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SYLLABUS

MATHEMATICS (041)
CLASS XII 2012-13
One Paper
Units

Annexure - ‘ F ’

Three Hours

Marks: 100
Marks

I.

RELATIONS AND FUNCTIONS

10

II.

ALGEBRA

13

III. CALCULUS

44

IV. VECTORS AND THREE - DIMENSIONAL GEOMETRY

17

V.

06

LINEAR PROGRAMMING

VI. PROBABILITY

10
Total

100

The Question Paper will include question(s) based on values

to the extent of 5 marks.

UNIT I. RELATIONS AND FUNCTIONS
1.

Relations and Functions :

(10) Periods

Types of relations: reflexive, symmetric, transitive and equivalence relations. One to one
and onto functions, composite functions, inverse of a function. Binary operations.
2.

Inverse Trigonometric Functions:

(12) Periods

Definition, range, domain, principal value branches. Graphs of inverse trigonometric
functions. Elementary properties of inverse trigonometric functions.

UNIT-II: ALGEBRA
1.

Matrices:

(18) Periods

Concept, notation, order, equality, types of matrices, zero matrix, transpose of a matrix, symmetric
and skew symmetric matrices. Addition, multiplication and scalar multiplication of matrices,
simple properties of addition, multiplication and scalar multiplication. Non-commutativity of
multiplication of matrices and existence of non-zero matrices whose product is the zero matrix
(restrict to square matrices of order 2). Concept of elementary row and column operations.
Invertible matrices and proof of the uniqueness of inverse, if it exists; (Here all matrices will
have real entries).
2.

Determinants:

(20) Periods

Determinant of a square matrix (up to 3 x 3 matrices), properties of determinants,
minors, cofactors and applications of determinants in finding the area of a triangle. Adjoint
and inverse of a square matrix. Consistency, inconsistency and number of solutions of
system of linear equations by examples, solving system of linear equations in two or
three variables (having unique solution) using inverse of a matrix.

87
88
5.

Differential Equations:

(10) Periods

Definition, order and degree, general and particular solutions of a differential equation.
Formation of differential equation whose general solution is given. Solution of
differential equations by method of separation of variables, homogeneous differential
equations of first order and first degree. Solutions of linear differential equation of the
type:
+ py = q, where p and q are functions of x or constant
+ px = q, where p and q are functions of y or constant

UNIT-IV: VECTORS AND THREE-DIMENSIONAL GEOMETRY
1.

2.

Vectors:

(12) Periods

Vectors and scalars, magnitude and direction of a vector. Direction cosines and direction
ratios of a vector. Types of vectors (equal, unit, zero, parallel and collinear vectors),
position vector of a point, negative of a vector, components of a vector, addition of vectors,
multiplication of a vector by a scalar, position vector of a point dividing a line segment in a
given ratio. Scalar (dot) product of vectors, projection of a vector on a line. Vector (cross)
product of vectors. Scalar triple product of vectors.
dx
Three - dimensional Geometry:
(12) Periods
dy
Direction cosines and direction ratios of a line joining two points. Cartesian and vector
equation of a line, coplanar and skew lines, shortest distance between two lines. Cartesian
and vector equation of a plane. Angle between (i) two lines, (ii) two planes. (iii) a line and
a plane. Distance of a point from a plane.

UNIT-V: LINEAR PROGRAMMING
1.

Linear Programming:

(12) Periods

Introduction, related terminology such as constraints, objective function, optimization,
different types of linear programming (L.P.) problems, mathematical formulation of L.P.
problems, graphical method of solution for problems in two variables, feasible and infeasible
regions, feasible and infeasible solutions, optimal feasible solutions (up to three non-trivial
constraints).

89
UNIT-VI: PROBABILITY
1.

Probability:

(18) Periods

Conditional probability, multiplication theorem on probability. independent events, total
probability, Baye's theorem, Random variable and its probability distribution, mean and
variance of random variable. Repeated independent (Bernoulli) trials and Binomial
distribution.
Recommended Textbooks.
1)
Mathematics Part I - Textbook for Class XI, NCERT Publication
2)
Mathematics Part II - Textbook for Class XII, NCERT Publication

90
MATHEMATICS (041)
CLASS XII 2012-13

Time : 3 Hours

Max. Marks : 100

Weightage of marks over different dimensions of the question paper shall be as follows:
A.

Weightage to different topics/content units
S.No.

Topics

Marks

1.

Relations and Functions

10

2.

Algebra

13

3.

Calculus

44

4.

Vectors & three-dimensional Geometry

17

5.

Linear programming

06

6.

Probability

10

Total

100

Note: The Question Paper will include question(s) based on values
to the extent of 5 marks.
B.

Weightage to different forms of questions
S.No.

Forms of Questions

Marks for
each question

No. of
Questions

Total marks

1.

Very Short Answer questions (VSA)

01

10

10

2.

Short Answer questions (SA)

04

12

48

3.

Long answer questions (LA)

06

07

42

29

100

Total
C.

Scheme of Options
There will be no overall choice. However, internal choice in any four questions of four marks each and
any two questions of six marks each has been provided.

D.

Difficulty level of questions
S.No.

Estimated difficulty level

Percentage of marks

1.

Easy

15

2.

Average

70

3.

Difficult

15

Based on the above design, separate sample papers along with their blue prints and Marking schemes
have been included in this document. About 20% weightage has been assigned to questions testing
higher order thinking skills of learners.
91
SAMPLE QUESTION PAPER
MATHEMATICS (041)
CLASS XII (2012-13)
BLUE PRINT
S. No.

Topics

VSA

SA

LA

–

4 (1)

–

2 (2)

4 (1)

–

(a) Matrices

2 (2)

–

6 (1)

(b) Determinants

1 (1)

4 (1)

(a) Continuity and

1 (1)

12 (3)

–

(b)Application of Derivatives

–

–

6 (1)

(c) Integration

–

12 (3)

(d) Applications of Integrals

–

–

6 (1)

(e) Differential Equations

1 (1)

–

6 (1)

(a) Vectors

2 (2)

4 (1)

–

(b) 3-Dimensional Geometry

1 (1)

4 (1)

6 (1)

17 (6)

(a) Relations and Functions
1.

(b) Inverse Trigonometric

TOTAL

10 (4)

Functions
2.

3.

13 (5)

Differentiability

4.

44 (11)

5.

Linear Programming

–

–

6 (1)

6 (1)

6.

Probability

–

4 (1)

6 (1)

10 (2)

10 (10)

48 (12)

42 (7)

100 (29)

Total

The Question Paper will include question(s) based on values to the extent of 5 marks.

92
Questionwise Analysis – Sample Paper
Question
Number
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29

Topics

Inverse Trigonometric Functions
Inverse Trigonometric Functions
Matrices
Matrices
Determinants
Differentiation
Differential Equations
Vectors
Vectors
3-Dimensional Geometry
Relations and functions (Type of
functions)
Inverse Trigonometric Functions
Determinants
Differentiation
Differentiation
Continuity of Functions
Integration * (Indefinite)
Integration * (Indefinite)
Integration * (Definite)
Vectors
3-Dimensional Geometry*
Probability
Matrices (Solution of System of equation)
Application of Derivative*
Application of Integration
Differential equations (Particular Solution)
3-Dimensional Geometry (Plane)
Linear Programming
Probability*
* With Alternative question

93

Form of
Question
VSA
VSA
VSA
VSA
VSA
VSA
VSA
VSA
VSA
VSA
SA

Marks

SA
SA
SA
SA
SA
SA
SA
SA
SA
SA
SA
LA
LA
LA
LA
LA
LA
LA

4
4
4
4
4
4
4
4
4
4
4
6
6
6
6
6
6
6

1
1
1
1
1
1
1
1
1
1
4

Remarks
SAMPLE QUESTION PAPER
MATHEMATICS (041)
CLASS XII (2012-13)
General Instructions
1. All questions are compulsory.
2.

The question paper consist of 29 questions divided into three sections A, B and C.
Section A comprises of 10 questions of one mark each, section B comprises of 12
questions of four marks each and section C comprises of 07 questions of six marks
each.

3.

All questions in Section A are to be answered in one word, one sentence or a s per the
exact requirement of the question.

4.

There is no overall choice. However, internal choice has been provided in 04 questions
of four marks each and 02 questions of six marks each. You have to attempt only one

5.

of the alternatives in all such quest ions.
Use of calculators in not permitted. You may ask for logarithmic tables, if required.

SECTION – A
Question numbers 1 to 10 carry 1 mark each.
1. Using principal values, write the value of 2 cos1 + 3 sin1
2. Evaluate tan1 [2cos (2sin1 )]
3. Write the value of x+y+z if

=

4. If A is a square matrix of order 3 such that |adj A| = 225, find |A’|
5. Write the inverse of the matrix
6.

The contentment obtained after eating x-units of a new dish at a trial function is
given by the Function C(x) = x3+6x2+5x+3. If the marginal contentment is defined
as rate of change of (x) with respect to the number of units consumed at an instant,
then find the marginal contentment when three units of dish are consumed.

7. Write the degree of the differential equation
8. If

and

are two vectors of magnitude 3 and

vector, write the angle between
9. If

= 7 +  4 and

2



+1=0

respectively such that x is a unit

and .

= 2 + 6  3 , find the projection of
94

on
10. Write the distance between the parallel planes 2xy+3z=4 and 2xy+3z=18

SECTION – B
Question numbers 11 to 22 carry 4 marks each.
11. Prove that the function f: N N, defined by f(x) = x2 + x+1 is one – one but not onto.
12. Show that sin[cot1{cos(tan1x)}] =
OR
Solve for x: 3sin1

-4 cos1

+ 2tan1

=

13. Two schools A and B decided to award prizes to their students for three values
honesty (x), punctuality (y) and obedience (z). School A decided to award a total
of Rs. 11000 for the three values to 5, 4 and 3 students respectively while school B
decided to award Rs. 10700 for the three values to 4, 3 and 5 students respectively.
If all the three prizes together amount to Rs. 2700, then.
i.
ii.
iii.

Represent the above situation by a matrix equation and form Linear
equations using matrix multiplication.
Is it possible to solve the system of equations so obtained using
matrices?
Which value you prefer to be rewarded most and why?

14. If x = a(θsin θ) and y = a (1cos θ), find
15. If y =

, show that (1x2)

 3x

y=0

16. The function f(x) is defined as f(x) =
If f(x) is continuous on [0,8], find the values of a and b
OR
Differentiate tan1
17. Evaluate:

with respect to cos1 x2

dx
OR

Evaluate:

dx
95
18. Evaluate:

dx

4

19. Evaluate:

 log

(1+tanx) dx, using properties of definite integrals

0

20. Let

=

Find a vector

perpendicular to both

and

which is

and satisfying . = 21.

21. Find the distance between the point P(6, 5, 9) and the plane determined by the
points A(3, -1, 2), B(5, 2, 4), and C(-1, -1, 6)
OR
Find the equation of the perpendicular drawn from the point P(2, 4, -1) to the line
=

=

. Also, write down the coordinates of the foot of the perpendicular

from P to the line.
22. There is a group of 50 people who are patriotic out of which 20 believe in non
violence. Two persons are selected at random out of them, write the probability
distribution for the selected persons who are non violent. Also find the mean of
the distribution. Explain the importance of Non violence in patriotism.

SECTION – C
Question numbers 23 to 29 carry 6 marks each
23. If A=

, find A1. Hence solve the following system of equations:

x+2y3z = 4, 2x+3y+2z = 2, 3x3y4z = 11
24. Find the equations of tangent and normal to the curve y=

at the point where

it cuts the x-axis
OR
Prove that the radius of the base of right circular cylinder of greatest curved surface
area which can be inscribed in a given cone is half that of the cone.
25. Find the area of the region enclosed between the two circles x 2+y2=1 and
(x-1)2 + y2 = 1
26. Find the particular solution of the differential equation:
(x-sin y)dy + (tany)dx = 0 : given that y=0 when x=0
27. Find the vector and Cartesian equations of the plane containing the two lines
and
96
28. A dealer in rural area wishes to purchase a number of sewing machines. He has
only Rs. 5760.00 to invest and has space for at most 20 items. A electronic sewing
machine costs him Rs.360.00 and a manually operated sewing machine Rs. 240.00.
He can sell an Electronic Sewing Machine at a profit of Rs. 22.00 and a manually
operated sewing machine at a profit of Rs.18.00. Assuming that he can sell all the
items that he can buy how should he invest his money in order to maximize his
profit. Make it as a linear programming problem and solve it graphically. Keeping
the rural background in mind justify the ‘values’ to be promoted for the selection
of the manually operated machine.
29. In answering a question on a MCQ test with 4 choices per question, a student
knows the answer, guesses or copies the answer. Let ½ be the probability that he
knows the answer, ¼ be the probability that he guesses and ¼ that he copies it.
Assuming that a student, who copies the answer, will be correct with the
probability ¾, what is the probability that the student knows the answer, given
that he answered it correctly?
Arjun does not know the answer to one of the questions in the test. The
evaluation process has negative marking. Which value would Arjun violate if he
resorts to unfair means? How would an act like the above hamper his character
development in the coming years?
OR
An insurance company insured 2000 cyclists, 4000 scooter drivers and 6000
motorbike drivers. The probability of an accident involving a cyclist, scooter
driver and a motorbike driver are 0.01, 0.03 and 0.15 respectively. One of the
insured persons meets with an accident. What is the probability that he is a
scooter driver? Which mode of transport would you suggest to a student and why?

97
MARKING SCHEME
1-10

1.

2.

4. 15

5.

7. 2

6. 68 units

3. Zero
8.

9.

10.

10x1=10

SECTION – B
11. f(x) = x2+x+1
Let x1, y1

N such that f(x1) = f(y1)

+ x1+1 =

+ y1 + 1

1

(x1y1) (x1+y1+1) = 0 [As x1+y1+1 0 for any N]
x1=y1

1

f is one-one function

Clearly f(x) = x2 + x+1 > 3 for x N

½

But f(x) does not assume values 1 and 2

1½

f:N

N is not onto function

12. cos (tan1x) = cos

=
cot1

1

= sin1

1

sin

1+1
OR

Let x = tan

½

LHS = 3sin 1 (sin2)  4 cos1 (cos2 ) + 2tan 1 (tan 2
98

1½
= 3x2  8 + 4 = 2 = 2tan1x
2 tan1 x =

tan x =

1
x=

1

13.
i)
5

4

3

x

4

3

5

y

1

1

1

z

˚.˚

11000
=

10700
2700

5x+4y+3z=11000

1½

4x+3y+5z=10700
X+y+z =2700
ii)

let A=

5

4

3

4

3

5

1

1

1

˚.˚

I AI = 5(-2) -4(-1)+3(1)

1½

= -10+4+3=-3≠0
˚.˚ A-1 exists, so equations have a unique solution.
iii) Any answer of three values which proper reasoning will be considered correct.

14. x=a( sin
y = a (1-cos )

= a (1-cos ) = 2a sin2
= a.sin = 2a sin

1

1
cos

99

1
=

=

½

cosec2 .

=

=

. y=sin1x

15. y =
+
(1-x2)

cosec4 



 

1½

½

=

1

– xy – 1=0

Diff. again we get
(1x2)
(1x2)

2x



 3x

=0

1

–y=0

1

16. lim f(x) = lim x2+ax+b = 2a+b+4


x 2

x 2

1

lim f( x) = lim (3x + 2) = 8

x2 

x2+

As f is continuous at x=2

2a+b+4=8

2a+b=4 - - - (i)

1

Similarly as f is continuous at x=4, 14 = 8a+5b - - - (ii)

1

From (i) and (ii), a = 3, b=2

1
OR

y = tan

= Let x2 =cos 2

1

tan

= tan1

1

= tan

= tan1

=

1

100
y=

cos1 x2 : Let z = cos1 x2

y=

z

17. I =
Let

=
=

dx
+

1
1

=

I=

A= ,B=

1+1

+ log (x-1) + log (x+1) + c
OR

=

dx

=

1

=

½

=

½

=

+

1

= ex cot

1

= ex cot + C
18. I =
Let x2=t, 2x dx = dt

I=

1½

Getting A=1, B = 1
I=

1

= log|t+1|log|t+2|+ C

1

= log|x2+1|log|x2+2|+ C

½

19. I =

- - - (i)

dx, I =

1
or I =

dx =

dx - - - (ii)

Adding (i) and (ii) , we get
101

1
2I =

1

I = log2

1

20. Let
As

and

. =0

. = 0 and . = 0

4x + 5y – z = 0 and

= 21

=0

1

x 4y + 5z = 0- - - (i)

1

3x + y – z = 21- - - (ii)

½

Solving (i) and (ii), we get x=7, y=7, z=7

1
½

21. The equation of plane passing through (3,-1, 2), (5, 2, 4) and (-1, -1, 6) is
= 0 or

=0

2

12x16y+12z = 76 or 3x  4y + 3z = 19 - - - (i)
length of

½

from (6, 5, 9) to (i) is
=

1+½
OR
Any point on the line

=

=

=

1

is

Let this point be Q
dr’s of
Since

are 7, 4 7,9 +7

½

1+
102
98 = 98

=1

1

The pt. Q is (4, 1, -3)
equation of PQ is

½
=

=

and foot of

is (4, 1, -3)

1

22. Let x denote the number of non-violent persons out of selected two. X can take values
0, 1, 2 non-violent 20: Violent patriotism: 30

½

P(x = 0)=(30x29)/50x49 = 87/245

½

P(x = 1) = (30x20x2)/50x49 = 120/245

½

P(x = 2) = (20x19)/50x49 = 38/245

½

Mean = 0x87/245 + 1x120/245 + 2x38/245 = 198/245

1

Importance: In order to have a peaceful environment both the values are required
patriotism and non-violence only patriotism with violence could be very dangerous

23. The given matrix is A =

, |A| = -6+28+45=67 0

1

1

A1 exists
Adj A =

,



2½

The given system of equations can be written as AX=B
Where A =

,

X = A1B =
x=3, y =2,

=

,B=

1

=

1

z =1

½

24. The given curve cuts the x-axis at x=7, and y=0
y=
(at x=7) =

½
1½

=

103
Equation of tangent to the curve at (7,0) is
y 0 =

(x7) or x20y7=0

1½

Equation of normal to the curve at (7,0) is
y 0 = 20(x7) = 20x +y 140 = 0

1½
OR

Let OC = x

VOB

B’DB

B’D =

1

= h’

Let S be the curved surface area of cylinder
S = 2 x h’ = 2 x
=
=0

(r2x),

=



S is Maximum

=

1

[rxx2]

2

1

r = 2x

S is maximum when x= , i.e, when radius of base of cylinder is half the radius of base
of cone.

1

25. Points of inter section are A

and D

1

Area of Shaded area = 2 (Area O ABCO)

=

1

=2

+

104
2

=

1

=
=

sq. units.

1

26. The given diff. eqn. can be written as
+ (coty) x = cosy

1

coty dy
I.F = e
= elog siny = siny
The solution is x siny =

1
=

or x siny =

cos2y + C

1

It is given that y=0, when x=0
C

1

C = 1/4
x siny = (1-cos 2y) = sin2 y

1

2x = siny is the reqd. solution
27. Here

1

and

1

and
=

= 20

1½

Vector eqn. of the reqd. plane is
2

The Cartesian equation of plane is 10x + 5y – 4z = 37
1½
28 Suppose number of electronic operated machine = x and number of manually
operated sewing machines = y
2
105
x+y < 20 - - - (i)
and, 360 x + 240y < 5760 or 3x+2y < 48 - - - (ii)
x>0, y>0
To maximise Z=22x + 18y
Corners of feasible region are A (0,20), P(8,12),
B(16,0)

2

ZA = 18x20 = 360, ZP = 22x8+18x12 = 392, ZB = 352
Z is maximum at x=8 and y=12

½

The dealer should invest in 8 electric and 12 manually operated machines

½

Keeping the ‘save environment’ factor in mind the manually operated machine
should be promoted so that energy could be saved.
1
29. Let A be the event that he knows the answer, B be the event that he guesses and C
be the event that he copies.

1

Then, P(A) = ½, P(B) = ¼ and P(C) = ¼

1

Let X be the event that he has answered correctly.
Also, P(X/A) = 1, P(X/B) = ¼ and P(X/C) = ¾
Thus, Required probability = P(A/X) =

1 for formula

P( X / A)  P( A)
P( X / A)  P( A)  P( X / B)  P( B)  P( X / C )  P(C )
1
1
2

1
1 1 1 3
1    
2
4 4 4 4
1
2

1 1 3
 
2 16 16
2

3

1

If Arjun copies the answer, he will be violating the value of honesty in his
character. He should not guess the answer as well as that may fetch him negative
marking for a wrong guess. He should accept the question the way it is and leave it
106
unanswered as cheating may get him marks in this exam but this habit may not let
him develop an integrity of character in the long run.

2

OR
Let the events defined are E1: Person chosen is a cyclist
E2: Person chosen is a scoter-driver
E3: Person chosen is a motorbike driver
A: Person meets with an Accident

½

P (E1) = 1/6, P(E2) = 1/3, P(E3)= 1/2

1

P (A/E1) = 0.01, P(A/E2) = 0.03, P(A/E3) = 0.15 2

1

P (E1/A) = P(A/E1).P(E1)/P(A)

1

=1/2

½

Suggestion: Cycle should be promoted as it is good for
i.
ii.
iii.

½

Health

½

No pollution

½

Saves energy( no petrol)

½

107

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Mathematics xii paper 13 with answer with value vased questions

  • 1. SYLLABUS MATHEMATICS (041) CLASS XII 2012-13 One Paper Units Annexure - ‘ F ’ Three Hours Marks: 100 Marks I. RELATIONS AND FUNCTIONS 10 II. ALGEBRA 13 III. CALCULUS 44 IV. VECTORS AND THREE - DIMENSIONAL GEOMETRY 17 V. 06 LINEAR PROGRAMMING VI. PROBABILITY 10 Total 100 The Question Paper will include question(s) based on values to the extent of 5 marks. UNIT I. RELATIONS AND FUNCTIONS 1. Relations and Functions : (10) Periods Types of relations: reflexive, symmetric, transitive and equivalence relations. One to one and onto functions, composite functions, inverse of a function. Binary operations. 2. Inverse Trigonometric Functions: (12) Periods Definition, range, domain, principal value branches. Graphs of inverse trigonometric functions. Elementary properties of inverse trigonometric functions. UNIT-II: ALGEBRA 1. Matrices: (18) Periods Concept, notation, order, equality, types of matrices, zero matrix, transpose of a matrix, symmetric and skew symmetric matrices. Addition, multiplication and scalar multiplication of matrices, simple properties of addition, multiplication and scalar multiplication. Non-commutativity of multiplication of matrices and existence of non-zero matrices whose product is the zero matrix (restrict to square matrices of order 2). Concept of elementary row and column operations. Invertible matrices and proof of the uniqueness of inverse, if it exists; (Here all matrices will have real entries). 2. Determinants: (20) Periods Determinant of a square matrix (up to 3 x 3 matrices), properties of determinants, minors, cofactors and applications of determinants in finding the area of a triangle. Adjoint and inverse of a square matrix. Consistency, inconsistency and number of solutions of system of linear equations by examples, solving system of linear equations in two or three variables (having unique solution) using inverse of a matrix. 87
  • 2. 88
  • 3. 5. Differential Equations: (10) Periods Definition, order and degree, general and particular solutions of a differential equation. Formation of differential equation whose general solution is given. Solution of differential equations by method of separation of variables, homogeneous differential equations of first order and first degree. Solutions of linear differential equation of the type: + py = q, where p and q are functions of x or constant + px = q, where p and q are functions of y or constant UNIT-IV: VECTORS AND THREE-DIMENSIONAL GEOMETRY 1. 2. Vectors: (12) Periods Vectors and scalars, magnitude and direction of a vector. Direction cosines and direction ratios of a vector. Types of vectors (equal, unit, zero, parallel and collinear vectors), position vector of a point, negative of a vector, components of a vector, addition of vectors, multiplication of a vector by a scalar, position vector of a point dividing a line segment in a given ratio. Scalar (dot) product of vectors, projection of a vector on a line. Vector (cross) product of vectors. Scalar triple product of vectors. dx Three - dimensional Geometry: (12) Periods dy Direction cosines and direction ratios of a line joining two points. Cartesian and vector equation of a line, coplanar and skew lines, shortest distance between two lines. Cartesian and vector equation of a plane. Angle between (i) two lines, (ii) two planes. (iii) a line and a plane. Distance of a point from a plane. UNIT-V: LINEAR PROGRAMMING 1. Linear Programming: (12) Periods Introduction, related terminology such as constraints, objective function, optimization, different types of linear programming (L.P.) problems, mathematical formulation of L.P. problems, graphical method of solution for problems in two variables, feasible and infeasible regions, feasible and infeasible solutions, optimal feasible solutions (up to three non-trivial constraints). 89
  • 4. UNIT-VI: PROBABILITY 1. Probability: (18) Periods Conditional probability, multiplication theorem on probability. independent events, total probability, Baye's theorem, Random variable and its probability distribution, mean and variance of random variable. Repeated independent (Bernoulli) trials and Binomial distribution. Recommended Textbooks. 1) Mathematics Part I - Textbook for Class XI, NCERT Publication 2) Mathematics Part II - Textbook for Class XII, NCERT Publication 90
  • 5. MATHEMATICS (041) CLASS XII 2012-13 Time : 3 Hours Max. Marks : 100 Weightage of marks over different dimensions of the question paper shall be as follows: A. Weightage to different topics/content units S.No. Topics Marks 1. Relations and Functions 10 2. Algebra 13 3. Calculus 44 4. Vectors & three-dimensional Geometry 17 5. Linear programming 06 6. Probability 10 Total 100 Note: The Question Paper will include question(s) based on values to the extent of 5 marks. B. Weightage to different forms of questions S.No. Forms of Questions Marks for each question No. of Questions Total marks 1. Very Short Answer questions (VSA) 01 10 10 2. Short Answer questions (SA) 04 12 48 3. Long answer questions (LA) 06 07 42 29 100 Total C. Scheme of Options There will be no overall choice. However, internal choice in any four questions of four marks each and any two questions of six marks each has been provided. D. Difficulty level of questions S.No. Estimated difficulty level Percentage of marks 1. Easy 15 2. Average 70 3. Difficult 15 Based on the above design, separate sample papers along with their blue prints and Marking schemes have been included in this document. About 20% weightage has been assigned to questions testing higher order thinking skills of learners. 91
  • 6. SAMPLE QUESTION PAPER MATHEMATICS (041) CLASS XII (2012-13) BLUE PRINT S. No. Topics VSA SA LA – 4 (1) – 2 (2) 4 (1) – (a) Matrices 2 (2) – 6 (1) (b) Determinants 1 (1) 4 (1) (a) Continuity and 1 (1) 12 (3) – (b)Application of Derivatives – – 6 (1) (c) Integration – 12 (3) (d) Applications of Integrals – – 6 (1) (e) Differential Equations 1 (1) – 6 (1) (a) Vectors 2 (2) 4 (1) – (b) 3-Dimensional Geometry 1 (1) 4 (1) 6 (1) 17 (6) (a) Relations and Functions 1. (b) Inverse Trigonometric TOTAL 10 (4) Functions 2. 3. 13 (5) Differentiability 4. 44 (11) 5. Linear Programming – – 6 (1) 6 (1) 6. Probability – 4 (1) 6 (1) 10 (2) 10 (10) 48 (12) 42 (7) 100 (29) Total The Question Paper will include question(s) based on values to the extent of 5 marks. 92
  • 7. Questionwise Analysis – Sample Paper Question Number 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 Topics Inverse Trigonometric Functions Inverse Trigonometric Functions Matrices Matrices Determinants Differentiation Differential Equations Vectors Vectors 3-Dimensional Geometry Relations and functions (Type of functions) Inverse Trigonometric Functions Determinants Differentiation Differentiation Continuity of Functions Integration * (Indefinite) Integration * (Indefinite) Integration * (Definite) Vectors 3-Dimensional Geometry* Probability Matrices (Solution of System of equation) Application of Derivative* Application of Integration Differential equations (Particular Solution) 3-Dimensional Geometry (Plane) Linear Programming Probability* * With Alternative question 93 Form of Question VSA VSA VSA VSA VSA VSA VSA VSA VSA VSA SA Marks SA SA SA SA SA SA SA SA SA SA SA LA LA LA LA LA LA LA 4 4 4 4 4 4 4 4 4 4 4 6 6 6 6 6 6 6 1 1 1 1 1 1 1 1 1 1 4 Remarks
  • 8. SAMPLE QUESTION PAPER MATHEMATICS (041) CLASS XII (2012-13) General Instructions 1. All questions are compulsory. 2. The question paper consist of 29 questions divided into three sections A, B and C. Section A comprises of 10 questions of one mark each, section B comprises of 12 questions of four marks each and section C comprises of 07 questions of six marks each. 3. All questions in Section A are to be answered in one word, one sentence or a s per the exact requirement of the question. 4. There is no overall choice. However, internal choice has been provided in 04 questions of four marks each and 02 questions of six marks each. You have to attempt only one 5. of the alternatives in all such quest ions. Use of calculators in not permitted. You may ask for logarithmic tables, if required. SECTION – A Question numbers 1 to 10 carry 1 mark each. 1. Using principal values, write the value of 2 cos1 + 3 sin1 2. Evaluate tan1 [2cos (2sin1 )] 3. Write the value of x+y+z if = 4. If A is a square matrix of order 3 such that |adj A| = 225, find |A’| 5. Write the inverse of the matrix 6. The contentment obtained after eating x-units of a new dish at a trial function is given by the Function C(x) = x3+6x2+5x+3. If the marginal contentment is defined as rate of change of (x) with respect to the number of units consumed at an instant, then find the marginal contentment when three units of dish are consumed. 7. Write the degree of the differential equation 8. If and are two vectors of magnitude 3 and vector, write the angle between 9. If = 7 +  4 and 2  +1=0 respectively such that x is a unit and . = 2 + 6  3 , find the projection of 94 on
  • 9. 10. Write the distance between the parallel planes 2xy+3z=4 and 2xy+3z=18 SECTION – B Question numbers 11 to 22 carry 4 marks each. 11. Prove that the function f: N N, defined by f(x) = x2 + x+1 is one – one but not onto. 12. Show that sin[cot1{cos(tan1x)}] = OR Solve for x: 3sin1 -4 cos1 + 2tan1 = 13. Two schools A and B decided to award prizes to their students for three values honesty (x), punctuality (y) and obedience (z). School A decided to award a total of Rs. 11000 for the three values to 5, 4 and 3 students respectively while school B decided to award Rs. 10700 for the three values to 4, 3 and 5 students respectively. If all the three prizes together amount to Rs. 2700, then. i. ii. iii. Represent the above situation by a matrix equation and form Linear equations using matrix multiplication. Is it possible to solve the system of equations so obtained using matrices? Which value you prefer to be rewarded most and why? 14. If x = a(θsin θ) and y = a (1cos θ), find 15. If y = , show that (1x2)  3x y=0 16. The function f(x) is defined as f(x) = If f(x) is continuous on [0,8], find the values of a and b OR Differentiate tan1 17. Evaluate: with respect to cos1 x2 dx OR Evaluate: dx 95
  • 10. 18. Evaluate: dx  4 19. Evaluate:  log (1+tanx) dx, using properties of definite integrals 0 20. Let = Find a vector perpendicular to both and which is and satisfying . = 21. 21. Find the distance between the point P(6, 5, 9) and the plane determined by the points A(3, -1, 2), B(5, 2, 4), and C(-1, -1, 6) OR Find the equation of the perpendicular drawn from the point P(2, 4, -1) to the line = = . Also, write down the coordinates of the foot of the perpendicular from P to the line. 22. There is a group of 50 people who are patriotic out of which 20 believe in non violence. Two persons are selected at random out of them, write the probability distribution for the selected persons who are non violent. Also find the mean of the distribution. Explain the importance of Non violence in patriotism. SECTION – C Question numbers 23 to 29 carry 6 marks each 23. If A= , find A1. Hence solve the following system of equations: x+2y3z = 4, 2x+3y+2z = 2, 3x3y4z = 11 24. Find the equations of tangent and normal to the curve y= at the point where it cuts the x-axis OR Prove that the radius of the base of right circular cylinder of greatest curved surface area which can be inscribed in a given cone is half that of the cone. 25. Find the area of the region enclosed between the two circles x 2+y2=1 and (x-1)2 + y2 = 1 26. Find the particular solution of the differential equation: (x-sin y)dy + (tany)dx = 0 : given that y=0 when x=0 27. Find the vector and Cartesian equations of the plane containing the two lines and 96
  • 11. 28. A dealer in rural area wishes to purchase a number of sewing machines. He has only Rs. 5760.00 to invest and has space for at most 20 items. A electronic sewing machine costs him Rs.360.00 and a manually operated sewing machine Rs. 240.00. He can sell an Electronic Sewing Machine at a profit of Rs. 22.00 and a manually operated sewing machine at a profit of Rs.18.00. Assuming that he can sell all the items that he can buy how should he invest his money in order to maximize his profit. Make it as a linear programming problem and solve it graphically. Keeping the rural background in mind justify the ‘values’ to be promoted for the selection of the manually operated machine. 29. In answering a question on a MCQ test with 4 choices per question, a student knows the answer, guesses or copies the answer. Let ½ be the probability that he knows the answer, ¼ be the probability that he guesses and ¼ that he copies it. Assuming that a student, who copies the answer, will be correct with the probability ¾, what is the probability that the student knows the answer, given that he answered it correctly? Arjun does not know the answer to one of the questions in the test. The evaluation process has negative marking. Which value would Arjun violate if he resorts to unfair means? How would an act like the above hamper his character development in the coming years? OR An insurance company insured 2000 cyclists, 4000 scooter drivers and 6000 motorbike drivers. The probability of an accident involving a cyclist, scooter driver and a motorbike driver are 0.01, 0.03 and 0.15 respectively. One of the insured persons meets with an accident. What is the probability that he is a scooter driver? Which mode of transport would you suggest to a student and why? 97
  • 12. MARKING SCHEME 1-10 1. 2. 4. 15 5. 7. 2 6. 68 units 3. Zero 8. 9. 10. 10x1=10 SECTION – B 11. f(x) = x2+x+1 Let x1, y1 N such that f(x1) = f(y1) + x1+1 = + y1 + 1 1 (x1y1) (x1+y1+1) = 0 [As x1+y1+1 0 for any N] x1=y1 1 f is one-one function Clearly f(x) = x2 + x+1 > 3 for x N ½ But f(x) does not assume values 1 and 2 1½ f:N N is not onto function 12. cos (tan1x) = cos = cot1 1 = sin1 1 sin 1+1 OR Let x = tan ½ LHS = 3sin 1 (sin2)  4 cos1 (cos2 ) + 2tan 1 (tan 2 98 1½
  • 13. = 3x2  8 + 4 = 2 = 2tan1x 2 tan1 x = tan x = 1 x= 1 13. i) 5 4 3 x 4 3 5 y 1 1 1 z ˚.˚ 11000 = 10700 2700 5x+4y+3z=11000 1½ 4x+3y+5z=10700 X+y+z =2700 ii) let A= 5 4 3 4 3 5 1 1 1 ˚.˚ I AI = 5(-2) -4(-1)+3(1) 1½ = -10+4+3=-3≠0 ˚.˚ A-1 exists, so equations have a unique solution. iii) Any answer of three values which proper reasoning will be considered correct. 14. x=a( sin y = a (1-cos ) = a (1-cos ) = 2a sin2 = a.sin = 2a sin 1 1 cos 99 1
  • 14. = = ½ cosec2 . = = . y=sin1x 15. y = + (1-x2) cosec4     1½ ½ = 1 – xy – 1=0 Diff. again we get (1x2) (1x2) 2x   3x =0 1 –y=0 1 16. lim f(x) = lim x2+ax+b = 2a+b+4   x 2 x 2 1 lim f( x) = lim (3x + 2) = 8 x2  x2+ As f is continuous at x=2 2a+b+4=8 2a+b=4 - - - (i) 1 Similarly as f is continuous at x=4, 14 = 8a+5b - - - (ii) 1 From (i) and (ii), a = 3, b=2 1 OR y = tan = Let x2 =cos 2 1 tan = tan1 1 = tan = tan1 = 1 100
  • 15. y= cos1 x2 : Let z = cos1 x2 y= z 17. I = Let = = dx + 1 1 = I= A= ,B= 1+1 + log (x-1) + log (x+1) + c OR = dx = 1 = ½ = ½ = + 1 = ex cot 1 = ex cot + C 18. I = Let x2=t, 2x dx = dt I= 1½ Getting A=1, B = 1 I= 1 = log|t+1|log|t+2|+ C 1 = log|x2+1|log|x2+2|+ C ½ 19. I = - - - (i) dx, I = 1 or I = dx = dx - - - (ii) Adding (i) and (ii) , we get 101 1
  • 16. 2I = 1 I = log2 1 20. Let As and . =0 . = 0 and . = 0 4x + 5y – z = 0 and = 21 =0 1 x 4y + 5z = 0- - - (i) 1 3x + y – z = 21- - - (ii) ½ Solving (i) and (ii), we get x=7, y=7, z=7 1 ½ 21. The equation of plane passing through (3,-1, 2), (5, 2, 4) and (-1, -1, 6) is = 0 or =0 2 12x16y+12z = 76 or 3x  4y + 3z = 19 - - - (i) length of ½ from (6, 5, 9) to (i) is = 1+½ OR Any point on the line = = = 1 is Let this point be Q dr’s of Since are 7, 4 7,9 +7 ½ 1+ 102
  • 17. 98 = 98 =1 1 The pt. Q is (4, 1, -3) equation of PQ is ½ = = and foot of is (4, 1, -3) 1 22. Let x denote the number of non-violent persons out of selected two. X can take values 0, 1, 2 non-violent 20: Violent patriotism: 30 ½ P(x = 0)=(30x29)/50x49 = 87/245 ½ P(x = 1) = (30x20x2)/50x49 = 120/245 ½ P(x = 2) = (20x19)/50x49 = 38/245 ½ Mean = 0x87/245 + 1x120/245 + 2x38/245 = 198/245 1 Importance: In order to have a peaceful environment both the values are required patriotism and non-violence only patriotism with violence could be very dangerous 23. The given matrix is A = , |A| = -6+28+45=67 0 1 1 A1 exists Adj A = ,  2½ The given system of equations can be written as AX=B Where A = , X = A1B = x=3, y =2, = ,B= 1 = 1 z =1 ½ 24. The given curve cuts the x-axis at x=7, and y=0 y= (at x=7) = ½ 1½ = 103
  • 18. Equation of tangent to the curve at (7,0) is y 0 = (x7) or x20y7=0 1½ Equation of normal to the curve at (7,0) is y 0 = 20(x7) = 20x +y 140 = 0 1½ OR Let OC = x VOB B’DB B’D = 1 = h’ Let S be the curved surface area of cylinder S = 2 x h’ = 2 x = =0 (r2x), =  S is Maximum = 1 [rxx2] 2 1 r = 2x S is maximum when x= , i.e, when radius of base of cylinder is half the radius of base of cone. 1 25. Points of inter section are A and D 1 Area of Shaded area = 2 (Area O ABCO) = 1 =2 + 104
  • 19. 2 = 1 = = sq. units. 1 26. The given diff. eqn. can be written as + (coty) x = cosy 1 coty dy I.F = e = elog siny = siny The solution is x siny = 1 = or x siny = cos2y + C 1 It is given that y=0, when x=0 C 1 C = 1/4 x siny = (1-cos 2y) = sin2 y 1 2x = siny is the reqd. solution 27. Here 1 and 1 and = = 20 1½ Vector eqn. of the reqd. plane is 2 The Cartesian equation of plane is 10x + 5y – 4z = 37 1½ 28 Suppose number of electronic operated machine = x and number of manually operated sewing machines = y 2 105
  • 20. x+y < 20 - - - (i) and, 360 x + 240y < 5760 or 3x+2y < 48 - - - (ii) x>0, y>0 To maximise Z=22x + 18y Corners of feasible region are A (0,20), P(8,12), B(16,0) 2 ZA = 18x20 = 360, ZP = 22x8+18x12 = 392, ZB = 352 Z is maximum at x=8 and y=12 ½ The dealer should invest in 8 electric and 12 manually operated machines ½ Keeping the ‘save environment’ factor in mind the manually operated machine should be promoted so that energy could be saved. 1 29. Let A be the event that he knows the answer, B be the event that he guesses and C be the event that he copies. 1 Then, P(A) = ½, P(B) = ¼ and P(C) = ¼ 1 Let X be the event that he has answered correctly. Also, P(X/A) = 1, P(X/B) = ¼ and P(X/C) = ¾ Thus, Required probability = P(A/X) = 1 for formula P( X / A)  P( A) P( X / A)  P( A)  P( X / B)  P( B)  P( X / C )  P(C ) 1 1 2  1 1 1 1 3 1     2 4 4 4 4 1 2  1 1 3   2 16 16 2  3 1 If Arjun copies the answer, he will be violating the value of honesty in his character. He should not guess the answer as well as that may fetch him negative marking for a wrong guess. He should accept the question the way it is and leave it 106
  • 21. unanswered as cheating may get him marks in this exam but this habit may not let him develop an integrity of character in the long run. 2 OR Let the events defined are E1: Person chosen is a cyclist E2: Person chosen is a scoter-driver E3: Person chosen is a motorbike driver A: Person meets with an Accident ½ P (E1) = 1/6, P(E2) = 1/3, P(E3)= 1/2 1 P (A/E1) = 0.01, P(A/E2) = 0.03, P(A/E3) = 0.15 2 1 P (E1/A) = P(A/E1).P(E1)/P(A) 1 =1/2 ½ Suggestion: Cycle should be promoted as it is good for i. ii. iii. ½ Health ½ No pollution ½ Saves energy( no petrol) ½ 107