I need help making a recursive Koch snowflake. Im using python. I ne.pdf

•

0 likes•3 views

I need help making a recursive Koch snowflake. Im using python. I needed to make a snowflake that uses 6 recursions. I did that part, the part Im having trouble with is coloring each of recursions a different color. here is what I have so far. //-------------koch snowflake void setup() { size(600, 600); background(255); stroke(0); //frameRate(1); //colorMode(HSB, 8, 100, 100); } int i = 1; void draw() { Koch(width/2, height/2, width*0.7, i); } void Koch(float X, float Y, float D, int order) { colorMode(HSB, 8, 100, 100); fill(0, 128/order, 128); pushMatrix(); translate(X, Y); translate(-D/2, D/3*sin(PI/3)); Koch(D, order); translate(D, 0); rotate(-2*PI/3); Koch(D, order); translate(D, 0); rotate(-2*PI/3); Koch(D, order); popMatrix(); } void Koch(float X, int order) { if (order == 1) { order++; Koch(X/3, order); pushMatrix(); translate(X/3, 0); rotate(PI/3); Koch(X/3, order); translate(X/3, 0); rotate(-2*PI/3); Koch(X/3, order); translate(X/3, 0); rotate(PI/3); Koch(X/3, order); popMatrix(); } if (order == 2) { order++; Koch(X/3, order); pushMatrix(); translate(X/3, 0); rotate(PI/3); Koch(X/3, order); translate(X/3, 0); rotate(-2*PI/3); Koch(X/3, order); translate(X/3, 0); rotate(PI/3); Koch(X/3, order); popMatrix(); } if (order == 3) { order++; Koch(X/3, order); pushMatrix(); translate(X/3, 0); rotate(PI/3); Koch(X/3, order); translate(X/3, 0); rotate(-2*PI/3); Koch(X/3, order); translate(X/3, 0); rotate(PI/3); Koch(X/3, order); popMatrix(); } if (order == 4) { order++; Koch(X/3, order); pushMatrix(); translate(X/3, 0); rotate(PI/3); Koch(X/3, order); translate(X/3, 0); rotate(-2*PI/3); Koch(X/3, order); translate(X/3, 0); rotate(PI/3); Koch(X/3, order); popMatrix(); } else { order = order - 1; beginShape(); vertex(0, 0); vertex(X/3, 0); vertex(X/2, X/3*sin(PI/3)); vertex(2*X/3, 0); vertex(X, 0); endShape(); } } Solution Try to implement in.

Education

void Koch(float X, int order) {
if (order == 1) {
order++;
Koch(X/3, order);
pushMatrix();
translate(X/3, 0);
rotate(PI/3);
Koch(X/3, order);
translate(X/3, 0);
rotate(-2*PI/3);
Koch(X/3, order);
translate(X/3, 0);
rotate(PI/3);
Koch(X/3, order);
popMatrix();
}
if (order == 2) {
order++;
Koch(X/3, order);
pushMatrix();
translate(X/3, 0);
rotate(PI/3);
Koch(X/3, order);
translate(X/3, 0);
rotate(-2*PI/3);
Koch(X/3, order);
translate(X/3, 0);
rotate(PI/3);
Koch(X/3, order);
popMatrix();

}
if (order == 3) {
order++;
Koch(X/3, order);
pushMatrix();
translate(X/3, 0);
rotate(PI/3);
Koch(X/3, order);
translate(X/3, 0);
rotate(-2*PI/3);
Koch(X/3, order);
translate(X/3, 0);
rotate(PI/3);
Koch(X/3, order);
popMatrix();
}
if (order == 4) {
order++;
Koch(X/3, order);
pushMatrix();
translate(X/3, 0);
rotate(PI/3);
Koch(X/3, order);
translate(X/3, 0);
rotate(-2*PI/3);
Koch(X/3, order);
translate(X/3, 0);
rotate(PI/3);
Koch(X/3, order);
popMatrix();

}
else {
order = order - 1;
beginShape();
vertex(0, 0);
vertex(X/3, 0);
vertex(X/2, X/3*sin(PI/3));
vertex(2*X/3, 0);
vertex(X, 0);
endShape();
}
}
Solution
Try to implement in

Similar to I need help making a recursive Koch snowflake. Im using python. I ne.pdf

Know more processing

YukiAizawa1

Proga 0608

Atsushi Tadokoro

Processing and Processing.js

jeresig

Introduction to graphics programming in c

baabtra.com - No. 1 supplier of quality freshers

HTML5 Canvas

Robyn Overstreet

Proga 0601

Atsushi Tadokoro

Exploring Canvas

Kevin Hoyt

FITC events. For digital creators. Save 10% off ANY FITC event with discount code 'slideshare' See our upcoming events at www.fitc.ca An Intro To ES6 with Grant Skinner OVERVIEW ECMAScript 6 is the approved and published standard for the next version of JavaScript. It offers new syntax and language features that provide new ways of tackling coding problems, and increase your productivity. This session will introduce ES6 and delve into many of the new features of the language. It will also cover real-world use, including transpilers, runtimes, and browser support. OBJECTIVE Create confidence in evaluating and getting started using ES6. TARGET AUDIENCE JavaScript developers. ASSUMED AUDIENCE KNOWLEDGE JavaScript. FOUR THINGS AUDIENCE MEMBERS WILL LEARN Status of ES6 How to get started with ES6 ES6 feature overview Practical considerations for adopting ES6

An Intro To ES6

FITC

wavelet decomposition process code in matlab??? Solution WAVELET DECOMPOSITION PROCESS :- function [coef,scf]=mywavedec2(x,N, wname) coef={cA_N;cV_N;cH_N;cD_N;cV_N-1;cH_N-1;cD_N-1;… …;cV_1;cH_1;cD_1} [Lo_D,Hi_D] = wfilters(wname,\'d\'); lf=length(Lo_D); imshow(x);title(\'Original Image\'); [r,c]=size(x); xlabel([\'Size : \',num2str(r),\'*\',num2str(c)]); xd=double(x); [rx,cx]=size(x); [o2sa,f1sa,rsx]=sizcoef([rx,cx],lf,N); a=[o2sa,f1sa,rsx] coef=[]; scf=[rx,cx]; for i=1:N [cA,cV,cH,cD]=mydwt2(xd,Lo_D,Hi_D); xd=cA; outmp={cV;cH;cD}; scf=[size(cV);scf]; coef=[outmp;coef]; end coef=[cA;coef]; scf=[size(cA);scf]; plotcoef(N,wname,coef); subplot(N+1,3,2); yt=uint8(coef{1}); [yrow,ycol]=size(yt); imshow(yt);title( [\'Approximation A\',num2str(N)]); xlabel([\'Size : \',num2str(yrow),\'*\',num2str(ycol)]); titllist={[\'Vertical Detail V\'];[\'Horizontal Detail H\']; [\'Diagonal Detail D\']}; pn=2; for pr=1:N for pc=1:3 subplot(N+1,3,pn+2); yt=[ ]; yt=uint8(coef{pn}); [yrow,ycol]=size(yt); imshow(yt);title([ titllist{pc},num2str(N-pr+1)]); xlabel([\'Size : \',num2str(yrow),\'*\',num2str(ycol)]); if mod(pn+2,3)==1 ylabel([\'Level \',num2str(N-pr+1)]); end pn=pn+1; end end function [o2sa,f1sa,rsx]=sizcoef(sx,lf,N)^4 o2sa=sx; f1sa=[0 0]; osx=sx; for i=1:N ot=osx+lf-1; sa=floor(ot/2); o2sa=[o2sa;ot]; f1sa=[f1sa;sa]; osx=sa; end rsx=zeros(N+1,2); rsx(1,:)=sx; addln=0; for j=2:N+1 aln=floor((addln+lf-1)/2); tsx=f1sa(j,:)-aln; rsx(j,:)=tsx; addln=aln; end function y=downspl(x) N=length(x); M=floor(N/2); i=1:M; y(i)=x(2*i).

wavelet decomposition process code in matlabSolution WAVE.pdf

brijeshagarwa329898l

Intro to HTML5 Canvas

Proga 090525

PBL1-v1-013e.pptx

ES6 PPT FOR 2016

ES6 is Nigh

NewTetrisScore.cppNewTetrisScore.cpp newTetris.cpp Defines t.docx

curwenmichaela

2Bytesprog2 course_2014_c9_graph

kinan keshkeh

Building a Visualization Language

jeresig

COMPAPPABCA49085rFunrAP__Practical Number 9 & 10.docx

TashiBhutia12

Computer graphics

snelkoli

Internal workshop es6_2015

Miguel Ruiz Rodriguez

Similar to I need help making a recursive Koch snowflake. Im using python. I ne.pdf (20)

Know more processing

Proga 0608

Processing and Processing.js

Introduction to graphics programming in c

HTML5 Canvas

Proga 0601

Exploring Canvas

An Intro To ES6

wavelet decomposition process code in matlabSolution WAVE.pdf

Intro to HTML5 Canvas

Proga 090525

PBL1-v1-013e.pptx

ES6 PPT FOR 2016

ES6 is Nigh

NewTetrisScore.cppNewTetrisScore.cpp newTetris.cpp Defines t.docx

2Bytesprog2 course_2014_c9_graph

Building a Visualization Language

COMPAPPABCA49085rFunrAP__Practical Number 9 & 10.docx

Computer graphics

Internal workshop es6_2015

More from kostikjaylonshaewe47

Which of the following organisms are similar to amoeboids in their locomotion? Euglena Flagellates Foraminiferan Paramecia Solution Euglena is a protist and it contains a flagellum and moves through it. Flagellates have the locomotary organs flagella. Paramecia contain cilia all over their body surface. The move through beating of cilia. Foraminiferans are protozoans that exhibit streaming movements like amoeba to capture food through granular cytoplasm and the external shells. Option 3 is correct..

Which of the following organisms are similar to amoeboids in their lo.pdf

kostikjaylonshaewe47

Which of the following are true? More than one answer may be correct. Flowers of Rhizanthes infanticida resemble rotting meat in both smell and appearance to attract their primary pollinator, the blowfly. Hydnora triceps, a parasitic plant of the Democratic Republic of the Congo, catches small insects, birds, mammals, and amphibiams in its pitcher shaped flower, high up in the camopy of the rainforest. Mistletoe seedlings germinate in the soil as a response to nearby trees, and use viscin covered roots to slowly climb trees. Root parasites find hosts through a reciprocal exchange of chemical signals that diffuse through the soil. Parasitism has arisen many times during the evolution of plants. Mistletoes find their hosts by tracking gases emitted by the host and growing toward them. Parasitism is an ecological relationship between organisms in which one organism (the parasite) kills the other (the host). Parasites exhibit a wide range of dependency on host plants, from the hemiparasites, which are photosynthetic to the holoparasites, which must obtain all nutrients from host plants. While parasitism in plants represents an interesting scientific subject, parasitic plants have little impact on human lives. Movement of nutrients from host to parasite is achieved by two primary mechanisms: transpiration and an osmotic gradient. Flowers of Rhizanthes infanticida resemble rotting meat in both smell and appearance to attract their primary pollinator, the blowfly. Hydnora triceps, a parasitic plant of the Democratic Republic of the Congo, catches small insects, birds, mammals, and amphibiams in its pitcher shaped flower, high up in the camopy of the rainforest. Mistletoe seedlings germinate in the soil as a response to nearby trees, and use viscin covered roots to slowly climb trees. Root parasites find hosts through a reciprocal exchange of chemical signals that diffuse through the soil. Parasitism has arisen many times during the evolution of plants. Mistletoes find their hosts by tracking gases emitted by the host and growing toward them. Parasitism is an ecological relationship between organisms in which one organism (the parasite) kills the other (the host). Parasites exhibit a wide range of dependency on host plants, from the hemiparasites, which are photosynthetic to the holoparasites, which must obtain all nutrients from host plants. While parasitism in plants represents an interesting scientific subject, parasitic plants have little impact on human lives. Movement of nutrients from host to parasite is achieved by two primary mechanisms: transpiration and an osmotic gradient. Solution True Flowers of Rhizanthes infanticida resemble rotting meat in both smell and appearance to attract their primary pollinator, the blowfly. False Hydnora triceps, a parasitic plant of the Democratic Republic of the Congo, catches small insects, birds, mammals, and amphibiams in its pitcher shaped flower, high up in the camopy of the rainforest-Native of Africa .

Which of the following are true More than one answer may be correct.pdf

kostikjaylonshaewe47

What was the Noble Prize winning advance that saved the magnetic recording industry and led to major advances in the personal music device industry? Solution In 1887, Heinrich Hertz discovered that electrodes illuminated with ultraviolet light create electric sparks more easily. In 1905 Albert Einstein published a paper that explained experimental data from the photoelectric effect as the result of light energy being carried in discrete quantized packets. This discovery led to the quantum revolution. In 1914, Robert Millikan\'s experiment confirmed Einstein\'s law on photoelectric effect. Einstein was awarded the Nobel Prize in 1921 for \"his discovery of the law of the photoelectric effect\",and Millikan was awarded the Nobel Prize in 1923 for \"his work on the elementary charge of electricity and on the photoelectric effect\". In magnetic tape recording, the sound waves vibrate the microphone diaphragm and are converted into a varying electric current, which is then converted to a varying magnetic field by an electromagnet, which makes a representation of the sound as magnetized areas on a plastic tape with a magnetic coating on it. Analog sound reproduction is the reverse process, with a bigger loudspeaker diaphragm causing changes to atmospheric pressure to form acoustic sound waves. Electronically generated sound waves may also be recorded directly from devices such as an electric guitar pickup or a synthesizer, without the use of acoustics in the recording process other than the need for musicians to hear how well they are playing during recording sessions..

What was the Noble Prize winning advance that saved the magnetic rec.pdf

kostikjaylonshaewe47

What is difference between the Tariff and tax Solution Difference between Tax and Tariff:- Tax is a compulsory payment made by an individual, household or a firm to the government without reference to anything in return. In other words, Tax is a legally compulsory payment imposed on the people by the government. Tariff is a tax imposed on imported goods and services. They are to increase the price of imported goods and services and thereby restrict the trade. Conclusion:-Taxes are collected internally whereas Tariffs are collected on import of goods and services..

What is difference between the Tariff and tax SolutionDifferen.pdf

kostikjaylonshaewe47

What are the most likely point in nutrient media preparation or later at which contamination may be introduced? What signs would indicate contamination? What is the source of the following elements in nutrient media prepared? (See Medium Recipes pg.20 of Microbiology Laboratory Theory & Applications) Carbon? Nitrogen? What are the two types of nutrient media prepared in BIQL3200L? Solution Most likely points of contamination introduction in nutrient media Signs of contamination. Since the media contents are not provided in the question , I will give you the general sources. Sources of Carbon is the Glucose, glycerol, tryptone soy, casein soy digest, beef extract, potato dextrose…etc Sources of Nitrogen is Yeast extract, NH4Cl, Beef extract..etc.

What are the most likely point in nutrient media preparation or later.pdf

kostikjaylonshaewe47

Toss a fair coin three times. Let X denote the number of heads in first two tosses and Y denote the number of heads in last two tosses. Calculate E(X), E(Y). Solution Tossing a fair coin three times is then the outcomes are {(H,H,H),(H,H,T),(H,T,H),(H,T,T),(T,H,T),(T,H,H,),(T,T,H),(T,T,T)}. Here X denote the number of heads in first two tosses are 2 and Y denote the number of heads in last two tosses are 2. E(X)=2/8=.25, E(Y)=2/8=.25..

Toss a fair coin three times. Let X denote the number of heads in fi.pdf

kostikjaylonshaewe47

TIA-569 lists six different areas or spaces where cabling is run. List these and briefly define each one. Solution Structured cabling falls into six subsystems: TIA-569 The purpose of this Standard is to standardize specific pathway and space design and construction practices in support of telecommunications media and equipment within buildings.Its scope is limited to telecommunications aspect of building design but influences design of other building services also (i.e. HVAC, electrical power, etc). Define requirements for key spaces : Building Spaces: Access & Service Provider Spaces: Building Pathways: Multitenant Building Spaces: For more detailed but brief information refer this link: https://www.bicsi.org/uploadedFiles/BICSI_Website/Global_Community/Presentations/Caribbea n/TIA-569UpdateOverview.pdf.

TIA-569 lists six different areas or spaces where cabling is run. Li.pdf

kostikjaylonshaewe47

This is a c++ binary search program I worked so far but still cant get it right. Can anyone help me? Big thanks!! the client should not be modified /* *File: client.cpp *Author: Yingwu Zhu *Warning: do not change this file and use it as is. *Last Modififcation: 10/21/2016 */ #include #include #include #include #include #include \"bst.h\" using namespace std; int main(int argc, char* argv[]) { if (argc != 2) { cout << \"Format: \" << argv[0] << \" [data file]\" << endl; return 0; } ifstream fin(argv[1]); int cases; fin >> cases; int passed = 0; for (int i = 1; i <= cases; i++) { cout << \"Checking test case #\" << i << \" ... \"; BST T; set S; int n, x; fin >> n; bool ok = true; vector tmp; int rem = 0; for (int j = 0; j < n; j++) { fin >> x; T.Insert(x); S.insert(x); ok &= (T.Search(x) && T.RecurSearch(x)); if (tmp.empty()) tmp.push_back(x); if (rand()%10 < 3) { T.Erase(tmp[0]); S.erase(tmp[0]); ok &= (T.Search(tmp[0]) == false); tmp.pop_back(); rem++; } } if (rem ok &= (T.MaxElement() == *S.rbegin()); while (!S.empty() && !T.Empty()) { int x = T.MinElement(); ok &= (x == *S.begin()); T.Erase(x); S.erase(S.begin()); } cout << (ok ? \"Passed!\" : \"Failed\") << endl; passed += ok; } cout << passed << \" of \" << cases << \" test cases have passed!\ \"; if (passed == cases) cout << endl << \"Congratulations! Good to Submit Your Code\ \"; else if ((double)passed/cases >= 0.95) cout << endl << \"You are almost there, but need to fix some bugs.\ \"; else cout << endl << \"Your code needs a lot of fixes for submission\ \"; return 0; } ===================================================================== ======= //bst.h #ifndef _BST_H_ #define _BST_H_ #include using namespace std; class BST { private: class Node { public: int data; Node* left; Node* right; }; Node* root; //root node pointer //you may add your auxiliary functions here! public: BST(); //constructor ~BST(); //destructor bool Empty() const; void Insert(int val); int MinElement() const; int MaxElement() const; bool Search(int val) const; bool RecurSearch(int val) const; void Erase(int val); }; #endif ===================================================================== ======= /* bst.cpp Subject: Binary Seach Tree Modification Time:10/26/2016 */ #include #include\"bst.h\" using namespace std; BST::BST(){ root= NULL; } BST::~BST(){ delete root; delete root->left; delete root->right; } bool BST::Empty() const { return data; } void BST::Insert(int val){ Node* p= new Node; p->data= val; Node* cur = root; if(val < cur->data){ cur = cur -> left; } else{ right->next=val; } } int BST::MinElement() const { Node* cur; while(cur->left != NULL){ cur = cur->left; } return(cur->data); } int BST::MaxElement() const{ if(root==NULL){ return 0; } if(root->left>root->data){ root->data=root->right; } else if(root->right>root->data){ root->data=root->right; } return root->data; } bool BST:: Search(int val) const{ Node* cur; cur = root; while(cur!=NULL){ if(cur->data == val){ return true; } else if(cur->data .

This is a c++ binary search program I worked so far but still cant g.pdf

kostikjaylonshaewe47

There are two large plants in the authors’ yard: a yucca tree and an enormous prickly pear cactus. Both have rough, scaly bark, but it is known that these plants are not closely related. (a) What are two different explanations for the similarity of the bark? (b) It is also known that yuccas are descended from a grass species instead of a tree species. Which of the two explanations given in part a is consistent with this fact? Solution A) Two different explanations for the similarity in bark i) yucca plants adapt to the environment that they live in. Depending on the type of environment, the yucca plants develop fleshy thick leaves for deserts. They also adapt to the mountains, coastal sands, grasslands and prairies. ii) there are some yuccas which are also common to the southwest desert scene. They have similar characteristics like the traditional cactus. There is a high chance that the yucca present in the author\'s yard is a desert origin yucca, thus a similarity in the bark. Yucca filamentosa , which is the grass species of yucca is more found in the desert environment than the other species of yucca. The second explanation for the similarity in bark is more consistent in this case with the variation in species ..

There are two large plants in the authors’ yard a yucca tree and an.pdf

kostikjaylonshaewe47

The seaport town of New Monopoly has become extremely popular with shipping companies due to its superior location. The port has become so congested that ships must wait hours every day just to dock. This is an example of The major of New Monopoly realizes that the congestion at the port costs the shipping companies and its town money. Which decision would NOT move him towards a command economy? Solution ans 1 b) private good as por is congested so it is rival and exclusive in use that\'s why port is private good ans 2 b) The mayor decides to let individual firms and consumers find a solution for the excessive wait time. this decision would not move him towards a command economy because this means giving individual firms and consumers power to decide about solution themselves which means mayor is not using his dominating power of command economy.

The seaport town of New Monopoly has become extremely popular with sh.pdf

kostikjaylonshaewe47

The figure below shows a series of SNP loci (A-O) loci for two strains of mice (Houston in blue, Dallas in red).Which locus would not be useful in mapping novel mutations? G H I J K A A BBC C D D E E F F G G H H I I J J K K M M N N O O Solution Ans: In the above gel pictureloci for two strains of mice (Houston in blue, Dallas in red) is given. Among the loci A-O, K locus is not useful in mapping novel mutations..

The figure below shows a series of SNP loci (A-O) loci for two strai.pdf

kostikjaylonshaewe47

The climatic stability hypothesis for the change in biodiversity with latitude states that: more stable climates will lead to lower biodiversity due to broad niches for individual species less stable climates leads to lower biodiversity due to the inability of many species to adapt to climatic variation more stable climates in the tropics provide greater solar energy to support biodiversity more stable climates in the tropics in greater rates of thereby enhancing biodiversity. Solution Less stable climate leads to lower biodiversity due to the inability of many species to adapt to climatic variation..

The climatic stability hypothesis for the change in biodiversity with.pdf

kostikjaylonshaewe47

Table 14.2 Primitive and Advanced Features of Nonvascular Plants as They Relate to Adaptat o Land features ACdeanced features Table 14.3 Primitive and Advanced Features of Seedless Vascula Plants as They Relate to Ada ation to Land Table 14.4-Structures and Functions of the Nonvascular Plants and Seedless Vascular Plants function Sporophyte/Gametophyte Example structure Archegonium Solution primitive and advanced features of non vascular plants for land adaptation. Primitive features: 1. Lack of proper vascular tissue . 2. gametpohyte is being dominant phase of life cycle. 3.sporophyte is dependent on the gametophyte. Advanced features: 1.Development of cuticle to avoid water loss through transpiration. 2. Sporophyte being erect. 3. Development of multicellular gametangia and complex embryonic development. primitive and advanced features of vascular plants for land adaptation. Primitive features: 1.Gametophyte is small , independent, lacks vascular tissue,cuticle,photosynthetic, found in moist shady habitats ,dispersal by spores. 2. sperms are motile and require water for fertilization . advanced features.: 1. Well developed photosynthetic sporophyte representing dominant phase of the life cycle. 2.plant well differentiated into aerial stem, leaves and underground roots. 3.Sporophyte has waxy cuticle , stomata and bears leaves or fronds as in ferns. 4.Development of vigorous rhizome for vegetative propagation..

Table 14.2 Primitive and Advanced Features of Nonvascular Plants as T.pdf

kostikjaylonshaewe47

Solar energy is channeled by molecular vibration from... to the ..pdf

kostikjaylonshaewe47

report “Rabbits and Wolves”Discuss the changes in parameters and how they affected the population growth curves for each organism (be sure to mention particular changes in the graphs and ending populations). Think about how this simulation could apply to the real world. What other factors or variables would have to be included. What if humans were added as a fourth organism, how would they affect this simulation? Also, do you think that a computer model is a useful tool to science? More precisely do you think there are times when such a model is useful and when such a model is not useful? Be sure to start your discussion with a statement of objectives - I have listed objectives above, write and state if you think you obtained the objectives and explain why or why not. There is absolutely no penalty for thinking that you didn\'t complete one of the objectives. Solution Ans.) To understand the different models that are used to represent population dynamics, first understand the general equation for the population growth rate (it is the change in number of individuals in a population over time): dT/dN=rN In this equation, T = growth rate of the population NNN = population size TTT = time rrr = per capita rate of increase (that is, how quickly the population grows per individual already in the population). The equation above is very general, and we can make more specific forms of it to describe two different kinds of growth models: exponential and logistic. A positive growth rate implies that the population is increasing, whereas a negative growth rate shows that the population is reducing. A growth ratio of zero indicates that there is a balance i.e. that there were the same number of organisms at the beginning and end of the particular time period. Sometimes, growth rate may be zero even when there are significant changes in the birth rates, death rates, immigration rates and age distribution between the two times period. Situation which includes exponential development, different age-independent density variable influencing survival, three influencing fertility. The one function meeting the presumptions of the calculated model delivered a strategic development bend typifying the right values or rm and K. The others created sigmoid bends to which self-assertive strategic bends could be fitted with differing achievement. In view of population time slacks, two of the capacities influencing fruitfulness created overshoots and damped motions amid the underlying way to deal with the enduring state. The other factors or variables would have been included in the given situation would be the climate condition. In my opinion computer model is a useful and informative tool in analyzing the population growth curves of any organism. In most of the cases, the computer model for population growth studies is logical..

report “Rabbits and Wolves”Discuss the changes in parameters and how.pdf

kostikjaylonshaewe47

prove thisSolutionSuppose that A is a product of element.pdf

kostikjaylonshaewe47

Our task this week is to diagnose patients who come in with various symptoms. We\'ll use the following random variables: F: The patient has the flu S: The patient has strep V: The patient has a fever T: The patient has a sore throat C: The patient has a cough The flu may cause a fever and/or a cough. Strep may cause a sore throat and/or a fever. Question 1: Using the following Bayes network as our model, which of the following statements are true and explain why?T C | V ? Solution Since the statements The following conditions are true. T V | S T C | S S F | V.

Our task this week is to diagnose patients who come in with various .pdf

kostikjaylonshaewe47

number of lines should be included in the last page of the paper after References. Assessment- Marks will be awarded for compliance with format specifications, organization and use of proper section headings and content. Warning- While you are free to source and use materials from the Internet, you must not copy these works verbatim. In addition you must not copy your classmate\'s work. The penalty for copying for the offender and the author of the copied work is severe. Protect your paper from plagiarism . Investigate modern Digital Satellite Communications Systems. Satellite communication systems are used to relay radio transmissions between earth terminals. A typical operational link involves an active satellite and two or more earth terminals. One station transmits to the satellite on a frequency called the UP-LINK frequency. The Saellite then amplifies the signal, converts it to the DOWN-LINK frequency, and transmits it back to earth. Your paper titled Digital Satellite Communication Systems should conform to the specifications and format gixen below Specifications and Format: Reference Report Size Paper Font CSC422/2015-16 Not less than 3500 words and not more than 4000 A4 Times New Roman, (Title: Size 14, Heading: Size 13, Sub heading: Size 12, Text: Size 9) Heading Frt Single Column Center Justification Title on a new Line Name on a new line Address on a new line Reference on a new line Double Column, ruil Justitication Left2o5m. Right2.5cm. Top 2.5cm and Bottom 2.5cm Single Page Format Page Margin Line Spacing A sample of the heading is shown below Digital Satellite Communication Systems by Kaxade Adeleke Matriculation Number 120805012) Department ofCompuer Sciences Uhiversity of Lagas (Ref CSC422/2014- 15) Your paper should have the following headings: Abstract, Introduction, Other Sections, Conclusion, References and Document Statistics. Do not use a separate page for your title. The coverage of the topic with well thought sections carries the bulk of awarded marks. Therefore, organize your sections carefully for maximum coverage of topic and good effect Document statistics - Word count, number of pages, number of paragraphs and Solution ANSWER-A communicaton satellite is an artificial satellite that relays and amplifies radio telecommunications signals via a transponder; it creates acommunication channel between a source transmitter and a receiver at different locations on Earth. Communications satellites are used for television, telephone, radio, internet, and military applications. There are over 2,000 communications satellites in Earth’s orbit, used by both private and government organizationsWireless communication uses electromagnetic waves to carry signals. These waves require line-of-sight, and are thus obstructed by the curvature of the Earth. The purpose of communications satellites is to relay the signal around the curve of the Earth allowing communication between widely separated points.[2] Communications satellites use .

number of lines should be included in the last page of the paper aft.pdf

kostikjaylonshaewe47

Modify the code below so that two separate listener classes are used - one for each of the two buttons. public class LettRight Panel extends JPanel {private JButton left, right; private JLabel label; public LeftRightPanel () {left = new JButton (\"Left\"); right = new JButton (\"Right\"); label = new JLabel(\"Left/Right\"); ButtonListener listener = new ButtonListener(); left.addActionListener (listener); right.addActionLiatener (listener); add (left); add (right); add (label);} private class ButtonListener implements ActionListener public void actionPerformed (ActionEvent event) {if (event.getSource() == left) label.setText(\"Left\"); else label.setText(\"Right\");}}} Solution Hi, I have modifief the code and highlighted the code changes below. LeftRightPanel.java import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import javax.swing.JButton; import javax.swing.JLabel; import javax.swing.JPanel; public class LeftRightPanel extends JPanel{ private JButton left, right; private JLabel label; public LeftRightPanel(){ left = new JButton(\"Left\"); right = new JButton(\"Right\"); label = new JLabel(\"Left/Right\"); LeftButtonListener leftListener = new LeftButtonListener(); RightButtonListener rightListener = new RightButtonListener(); left.addActionListener(leftListener); right.addActionListener(rightListener); add(left); add(right); add(label); } private class LeftButtonListener implements ActionListener{ public void actionPerformed(ActionEvent e) { label.setText(\"Left\"); } } private class RightButtonListener implements ActionListener{ public void actionPerformed(ActionEvent e) { label.setText(\"Right\"); } } }.

Modify the code below so that two separate listener classes are used .pdf

kostikjaylonshaewe47

Lie detector tests are notoriously flawed. Assume that a particular .pdf

kostikjaylonshaewe47

More from kostikjaylonshaewe47 (20)