This is the last homework problem i\'m having trouble with. Can anyone help me and explain what to do. i cannot seem to get it right. Thank you so much for the help!! (The 17\'s are not correct, i just put them is as placeholders!!!)*** Solution 2pr = x where r is the radius of the circle. r = x/2p Area of the circle = p (x/2p)2 = x2/4p. 4l = 17-x where l is the length of the side of the square. l = (17-x)/4 Area of the square = l2 Net area = (17-x)2/16 total area = x2/4p + (17-x)2/16 A(x) = x2/4p + (17-x)2/16 A\'(x) = x/2p + [-(17-x)/8] A\'(x) = 0, x/2p + [-(17-x)/8] = 0 8x - 2p(17-x) = 0 8x + 2px - 34p = 0 x = 34p/(8+2p) = 17p/(4+p). The wire should be cut so that 7.476 feet are used for the circle and 9.524 feet are used for the square. The radius of the circle = 1.190 feet Each side of the square = 2.381 feet.