Complete a Punnett square to show the genotypes and phenotypes expected for the following cross: heterozygous tall x heterozygous tall Solution Here is a single trait Punnett Square which tracks two alleles for each parent. The square has two rows and two columns. since both the parents are heterozygous for the trait (Hh); out of the 4 progeny; 1 would be homozygous dominant (HH, tall), one would be homozygous recessive (hh, short) and the other two would be heterzygous (Hh, tall) Hh X Hh HH (Homozygous dominant: Tall) Hh (Heterozygous: Tall) Hh (Heterozygous: Tall) hh (Homozygous Recessive: Short) . HH (Homozygous dominant: Tall) Hh (Heterozygous: Tall) Hh (Heterozygous: Tall) hh (Homozygous Recessive: Short).