) must have no unit.
1
Consistency: All values of raw R must be given to the nearest 0.1 . 1
Significant figures: All (n – 1 / n) values must be given to three significant figures. 1
Calculation: (n – 1 / n) calculated correctly. 1
1(c)(i) Axes:
1
Plotting of points:
1
Quality:
All points in the table must be plotted (at least 4) for this mark to be awarded.
Trend of points must be negative.
It must be possible to draw a straight line that is within ± 0.5  in the R direction of all plotted points.
1

PUBLISHED
May/June 2022
1(c)(ii) Line of best fit:
Allow one anomalous point only if clearly indicated (i.e. circled or labelled) by the candidate. There must be at least 4 points
left after the anomalous point is disregarded.
1
1(c)(iii) Gradient:
1
y-intercept:
Correct read-off from a point on the line substituted into y = mx + c or an equivalent expression, with read-off accurate to
half a small square in both x and y directions.
or
Intercept read directly from the graph, with read-off at (n – 1 / n) = 0 accurate to half a small square in y direction.
1
1(d) Value of a = candidate’s gradient and value of b = candidate’s intercept.
The values must not be written as fractions.
1
Units for a and b correct (e.g.  for a and  for b). 1
1(e) Correct value of r and correct unit (e.g.  m–1) given. 1

PUBLISHED
May/June 2022
2(a)(i) Value for L with unit and raw values of L to nearest mm. 1
2(a)(ii) Value for ts with unit and in range 2.0–5.0 s. 1
Evidence of repeat readings for ts. 1
2(a)(iii) Percentage uncertainty in ts based on an absolute uncertainty of 0.2–0.5 s.
If several readings have been taken, then the absolute uncertainty can be half the range (but not zero) provided working is
clearly shown.
1
2(b)(i) Value for T1 with unit. All raw values given to nearest 0.01 s or all raw values given to nearest 0.1 s. 1
2(b)(ii) Value for T2 less than T1. 1
2(b)(iii) Correct calculation of B with unit of s. 1
2(c) Second L < first L. 1
Second value of ts. 1
Second values of T1 and T2. 1
2(d) Two values of k calculated correctly. The final k values must not be written as fractions. 1
1

PUBLISHED
May/June 2022
B Difficult to measure ts with a reason i.e. difficult to judge when twisting changes to swinging.
C Difficult to measure L with a reason: difficult to judge when strings are vertical/hand moves when holding the
ruler/difficult to hold ruler still/ruler moves the strings/ruler not horizontal.
D Loops move on rod/string slides off rod.
E Large uncertainty in B with a reason e.g. difference between T1 and T2 is small.
4
2(f)(ii) A Take more readings and plot a graph or take more readings and compare k values (not “repeat readings” on its own).
B Record/film/video rod with timer in view.
or
record/film/video rod and view frame by frame.
C Support ruler being used to measure L in a clamp/use set square between clamp and string/use plumb-line/use a spirit
level.
D Make grooves around rod/add notches to rod/use tape to hold string on rod/use a rough rod.
E Tilt rod at steeper angle/increase difference in length of the strings.
4

PHYSICS 9702/33
MARK SCHEME
Maximum Mark: 40
Published
Teachers.

PUBLISHED
May/June 2022
marking principles.
descriptors.

PUBLISHED
May/June 2022
awarded for any responses that are contradicted within the rest of the response. Where two responses contradict one another, this should
be treated as a single incorrect response.

PUBLISHED
May/June 2022
your working’.

PUBLISHED
May/June 2022
1(a) Value of L to the nearest mm with unit and in the range 74.0–76.0 cm. 1
1(b) Values of raw V1 and V2 to the nearest mV with unit. 1
V2  V1. 1
1(c) Six sets of readings of d, V1 and V2 with correct trend (d increases as average V1 increases and average V2 decreases) and
without help from the Supervisor scores 4 marks, five sets scores 3 marks, etc.
4
Range: dmin ⩽ 22.0 cm and dmax ⩾ 65.0 cm. 1
Column headings:
The presentation of quantity and unit must conform to accepted scientific convention e.g. ( 2
1
V
V
)d / m, d2 / m2.
1
All values of ( 2
1
V
V
)d must be given to the same number of s.f. as (or one more than) the least number of s.f. in d, V1 and V2.
1
Calculation: Correct calculation of ( 2
1
V
V
)d.
1

PUBLISHED
May/June 2022
1(d)(i) Axes:
1
Plotting of points:
1
Quality:
All points in the table must be plotted (at least 5) on the grid for this mark to be awarded.
Trend of points must be negative.
It must be possible to draw a straight line that is within  2.5 cm (to scale) on the ( 2
1
V
V
)d axis of all plotted points.
1
Allow one anomalous point only if clearly indicated (i.e. circled or labelled) by the candidate. There must be at least 5 points
left after the anomalous point is disregarded.
1
1(d)(iii) Gradient:
1
y-intercept:
Correct read-off from a point on the line and substituted into y = mx + c or an equivalent expression.
Read-off accurate to half a small square in both x and y directions.
or
Intercept read directly from the graph, with read-off at d2 = 0, accurate to half a small square.
1

PUBLISHED
May/June 2022
1(e) Value of P = candidate’s gradient and value of Q = candidate’s intercept.
1
Unit for P: m–1, cm–1 or mm–1
and
unit for Q: m, cm or mm.
1
1(f) Line labelled W with steeper gradient and smaller intercept.
W
1

PUBLISHED
May/June 2022
2(a)(i) Raw value(s) of A to the nearest mm with unit and A ⩾ 5.0 cm. 1
Evidence of repeat readings. 1
2(a)(ii) Percentage uncertainty in A based on absolute uncertainty ⩾ 3 mm.
If several readings have been taken, then the absolute uncertainty can be half the range (but not zero) provided the working
is clearly shown.
1
2(b)(i) Value of  to the nearest degree in the range 60°–70°. 1
Value of H with unit. 1
2(b)(ii) Correct calculation of cos2 . 1
2(c) Second value of . 1
Second value of H. 1
Second value of H > first value of H. 1
2(d)(i) Two values of k calculated correctly. The final k values must not be written as fractions. 1
2(d)(ii) Justification for significant figures in k linked to significant figures in H, A and either  or cos  . 1
1

PUBLISHED
May/June 2022
B Difficult to measure  or angle with reason e.g. hand moves during measurement/holding protractor in hand/parallax
error/string too thick.
C Difficult to judge the horizontal or vertical.
D Masses or strings collide/hit stand/string wraps around boss/string slips off rod of clamp/trajectory of motion out of
alignment/masses not in the right plane.
E Difficult to measure H or A with reason e.g. uncertain where the top measurement is/measured distance not the same as
the height the mass falls/mass moves when touched or measured.
4
2(f)(ii) A Take more readings and plot a graph or take more readings and compare k values (not “repeat readings” on its own).
B Method to improve measurement of  e.g. clamp the 10g mass or clamp protractor/thinner string/put a board behind
with marked angle(s)/take a photo and measure angle/project angle onto a screen/use a stop at the correct angle.
C Method to determine the vertical or horizontal e.g. use a plumb-line/spirit level/set square with detail.
D Method to improve alignment e.g. use longer rod/notched rod/larger diameter on end of rod/place plasticine on the end
of the rod/use guide.
E Improved method to measure H or A e.g. use a clamped pointer/take a photo with a scale/use large dividers or calipers.
4

PHYSICS 9702/34
MARK SCHEME
Maximum Mark: 40
Published
Teachers.

PUBLISHED
May/June 2022
marking principles.
descriptors.

PUBLISHED
May/June 2022
terms with which they may be confused (e.g. ethane ethene, glucagon / glycogen, refraction / reflection).

PUBLISHED
May/June 2022
your working’.

PUBLISHED
May/June 2022
1(a) Value of V in range 5.00–7.00 V with unit and to the nearest 0.01 V. 1
1(b) Value for t with unit in the range 2.0–20.0 s. 1
Evidence of repeat readings for t. 1
1(c) Six sets of readings of R and t with correct trend (as R increases, t increases) and without help from the Supervisor scores
4 marks, five sets scores 3 marks etc.
4
Range: Rmin ⩽ 22 k and Rmax ⩾ 470 k. 1
Column headings:
The presentation of quantity and unit must conform to accepted scientific convention e.g. 1 / R (k–1).
1
Consistency:
Values of t must all be given to the nearest 0.1 s or all to the nearest 0.01 s.
1
All values of 1 / t must be given be to the same number of s.f. as (or one more than) the s.f. in the corresponding value of t.
1
Calculation: Values of 1 / t calculated correctly. 1

PUBLISHED
May/June 2022
1(d)(i) Axes:
1
Plotting of points:
1
Quality:
All points in the table must be plotted (at least 5) for this mark to be awarded.
Trend of points must be positive
It must be possible to draw a straight line that is within  0.0025 k–1 on the 1 / R axis of all plotted points.
1
Allow one anomalous point only if clearly indicated (i.e. circled or labelled) by the candidate. There must be at least 5
points left after the anomalous point is disregarded.
1
1(d)(iii) Gradient:
1
y-intercept:
Correct read-off from a point on the line substituted into y = mx + c or an equivalent expression, with read-off accurate to
half a small square in both x and y directions.
or
Intercept read directly from the graph, with read-off at 1 / R = 0, accurate to half a small square.
1

PUBLISHED
May/June 2022
1(e) Value of a = candidate’s gradient and value of b = candidate’s intercept.
1
Units for a and b correct (e.g.  s–1 for a and s–1 for b). 1

9702_s22_ms_all.pdf

Recommended

Recommended

More Related Content

What's hot

What's hot (20)

Similar to 9702_s22_ms_all.pdf

Similar to 9702_s22_ms_all.pdf (20)

More from Sajit Chandra Shakya

More from Sajit Chandra Shakya (20)

Recently uploaded

Recently uploaded (20)

9702_s22_ms_all.pdf