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GE8152
ENGINEERING GRAPHICS
Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
UNIT - V
ISOMETRIC PROJECTIONS
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Definitions
Isometric Projection :
ISO (in Greek) means equal
METRIC means measure.
Hence Isometric Projection means a system of
projection of equality of measure.
NOTE :
To distinguish Isometric Projection from
Orthographic Projection, use CAPITAL
LETTERS for the corners in the Isometric
projection. Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Terminology
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Terminology
30°30°
U
V
W
S
N
Q
T R
30°
45°
O
P
M
120°
S
Q
V
120°
120°
30° 30°
R
RQ, RS & RV are isometric axes
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Terminology
Isometric Axes : The three lines RQ, RS and RV
making 120° with each other are called the
isometric axes.
Isometric Lines : A line parallel to any of these
isometric axes is known as an isometric line.
Isometric Planes : The planes containing the
faces of the cube and all the planes parallel
to these planes are termed isometric planes.
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Isometric Scale
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Isometric Scale
15°
P 0 1 2 3 4 R
Q
0’
1’
2’
3’
4’
45°
ISOMETRIC LENGTHS
TRUE LENGTHS
Isometric Length = 0.82 X True length
Example :
True length = 10 mm
Isometric length = 0.82 X 10 = 8.2 mm
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 1
Draw the isometric projection of a square
prism of base side 35 mm and height 65 mm.
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 1
65
35
a (a1) b (b1)
c (c1)d (d1)
a’1 (d’1) b’1 (c’1)
b’(c’)a’(d’)
Draw the top and front views of the prism using actual
scale.
Draw the isometric scale.
15°
A 0 1 2 3 4 C
D
0’ 1’ 2’
3’
4’
45°
ISOMETRIC LENGTHS
TRUE LENGTHS
Isometric length = 0.82 X true length
5 6
5’
6’
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Isometric Length = 0.82 X True length
Example :
Isometric length = 0.82 X 35 = 28.7 mm
= 0.82 X 65 = 53.3 mm
65
35
a (a1) b (b1)
c (c1)d (d1)
a’1 (d’1) b’1 (c’1)
b’(c’)a’(d’)
Problem 1
A1
30°
30°
A
B
B1
D1
D
C
C1
No need to draw hidden lines in Isometric
drawings. Here it is only for understanding
purpose only.
Front View
Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
Problem 2
A hexagonal prism of base side 20 mm and
height 45 mm has a square hole of side 16
mm at the centre. The axes of the square and
hexagon coincide. One of the faces of the
square hole is parallel to a face of the
hexagon. Draw the isometric projection of
the prism with hole to full scale.
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
p
q r
s
tu
20
45
16
1 4
32
Isometric Length = 0.82 X True length
Example :
Isometric length = 0.82 X 20 = 16.4 mm
= 0.82 X 45 = 36.9 mm
1
30° 30°
U
T
4
2
Q
P
3
P1
Q1
U1
T1
R
S
d
b
c
a
A
B
C
D
+
Problem 2 Mark U1 , measure the distance “1u”
in top view . Convert it into
isometric length
(p1)
(q1) (r1)
(s1)
(t1)(u1)
p’ u’(q’) t’(r’) s’
(p1) u1(q1) t1(r1) s1
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 3
A square prism of base 20 mm side and
height 40 mm rests on one of its ends on the
HP. All the base sides of the prism are equally
inclined to the VP. It is cut by a plane
perpendicular to the VP and inclined at 45°
to the HP that passes through a point on the
axis 7 mm from the top. Draw the isometric
projection of the prism. Page no 393
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
V.P
.
X Y
H.P
.
Problem 3
p (t)
2
s(w)
q (u)
p’
t’
s’(q’)
w’(u’)
r’
403’
v’
1
1’
2’(4’)
r (v)
745°
3
4
m
n
5
a b
cd
B
30°
30°
C
A
D
Front View
P
T
W V
U
S R
Q
1
2
3
4
5
m1 = M1 ; n1 = N1
M
N
W2 = w’2’ ; V3 = v’3’ ; U4 = u’4’
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 4
Draw the isometric projections of a cylinder
of base diameter 50 mm and axis 80 mm long
when it rests with its base on HP and on VP.
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
p q
rs
a
b
c
d
φ50
Problem 4
(a1)
(b1)
(c1)
(d1)
d’1 b’1a’1(c’1)
a’(c’) b’d’
P
30° 30°
A
B
QS
R
D1
C1 B1
A1
D
C
O1 O2
Mark the mid-points of PQ, QR, RS
and SP as A1, B1, C1, D1
P as center and PC as radius draw
an arc C1B1
80
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 4
Q
30° 30°
S
P
R
A
B
D
C
O1
O2
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 5
A pentagonal pyramid, 30 mm edge of base
and 65 mm height stands on HP such that an
edge of the base is parallel to VP and nearer
to it. A section plane perpendicular to VP and
inclined at 30° to HP cuts the pyramid
passing through a point on the axis at a
height of 35 mm from the base. Draw the
isometric projection of the truncated
pyramid, showing the cut surface.
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 5
a
30
b
c
de
a’ b’ c’(d’)(e’)
o
65
o’
35
1’
2’
3’(4’)
(5’)
30°
1 3
45
2
p q
rs
Q
30° 30°
2
RP
S
B C
D
A
1
O1
E
O
O1O = isometric length of the axis
3
4
5
Front View
11
21
31
41
51
At 11 erect vertical to meet the
slant edge OA at 1.
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 6
A cylinder 50 mm diameter and 60 mm
height stands on HP. A section plane
perpendicular to VP inclined at 55° to HP cuts
the cylinder and passes through a point on
the axis at a height of 45 mm above the base.
Draw the isometric projection of the
truncated portion of the cylinder, when the
cut surface is clearly visible to the observer.
Page no 19.26
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 6
V.P
.
X Y
H.P
.
60
a b’ c’ d’ e’
a1’
e1’
55°
a(a1)
b(b1)
c(c1)
d(d1)
e(e1)
(f’)(g’)(h’)
d1’(f1’)
c1’(g1’)
b1’(h1’)
f(f1)h(h1)
g(g1)
φ50
45
1’
2’(7’)
3’(6’)
4’(5’)
1
2
3
4
56
7
p(p1) q(q1)
r(r1)s(s1)
P1
30° 30°
P
R
Q1
S1
R1
A1
G1
E1
C1
1
S
O1 O2
Q
2
3
4
5
6
7
Mark the section point 1 on the generator A1A in the
isometric projection such that A11 = isometric length of a1’1’
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 7
A cone of base diameter 50 mm and height
55 mm is resting on its base on the HP. It is
cut by a plane perpendicular to the VP and
inclined at 30° to the HP. The plane meets
the axis at a distance of 25 mm from the
apex. Draw the isometric view of the
truncated cone. Page no 401
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 7
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 8
Draw the isometric view of a frustum of a
hexagonal pyramid when it is resting on its
base on the HP with two sides of the base
parallel to the VP. The side of base is 20 mm
and top 8 mm. The height of the frustum is
55 mm. page no 391
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 8
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 8
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 9
A hexagonal shaped solid of base edge 20 mm
and height 40 mm lies centrally on a cylinder
of 60 mm diameter and 20 mm thick. Draw
the isometric projection of the solids if their
axes lie on the same line.
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
c
s r
q
a b
p
d
φ60
Problem 9
30° 30°
A
BD
C
20
40
P
Q
R
S
20
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni
Problem 9
Ravi Sivaprakash AP/MECH AAMEC
Kovilvenni

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GE8152 ENGINEERING GRAPHICS Unit v-1. isometric projection

  • 2. UNIT - V ISOMETRIC PROJECTIONS Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 3. Definitions Isometric Projection : ISO (in Greek) means equal METRIC means measure. Hence Isometric Projection means a system of projection of equality of measure. NOTE : To distinguish Isometric Projection from Orthographic Projection, use CAPITAL LETTERS for the corners in the Isometric projection. Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 5. Terminology 30°30° U V W S N Q T R 30° 45° O P M 120° S Q V 120° 120° 30° 30° R RQ, RS & RV are isometric axes Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 6. Terminology Isometric Axes : The three lines RQ, RS and RV making 120° with each other are called the isometric axes. Isometric Lines : A line parallel to any of these isometric axes is known as an isometric line. Isometric Planes : The planes containing the faces of the cube and all the planes parallel to these planes are termed isometric planes. Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 7. Isometric Scale Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 8. Isometric Scale 15° P 0 1 2 3 4 R Q 0’ 1’ 2’ 3’ 4’ 45° ISOMETRIC LENGTHS TRUE LENGTHS Isometric Length = 0.82 X True length Example : True length = 10 mm Isometric length = 0.82 X 10 = 8.2 mm Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 9. Problem 1 Draw the isometric projection of a square prism of base side 35 mm and height 65 mm. Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 10. Problem 1 65 35 a (a1) b (b1) c (c1)d (d1) a’1 (d’1) b’1 (c’1) b’(c’)a’(d’) Draw the top and front views of the prism using actual scale. Draw the isometric scale. 15° A 0 1 2 3 4 C D 0’ 1’ 2’ 3’ 4’ 45° ISOMETRIC LENGTHS TRUE LENGTHS Isometric length = 0.82 X true length 5 6 5’ 6’ Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 11. Isometric Length = 0.82 X True length Example : Isometric length = 0.82 X 35 = 28.7 mm = 0.82 X 65 = 53.3 mm 65 35 a (a1) b (b1) c (c1)d (d1) a’1 (d’1) b’1 (c’1) b’(c’)a’(d’) Problem 1 A1 30° 30° A B B1 D1 D C C1 No need to draw hidden lines in Isometric drawings. Here it is only for understanding purpose only. Front View Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 12. Problem 2 A hexagonal prism of base side 20 mm and height 45 mm has a square hole of side 16 mm at the centre. The axes of the square and hexagon coincide. One of the faces of the square hole is parallel to a face of the hexagon. Draw the isometric projection of the prism with hole to full scale. Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 13. p q r s tu 20 45 16 1 4 32 Isometric Length = 0.82 X True length Example : Isometric length = 0.82 X 20 = 16.4 mm = 0.82 X 45 = 36.9 mm 1 30° 30° U T 4 2 Q P 3 P1 Q1 U1 T1 R S d b c a A B C D + Problem 2 Mark U1 , measure the distance “1u” in top view . Convert it into isometric length (p1) (q1) (r1) (s1) (t1)(u1) p’ u’(q’) t’(r’) s’ (p1) u1(q1) t1(r1) s1 Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 14. Problem 3 A square prism of base 20 mm side and height 40 mm rests on one of its ends on the HP. All the base sides of the prism are equally inclined to the VP. It is cut by a plane perpendicular to the VP and inclined at 45° to the HP that passes through a point on the axis 7 mm from the top. Draw the isometric projection of the prism. Page no 393 Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 15. V.P . X Y H.P . Problem 3 p (t) 2 s(w) q (u) p’ t’ s’(q’) w’(u’) r’ 403’ v’ 1 1’ 2’(4’) r (v) 745° 3 4 m n 5 a b cd B 30° 30° C A D Front View P T W V U S R Q 1 2 3 4 5 m1 = M1 ; n1 = N1 M N W2 = w’2’ ; V3 = v’3’ ; U4 = u’4’ Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 16. Problem 4 Draw the isometric projections of a cylinder of base diameter 50 mm and axis 80 mm long when it rests with its base on HP and on VP. Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 17. p q rs a b c d φ50 Problem 4 (a1) (b1) (c1) (d1) d’1 b’1a’1(c’1) a’(c’) b’d’ P 30° 30° A B QS R D1 C1 B1 A1 D C O1 O2 Mark the mid-points of PQ, QR, RS and SP as A1, B1, C1, D1 P as center and PC as radius draw an arc C1B1 80 Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 18. Problem 4 Q 30° 30° S P R A B D C O1 O2 Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 19. Problem 5 A pentagonal pyramid, 30 mm edge of base and 65 mm height stands on HP such that an edge of the base is parallel to VP and nearer to it. A section plane perpendicular to VP and inclined at 30° to HP cuts the pyramid passing through a point on the axis at a height of 35 mm from the base. Draw the isometric projection of the truncated pyramid, showing the cut surface. Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 20. Problem 5 a 30 b c de a’ b’ c’(d’)(e’) o 65 o’ 35 1’ 2’ 3’(4’) (5’) 30° 1 3 45 2 p q rs Q 30° 30° 2 RP S B C D A 1 O1 E O O1O = isometric length of the axis 3 4 5 Front View 11 21 31 41 51 At 11 erect vertical to meet the slant edge OA at 1. Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 21. Problem 6 A cylinder 50 mm diameter and 60 mm height stands on HP. A section plane perpendicular to VP inclined at 55° to HP cuts the cylinder and passes through a point on the axis at a height of 45 mm above the base. Draw the isometric projection of the truncated portion of the cylinder, when the cut surface is clearly visible to the observer. Page no 19.26 Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 22. Problem 6 V.P . X Y H.P . 60 a b’ c’ d’ e’ a1’ e1’ 55° a(a1) b(b1) c(c1) d(d1) e(e1) (f’)(g’)(h’) d1’(f1’) c1’(g1’) b1’(h1’) f(f1)h(h1) g(g1) φ50 45 1’ 2’(7’) 3’(6’) 4’(5’) 1 2 3 4 56 7 p(p1) q(q1) r(r1)s(s1) P1 30° 30° P R Q1 S1 R1 A1 G1 E1 C1 1 S O1 O2 Q 2 3 4 5 6 7 Mark the section point 1 on the generator A1A in the isometric projection such that A11 = isometric length of a1’1’ Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 23. Problem 7 A cone of base diameter 50 mm and height 55 mm is resting on its base on the HP. It is cut by a plane perpendicular to the VP and inclined at 30° to the HP. The plane meets the axis at a distance of 25 mm from the apex. Draw the isometric view of the truncated cone. Page no 401 Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 24. Problem 7 Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 25. Problem 8 Draw the isometric view of a frustum of a hexagonal pyramid when it is resting on its base on the HP with two sides of the base parallel to the VP. The side of base is 20 mm and top 8 mm. The height of the frustum is 55 mm. page no 391 Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 26. Problem 8 Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 27. Problem 8 Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 28. Problem 9 A hexagonal shaped solid of base edge 20 mm and height 40 mm lies centrally on a cylinder of 60 mm diameter and 20 mm thick. Draw the isometric projection of the solids if their axes lie on the same line. Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 29. c s r q a b p d φ60 Problem 9 30° 30° A BD C 20 40 P Q R S 20 Ravi Sivaprakash AP/MECH AAMEC Kovilvenni
  • 30. Problem 9 Ravi Sivaprakash AP/MECH AAMEC Kovilvenni