5. If we found AB+ blood at a crime scene and we knew one of our 5 s.pdf

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5. If we found AB+ blood at a crime scene and we knew one of our 5 suspects had a partial Genotype that was determined to be IAI B CcEe would this be enough evidence to make this suspect now a lead suspect. Why or Why not? Use Punnett squares to make your case. What additional test would need to be performed? 6. A homicidal maniac has a genotype of IB I B Ccddeehhsese. At this murderer’s most recent crime scene we find the murder’s baseball cap without blood, a pair of stained underwear no blood, no fingerprints, no fibers, no hairs. Based on these items, do we have any possible chemical, or immunological or other analyses we can perform that will identify the murderer as it relates to the genotypic info we have on him or her. If so how would you go about doing those studies Solution 5. ANS: No, At first the D antigen additional test would need to be performed. It is because AB+ is the most common blood group and the the perp would have to be either Dd or DD (Rh+ve). we could only really use the evidence to exclude suspects. 6. ANS: In this case the blood strains are not there. Genetic material on it and use that to identify the genotype is the best way to detects suspect. So genotyping performing will identify the murderer. Genotype is used to determine the alleles that an individual possesses. Genotyping test is used for crime and paternity testing because in genome there is 1 difference present in every 1,000 base pairs (in humans 3,000,000 difference sequence are present)..

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What is the difference between a hash in perl and a hashtable in Java? What are some concrete examples? Solution There are lot of differece between hash in perl and hashtable in java concrete Examples: 1) Insertion is done using a put method in java. It is done directly in perl In Java: data.put(\'John Paul\',45) In Perl; $data{\'John Paul\'} = 45; 2) In Java We have to specify datatypes of key and value before hand while defing the hashtable variable. It is not necessary in perl..

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What are the specific linkages among immune surveillance, clonal selection, and lymph nodes? Solution Immune Surveillance - A hypothesis that the immune system perceives and pulverizes tumor cells that are continually emerging amid the life of the person. A body component by which early growths are recognized as being strange and are assaulted and typically pulverised. Immune Surveillance is a process in which a T cell-intervened handle without which tumor would be much ordinary. The immune sytem can distinguish and crush rising cancer cells since it perceives strange antigens on the cell surface as \'foreign substance\' or outsider. Since outside substances are typically risky to the body, the immune system is customised to demolish them. This consistent checking of the body for little tumors is immune surveillance. The immune surveillance of living body is known to work in the dismissal of tumor cells in people with inherited nonpolyposis colon growth, likewise called Lynch disorder. Those people acquire a broken DNA confound repair framework and as an outcome deliver numerous mutant proteins. At the point when such mutant proteins show up on the surface of tumor cells, they are perceived as foriegn and rejected. Tumors that do rise are those that have figured out how to sidestep the body\'s immune system. Lymph nodes are Bean Shaped and encapsulated antigen gathering tissues that channel lymph and permit lymphocytes to test antigens gained from skin, GI tract and respiratory tract - deliberately situated all through body, bolstered by reticular system of follicular DCs and macrophages - lymphocytes enter from blood crosswise over high endothelial venules and from the interconnected lymphatic vessels; B cells relocate to the cortex and immune system microorganisms move to paracortical area; plasma move to medulla and emit counter acting agent - DCs with antigen enter from lymphatic vessel; T cells and DCs reach each other the T cell tests the antigens in setting of the MHC on the DC; enacted T cells leaves lymph hubs and enter the blood to site of contamination. Clonal Selection - Clonal selecction is a hypothesis clarifying how the cells of the immune system deliver vast amounts of the correct counter acting agent at the ideal time, in the sense, at the point when the proper antigen is experienced. It suggests that there is a previous pool of lymphocytes i.e B cells comprising of various little subsets. Every subset conveys a one of a kind arrangement of surface counter acting agent atoms with its own specific restricting qualities. In the event that a cell experiences and ties the comparing antigen it is `selected\' – empowered to partition more than once and deliver a substantial clone of indistinguishable cells, all emitting the counter acting agent. The contribution of aide T cells is basic for actuation of the B cell. A type of clonal determination is additionally summoned to clarify the improvement of immunological resistance.

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True or False – Paraeducators provide direct or indirect instructional and other services to students under the supervision of a lead paraeducator. Solution it is true Roles And Responsibilities Of Paraeducators Over the years, the roles and responsibilities of paraeducators have become more complex and have expanded to include numerous aspects of the educational process for studentswith disabilities (Drecktrah, 2000; French & Pickett, 1997; Pickett, 1999). In practice, the dutiesof a paraeducator may include, but are not limited to: • providing direct and small group instruction • adapting and modifying curriculum • monitoring student behavior • communicating with parents and families (many believe this should not reflect the role of paraeducators) • performing clerical duties, and • providing personal care.

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The situation where \"the few who yell the loudest get heard\" Is referred to as the Multiple Choice special-interest effect. principal-agent problem. moral hazard problem. Solution Answer:- the situation where the few who yell the loudest gets heard is referred to as the Correct Answer:- Special interest effect Reason:- “the special interest effect,” explains why, over time, the legislative process tends to generate more expansive government..

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\"Templated Binary Tree\" implementing function help ? I need to implement header file which i am working on. Void expandExternal and void preorder part : 1. Header File : #ifndef BINARYTREE_H #define BINARYTREE_H #include //////////////////////////////////// // Templated Node Interface /////////////////////////////////// template // base element type class Node { // a node of the tree public: Node() : elt(), par(NULL), left(NULL), right(NULL) { } // constructor private: E elt; // element value Node* par; // parent Node* left; // left child Node* right; // right child template friend class BinaryTree; template friend class Position; }; //////////////////////////////////// // Templated Binary Tree Interface /////////////////////////////////// template // base element type class BinaryTree { public: // public types //Defines a node position class Position { public: Position(Node * _v = NULL) : v(_v) { } // constructor //Returns the element at the position E& operator*() { return v->elt; } //Returns a Position object Position left() const // get left child { return Position(v->left); } //Returns a Position object Position right() const // get right child { return Position(v->right); } //Returns a Position object Position parent() const // get parent { return Position(v->par); } //Returns true or false bool isRoot() const // root of tree? { return v->par == NULL; } //Returns true or false bool isExternal() const // an external node? { return v->left == NULL && v->right == NULL; } //Returns true or false bool isInternal() const // an external node? { return ! isExternal(); } private: Node* v; template friend class BinaryTree; };//End Position class definition /* Position List type definition*/ typedef std::list PositionList; public: //Binary member functions BinaryTree() : _root(NULL), n(0) { } ~BinaryTree(); // The destructor need to properly deletes all nodes in the tree to prevent memory leaks. int size() const; // Returns and integer tof the number of nodes. bool empty() const; // Returns a true if the tree is empty else false. Position root() const; // Return the position of the root node. void addRoot(); // Creates and adds the initial root node to the tree this must be added first. void expandExternal(const Position& p); //Expands each external node with a left and right child that are empty. // What goes here? PositionList positions() const; // Returns a std:list of the nodes in the tree call preorder() function. void preorder(Node* v, PositionList& pl) const; // Traversal algorithm for the tree to populate the PositionList // What goes here? private: Node * _root; // pointer to the root int n; // number of nodes }; #endif Thank you Solution for the main function, try writing the code like this : struct Node{ Comparable element; Node *left; Node *right; Node(const Comparable & theElement, Node *lt, Node *rt ) : element( theElement ), left( lt ), right( rt ) {} }; // Node{} Node *root; Node * findMin( Node *t ) const; Node * findMax( Node *.

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State if you agree or disagree with the question and comments made below and why? Does Maryland’s new social media campaign rule go far enough to validate who is posting the political information on social media? Maryland has begun a great new way of identifying political advertisers support of particular politicians. But, this may not do everything that it needs to do in order to validate who is behind the postings or what is the motivation of the poster. If a political poster wished to disguise themselves and pretend to support a particular candidate, he or she could easily tag the advertisement with the legally required statement but still not be affiliated with the campaign they are supporting. This law would need to be broadened to include campaign-assuming responsibility for monitoring or approving any post made in their name. In order to achieve this goal, campaigns would need huge numbers of paid and volunteer team members just to monitor social media. Otherwise, social media, such as Facebook and Twitter, would need to have to take more responsibility for the IP addresses they allow to advertise on their platforms. Since this is a new legal development, it will need to be fine-tuned in order to protect the public from scammers. Solution With the emergence of social media networking being used to advertising in every field, the same has been done by the political advertisers. With this grew the forgery in the posts that were made in the name of political parties. So Maryland levied this law in which the political advertisers will have to identify their political campaign material before posting it on social media and can post it following set rules and guidelines. In the above matter it is mentioned that these rules will not eradicate the issue of false advertising totally as the political poster can be disguised and pretend to support a particular candidate. Tagging the advertisement with a legally required statement can be done even though they may not be affiliated with the campaign they are showing support for. To overcome this forgery ways will have to be found out to monitor and approve any post made in the name of a candidate or party by the party or candidates. For this special team members will have to be hired to keep a monitoring eye on the posts on social media. Also the social media can help by keeping a track of all the IP addresses they allow for the advertisements done ussing their platforms. These steps are essential to be taken in the political advertising campaigns as they will help erasing the false advertising in the names of political parties and make social media a trusted and genuine platform for such advertising..

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A number of benefits that one might expect to see from using a database such as MySQL. List four of these benefits and in your own words describe the benefit. Solution Some of the benefits are: Heavily Supported: It supports software on a variety of platforms and operating systems including Windows, Linux, Novell NetWare, UNIX and more. Secure: It help solid data security layers to safeguard sensitive data from outside access. All passwords used to entry the MySQL database are encrypted. Fast: When compared to other database software MySQL is much agile in terms of performance, and users still have approach to all the required features they would through other database platforms. Data Storage is Scalable: MySQL can handle a overall file size limit of about 4GB, however, this can be enlarged to meet our needs – by as much as 8TB of data. Manages Memory: The database software has been shown to guide memory vastly well and prevents memory leaks which we might experience on a server where it’s not deployed..

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QUESTION: If you look at the code, you\'ll see that we keep two lists, one to print the text in forward order, and one to print the text in reverse order. The forward one is using our empty add() function, so nothing gets put into it. You\'ll fix that, as well as modifiying insert() and erase(). The reverse on works by inserting always at the head of the list, like a Stack.Functions insert(), erase(), and add() must be modified so that if the last node of the list changes, List::last must change, as well. YOU JUST HAVE TO COMPLETE THE LIST.CPP FILE SO THAT IT PRINTS THE OUTPUT IN THE FORWARD ORDER.FINISH THE CODE ONLY IN LIST.CPP FILE AND OTHER FILES ARE JUST FOR REFERENCE. MORE INFORMATION AND HINTS ARE GIVEN IN THE COMMENTS IN LIST.CPP FILE. HINT: AFTER the existing code runs, there\'s an easy way to know if you just changed the last node in the list; if you did, it\'s time to update the \"last\" pointer. And remember that \'add\'-ing the first item is a special case. We could make a Linked List behave a lot like a Queue if it were really efficient to add a node at the end of the list, that is, without having to chase links from the head to the tail. So we will add another pointer to our List class that will always point at the last item in the list. Read the existing code carefully and understand how it works. The \"add\" function is now empty. If you run the file you should get an output that starts out like this: ?CURRENT LIST.CPP: CURRENT OUTPUT: MAIN.CPP FILE: LIST.H FILE: include list include Solution PROGRAM CODE: /* * List.cpp * * Created on: 29-Nov-2016 * Author: kasturi */ #include \"List.h\" #include #include #include using namespace std; void List::insert(ElemetType item, int position) { Node * predptr = first; for(int i=1; i< position && predptr && predptr->next; i++) { predptr = predptr->next; } Node * newptr = new Node; newptr->payload = item; if(!predptr) { newptr->next = 0; first = newptr; } else if(position == 0) { newptr->next = first; first = newptr; } else { newptr->next = predptr->next; predptr->next = newptr; } } void List::erase(int position) { Node * predptr = first; for(int i=1; inext; i++) { predptr = predptr->next; } if(!predptr) { } else if(position == 1) { first = predptr->next; delete predptr; } else { Node *ptr = predptr->next; predptr->next = ptr->next; delete ptr; } } void List::display(ostream& ostr) { Node * ptr = last; //changed the display function to print the first while(ptr) { ostr<payload<next; } } List::List() { first = 0; last = 0; } List::~List() { while(first) { Node *nxt = first->next; delete first; first = nxt; } } void List::add(ElemetType item) { //added code to add values into the last node Node * predptr = last; Node *newptr = new Node; newptr->payload= item; while( predptr && predptr->next) { predptr = predptr->next; } if(!predptr) { newptr->next = 0; last = newptr; } else { newptr->next = predptr->next; predptr->next = newptr; } } OUTPUT: Forward: The quick brown fox jumped over the back.

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Question 11 What is the volume of 17.0 grams of carbon dioxide gas if.pdf

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Please help with this. program must be written in C# .. All of the game logic must be written in a seperate class using using an array that is passed in through a prperty that represents the game board. The class needs to have methods to determine of someone won, or if there was a tie, make sure all business logic is in a seperate class anot behind the UI.. ***** These are the complete in instructions for the game assignment design Create a Tic-Tac-Toe game that can be played by two players. The form will consist of a Tic- Tac-Toe board in which the users’ click on to choose their space. As the game is being played the Game Status section will tell whose turn it is. When someone wins or there is a tie, a message will be displayed in the Game status section telling the users the status. When someone wins the game the winning move needs to be indicated. There also needs to be a section that keeps track of the number of wins for each player, and the number of ties. When the game is finished the user may click the “Start Game” button to start a new game. This program will consist of the main form and at least one class that will define the rules of the game. This class will have an array that is passed in through a property that represents the game board. The class will then have methods within it that determines if someone won, if there is a tie, or if neither has occurred yet. Make sure all business logic is in a separate class and not behind the UI. EXTRA CREDIT (10 Points) Create a computer player that can be played against. The computer player will need to be smart enough to make a winning move or to block a winning move. Solution using System; using System.Collections.Generic; using System.Drawing; using System.Windows.Forms; namespace Tic_Tac_Toe { /// /// Description of MainForm. /// public partial class MainForm : Form { Logic logicObj = new Logic(); public MainForm() { // // The InitializeComponent() call is required for Windows Forms designer support. // InitializeComponent(); // // TODO: Add constructor code after the InitializeComponent() call. // } int turn=1; int click1=0,click2=0,click3=0,click4=0,click5=0,click6=0,click7=0,click8=0,click9=0; int player1=0,player2=0; void Button1Click(object sender, EventArgs e) { if(click1==0) { if(turn%2!=0) { button1.Text=\"X\"; click1++; } else { button1.Text=\"O\"; click1++; } turn++; } else { button1.Text=button1.Text; } display(); int a = logicObj.winLossFunc(button1.Text, button2.Text, button3.Text, button4.Text, button5.Text, button6.Text, button7.Text, button8.Text, button9.Text); if (a==1) { player1++; player1score.Text = player1.ToString(); cleargame(); } else if(a==2) { player2++; player2score.Text = player2.ToString(); cleargame(); } } void Button2Click(object sender, EventArgs e) { if(click2==0) { if(turn%2!=0) { button2.Text=\"X\"; click2++; } else { button2.Text=\"O\"; click2++; } turn++; } else { button2.Text=button2.Text; } display(); int a = logicObj.winLossFunc(button1.Text, b.

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Match the enzyme activity in DNA synthesis with its function. DNA pol III (_) fragments Helicase (_) Primase (_) using template strand DNA pol I (_) double helix DNA ligase (_) adds nucleotides Topoisomerase (_) primer A. anneals DNA B. relieves overwinding C. adds nucleotides D. unwinds parental E. removes RNA primer, F. adds a short RNA 10 Proofreading and repair of the DNA double helix does NOT involves a. detecting a mis-match in base pairs. b. removing the mis-match with a nuclease. c. annealing the Okazaki fragments together with DNA ligase. d. repairing the mis-match with polymerase. e. annealing the edited DNA with the rest of the molecule with ligase. Solution 4. DNA Pol III- (C)- DNA polymerase III is the primary enzyme involved in DNA replication which adds nucleotides to the 3\' end of the forming DNA strand during replication. 5. Helicase- (D)- Helicases are enzymes that separates double-stranded DNA into single strands allowing each strand to be copied. 6. Primase- (F)- Primase functions by synthesizing short RNA sequences that are complementary to a single-stranded DNA. 7. DNA Pol I- (E)- DNA polymerase-I fills in the necessary nucleotides between the Okazaki fragments in a 5\'3\' direction. 8. DNA ligase- (A)- DNA ligases are essential for the joining of DNA fragments during replication. 9. Topoisomerase- (B)-Topoisomerases are enzymes that participate in the overwinding or underwinding of DNA. 10. Okazaki fragments are only formed during DNA replication and not observed during DNA proof reading and repair. Therefore answer is (C).

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Introduction to Engineering Experimentation Surface temperature conduction error of a thermal probe...(more than one answer may be correct) a. is systematic b. is random c. will produce a lower reading (assuming the surface is hotter than the surroundings) d. will produce a higher reading Solution answer is C and D. Systematic errors are situation dependent. sometimes poor probe design or bad installation can easily give a system significant temperature reading errors..

Introduction to Engineering ExperimentationSurface temperature con.pdf

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In Java.... The methods should work as: add(Node) It has to take a new Node and add that to the next address of previous Node. findNode(Node) It has to take a node and checks if the node is in the list. size() It should return the size of the NodeList. public class NodeList { private int size = 0; private Node root = null; /* * It has to take a new Node and add that to the next address of previous Node. * If the list is empty, assign it as the \"root\" * @Param - Node */ public void add(Node node) { // Implement this method!!! } /* * It has to return the size of the NodeList * * @return size */ public int size() { // Implement this method!!! } /* * It has to take a Node and checks if the node is in the list. * If it finds the node, it returns true, otherwise false * * @param - Node * @return boolean true/false */ public boolean findNode(Node node){ // Implement this method!!! } } Solution public class NodeList { private int size = 0; private Node root = null; /* * It has to take a new Node and add that to the next address of previous Node. * If the list is empty, assign it as the \"root\" * @Param - Node */ public void add(Node node) { // Implement this method!!! if(node==null) return; if(root == null) root=node; else{ Node temp = root; while(temp.next!=null){ temp = temp.next; } temp.next = node; } } /* * It has to return the size of the NodeList * * @return size */ public int size() { // Implement this method!!! int count =0; if(root==null) return count; else{ Node temp = root; while(temp!=null){ temp= temp.next; count++; } } return count; } /* * It has to take a Node and checks if the node is in the list. * If it finds the node, it returns true, otherwise false * * @param - Node * @return boolean true/false */ public boolean findNode(Node node){ // Implement this method!!! boolean flag = false; if(root == null) return false; else{ Node temp = root; while(temp!=null){ if(temp==node){ flag = true; break; } } return flag; } } } also find the defination of class Node class Node{ int data; Node next; }.

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In a 300-600 word statement, explain ONE of the following perspectives: World Risk Society, Runaway World, Globalization from Below, Globalscapes. Do not merely copy the language in the text - think carefully about the theory. How does the theory work? Do your best to explain the theory in your own words! Write in clear, jargon-free language. Elaborate as much as you can. Last, please write this in the format of a formal paper. Please have a clear introduction with a thesis statement, a body that answers the questions posed in the prompt, and a concluding section. Arrange this paper with structure and in distinct paragraphs. If using other sources other than your textbook, please make appropriate citations (you must give credit in paraphrasing or quoting text from others! If not, it\'s plagiarism). Solution Globalization from below Utilization of mobile technologies by poor people and by network based systems to associate with both their partners in the worldwide north and south as methods for building spans for promoting, exchange and for social trade. This is in contradistinction to Globalization from Above, where the ICT apparatuses are utilized by great organizations, governments and the built up techno-elites to sustain rejection and advance their corporate wage and class interests. Globalization from below has risen up out of differing concerns and encounters. Hippies distinguished globalization as a wellspring of corrosive rain and a dangerous atmospheric deviation and saw worldwide enterprises and the World Bank supporting the obliteration of nearby situations around the globe. Destitute individuals\' developments in the Third World and their supporters around the world saw neoliberalism, universal budgetary capital and auxiliary alteration as key reasons for worldwide neediness. Supporters for little ranchers in both the First and Third Worlds recognized new exchange assentions as a way to decimate family cultivating in light of a legitimate concern for agribusiness. Work developments understood that global capital portability was driving not to common profit for laborers but rather to focused wage- cutting. Ladies\' developments distinguished specialists misused in the worldwide sweatshop as dominatingly ladies and basic change as an assault on open projects that ladies especially require. Purchaser developments recognized neoliberalism and new exchange understandings as assaults on high national norms for sustenance and item wellbeing. Understudies ended up insulted that items bearing their schools\' logos were being made by kids and ladies compelled to work at least sixty hours for every week for not as much as a living pay. Those influenced by globalization from above have started to focalize, united by normal interests, objectives and various particular battles. This developing movement– this system of networks– is the ice sheet of which the road exhibitions frame the most noticeable tip. It is the potential intensity of this co.

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if the solubility of CaSO4 is 5*10^-3 mol/L what is the Ksp of CaSO4? Solution The dissolution of calcium sulfate forms equal amounts of calcium ions and sulfate ions according to the following equation. CaSO4(s) Ca+2(aq) + SO4-2(aq) If we let [Ca+2] = [SO4-2] = x , then we can solve for the Molarity of calcium sulfate that would be soluble. Ksp = [Ca+2][SO4-2] Ksp = (x)(x) x= [Ca+2] = [SO4-2] = 5E-3 M so Ksp = 25E-6.

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How to create an array restaurant menu out of the main class using methods, mutators, accessors, constructors and objects in Java. Solution /** * @fileName :Restaurant.java * @author * @since 10-02-2017 **/ package restaurant; public class Restaurant { public static void main(String[] args) { //creating array of menu Menu[] menu =new Menu[4]; //creating 4 menu object Menu item1 = new Menu(\"Corn Soup\",10.0f,true); Menu item2 = new Menu(\"bread\",20.0f,true); Menu item3 = new Menu(\"Chicken roll\",80.0f,false); Menu item4 = new Menu(\"fish\",60.0f,true); //assigning the items to menu array menu[0]=item1; menu[1]=item2; menu[2]=item3; menu[3]=item4; } } class Menu{ private String itemName; private float price; private boolean veg; /** * this is default constructor */ public Menu() { itemName=\"\"; price=0.0f; veg=false; } /** * * @param itemName * @param price * @param veg */ public Menu(String itemName, float price, boolean veg) { this.itemName = itemName; this.price = price; this.veg = veg; } public String getItemName() { return itemName; } public void setItemName(String itemName) { this.itemName = itemName; } public float getPrice() { return price; } public void setPrice(float price) { this.price = price; } public boolean isVeg() { return veg; } public void setVeg(boolean veg) { this.veg = veg; } }.

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How does Zoning support human and environmental sustainable community development. Solution Now a day’s sustainable community development has received considerable attention in planning of cities & development projects. Sustainable community development can be achieved when development meets the needs of the present without affecting the ability of future generations to meet their needs. It is about having a balance in ecology, equity & economy of a region. Zoning is a part of land use regulations which regulates different types of activities that can be accommodated on a given piece of land & space provided to do those activities. A planned unit development zoning helps in land regulation which promotes large scale, unified land development. Since it is a highly negotiated regulatory approach it gives flexibility to custom design, community interests & environmental preferences. Zoning helps in shaping our public spaces, maximizing positive social interaction & saving time needed for travel. Zoning also reduces costs for roads & utilities through proper marking & planning. Zoning helps in implementing community goals & objectives. Zoning can protect existing neighborhoods & structures of importance. Zoning prevents incompatible land uses near important institutions such as dance clubs which affects the environment in that area. Zoning helps in protecting environmentally sensitive area. Zoning provides adequate light, air & privacy to households. So we can say that zoning supports human and environmental sustainable community development by giving community a good control over land use, its appearance & quality of life in future..

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First, create a class called Person that implements the Comparable interface. Person will contain a member variable to hold a name, a constructor that sets up the name, and three methods (getName, compareTo, toString). getName returns the member variable, compareTo works as defined by the Comparable interface, and toString returns the name neatly formatted. Second, you\'ll compare Persons by their names. Include a main method in Person that asks the user to input ten names and generates ten Person objects. A blank name should not be used to create an object. Using the compareTo method, determine first and last person among them and print them. Do not simply sort the Person data. Solution Person.java import java.util.Scanner; public class Person implements Comparable { private String name; public Person(){ } public Person(String name) {this.name = name; } public String getName() { return name; } public void setName(String name) { this.name = name; } public String toString() { return \"Name: \" + name ; } public int compareTo(Person p) { return getName().compareTo(p.getName()); } public static void main(String a[]){ Scanner scan = new Scanner(System.in); Person p[] = new Person[10]; System.out.println(\"Enter 10 persons names: \"); for(int i=0; i.

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