I\'m confused the other people obtained a result of 16. Are we simply saying that the integral over the interval [0,2] is the integral of [0,8] divided by 4 then multiplied by 4? Solution In integration from 0 to 2 f(4x)dx Let, 4x = t dx = dt/4 when - x=0, t=0 x=2, t=8 Thus, integration from 0 to 8 (1/4)f(t)dt using change of variable from t to x integration from 0 to 8 (1/4)f(x)dx Hence, answer is 4/4 = 1.