3. Cables
• Cables are often used in engineering structure to
support and or transmit loads from one member to
another
Structural Analysis IDr. Mohammed Arafa
11.
0
0
0 cos cos 0
0 sin sin 0
0 cos sin 0
2
Dividingeach eq. byΔx and taking thelimit as Δx 0
and hence y 0, 0 and T 0
x
y
o
F T T T
F T w x T T
x
M w x T y T x
Analysis Procedure
Structural Analysis IDr. Mohammed Arafa
12.
0
cos
0 (1)
sin
(2)
tan (3)
d T
dx
d T
w
dx
dy
dx
Analysis Procedure
13.
H
0
0
at x=0 T=F
Integrate eqs. 1 where T=F at x=0
cos (4)
Integrate eqs. 2 where Tsin =0 at x=0
sin (5)
dividing 4 by 5
tan =
H
H
H
T F
T w x
w xdy
dx F
Analysis Procedure
15.
max
2 2
max
0
2
22
max 0 0
cos
cos
is at where is maximum
( )
In our Case at x=L
1
2
H
H
H
H
T F
F
T
T
at x L
T F V
V w L
L
T F w L w L
h
Analysis Procedure
16.
2
2
2
0
2 2
22 2 2
max max 0
2
cos
H
H
H
H H
h
y x
L
w L
F
h
F
T F V
T F V F w L
Summary
20. Example 2
Determine the tension of the cable at points A, B, C
Assume the girder weight is 850 lb/ft
Structural Analysis IDr. Mohammed Arafa
21.
22.
23.
24.
25. 2 2 2 2
max
500 30
7500 Ib=7.5k
2 2
7.031 7.5 10.280
A B
A B
WL
V V
T T T H V
Example 3
Determine the tension of the cable at points A, B
2
500 15
7031.25
2 8
HF
2
0
2
H
w L
F
h
HF
AV BV
HF
30. Problem 1: The cable AB is subjected to a uniform loading of
200kN/m. If the weight of the cable is neglected and the slope angles at
points A and B are 30 and 60, respectively, determine the curve that
defines the cable shape and the maximum tension developed in the
cable.
31.
0 0 1
Integrate the equations
(1)
(2)
cos
0 cos
sin
sin
H
d T
T F
dx
d T
w T w x C
dx
1
0
Substitute at 0
sin30 tan3
30
cos cos30
eq.(2) willbe:
sin tan
0
(3)30
A
H H
H
A H
F F
T T
T
x
C T
F
F
w x
32.
0
2
tan30
tan
1
0.2 tan30
60
1
tan 60 0.2 15 tan30
Divide
2.6
1 1
0.2 tan30 0.2 2.
(3) by (1)
Substitute
6 0.577
2.60
0
at 15
(Equation of thecablecurv.0385 0.577 e)
H
H
H
H
H
H
H
H
H
w x F
F
dy
x F
dx F
F
F
F kN
dy
x F x
dx F
x x
x
y
33. max
cos
2.6
cos cos
At 0 30
2.6
3.0
cos3
Substitute in (1)
0
At 15 60
2.6
5.2
cos60
H
H
A
B
T F
F
T
x
T kN
x
T kN T
34. Problem 2: Determine the maximum and minimum tension in the
parabolic cable and the force in each of the hangers. The girder is
subjected to the uniform load and is pin connected at B.
Draw the shear and moment diagrams for the pin connected girders
AB and BC.
35. HF
HF
HF
HF
0
5 5 2.5 0.5 0 (1)
0
20 20 10 8 0 (2)
Solve(1) and (2) 0 & 25
A
y H
C
y H
y H
M
B F
M
B F
B F kN
36.
2
0
2
0
0
min
22
max 0
22
2
20
25
2 8
1 /
For the main Cabl
25
25 1 20 32.02
e
H
H
H
w L
F
h
w
w kN m
T F kN
T F w L
kN
0
Force in each ha
2.5 1 2.5 2
g
.5
n er
T w kN
37.
38. Problem ٣: The beams AB and BC are supported by the cable that
has a parabolic shape. Determine the tension in the cable at points
D, F, and E, and the force in each of the equally spaced hangers
46. Example 5
Determine the internal forces at Section D
kNA
kNA
F
kNB
BM
kNB
BM
y
x
x
x
xRightC
y
yA
93
0F
86
0
86
0)20(67)8(60)6(0
67
0)28(60)10(100)40(0
y