The following table is a probability distribution where the random variable x represents the number of activities at least one parent of a student is involved in. Based on this distribution, what is the expected number of activities a parent is involved in? Solution Find the weighted average of the X\'s: mean = E(X) = piXi = 0(.035) + 1(.074) + 2(.197) + 3(.320) + 4(.374) = 2.924.