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BOOLEAN ALGEBRA
PART 3
CONVERSION OF STANDARD SOP FORM TO POS FORM
• The complement of a function expressed as the sum of minterms equals the sum of
minterms missing from the original function.
• The original function is expressed by those minterms that make the function equal to 1,
whereas its complement is a 1 for those minterms that make the function equal to 0.
• The SOP and POS forms are Duals to each other.
• The minterms and maxterms have a complementary relationship for a given Boolean
expression.
TRUTH TABLE OF A TYPICAL BOOLEAN FUNCTION
The original function can be expressed by the minterms which make the function equal to
‘1’. When we take complement of minterms, we can represent the same function in
maxterms which make the function equal to ‘0’.
CANONICAL SOP TO CANONICAL POS FORM
-EXAMPLE-
CANONICAL POS TO CANONICAL SOP FORM
-EXAMPLE-
KARNAUGH MAP METHOD
• A Karnaugh map provides a systematic method for simplifying Boolean expressions.
• This map method is graphical representation of Boolean functions. Like a truth table, it is
a means of showing the relationship between the logic inputs and the desired output.
• K map composed of an arrangement of adjacent cells, each representing a minterm or
maxterm of a Boolean expression.
• The number of cells in K-map depends upon the number of variables in the Boolean
expression. For three variables, the number of cells is 23 = 8. For four variables, the
number of cells is 24 = 16.
TWO VARIABLE K MAP
• Two variable K Map is drawn for a boolean expression consisting of two variables.
• The number of cells present in two variable K Map = 22 = 4 cells.
• So, for a boolean function consisting of two variables, we draw a 2 x 2 K Map.
• Here, A and B are the two variables of the given boolean function.
THREE VARIABLE K MAP
• Three variable K Map is drawn for a boolean expression consisting of three variables.
• The number of cells present in three variable K Map = 23 = 8 cells.
• So, for a boolean function consisting of three variables, we draw a 2 x 4 K Map.
FOUR VARIABLE K MAP
• Four variable K Map is drawn for a boolean expression consisting of four variables.
• The number of cells present in four variable K Map = 24 = 16 cells.
• So, for a boolean function consisting of four variables, we draw a 4 x 4 K Map.
PLOTTING SOP EXPRESSION IN A K-MAP
PLOTTING POS EXPRESSION IN A K-MAP

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Boolean algebra part 3 [Autosaved] (1).pdf

  • 2. CONVERSION OF STANDARD SOP FORM TO POS FORM • The complement of a function expressed as the sum of minterms equals the sum of minterms missing from the original function. • The original function is expressed by those minterms that make the function equal to 1, whereas its complement is a 1 for those minterms that make the function equal to 0. • The SOP and POS forms are Duals to each other. • The minterms and maxterms have a complementary relationship for a given Boolean expression.
  • 3. TRUTH TABLE OF A TYPICAL BOOLEAN FUNCTION The original function can be expressed by the minterms which make the function equal to ‘1’. When we take complement of minterms, we can represent the same function in maxterms which make the function equal to ‘0’.
  • 4. CANONICAL SOP TO CANONICAL POS FORM -EXAMPLE-
  • 5. CANONICAL POS TO CANONICAL SOP FORM -EXAMPLE-
  • 6. KARNAUGH MAP METHOD • A Karnaugh map provides a systematic method for simplifying Boolean expressions. • This map method is graphical representation of Boolean functions. Like a truth table, it is a means of showing the relationship between the logic inputs and the desired output. • K map composed of an arrangement of adjacent cells, each representing a minterm or maxterm of a Boolean expression. • The number of cells in K-map depends upon the number of variables in the Boolean expression. For three variables, the number of cells is 23 = 8. For four variables, the number of cells is 24 = 16.
  • 7. TWO VARIABLE K MAP • Two variable K Map is drawn for a boolean expression consisting of two variables. • The number of cells present in two variable K Map = 22 = 4 cells. • So, for a boolean function consisting of two variables, we draw a 2 x 2 K Map. • Here, A and B are the two variables of the given boolean function.
  • 8. THREE VARIABLE K MAP • Three variable K Map is drawn for a boolean expression consisting of three variables. • The number of cells present in three variable K Map = 23 = 8 cells. • So, for a boolean function consisting of three variables, we draw a 2 x 4 K Map.
  • 9. FOUR VARIABLE K MAP • Four variable K Map is drawn for a boolean expression consisting of four variables. • The number of cells present in four variable K Map = 24 = 16 cells. • So, for a boolean function consisting of four variables, we draw a 4 x 4 K Map.