Toss a fair coin three times. Let X denote the number of heads in first two tosses and Y denote the number of heads in last two tosses. Calculate E(X), E(Y). Solution Tossing a fair coin three times is then the outcomes are {(H,H,H),(H,H,T),(H,T,H),(H,T,T),(T,H,T),(T,H,H,),(T,T,H),(T,T,T)}. Here X denote the number of heads in first two tosses are 2 and Y denote the number of heads in last two tosses are 2. E(X)=2/8=.25, E(Y)=2/8=.25..