What is the wobble position What is the consequence of its pres.pdf

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What is the \'wobble\' position? What is the consequence of its presence? Solution Answer : During intercation between mRNA/codons and tRNA/anticodons, The third base of the codon and the first base of the anticodon constitutes the wobble position. Wobble Allows Some tRNAs to Recognize More than One Codon. This is due to the fact that strict watson and crick base pairing rules applies only to the first two bases of the codon where as third base tRNA can recognise more than one codon..

What is the 'wobble' position? What is the consequence of its presence?
Solution
Answer : During intercation between mRNA/codons and tRNA/anticodons, The third base of the
codon and the first base of the anticodon constitutes the wobble position.
Wobble Allows Some tRNAs to Recognize More than One Codon. This is due to the fact that
strict watson and crick base pairing rules applies only to the first two bases of the codon where as
third base tRNA can recognise more than one codon.

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Although some male crab spiders find and mate with adult female spiders, others that find immature females remain with them although the sub adult females are incapable of mating until they become adults. This behavior would puzzle most evolutionary biologists because: a. The genetic basis for this behavior would be very difficult to determine. b. Mating is instinctive in spiders and therefore all males should behave the same, either mating with adult females only or guarding sub adult females only. c. Males that guard sub adults cannot use the time to find receptive females. d. One would think that immature female spiders should accept and store sperm from males in order to permit good female-finding males to have time to find many mates. Solution The answer to this concept is ans (4)..one the female immature spider should store the sperms in them for good female - findings males to have time to find many other...

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–PLS write program in c++ thanx Linked List Sorting and Reversing Write a C++ using your own linked list class to manage a list of string elements. Besides the basic operations expected of a linked list (add an element, remove an element, check for empty list, report size (number) of elements in the list, and print out the content of the list), the linked list class also needs to have a method called sort() and a method called reverse() the manipulate the string elements. The sort method rearranges the elements in the list so they are sorted in alphabetical order. The reverse method reverses the order of the elements of the list. Do NOT use recursion to implement either of these operations. pls write program in c++ thanx Solution #include #include using namespace std; class Node{ //class node public: string data; Node* next; void SetData(string aData) { data = aData; }; void SetNext(Node* aNext) { next = aNext; }; }; class List{ //class list Node *head; public: List() { head = NULL; }; void addElement(string data); void removeElement(string data); int isEmpty(Node* temp); int size(); void print(); void sort(); void reverse(); }; int List::isEmpty(Node* temp){ //method to check whether list is empty or not if(temp!=NULL) return 1; else return 0; } void List::addElement(string data){ //method to add Node* newNode=new Node(); newNode->SetData(data); newNode->SetNext(NULL); Node* temp=head; if(temp!=NULL) { while(temp->next!=NULL) {temp=temp->next;} temp->next=newNode; } else head=newNode; } void List::removeElement(string data){ //method for delete Node* temp=head; Node *prev=head; if(isEmpty(temp)==1) {//prev=temp; while(temp!=NULL) { if(temp->data==data) {prev->next=temp->next; temp->next=NULL; } else {prev=temp; temp=temp->next; } } } else cout<<\"Nothing to delete as linked list is empty \"<next; } } return count; } void List::print(){ //method for print Node* temp=head; if(isEmpty(temp)==1){ while(temp!=NULL) { cout<data<<\" \"; temp=temp->next; } } } int main() { List list; list.addElement(\"anshu\"); list.addElement(\"anurag\"); list.addElement(\"how\"); list.addElement(\"are\"); list.addElement(\"you?\"); int count=list.size(); cout<<\"size of the linked list= \"<.

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Write a Java program that calculates the distance between two points when a user types the coordinates. Solution DistBetPoints.java import java.util.Scanner;//package for keyboard inputting //distance = square root of [(a2-a1)squared + (b2-b1)squared] public class DistBetPoints {//main class static double distance(double a1, double b1, double a2, double b2) { return Math.sqrt((a2-a1)*(a2-a1) + (b2-b1)*(b2-b1)); } public static void main(String[] args) { //main function double a2, a1, b2, b1; double distance; Scanner scan = new Scanner (System.in); System.out.println(\"Enter the x coordinate for point 1: \"); a1 = scan.nextDouble();//keyboard inputting System.out.println(\"Enter the y coordinate for point 1: \"); b1 = scan.nextDouble();//keyboard inputting System.out.println(\"Enter the x coordinate for point 2: \"); a2 = scan.nextDouble();//keyboard inputting System.out.println(\"Enter the y coordinate for point 2: \"); b2 = scan.nextDouble();//keyboard inputting distance = distance(a1,b1,a2,b2);//calling function System.out.println(\"The distance between the two points is \" + distance + \" .\"); } } output Enter the x coordinate for point 1: 0 Enter the y coordinate for point 1: 0 Enter the x coordinate for point 2: 2 Enter the y coordinate for point 2: 2 The distance between the two points is 2.8284271247461903 ..

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poblettesedanoree498

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What is an advantage of having homologous chromosomes (compared to haploid cells that only have a single copy of each gene)? Solution Humans, including many other organisms contain a double set of chromosomes in their genetic material. The purpose and benefits of having a homologus chromosomes can be discussed as below: Thus, the above given explanations represent the benefits of having a homologous pair of chromosomes in diploid organisms over haploids..

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poblettesedanoree498

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Unlike the biological species concept, the morphospecies concept relies on: a. offspring. phenotype. physiology. behavior. a. offspring.b. phenotype.c. physiology.d. behavior. Solution B). Phenotype Biological species concept (BSC): According to the biological species concept, a biological species is the one in which, organisms can have interbreeding and produce the viable offspring. In contrast, the morphospecies concept relies on phenotype. The species are grouped according to the similarities in their morphological features..

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8. Which of the following sentences defines adequately horizontal gene transfer? a) Exchange of genetic information across species b) Movement of genetic information via binary fission c) Exchange of genetic information via sexual reproduction d) Transmission of genetic information from ancestors to descendants e) Exchange of genetic information via asexual reproduction Solution 1. The correct answer is Option A. Horizontal gene transfer is defined as the movement of genetic material between bacteria other than by descent in which information travels through the generations as the cell divides. The bacterial species cannot divide sexually so there are other methods like transformation, conjugation and transduction which are employed for horizontal gene transfer..

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Part A According to theory of natural selection, what factor below contributed to the current variations in beak sizes of finch species on the Galapagos islands? the O Non-heritable variation between individual was important for natural selection to work O Genetic drift alowed beneficialtraits to spreadthroughout the population O Different finch populations needed to change in order to survive, so benescialnewtrats arose O Finches dispersed to islands where their beak sizes dosely matched awailable seedsizes O Seeds are a limited resource Submit My Answers Give Up Solution Finches dispersed to the island where thier beak size is closely is closely mathed available seed size. larger beak resulted from ability to harvest rare, large seeds. Part A c. Canis lupus They also known as the timber wolf or western wolf..

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In gene therapy, how is the malfunctioning gene replaced? No plagarism! Solution Gene therapy is replacing defective genes with the genes having normal functionality. This treatment can be done at different stages.Therapy done at earliest stage of life (embyonic stage) is the most effective as it ensures gene replacement in whole lineage of cells having origin from therapeutic cell. Most common tool used for gene therapy are Viruses. These viruses are used as vector to carry desirable gene. Viruses are disarmed by removal of their harmful genes .Therapeutic gene is inserted in these viruses. While inserting therapeutic genes it is ensured that genetic material of viruses that has coding to control entry into host cells remains intact. These viruses are then exposed to target cells with malfunctioned genes.These viruses then transfer desired genes into the target cells.This step can be dne in situ or in vivo depending upon tissue being treated. Different types of viruses can be used for different mechanisms of DNA transfer. Challenges in gene therapy: 1. To ensure right positioning of desirable gene into host cell. 2. Sometimes gene may be over expressed. 3. Wrong position of gene in host cell may trigger changes in expression of DNA in vicinity..

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i have a code that runs, but it only lets the player to guess where the ships are(which is a one player game with one board). is there a way some one can help turn this game into a player vs computer game (with two boards one for player and one for computer) Please help me. BattleShipGame.java package battleship; import java.util.ArrayList; import java.util.Scanner; public class BattleshipGame { private Ocean ocean; private boolean[][] availableSpot; private Scanner sc; public BattleshipGame() { // define a new ocean and a new 2D array to store available coordinates ocean = new Ocean(); availableSpot = new boolean[10][10]; for (int i = 0; i < 10; i++) { for (int j = 0; j < 10; j++){ availableSpot[i][j] = true; } } } /** * prints the game menu and info * //param select */ public void print(int select){ String info; switch (select) { case 1: info = \"Welcome to the World of Battleship!\"; break; case 2: info = \"Enter coordinates to fire: \"; break; case 3: info = \"Shots fired: \"+ocean.getShotsFired()+\", Ships sunk: \"+ocean.getShipsSunk(); break; case 4: info = \"Congratulations! You win!\"; break; case 99: info = \"Invalid input. Please re-enter:\"; break; case 100: info = \"--------------------------------------------\"; break; case 101: info = \"\ ============================================\"; break; default: info = \"Error selection\"; break; } System.out.println(info); } /** * check if the input is valid * //param input * //return boolean */ public boolean checkValidInput(String input){ ArrayList numList = new ArrayList(); for (int i=0;i<10;i++){ numList.add(\"\"+i); } String[] coordinates = input.split(\" \"); //returns false if there are not 2 strings if (coordinates.length!=2){ return false; } //returns false if any of the strings is not a single digit number for (String str: coordinates){ if (numList.contains(str)==false){ return false; } } //returns false if the coordinates have already been shot at int row = Integer.parseInt(coordinates[0]); int column = Integer.parseInt(coordinates[1]); if (this.availableSpot[row][column]==false){ return false; } return true; } /** * get the coordinates to shoot at from the String input * //param input * //return int[] coordinates */ public int[] getCoordinates(String input){ int[] coordinates = new int[2]; String[] strList = input.split(\" \"); int row = Integer.parseInt(strList[0]); int column = Integer.parseInt(strList[1]); coordinates[0] = row; coordinates[1] = column; return coordinates; } /** * play the battleship game */ public void play(){ print(101); print(1); ocean.placeAllShipsRandomly(); boolean isGameOver = ocean.isGameOver(); sc = new Scanner(System.in); //print the ocean and start the game ocean.print(); print(3); while (!isGameOver){ print(2); String input = sc.nextLine(); //check if input is valid while (!checkValidInput(input)){ print(99); input = sc.nextLine(); } //get coordinates and fire int[] coordinates = getCoordinates(input); int row = coordinates[0]; int column = coord.

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