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1. ans is =2z+1 2. ans is =-1(z^2) 3. ans is =sec^2x as sinzco.pdf

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1. ans is =2z+1 2. ans is =-1/(z^2) 3. ans is =sec^2x as sinz/cosz = tanz 4. let z-1=t =>dz=dt so the answer is =[-5/(t^2)]*[exp(5/t)] that is =[-5/{(z-1)^2}]*[exp(5/z-1)] Solution 1. ans is =2z+1 2. ans is =-1/(z^2) 3. ans is =sec^2x as sinz/cosz = tanz 4. let z-1=t =>dz=dt so the answer is =[-5/(t^2)]*[exp(5/t)] that is =[-5/{(z-1)^2}]*[exp(5/z-1)].

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1. ans is =2z+1 2. ans is =-1/(z^2) 3. ans is =sec^2x as sinz/cosz = tanz 4. let z-1=t =>dz=dt so the answer is =[-5/(t^2)]*[exp(5/t)] that is =[-5/{(z-1)^2}]*[exp(5/z-1)] Solution 1. ans is =2z+1 2. ans is =-1/(z^2) 3. ans is =sec^2x as sinz/cosz = tanz 4. let z-1=t =>dz=dt so the answer is =[-5/(t^2)]*[exp(5/t)] that is =[-5/{(z-1)^2}]*[exp(5/z-1)]

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1. ans is =2z+1 2. ans is =-1(z^2) 3. ans is =sec^2x as sinzco.pdf

  • 1. 1. ans is =2z+1 2. ans is =-1/(z^2) 3. ans is =sec^2x as sinz/cosz = tanz 4. let z-1=t =>dz=dt so the answer is =[-5/(t^2)]*[exp(5/t)] that is =[-5/{(z-1)^2}]*[exp(5/z-1)] Solution 1. ans is =2z+1 2. ans is =-1/(z^2) 3. ans is =sec^2x as sinz/cosz = tanz 4. let z-1=t =>dz=dt so the answer is =[-5/(t^2)]*[exp(5/t)] that is =[-5/{(z-1)^2}]*[exp(5/z-1)]