1. TV30003 PENGENALAN KIMIA ANALISIS DAN FIZIKAL
SAINS KOHORT 1
1
REVISION EXERCISE 10 (Section A)
1. Answer:D. This is because:
Temperature High When temperature increase,the speed of reaction will also
increase.
Pressure High Increasing in pressure will speed up the reaction. Thus the
production of ammonia will also increase.
Catalyst Present The presence of catalyst will increase the yield of ammonia
2. Answer: C.
Rate of effective collision will increase in presence of catalyst. This is because the high effective
collision will speed up the reaction.
3.
(Answer:A) Calculation:
Initial concentration 0.84 mol 0.18 mol -
Change of concentration -x +x +x
Equilibrium concentration 0.84 - x 0.18 + x x
=> 0.05 =
0.042 - 0.05x = 0.18x +
0 = + 0.18x + 0.05x – 0.042
0 = + 0.23x – 0.042, x = 0.12
4. Answer:A.
The pressure in the container increases to a maximum constant value. The pressure will maintain at
certain value and become constant.
5. Answer:D. .
concentration of a product will increase when the pressure of gas increase.
6. Answer: A. Decrease, Increase.
2. TV30003 PENGENALAN KIMIA ANALISIS DAN FIZIKAL
SAINS KOHORT 1
2
As the temperature increase, the rate constant also will increases. In this case, when R react to
become S, the energy is being release therefore the temperature decreases.
7.
(Answer:D)
Calculation:
Initial concentration 0.6 mol 3.0 mol - -
Change of concentration -x -x +x +3x
Equilibrium
concentration
0.1 mol 2.5 mol 0.5 mol 1.5 mol
3x = 1.5 => x = = 0.5
= = 6.75
8.
(Answer:D)
Calculation:
PN2O4 = XN2O4.Ptotal = 1/3 X 100 = 100/3
PNO2 = XNO2.Ptotal = 2/3 X 100 = 200/3
9.
(Answer:B)
Calculation:
3. TV30003 PENGENALAN KIMIA ANALISIS DAN FIZIKAL
SAINS KOHORT 1
3
Initial concentration 2 mol 4 mol - -
Change of concentration -x -x +x +x
Equilibrium concentration 1 mol 3 mol 1 mol 1 mol
mol
10.
(Answer:B)
Calculation:
Initial concentration 2 mol - -
Change of concentration -2x +2x +x
Equilibrium concentration 1 mol 1 mol 0.5 mol
Degree of dissociation = x = 0.5 (substitute into the x in the table)
= 0.5
11. positive
Answer:C.
This is because the number of moles of product increase as number of moles of reactant decrease.
12. Answer:B.
The changing of pressure does not affect the rate of reaction for solids or liquid phase.
13.
4. TV30003 PENGENALAN KIMIA ANALISIS DAN FIZIKAL
SAINS KOHORT 1
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Which of the following is correct when the above system achieve equilibrium?
Answer:D. constant =
This occur in reverse reaction.
14. , positive
Which of the following will increase the of the above reaction?
Answer:C. Increasing the partial pressure of
The yield of product will increase when the pressure increase.
15.
Answer:B.
The energy increases as the temperature increases.
16.
Answer:B
Calculation:
Initial concentration 3 mol 5 mol -
Change of concentration -x -x +2x
Equilibrium 2 mol 4 mol 2 mol
5. TV30003 PENGENALAN KIMIA ANALISIS DAN FIZIKAL
SAINS KOHORT 1
5
concentration
2x = 2 mol => x = 1 mol
0.5
17. Answer:D.
Intersection shaded region for Q
18.
Answer:D
Calculation:
Initial concentration 4 mol - -
Change of concentration -2x +2x +x
Equilibrium
concentration
2.4 mol 1.6 mol 0.8 mol
19. Answer:C.
In equilibrium state, z increase with time. On the other hand, x and y will decrease with time. After
that, they will remain unchanged.
20) Answer: B.
Thus,
