3. LIMITATIONS
The test is approximate and assumes
that the counts are large enough for
the normal approximation to the
Poisson to apply.
4. METHOD
Let n1 and n2 be the two counts taken over times
t1 and t2, respectively. Then the two average
frequencies are R1 = n1/t1 and R2 = n2 t2 . To
test the assumption of equal average frequencies
we use the test statistic
5. 𝑍 =
𝑅1 − 𝑅2
𝑅1
𝑡1
+
𝑅2
𝑡2
This may be compared with a
standard normal distribution using
either a one-tailed or two-tailed test.
7. 1.) Two traffic roundabouts are compared for intensity
of traffic at non-peak times with steady conditions.
Roundabout one has 952 arrivals over 22 minutes and
roundabout two has 1168 arrivals over 20 minutes.
The arrival rates per minute are : 952/22 (43.27) and
1168/30 (38. 93) respectively. What do these results
say about the two arrival rates or frequency taken over
the two time intervals?
13. (V) DECISION
Reject the Ho o f no difference
between two rates at 5% level of
significance.
14. (VI) CONCLUSION
Therefore, the roundabout one has
an intensity of arrival significantly
higher than the roundabout two.
15. 2.) Mila and Christine are law students; they
are being compared of their capacity to
memorized laws and articles over times. Mila
was able to memorized 604 words over 15
minutes, and Christine memorized 911 words
over 23 minutes. The average frequency per
minute are: 604/15 (40.27) and 911/23(39.01),
respectively. At 5% level of significance, are
the two counts differ significantly?