Write a Pep8 Assembly program that reads in and stores two integers .pdf

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Write a Pep/8 Assembly program that reads in and stores two integers from the user and prints out their sum in the form: Total = Submit: Pep/8 formatted program in a text file Solution Answer: Assembly Language Program : .zero 1 .LC0: .string \"Enter two integers: \" .LC1: .string \"Total\" .LC2: .string \" = \" main: push rbp mov rbp, rsp sub rsp, 16 mov esi, OFFSET FLAT:.LC0 mov edi, OFFSET FLAT:std::cout call std::basic_ostream >& std::operator<< >(std::basic_ostream >&, char const*) lea rax, [rbp-8] mov rsi, rax mov edi, OFFSET FLAT:std::cin call std::basic_istream >::operator>>(int&) mov rdx, rax lea rax, [rbp-12] mov rsi, rax mov rdi, rdx call std::basic_istream >::operator>>(int&) mov edx, DWORD PTR [rbp-8] mov eax, DWORD PTR [rbp-12] add eax, edx mov DWORD PTR [rbp-4], eax mov esi, OFFSET FLAT:.LC1 mov edi, OFFSET FLAT:std::cout call std::basic_ostream >& std::operator<< >(std::basic_ostream >&, char const*) mov esi, OFFSET FLAT:.LC2 mov rdi, rax call std::basic_ostream >& std::operator<< >(std::basic_ostream >&, char const*) mov rdx, rax mov eax, DWORD PTR [rbp-4] mov esi, eax mov rdi, rdx call std::basic_ostream >::operator<<(int) mov eax, 0 leave ret __static_initialization_and_destruction_0(int, int): push rbp mov rbp, rsp sub rsp, 16 mov DWORD PTR [rbp-4], edi mov DWORD PTR [rbp-8], esi cmp DWORD PTR [rbp-4], 1 jne .L5 cmp DWORD PTR [rbp-8], 65535 jne .L5 mov edi, OFFSET FLAT:std::__ioinit call std::ios_base::Init::Init() mov edx, OFFSET FLAT:__dso_handle mov esi, OFFSET FLAT:std::__ioinit mov edi, OFFSET FLAT:std::ios_base::Init::~Init() call __cxa_atexit .L5: nop leave ret push rbp mov rbp, rsp mov esi, 65535 mov edi, 1 call __static_initialization_and_destruction_0(int, int) pop rbp ret.

Write a Pep/8 Assembly program that reads in and stores two integers from the user and prints
out their sum in the form: Total = Submit: Pep/8 formatted program in a text file
Solution
Answer:
Assembly Language Program :
.zero 1
.LC0:
.string "Enter two integers: "
.LC1:
.string "Total"
.LC2:
.string " = "
main:
push rbp
mov rbp, rsp
sub rsp, 16
mov esi, OFFSET FLAT:.LC0
mov edi, OFFSET FLAT:std::cout
call std::basic_ostream >& std::operator<< >(std::basic_ostream >&, char const*)
lea rax, [rbp-8]
mov rsi, rax
mov edi, OFFSET FLAT:std::cin
call std::basic_istream >::operator>>(int&)
mov rdx, rax
lea rax, [rbp-12]
mov rsi, rax
mov rdi, rdx
call std::basic_istream >::operator>>(int&)
mov edx, DWORD PTR [rbp-8]
mov eax, DWORD PTR [rbp-12]
add eax, edx
mov DWORD PTR [rbp-4], eax
mov esi, OFFSET FLAT:.LC1
mov edi, OFFSET FLAT:std::cout

call std::basic_ostream >& std::operator<< >(std::basic_ostream >&, char const*)
mov esi, OFFSET FLAT:.LC2
mov rdi, rax
call std::basic_ostream >& std::operator<< >(std::basic_ostream >&, char const*)
mov rdx, rax
mov eax, DWORD PTR [rbp-4]
mov esi, eax
mov rdi, rdx
call std::basic_ostream >::operator<<(int)
mov eax, 0
leave
ret
__static_initialization_and_destruction_0(int, int):
push rbp
mov rbp, rsp
sub rsp, 16
mov DWORD PTR [rbp-4], edi
mov DWORD PTR [rbp-8], esi
cmp DWORD PTR [rbp-4], 1
jne .L5
cmp DWORD PTR [rbp-8], 65535
jne .L5
mov edi, OFFSET FLAT:std::__ioinit
call std::ios_base::Init::Init()
mov edx, OFFSET FLAT:__dso_handle
mov esi, OFFSET FLAT:std::__ioinit
mov edi, OFFSET FLAT:std::ios_base::Init::~Init()
call __cxa_atexit
.L5:
nop
leave
ret
push rbp
mov rbp, rsp
mov esi, 65535
mov edi, 1

call __static_initialization_and_destruction_0(int, int)
pop rbp
ret

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Differentiate the processes of oogenesis and spermatogenesis. Are there similarities between the two processes? Differences? Consider the cells, their structures and functions. Solution Comparison between Spermatogenesis and Oogenesis Characteristics Spermatogenesis Oogenesis Definition The process of formation of sperm cells is called spermatogenesis Formation of ovum is called oogenesis Primary organ Testis (in males) Ovary (in females) The source cell/ structure that undergoes gametogenesis Spermatogonium Primordial follicle Source cell is preserved Yes, Spermatogonium is a stem cell. No Type of cell division Meiosis Meiosis Onset of gametogenesis At puberty. Both meiosis I and II in spermatogonium begin at onset of puberty. During embryonic development. Meiosis I begins in fetal ovary. Meiosis II completes after onset of puberty in reproductive cycles. Continuous or cyclic Continuous. Millions of sperms are produced each day. Cyclic. Only one mature ovum is produced per reproductive cycle (of 28 days). Occurrence of gametogenesis in life Begins at puberty Continues throughout life Begins at menarche Ends at menopause No. of functional gametes in one cycle 4 1 Polar cells (that degenerate later) produced No Yes, one polar cell in each of meiosis I and II. In spite of major difference of these two processes, they both share a common path and fate- they meiotic divisions that produce haploid gametes. Characteristics Spermatogenesis Oogenesis Definition The process of formation of sperm cells is called spermatogenesis Formation of ovum is called oogenesis Primary organ Testis (in males) Ovary (in females) The source cell/ structure that undergoes gametogenesis Spermatogonium Primordial follicle Source cell is preserved Yes, Spermatogonium is a stem cell. No Type of cell division Meiosis Meiosis Onset of gametogenesis At puberty. Both meiosis I and II in spermatogonium begin at onset of puberty. During embryonic development. Meiosis I begins in fetal ovary. Meiosis II completes after onset of puberty in reproductive cycles. Continuous or cyclic Continuous. Millions of sperms are produced each day. Cyclic. Only one mature ovum is produced per reproductive cycle (of 28 days). Occurrence of gametogenesis in life Begins at puberty Continues throughout life Begins at menarche Ends at menopause No. of functional gametes in one cycle 4 1 Polar cells (that degenerate later) produced No Yes, one polar cell in each of meiosis I and II..

Differentiate the processes of oogenesis and spermatogenesis. Are th.pdf

Differentiate the processes of oogenesis and spermatogenesis. Are th.pdf

Differentiate the processes of oogenesis and spermatogenesis. Are th.pdf

Define induction and give an example of deductive reasoning? Solution There are two methods of reasoning. One is Deductive approach and another is Inductive approach. Deductive reasoning:-This kind of reasoning works from the general to more specific. It is also referred to as \"Top-down\" approach. Examples:- 1) If X = Y and Y = Z, then by deductive reasoning X = Z. 2) Snakes are reptiles and reptiles are cold-blooded, by deductive reasoning it can be said that snakes are cold-blooded. Inductive reasoning:- Inductive reasoning as opposed to deductive reasoning work from specific observations to broader generalizations and theories. It is also referred to as \"bottom up\" approach in informal sense. Example:- 1) A just moved here from Hongkong. A has red hair, therefore by inductive reasoning, it can be said that People from Hongkong have red hair..

Define induction and give an example of deductive reasoningSolu.pdf

Define induction and give an example of deductive reasoningSolu.pdf

Define induction and give an example of deductive reasoningSolu.pdf

A report says that the between-subjects factor of participants sal.pdf

A report says that the between-subjects factor of participants sal.pdf

A report says that the between-subjects factor of participants sal.pdf

City GUI Write a Java GUI program which reads data about US cities. The data file is different, but is in the same format as in Lab #01. The GUI provides a combo box with the cities in the data file. As cities are selected in the combo box, information about the city is displayed. Requirements 1. The program must have a graphical user interface similar to the one on the bottom of the Requirements section. It must have a text field, a button, a combo box, and labels. 2. One or more layout managers must be used. This example was created using a border layout. The east and west panels each used a grid layout in addition. 3. A message must be displayed in the GUI after the data has been successfully read. A message should also be displayed if the file is not found. The program should not exit in that case, but allow the user to enter a different file name. 4. The combo box must be populated by the names of the cities in the data file in alphabetical order. Note that this means the GUI starts with an empty combo box. Items are added to it as or after the data file is read. 5. The program must provide an ActionListener for the Read button. It must also provide either an ActionListener or an ItemListener for the combo box, which displays the state, zip code, and time zone for that city. 6. The information for each city must be stored in its own object. Another object must be used to manage the collection of cities. This is similar to Lab #01. For this assignment you may assume that there will be no more than 100 cities. 7. The time zone should be displayed as the correct abbreviation for that city’s time zone in July. Here are the abbreviations. If the city observes daylight savings time, the S should be changed to a D. Note that some cities in the data file do not observe daylight savings time. Hours relative to GMT -4 -5 -6 -7 -8 -9 -10 Standard Time Abr. AST EST CST MST PST AKST HST I have attached an executable .jar file to the assignment that you can run to see how this program should work. Copy it to your computer. Copy the data file into the same directory as the .jar file. Suggestions 1. Create class diagrams first. This will help you think through and organize your program. There are many ways to do this. Start with the class diagrams from Lab #01. Both classes will require some additions. 2. Create the GUI and handle the IO in a separate class which extends JFrame. The main method can be included in this class. 3. Don’t worry about making your implementation efficient or using wonderful abstract data types (ADTs). You will be required to do that soon enough. 4. This program will take you several days to complete. Break it down into smaller tasks. This is the order I used, yours may be different. *Modify the class diagrams from Lab #01 to include new requirements that you identify now. You can add additional functionality later as you discover the need. *Implement those changes in the classes. * Create a GUI class. Implement a non-functiona.

City GUIWrite a Java GUI program which reads data about US cities..pdf

City GUIWrite a Java GUI program which reads data about US cities..pdf

City GUIWrite a Java GUI program which reads data about US cities..pdf

What is the role of sulfur chemoautotrophs in the sulfur cycle? Decomposition reduction oxidation assimilation Reduction of CO2 to generate carbohydrates can occur when coupled to the oxidation of reduced sulfur compounds (for examples, H2S). This latter process is carried out by what type of sulfate oxidizers sulfate reducers Solution 10 Oxidation Sulfur chemotrophs oxidize sufur to derive energy for the synthesis of ATP.

What is the role of sulfur chemoautotrophs in the sulfur cycle Deco.pdf

What is the role of sulfur chemoautotrophs in the sulfur cycle Deco.pdf

What is the role of sulfur chemoautotrophs in the sulfur cycle Deco.pdf

What is the PDU at Layer 4 called? A. Data B. Segment C. Packet D. Frame E. Bit Solution B is correct. The Layer 4 PDU is called a segment. A, C, D, and E are incorrect. A is incorrect because the data is the PDU for the top three layers. C is incorrect because the packet is the PDU at the Network layer. D is incorrect because the frame is the PDU for the Data Link layer. E is incorrect because the bit is the PDU at the Physical layer..

What is the PDU at Layer 4 calledA. DataB. SegmentC. Packet.pdf

What is the PDU at Layer 4 calledA. DataB. SegmentC. Packet.pdf

What is the PDU at Layer 4 calledA. DataB. SegmentC. Packet.pdf

Briefly describe the contributions to the quality movement made by each of the following pioneers. Shewhart Dodge and Romig Sarasohn Deming Juran Solution Walter Shewhart - The Grandfather of Total Quality Management. His Ideas The original notions of Total Quality Management and continuous improvement trace back to a former Bell Telephone employee named Walter Shewhart. One of W. Edwards Deming\'s teachers, he preached the importance of adapting management processes to create profitable situations for both businesses and consumers, promoting the utilization of his own creation -- the SPC control chart. Dr. Shewhart believed that lack of information greatly hampered the efforts of control and management processes in a production environment. In order to aid a manager in making scientific, efficient, economical decisions, he developed Statistical Process Control methods. Many of the modern ideas regarding quality owe their inspirtation to Dr. Shewhart. He also developed the Shewhart Cycle Learning and Improvement cycle, combining both creative management thinking with statistical analysis. This cycle contains four continuous steps: Plan, Do, Study and Act. These steps (commonly refered to as the PDSA cycle), Shewhart believed, ultimately lead to total quality improvement. The cycle draws its structure from the notion that constant evaluation of management practices -- as well as the willingness of management to adopt and disregard unsupported ideas --are keys to the evolution of a successful enterprise. Harold French Dodge (January 23, 1893 in Lowell, Massachusetts – December 10, 1976) was one of the principal architects of the science of statistical quality control. He is universally known for his work in originating acceptance sampling plans for putting inspection operations on a scientific basis in terms of controllable risks. From 1917 to 1958 worked at quality assurance department at Bell Laboratories with Walter Shewhart, George Edwards, Harry Romig, R. L. Jones, Paul Olmstead, E.G.D. Paterson, and Mary N. Torrey. At that time the basic concepts of acceptance sampling was developed, such as : · Consumer\'s Risk, · Producer\'s Risk, · double sampling, · lot tolerance percent defective (LTPD), and · average outgoing quality limit (AOQL). Also he originated several types of: · acceptance sampling schemes, · CSP type continuous sampling plans, · chain sampling plans, and · skip-lot sampling plans. During World War II, Dodge served as a consultant to the Secretary of War, and was chairman of the American Standards Association (now the American National Standards Institute) War Committee Z1, which prepared the Z1.1, Z1.2, and Zl.3 quality control standards. After he retired from Bell Labs in 1958, Dodge became a professor of applied mathematical statistics at Rutgers. He also served as a consultant to NASA and the Sandia Corporation. The American Society for Testing and Materials honors Harold Dodge\'s memory with the Harold F. Dodge Award. Ho.

Briefly describe the contributions to the quality movement made by e.pdf

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Background Angiosperms (flowering plants) are the largest Phylum in the plant kingdom Plantae, (Note that the Phylum A may also called Anthophyta or Magnoliophyta in different classification systems.) These plants have true roots, stems, leaves, and flowers. The roots grow into the soil to anchor the plant in place and take up water and nutrients. The leaves are above ground and act as the main organs for photosynthesis. Stems provide above ground support for the plant and operate as conduits to move nutrients and water throughout the plant. Flowers contain the male and female reproductive organs of the plant. Assignment Details Part 1 Plants develop specialized roots, stems, leaves, and flowers to make them better adapted to their environment. People exploit many modifications as vegetables. An example of this is the taproot of carrots. The carrot plant stores sugars in the taproot to supply energy for the formation of flowers in later development. People dig up and eat the taproots while the sugar content is still high. Complete the following: Describe the anatomy (structure) and physiology (function) of a plant. Is the structure of your plant a modification from the standard root, stem, leaf, or flower? Explain how this structure differs from the standard root, stem, leaf, or flower. Compare the plant that you have chosen, its structure, and its function with 1 or more of your classmates\' choices. Part 2 Animals are important for humans in ways other than providing food. Medicines, clothing, beauty, fuel, air quality, building materials, and industrial products are a few of the ways in which humans exploit animals. Complete the following: Choose l product or benefit that people get from animals (besides food), describe it, and explain how people benefit. Which do you think is the most important benefit of animals? Select 1 benefit and explain. List 3 adaptations that animals have that plants do not have. Provide references in APA format. This includes a reference list and in-text citations for references used throughout the assignment Solution 1. the normal function of roots is fixation of the plant in the soil absorption of water and Minerals from the soil and conduction of the materials to the stem but in some plants roots perform special functions like storage of food materials(carrot,raddish) respiration(rhizopora) vegetative reproduction (sweet potato)support(betel vine) photosynthesis(orchids). Betel vine: Weak Climbing Plants produce some advantitious roots which cling to the supports and help the plants in climbing they sometimes they secrete sticky substance or a disc like structures for this purpose. Betel Vine is a plant having climbing roots these adventitious roots are produced from their nodes which help them to climb over a support another example is money plant. These roots are aerial roots which twist and clasp the support to help plant to vlimb. Normal rootsd show positive geotropism but these climbing roots show negativ.

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