III. Mobilization of stored seed reserves after germination.25. Wh.pdf

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III. Mobilization of stored seed reserves after germination. 25. What happens to seed storage proteins after germination begins? 26. What is a peptidase? 27. What are the four peptidases found in seeds and how do they differ? Solution III. Mobilization of stored seed reserves after germination: When water is taken up by dry seed during germination, various metabolic processes starts leading to emergence of radicle. The major stored food reserve of the seed is mobilised to provide nutrients for growing seedling. Seedling growth is initiated with the support of metabolites formed after hydrolysis of stored reserves like proteins, oils, carbohydrates etc. 25 & 26. What happens to seed storage proteins after germination begins? And what is a peptidase? Peptidases/ proteases are enzymes which causes proteolysis (degradation) of proteins/ peptides. Dry seed contain various stored proteins like globulins, prolamins etc. During seed germination endogenous or exogenous proteases such as cysteine endopeptidases, serine carboxypeptidases and neutral aminopeptidases etc. caused protein proteolysis know as protein mobilization help in seedling growth. 27. What are the four peptidases found in seeds and how do they differ? There are various peptidases found in different seeds and these have fuction of protein degradation but site of action of every enzyme is different. Few of proteases with their active sites are mentioned bellow: 1. Carboxypeptidase (hydrolyzing carbobenzoxy-Phe-Ala at pH 5.9) 2. Amino peptidases (hydrolyzing Leu-Tyr at pH 9.2) 3. Dipeptidase (act at Ala-Gly at pH 8.5) 4. naphthylamidases (hydrolyzing Leu--naphthylamide at pH 6.4) 5. proteinases (acting on haemoglobin at pH 3.7 and on casein at pH 5.4 and 7.0) 6. Cysteine endopeptidases.

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gen diffuses Oxygen enters a from the blood to red blood cell. the body\'s tissues oxygen is di through blood from the alveoli vessels to a into sumounding capillaries. capillary. a molecule of hemoglobin reset help Solution Steps wise - 1.Oxygen is carried through blood vessels to a capillary. 2.Oxygen diffuses from the alveoli into surrounding capillaries. 3.Oxygen enters a red blood cell. 4.Oxygen binds to a molecule of hemoglobin. 5.Oxygen diffuses form the blood to the body\'s tissues..

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Fill in parameters Public New Hash table (int initial Capacity, float load Factor) Constructs a new, empty hash table with the specified initial capacity and the specified load factor. Parameters: initial Capacity - the initial capacity of the hash table. load Factor - the load factor of the hash table. Throws: if the initial capacity is less than zero, or if the load factor is nonpositive. public New hostable (int initial 1Capac.ity) Constructs a new, empty hash table with the specified initial capacity and default load factor (0.75). Parameters: initia1Capacity - the initial capacity of the hash table. Throws: IllegalArqumentException - if the initial capacity is less than zero. public NewHashtable() Constructs a new, empty hash table with a default initial capacity (11) and load factor (0.75). Solution //NewHashTable.java import java.util.LinkedList; @SuppressWarnings({ \"unchecked\", \"unused\", \"rawtypes\", \"hiding\" }) public class NewHashTable { //private class to hold a key and its value private class HashEntry{ private K key; private V value; public HashEntry(K key, V value){ this.key = key; this.value = value; } public String toString(){ return key+\"=\"+value; } @Override public boolean equals(Object obj) { if(!(obj instanceof HashEntry)) return false; HashEntry other = (HashEntry) obj; return (key.equals(other.key)); } } private int capacity; private float loadFactor; private LinkedList[] table; private int size; //Default Constructor public NewHashTable(){ capacity = 11; loadFactor = .75f; table =new LinkedList[capacity]; for(LinkedList bucket : table) bucket = null; size = 0; } //One argument Constructor //@param initialCapacity initial capacity of table public NewHashTable(int initialCapacity){ if(initialCapacity<0) throw new IllegalArgumentException(\"\"+initialCapacity); capacity = initialCapacity; loadFactor = .75f; table = new LinkedList[capacity]; for(LinkedList bucket : table) bucket = null; size = 0; } //Two argument Constructor //@param initialCapacity initial capacity of this NewHashTable //@param loadFactor customized loadFactor public NewHashTable(int initialCapacity, float loadFactor){ if(initialCapacity<0) throw new IllegalArgumentException(\"Capacity: \"+initialCapacity); if(loadFactor<0) throw new IllegalArgumentException(\"Load Factor: \"+loadFactor); capacity = initialCapacity; this.loadFactor = loadFactor; } //@return capacity the capacity of this NewHashTable public int getCapacity(){ return capacity; } //@return true if this NewHashTable is empty, false otherwise public boolean isEmpty(){ return size==0; } //@return size the number of keys in this NewHashTable public int size(){ return size; } //@param key key to be searched for in this NewHashTable //@return true if key is found within this NewHashTable public boolean containsKey(K key){ int hash = Math.abs(key.hashCode()%capacity); return table[hash]!=null &&table[hash].contains(new HashEntry(key,null)); } //Increases the capacity and reorganizes this Ne.

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For Phantom Limb Syndrome, please describe the symptoms and the part of the brain affected explicitly, and the cure. How do sea stars\' cat? Describe the Water Vascular System in Sea Stars (WVS). What is its structure? How does the water get into the WVS? How does it control the tube feet? Besides moving the tube feet, what does the WVS do? Solution 1) Phantom limb syndrome is a condition or a sensation in which the cut or missed limb is being still attached with the person\'s body. It can also be caused due to removal of the body parts due to the certain reasons.. It affects the brain nerve ending called Neuromas..!! The symptoms include limb pain in some cases, gesturing, feeling itchiness, and most important is the feeling of one hand small and long which can bring to severe pain..!! Some of the cure way of this is meditation, acupuncture, anti-depressants, spinal cord stimulation..!! Some chemicals like morphine could also be a used... 3) water vascular system is a hydraulic water system present in echinodermata like sea stars.. It help in food, water movement, locomotion, waste transportation and even respiration too.. They are composed of canals which connects to tube feet . it moves by contacting muscles present in them which forces the water inside it resulting in extending, pushing on to the ground and again retracing.. The structure of it is like it has a sieve like structure which is connected to central duct called amphula. This amphula is connected to another duct called stone canal. This canal runs as a ambulagrel grooves on each arm of the sea star underside..!! This gives its appearance like a tube foot. The contraction of the amphulle cause podia to stretch water inside which allows for the movement..!!.

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Explain why the organisms that were studied by Sergei Winogradsky could not be grown on Robert Koch’s plate media containing agar or gelatin. Solution The organisms studied by Sergei Winogradsky are lithotrophs. Lithotrophs are the organisms that need inorganic nutrients to synthesise the biomolecules necessary for the survival. Robert Koch’s plate media containing agar or gelatin provides only organic nutrients. So, the lithotrophs studied by Sergei Winogradsky could not be grown on Robert Koch’s plate media..

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Describe 5 key traits the lung cancer cells within the primary tumor acquire and why they are significant. •As genetic stability is lost and genetic mutations accumulate some of these mutation result in advantageous changes to cellular function. As a result, lung cancer cells acquire traits effective for growth and development of tumors and invasion into surrounding tissue. Describe five of the traits lung cancer cells have that are advantageous and justify why you chose those traits. Solution Thanks for the question 1. self-sufficiency in growth signals- the cell can keep growing by itself 2. insensitivity to growth-inhibitory (antigrowth) signals - the cell looses the ability to restrict its unrestricted growth 3. evasion of programmed cell death (apoptosis),- the cell looses the ability of the body to evade death and discard. 4. limitless replicative potential - the cell can keep on multiplying as much as it can without any blocks or barriers 5. sustained angiogenesis- there is a constant and adequate emergence of blood supply for the new grown tissues and cells 6. tissue invasion and metastasis. - the cancer cells are able to spread themselves into other tissues physically and through blood Each of these physiologic changes cause the successful transformation of non cancer cells to cancer cells and make ineffective the anticancer defense mechanism present in the cells. These six capabilities are shared in common by most and perhaps all types of human tumors. Regards.

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