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Trig Ratios & Unit Circle
Using Pyth

On unit circle
This is true for
on the unit circle

Ex. Is the point (2, 1/2) on the unit circle?
Coordinates of Points on Unit Circle
cos

=x=x=x
=y=y=y
r 1

Conclusion: For all points on the unit circle, since
r = 1, we can replace cos with x and sin with y
) represent any point on the unit circle
and has the coordinates (cos , sin )
SO, P( ) = (cos , sin )
How about, tan = y = sin
x cos
This is summarized in CAST rule

In which quadrant does the terminal arm of
a) sin < 0 and tan > 0
b) cos < 0 and tan < 0

lie if:
Finding P( ) on Unit Circle
If given a point with coordinates (5, 12),
how do you find the corresponding point
on the unit circle, ie, P( ) ?

If sin

=

Find tan

and

cos

=
If cos =

Given sin =

, find sin

and tan < 0, find cos.
3 New Reciprocal Trig
Ratios or Functions
= sec =

1 = 1 = r
cos
x
x
r

cosecant = csc =

1 = 1 = r
sin
y
y
r

cotangent = cot = cos

CAST still applies
Give 6 trig ratios over (0, ) if sin = 3
5
Day 5 examples u2w14

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Day 5 examples u2w14

  • 1. Trig Ratios & Unit Circle Using Pyth On unit circle This is true for on the unit circle Ex. Is the point (2, 1/2) on the unit circle?
  • 2. Coordinates of Points on Unit Circle cos =x=x=x =y=y=y r 1 Conclusion: For all points on the unit circle, since r = 1, we can replace cos with x and sin with y
  • 3. ) represent any point on the unit circle and has the coordinates (cos , sin ) SO, P( ) = (cos , sin ) How about, tan = y = sin x cos
  • 4. This is summarized in CAST rule In which quadrant does the terminal arm of a) sin < 0 and tan > 0 b) cos < 0 and tan < 0 lie if:
  • 5. Finding P( ) on Unit Circle If given a point with coordinates (5, 12), how do you find the corresponding point on the unit circle, ie, P( ) ? If sin = Find tan and cos =
  • 6. If cos = Given sin = , find sin and tan < 0, find cos.
  • 7. 3 New Reciprocal Trig Ratios or Functions = sec = 1 = 1 = r cos x x r cosecant = csc = 1 = 1 = r sin y y r cotangent = cot = cos CAST still applies Give 6 trig ratios over (0, ) if sin = 3 5