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PRISMS
Kelas : VIII-B
GROUP 5
GROUP 5
The Understanding of Prisms
BASE
FACE
TOP
FACE
BASE
FACE
TOP
FACE
BASE
FACE
TOP
FACE
35 cm
A
B
C
D E
F
20CM
35 cm
A
B
C
D E
F
20CM
a) FE2 =DE2 - DF2
= 352 -212
= 1225 – 441
= 784
=
FE = 28
Surface area = ( 2 x Area of base face) + (perimeter of base face x
height)
= (2 x ½ x 21 x 28) + ((21+28+35) x 20)
= (2 x 294 ) + (84 x 20)
= 588 + 1680
= 2268 (D)
b) Volume of the prism
= area of base face x height
=( ½ x 21 x 28) x 20
= ( ½ x 588) x 20
= 294 x 20
= 5880 (A)
B
35 cm
A C
D E
F
20CM
2. Find the surface area !
30 cm
= 152 – 392
= 1521 – 225
= 1296
=
= 36
Surface area = ( 2 x Area of base face) + (perimeter of
base face x height)
= (2 x ½ x 30 x 36 ) + ((30+39+39) x 36)
= (30 x 36) + (108 x 36)
= 1080 + 3888
= 4968 cm
30 cm
36cm
3. Length, width, and height a rectangular prism
are 3 : 2 : 1. If the volume of prism is 750 cm3.
So, the surface area of the prism is . . . .
Given :
• P = 3n t = n
• l = 2n V = 750 cm3
Answer :
Vprism = Area of base face x height
= (P x l ) x t
750 = (3n x 2n) x n
750 = 6n2 x n
750 = 6n3
= n3
125 = n3
= n
5 = n

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Prisms

  • 4.
  • 5.
  • 9.
  • 10.
  • 11.
  • 12.
  • 14. 35 cm A B C D E F 20CM a) FE2 =DE2 - DF2 = 352 -212 = 1225 – 441 = 784 = FE = 28 Surface area = ( 2 x Area of base face) + (perimeter of base face x height) = (2 x ½ x 21 x 28) + ((21+28+35) x 20) = (2 x 294 ) + (84 x 20) = 588 + 1680 = 2268 (D)
  • 15. b) Volume of the prism = area of base face x height =( ½ x 21 x 28) x 20 = ( ½ x 588) x 20 = 294 x 20 = 5880 (A) B 35 cm A C D E F 20CM
  • 16. 2. Find the surface area ! 30 cm
  • 17. = 152 – 392 = 1521 – 225 = 1296 = = 36 Surface area = ( 2 x Area of base face) + (perimeter of base face x height) = (2 x ½ x 30 x 36 ) + ((30+39+39) x 36) = (30 x 36) + (108 x 36) = 1080 + 3888 = 4968 cm 30 cm 36cm
  • 18. 3. Length, width, and height a rectangular prism are 3 : 2 : 1. If the volume of prism is 750 cm3. So, the surface area of the prism is . . . .
  • 19. Given : • P = 3n t = n • l = 2n V = 750 cm3 Answer : Vprism = Area of base face x height = (P x l ) x t 750 = (3n x 2n) x n 750 = 6n2 x n 750 = 6n3 = n3 125 = n3 = n 5 = n