Please explain In a Drosophila dihybrid cross, a sepia male was mated to a apterous female. Their phenotypically wild F_1 female produced the following offspring when crossed to phenotypically wild F_1 males: Please set up a null hypothesis and use a Chi-square analysis to see if the observation follows the Mendelian phenotypic ratio. Solution Answer: Chi-Square value= 1.33 The degrees of freedom = 4-1 = 3 The probability level for df 3 Chi-Square value, 1.33 lies below 0.5 (probability), so we fail to reject null hypothesis.PhenotypeObserved(O)Expected (E)O-E(O-E)2(O-E)2/EWild type45045000.000.00Sepia16015010100.000.67Apterous140150- 10100.000.67sepia/aprerous505000.000.008008001.33.