SlideShare a Scribd company logo
1 of 31
Download to read offline
Logarithms
Prepared by
Ismail Mohammad El-Badawy
ismailelbadawy@gmail.com
Logarithmic and exponential forms
• Log 2 8
• Log 3 81
• Log 6 36
2 to the power of ?? gives 8
3 to the power of ?? gives 81
6 to the power of ?? gives 36
What is the base 2 logarithm of 8 ?
What is the base 3 logarithm of 81?
What is the base 6 logarithm of 36?
Logarithmic and exponential forms
• Log 2 8 = 3 23 = 8
• Log 3 81 = 4 34 = 81
• Log 6 36 = 2 62 = 36
2 to the power of 3 gives 8
3 to the power of 4 gives 81
6 to the power of 2 gives 36
What is the base 2 logarithm of 8 ? 3
What is the base 3 logarithm of 81? 4
What is the base 6 logarithm of 36? 2
Logarithmic and exponential forms
Note: The default value of
the base is 10.
e.g. Log (100) = 2
102 = 100
• Find the value of a :
• Log 4 𝑎 = 3
• Log 2 𝑎 = 5
• Log 5 𝑎 = 4
The argument is unknown
• Find the value of a :
• Log 4 𝑎 = 3
✓ 43
= 𝑎 ∴ 𝑎 = 64
• Log 2 𝑎 = 5
✓ 25
= 𝑎 ∴ 𝑎 = 32
• Log 5 𝑎 = 4
✓ 54 = 𝑎 ∴ 𝑎 = 625
The argument is unknown
Check your answers
𝐿𝑜𝑔4 64 =
𝐿𝑜𝑔 64
𝐿𝑜𝑔 4
𝐿𝑜𝑔2 32 =
𝐿𝑜𝑔 32
𝐿𝑜𝑔 2
𝐿𝑜𝑔5 625 =
𝐿𝑜𝑔 625
𝐿𝑜𝑔 5
• Find the value of b :
• Log 𝑏 81 = 2
• Log 𝑏 243 = 5
• Log 𝑏 216 = 3
The base is unknown
• Find the value of b :
• Log 𝑏 81 = 2
✓ 𝑏2
= 81 → 𝑏2
= 92
∴ 𝑏 = 9
• Log 𝑏 243 = 5
✓ 𝑏5
= 243 → 𝑏5
= 35
∴ 𝑏 = 3
• Log 𝑏 216 = 3
✓ 𝑏3 = 216 → 𝑏3 = 63 ∴ 𝑏 = 6
The base is unknown
Check your answers
𝐿𝑜𝑔9 81 =
𝐿𝑜𝑔 81
𝐿𝑜𝑔 9
𝐿𝑜𝑔3 243 =
𝐿𝑜𝑔 243
𝐿𝑜𝑔 3
𝐿𝑜𝑔6 216 =
𝐿𝑜𝑔 216
𝐿𝑜𝑔 6
• Find the value of c :
• Log 3 81 = 𝑐
• Log 7 49 = 𝑐
• Log 5 125 = 𝑐
The exponent is unknown
• Find the value of c :
• Log 3 81 = 𝑐
✓ 3 𝑐
= 81 → 3 𝑐
= 34
∴ 𝑐 = 4
• Log 7 49 = 𝑐
✓ 7 𝑐 = 49 → 7 𝑐 = 72 ∴ 𝑐 = 2
• Log 5 125 = 𝑐
✓ 5 𝑐 = 125 → 5 𝑐 = 53 ∴ 𝑐 = 3
The exponent is unknown
Check your answers
𝐿𝑜𝑔3 81 =
𝐿𝑜𝑔 81
𝐿𝑜𝑔 3
𝐿𝑜𝑔7 49 =
𝐿𝑜𝑔 49
𝐿𝑜𝑔 7
𝐿𝑜𝑔5 125 =
𝐿𝑜𝑔 125
𝐿𝑜𝑔 5
• Find the value of x :
• Log 7 (2𝑥 − 5) = 3
• Log (𝑥2) = 4
• Log 5 3𝑥 = 1.6
• Find the value of x :
• Log 7 (2𝑥 − 5) = 3
✓ 73
= 2𝑥 − 5 → 343 = 2𝑥 − 5 ∴ 𝑥 = 343 + 5 ÷ 2 = 174
• Log (𝑥2) = 4
✓ 104
= 𝑥2
→ 10000 = 𝑥2
∴ 𝑥 = ± 10000 = ±100
• Log 5 3𝑥 = 1.6
✓ 51.6
= 3𝑥 → 13.1 = 3𝑥 ∴ 𝑥 = 13.1 ÷ 3 = 4.37
• Find the value of x :
• Log (𝑥−3) 5 = 0.5
• Log 2 16 = 7𝑥 − 3
• Find the value of x :
• Log (𝑥−3) 5 = 0.5
✓ (𝑥 − 3)0.5
= 5 → 𝑥 − 3 = 5
→ 𝑥 − 3 = 52
→ 𝑥 − 3 = 25 ∴ 𝑥 = 28
• Log 2 16 = 7𝑥 − 3
✓ 2(7𝑥−3)
= 16 → 2(7𝑥−3)
= 24
→ 7𝑥 − 3 = 4 ∴ 𝑥 = 1
• Log 4 4 = ? ?
• Log 3 1 = ? ?
• Log 6 ? ? = 1
• Log 5 ? ? = 0
• Log 2 12 = Log 2 3 + Log 2 ? ?
• Log 𝑥 (? ? ) = Log 𝑥 5 + Log 𝑥 𝑦
Rules of logs
• Log 4 4 = 1
• Log 3 1 = 0
• Log 6 6 = 1
• Log 5 1 = 0
• Log 2 12 = Log 2 3 + Log 2 4
• Log 𝑥 (5𝑦) = Log 𝑥 5 + Log 𝑥 𝑦
Rules of logs
• Log 3 25 = ? ? Log 3 5
• 4 Log 7 2 = Log 7 (? ? )
• Log 2 12 = Log 2 36 − Log 2 ? ?
• Log
??
??
= Log 𝑥 − Log 5𝑦
• Log 4
2
10
= −Log 4 (? ? )
• Log 3 25 =
Log 𝑥 (??)
Log 𝑥 (??)
Rules of logs
• Log 3 25 = 2 Log 3 5
• 4 Log 7 2 = Log 7 (16)
• Log 2 12 = Log 2 36 − Log 2 3
• Log
𝑥
5𝑦
= Log 𝑥 − Log 5𝑦
• Log 4
2
10
= −Log 4 (5)
• Log 3 25 =
Log 𝑥 (25)
Log 𝑥 (3)
Rules of logs
• Evaluate:
• Log 2
1
16
• Log 16 8 =
• Log 5 1
Using rules of Logs
• Evaluate:
• Log 2
1
16
✓ Log 2
1
16
= −Log 2 16 = −4
• Log 16 8
✓ Log 16 8 =
Log 2 8
Log 2 16
=
3
4
• Log 5 1 = 0
Using rules of Logs
• Evaluate:
• Log 5 3 − Log 5 75
• 2 Log 2 6 − Log 2 9
•
1
2
Log 10 4 + Log 10 50
Using rules of Logs
• Evaluate:
• Log 5 3 − Log 5 75
✓ Log 5
3
75
= Log 5
1
25
= −Log 5 25 = −2
• 2 Log 2 6 − Log 2 9
✓ Log 2 62 − Log 2 9 = Log 2 36 − Log 2 9 = Log 2
36
9
= Log 2 4 = 2
•
1
2
Log 10 4 + Log 10 50
✓ Log 10 40.5 + Log 10 50 = Log 10 2 + Log 10 50 = Log 10 2 × 50 = Log 10 100 = 2
Using rules of Logs
• Simplify the following logarithms:
• Log 10 + Log 2 − Log 4
•
1
2
Log 𝑥 − 3 Log y
•
1
3
Log 8 + 2 Log 4
Using rules of Logs
• Simplify the following logarithms:
• Log 10 + Log 2 − Log 4
✓ Log 10 × 2 − Log 4 = Log 20 − Log 4 = Log
20
4
= Log 5
•
1
2
Log 𝑥 − 3 Log y
✓ Log 𝑥 Τ1
2 − Log 𝑦3 = Log
𝑥
𝑦3
•
1
3
Log 8 + 2 Log 4 = Log 8 Τ1
3 + Log 42 = Log 2 + Log 16 = Log 2 × 16 = Log 32
Using rules of Logs
• The point P on the curve 𝑦 = 9 𝑥 has y-coordinate equal to 150. Use logarithms to find the
x-coordinate of P, correct to 3 significant figures.
Using rules of Logs
• The point P on the curve 𝑦 = 9 𝑥 has y-coordinate equal to 150. Use logarithms to find the
x-coordinate of P, correct to 3 significant figures.
✓ 150 = 9 𝑥 Log 150 = Log 9 𝑥
Log 150 = 𝑥 Log 9
∴ 𝑥 =
Log 150
Log 9
= Log9150 = 2.28
Using rules of Logs
• Given that Log 𝑥 5𝑦 + 1 − Log 𝑥 3 = 4, express y in terms of x.
Using rules of Logs
• Given that Log 𝑥 5𝑦 + 1 − Log 𝑥 3 = 4, express y in terms of x.
✓ Log 𝑥
5𝑦+1
3
= 4
𝑥4
=
5𝑦 + 1
3
3𝑥4
= 5𝑦 + 1
∴ 𝑦 =
3𝑥4 − 1
5
Using rules of Logs
• Use logarithms to solve the following equation, giving the value of x correct to 3 s.f:
• 7 𝑥
= 2 𝑥+1
Using rules of Logs
• Use logarithms to solve the following equation, giving the value of x correct to 3 s.f:
• 7 𝑥 = 2 𝑥+1
✓ Log 7 𝑥 = Log 2 𝑥+1 → 𝑥 Log 7 = 𝑥 + 1 Log 2
𝑥
𝑥+1
=
Log 2
Log 7
= 0.356
𝑥 = 𝑥 + 1 0.356 = 0.356𝑥 + 0.356
𝑥 − 0.356𝑥 = 0.356
0.644 𝑥 = 0.356
∴ 𝑥 = 0.356 ÷ 0.644 = 0.553
Using rules of Logs
Assignment

More Related Content

What's hot

Log summary & equations
Log summary & equationsLog summary & equations
Log summary & equationsrouwejan
 
Evaluating algebraic expression
Evaluating algebraic expressionEvaluating algebraic expression
Evaluating algebraic expressionMarites Ablay
 
Position and 3 d vectors amended
Position and 3 d vectors amendedPosition and 3 d vectors amended
Position and 3 d vectors amendedShaun Wilson
 
Evaluating Algebraic Expressions
Evaluating Algebraic ExpressionsEvaluating Algebraic Expressions
Evaluating Algebraic Expressionsbizarregirl
 
Number Theory Review Revised
Number Theory Review RevisedNumber Theory Review Revised
Number Theory Review Revisedrsriram
 
Calculus class one
Calculus class oneCalculus class one
Calculus class oneDanielAmutah
 
Exponential and logarithmic graphs
Exponential and logarithmic graphsExponential and logarithmic graphs
Exponential and logarithmic graphsShaun Wilson
 
Expresiones algebraicas de suma, resta y valor
Expresiones algebraicas de suma, resta y valorExpresiones algebraicas de suma, resta y valor
Expresiones algebraicas de suma, resta y valorTrapSounds
 

What's hot (17)

Counting sort
Counting sortCounting sort
Counting sort
 
Log summary & equations
Log summary & equationsLog summary & equations
Log summary & equations
 
Algoritmo Counting sort
Algoritmo Counting sortAlgoritmo Counting sort
Algoritmo Counting sort
 
Evaluating algebraic expression
Evaluating algebraic expressionEvaluating algebraic expression
Evaluating algebraic expression
 
Position and 3 d vectors amended
Position and 3 d vectors amendedPosition and 3 d vectors amended
Position and 3 d vectors amended
 
Evaluating Algebraic Expressions
Evaluating Algebraic ExpressionsEvaluating Algebraic Expressions
Evaluating Algebraic Expressions
 
Msm1 fl ch11_04
Msm1 fl ch11_04Msm1 fl ch11_04
Msm1 fl ch11_04
 
Number Theory Review Revised
Number Theory Review RevisedNumber Theory Review Revised
Number Theory Review Revised
 
Tricky log graphs
Tricky log graphsTricky log graphs
Tricky log graphs
 
Evaluate Algebraic Expressions
Evaluate Algebraic ExpressionsEvaluate Algebraic Expressions
Evaluate Algebraic Expressions
 
S 4
S 4S 4
S 4
 
Quick sort
Quick sortQuick sort
Quick sort
 
Calculus class one
Calculus class oneCalculus class one
Calculus class one
 
Exponential and logarithmic graphs
Exponential and logarithmic graphsExponential and logarithmic graphs
Exponential and logarithmic graphs
 
Algebra
AlgebraAlgebra
Algebra
 
Expresiones algebraicas de suma, resta y valor
Expresiones algebraicas de suma, resta y valorExpresiones algebraicas de suma, resta y valor
Expresiones algebraicas de suma, resta y valor
 
Order of Operations
Order of OperationsOrder of Operations
Order of Operations
 

Similar to Tutorial on Logarithms

Semana 26 logaritmos álgebra uni ccesa007
Semana 26 logaritmos álgebra uni ccesa007Semana 26 logaritmos álgebra uni ccesa007
Semana 26 logaritmos álgebra uni ccesa007Demetrio Ccesa Rayme
 
Algebra 2 06 Exponential and Logarithmic Functions 2.pptx
Algebra 2 06 Exponential and Logarithmic Functions 2.pptxAlgebra 2 06 Exponential and Logarithmic Functions 2.pptx
Algebra 2 06 Exponential and Logarithmic Functions 2.pptxPallaviGupta66118
 
Algebra 2 01-Systems of Linear Equations and Matrices (RW 2022).pptx
Algebra 2 01-Systems of Linear Equations and Matrices (RW 2022).pptxAlgebra 2 01-Systems of Linear Equations and Matrices (RW 2022).pptx
Algebra 2 01-Systems of Linear Equations and Matrices (RW 2022).pptxBivekRegmi1
 
5indiceslogarithms 120909011915-phpapp02
5indiceslogarithms 120909011915-phpapp025indiceslogarithms 120909011915-phpapp02
5indiceslogarithms 120909011915-phpapp02Sofia Mahmood
 
CVE 409 SERIES PART A.pdf
CVE 409 SERIES PART A.pdfCVE 409 SERIES PART A.pdf
CVE 409 SERIES PART A.pdfMaxWell507618
 
Precalculus 10 Sequences and Series.pptx
Precalculus 10 Sequences and Series.pptxPrecalculus 10 Sequences and Series.pptx
Precalculus 10 Sequences and Series.pptxDominicCaling
 
Dividing integers web
Dividing integers   webDividing integers   web
Dividing integers webbweldon
 
QUESTION 11. Find the limit.Does not exist-∞.docx
QUESTION 11. Find the limit.Does not exist-∞.docxQUESTION 11. Find the limit.Does not exist-∞.docx
QUESTION 11. Find the limit.Does not exist-∞.docxmakdul
 
Factoring Polynomials to find its zeros
Factoring Polynomials to find its zerosFactoring Polynomials to find its zeros
Factoring Polynomials to find its zerosDaisy933462
 
Factoring common monomial
Factoring common monomialFactoring common monomial
Factoring common monomialAjayQuines
 
Patterns, sequences and series
Patterns, sequences and seriesPatterns, sequences and series
Patterns, sequences and seriesVukile Xhego
 
Ejercicios resueltos
Ejercicios resueltosEjercicios resueltos
Ejercicios resueltossialalsi
 
Class 6 - Maths (Integers).pptx
Class 6 - Maths (Integers).pptxClass 6 - Maths (Integers).pptx
Class 6 - Maths (Integers).pptxSadiqHameed2
 
鳳山高級中學 B1 3 3---ans
鳳山高級中學   B1  3 3---ans鳳山高級中學   B1  3 3---ans
鳳山高級中學 B1 3 3---ans祥益 顏祥益
 

Similar to Tutorial on Logarithms (20)

Semana 26 logaritmos álgebra uni ccesa007
Semana 26 logaritmos álgebra uni ccesa007Semana 26 logaritmos álgebra uni ccesa007
Semana 26 logaritmos álgebra uni ccesa007
 
Algebra 2 06 Exponential and Logarithmic Functions 2.pptx
Algebra 2 06 Exponential and Logarithmic Functions 2.pptxAlgebra 2 06 Exponential and Logarithmic Functions 2.pptx
Algebra 2 06 Exponential and Logarithmic Functions 2.pptx
 
Logaritmos
LogaritmosLogaritmos
Logaritmos
 
Algebra 2 01-Systems of Linear Equations and Matrices (RW 2022).pptx
Algebra 2 01-Systems of Linear Equations and Matrices (RW 2022).pptxAlgebra 2 01-Systems of Linear Equations and Matrices (RW 2022).pptx
Algebra 2 01-Systems of Linear Equations and Matrices (RW 2022).pptx
 
8.4 logarithms1
8.4 logarithms18.4 logarithms1
8.4 logarithms1
 
5indiceslogarithms 120909011915-phpapp02
5indiceslogarithms 120909011915-phpapp025indiceslogarithms 120909011915-phpapp02
5indiceslogarithms 120909011915-phpapp02
 
Chapter 31 logarithms
Chapter 31 logarithmsChapter 31 logarithms
Chapter 31 logarithms
 
indice-ppt.ppt
indice-ppt.pptindice-ppt.ppt
indice-ppt.ppt
 
CVE 409 SERIES PART A.pdf
CVE 409 SERIES PART A.pdfCVE 409 SERIES PART A.pdf
CVE 409 SERIES PART A.pdf
 
Precalculus 10 Sequences and Series.pptx
Precalculus 10 Sequences and Series.pptxPrecalculus 10 Sequences and Series.pptx
Precalculus 10 Sequences and Series.pptx
 
Exponents and powers
Exponents and powersExponents and powers
Exponents and powers
 
Dividing integers web
Dividing integers   webDividing integers   web
Dividing integers web
 
QUESTION 11. Find the limit.Does not exist-∞.docx
QUESTION 11. Find the limit.Does not exist-∞.docxQUESTION 11. Find the limit.Does not exist-∞.docx
QUESTION 11. Find the limit.Does not exist-∞.docx
 
Factoring Polynomials to find its zeros
Factoring Polynomials to find its zerosFactoring Polynomials to find its zeros
Factoring Polynomials to find its zeros
 
Factoring common monomial
Factoring common monomialFactoring common monomial
Factoring common monomial
 
Patterns, sequences and series
Patterns, sequences and seriesPatterns, sequences and series
Patterns, sequences and series
 
Ejercicios resueltos
Ejercicios resueltosEjercicios resueltos
Ejercicios resueltos
 
Class 6 - Maths (Integers).pptx
Class 6 - Maths (Integers).pptxClass 6 - Maths (Integers).pptx
Class 6 - Maths (Integers).pptx
 
0404 ch 4 day 4
0404 ch 4 day 40404 ch 4 day 4
0404 ch 4 day 4
 
鳳山高級中學 B1 3 3---ans
鳳山高級中學   B1  3 3---ans鳳山高級中學   B1  3 3---ans
鳳山高級中學 B1 3 3---ans
 

Recently uploaded

Measures of Central Tendency: Mean, Median and Mode
Measures of Central Tendency: Mean, Median and ModeMeasures of Central Tendency: Mean, Median and Mode
Measures of Central Tendency: Mean, Median and ModeThiyagu K
 
Hybridoma Technology ( Production , Purification , and Application )
Hybridoma Technology  ( Production , Purification , and Application  ) Hybridoma Technology  ( Production , Purification , and Application  )
Hybridoma Technology ( Production , Purification , and Application ) Sakshi Ghasle
 
Paris 2024 Olympic Geographies - an activity
Paris 2024 Olympic Geographies - an activityParis 2024 Olympic Geographies - an activity
Paris 2024 Olympic Geographies - an activityGeoBlogs
 
A Critique of the Proposed National Education Policy Reform
A Critique of the Proposed National Education Policy ReformA Critique of the Proposed National Education Policy Reform
A Critique of the Proposed National Education Policy ReformChameera Dedduwage
 
Mastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory InspectionMastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory InspectionSafetyChain Software
 
Introduction to ArtificiaI Intelligence in Higher Education
Introduction to ArtificiaI Intelligence in Higher EducationIntroduction to ArtificiaI Intelligence in Higher Education
Introduction to ArtificiaI Intelligence in Higher Educationpboyjonauth
 
Introduction to AI in Higher Education_draft.pptx
Introduction to AI in Higher Education_draft.pptxIntroduction to AI in Higher Education_draft.pptx
Introduction to AI in Higher Education_draft.pptxpboyjonauth
 
Science 7 - LAND and SEA BREEZE and its Characteristics
Science 7 - LAND and SEA BREEZE and its CharacteristicsScience 7 - LAND and SEA BREEZE and its Characteristics
Science 7 - LAND and SEA BREEZE and its CharacteristicsKarinaGenton
 
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptxPOINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptxSayali Powar
 
Accessible design: Minimum effort, maximum impact
Accessible design: Minimum effort, maximum impactAccessible design: Minimum effort, maximum impact
Accessible design: Minimum effort, maximum impactdawncurless
 
BASLIQ CURRENT LOOKBOOK LOOKBOOK(1) (1).pdf
BASLIQ CURRENT LOOKBOOK  LOOKBOOK(1) (1).pdfBASLIQ CURRENT LOOKBOOK  LOOKBOOK(1) (1).pdf
BASLIQ CURRENT LOOKBOOK LOOKBOOK(1) (1).pdfSoniaTolstoy
 
Incoming and Outgoing Shipments in 1 STEP Using Odoo 17
Incoming and Outgoing Shipments in 1 STEP Using Odoo 17Incoming and Outgoing Shipments in 1 STEP Using Odoo 17
Incoming and Outgoing Shipments in 1 STEP Using Odoo 17Celine George
 
Q4-W6-Restating Informational Text Grade 3
Q4-W6-Restating Informational Text Grade 3Q4-W6-Restating Informational Text Grade 3
Q4-W6-Restating Informational Text Grade 3JemimahLaneBuaron
 
18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf
18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf
18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdfssuser54595a
 
The basics of sentences session 2pptx copy.pptx
The basics of sentences session 2pptx copy.pptxThe basics of sentences session 2pptx copy.pptx
The basics of sentences session 2pptx copy.pptxheathfieldcps1
 
The Most Excellent Way | 1 Corinthians 13
The Most Excellent Way | 1 Corinthians 13The Most Excellent Way | 1 Corinthians 13
The Most Excellent Way | 1 Corinthians 13Steve Thomason
 
APM Welcome, APM North West Network Conference, Synergies Across Sectors
APM Welcome, APM North West Network Conference, Synergies Across SectorsAPM Welcome, APM North West Network Conference, Synergies Across Sectors
APM Welcome, APM North West Network Conference, Synergies Across SectorsAssociation for Project Management
 
Solving Puzzles Benefits Everyone (English).pptx
Solving Puzzles Benefits Everyone (English).pptxSolving Puzzles Benefits Everyone (English).pptx
Solving Puzzles Benefits Everyone (English).pptxOH TEIK BIN
 

Recently uploaded (20)

Measures of Central Tendency: Mean, Median and Mode
Measures of Central Tendency: Mean, Median and ModeMeasures of Central Tendency: Mean, Median and Mode
Measures of Central Tendency: Mean, Median and Mode
 
Hybridoma Technology ( Production , Purification , and Application )
Hybridoma Technology  ( Production , Purification , and Application  ) Hybridoma Technology  ( Production , Purification , and Application  )
Hybridoma Technology ( Production , Purification , and Application )
 
Model Call Girl in Tilak Nagar Delhi reach out to us at 🔝9953056974🔝
Model Call Girl in Tilak Nagar Delhi reach out to us at 🔝9953056974🔝Model Call Girl in Tilak Nagar Delhi reach out to us at 🔝9953056974🔝
Model Call Girl in Tilak Nagar Delhi reach out to us at 🔝9953056974🔝
 
Paris 2024 Olympic Geographies - an activity
Paris 2024 Olympic Geographies - an activityParis 2024 Olympic Geographies - an activity
Paris 2024 Olympic Geographies - an activity
 
Staff of Color (SOC) Retention Efforts DDSD
Staff of Color (SOC) Retention Efforts DDSDStaff of Color (SOC) Retention Efforts DDSD
Staff of Color (SOC) Retention Efforts DDSD
 
A Critique of the Proposed National Education Policy Reform
A Critique of the Proposed National Education Policy ReformA Critique of the Proposed National Education Policy Reform
A Critique of the Proposed National Education Policy Reform
 
Mastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory InspectionMastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory Inspection
 
Introduction to ArtificiaI Intelligence in Higher Education
Introduction to ArtificiaI Intelligence in Higher EducationIntroduction to ArtificiaI Intelligence in Higher Education
Introduction to ArtificiaI Intelligence in Higher Education
 
Introduction to AI in Higher Education_draft.pptx
Introduction to AI in Higher Education_draft.pptxIntroduction to AI in Higher Education_draft.pptx
Introduction to AI in Higher Education_draft.pptx
 
Science 7 - LAND and SEA BREEZE and its Characteristics
Science 7 - LAND and SEA BREEZE and its CharacteristicsScience 7 - LAND and SEA BREEZE and its Characteristics
Science 7 - LAND and SEA BREEZE and its Characteristics
 
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptxPOINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
 
Accessible design: Minimum effort, maximum impact
Accessible design: Minimum effort, maximum impactAccessible design: Minimum effort, maximum impact
Accessible design: Minimum effort, maximum impact
 
BASLIQ CURRENT LOOKBOOK LOOKBOOK(1) (1).pdf
BASLIQ CURRENT LOOKBOOK  LOOKBOOK(1) (1).pdfBASLIQ CURRENT LOOKBOOK  LOOKBOOK(1) (1).pdf
BASLIQ CURRENT LOOKBOOK LOOKBOOK(1) (1).pdf
 
Incoming and Outgoing Shipments in 1 STEP Using Odoo 17
Incoming and Outgoing Shipments in 1 STEP Using Odoo 17Incoming and Outgoing Shipments in 1 STEP Using Odoo 17
Incoming and Outgoing Shipments in 1 STEP Using Odoo 17
 
Q4-W6-Restating Informational Text Grade 3
Q4-W6-Restating Informational Text Grade 3Q4-W6-Restating Informational Text Grade 3
Q4-W6-Restating Informational Text Grade 3
 
18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf
18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf
18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf
 
The basics of sentences session 2pptx copy.pptx
The basics of sentences session 2pptx copy.pptxThe basics of sentences session 2pptx copy.pptx
The basics of sentences session 2pptx copy.pptx
 
The Most Excellent Way | 1 Corinthians 13
The Most Excellent Way | 1 Corinthians 13The Most Excellent Way | 1 Corinthians 13
The Most Excellent Way | 1 Corinthians 13
 
APM Welcome, APM North West Network Conference, Synergies Across Sectors
APM Welcome, APM North West Network Conference, Synergies Across SectorsAPM Welcome, APM North West Network Conference, Synergies Across Sectors
APM Welcome, APM North West Network Conference, Synergies Across Sectors
 
Solving Puzzles Benefits Everyone (English).pptx
Solving Puzzles Benefits Everyone (English).pptxSolving Puzzles Benefits Everyone (English).pptx
Solving Puzzles Benefits Everyone (English).pptx
 

Tutorial on Logarithms

  • 1. Logarithms Prepared by Ismail Mohammad El-Badawy ismailelbadawy@gmail.com
  • 2. Logarithmic and exponential forms • Log 2 8 • Log 3 81 • Log 6 36 2 to the power of ?? gives 8 3 to the power of ?? gives 81 6 to the power of ?? gives 36 What is the base 2 logarithm of 8 ? What is the base 3 logarithm of 81? What is the base 6 logarithm of 36?
  • 3. Logarithmic and exponential forms • Log 2 8 = 3 23 = 8 • Log 3 81 = 4 34 = 81 • Log 6 36 = 2 62 = 36 2 to the power of 3 gives 8 3 to the power of 4 gives 81 6 to the power of 2 gives 36 What is the base 2 logarithm of 8 ? 3 What is the base 3 logarithm of 81? 4 What is the base 6 logarithm of 36? 2
  • 4. Logarithmic and exponential forms Note: The default value of the base is 10. e.g. Log (100) = 2 102 = 100
  • 5. • Find the value of a : • Log 4 𝑎 = 3 • Log 2 𝑎 = 5 • Log 5 𝑎 = 4 The argument is unknown
  • 6. • Find the value of a : • Log 4 𝑎 = 3 ✓ 43 = 𝑎 ∴ 𝑎 = 64 • Log 2 𝑎 = 5 ✓ 25 = 𝑎 ∴ 𝑎 = 32 • Log 5 𝑎 = 4 ✓ 54 = 𝑎 ∴ 𝑎 = 625 The argument is unknown Check your answers 𝐿𝑜𝑔4 64 = 𝐿𝑜𝑔 64 𝐿𝑜𝑔 4 𝐿𝑜𝑔2 32 = 𝐿𝑜𝑔 32 𝐿𝑜𝑔 2 𝐿𝑜𝑔5 625 = 𝐿𝑜𝑔 625 𝐿𝑜𝑔 5
  • 7. • Find the value of b : • Log 𝑏 81 = 2 • Log 𝑏 243 = 5 • Log 𝑏 216 = 3 The base is unknown
  • 8. • Find the value of b : • Log 𝑏 81 = 2 ✓ 𝑏2 = 81 → 𝑏2 = 92 ∴ 𝑏 = 9 • Log 𝑏 243 = 5 ✓ 𝑏5 = 243 → 𝑏5 = 35 ∴ 𝑏 = 3 • Log 𝑏 216 = 3 ✓ 𝑏3 = 216 → 𝑏3 = 63 ∴ 𝑏 = 6 The base is unknown Check your answers 𝐿𝑜𝑔9 81 = 𝐿𝑜𝑔 81 𝐿𝑜𝑔 9 𝐿𝑜𝑔3 243 = 𝐿𝑜𝑔 243 𝐿𝑜𝑔 3 𝐿𝑜𝑔6 216 = 𝐿𝑜𝑔 216 𝐿𝑜𝑔 6
  • 9. • Find the value of c : • Log 3 81 = 𝑐 • Log 7 49 = 𝑐 • Log 5 125 = 𝑐 The exponent is unknown
  • 10. • Find the value of c : • Log 3 81 = 𝑐 ✓ 3 𝑐 = 81 → 3 𝑐 = 34 ∴ 𝑐 = 4 • Log 7 49 = 𝑐 ✓ 7 𝑐 = 49 → 7 𝑐 = 72 ∴ 𝑐 = 2 • Log 5 125 = 𝑐 ✓ 5 𝑐 = 125 → 5 𝑐 = 53 ∴ 𝑐 = 3 The exponent is unknown Check your answers 𝐿𝑜𝑔3 81 = 𝐿𝑜𝑔 81 𝐿𝑜𝑔 3 𝐿𝑜𝑔7 49 = 𝐿𝑜𝑔 49 𝐿𝑜𝑔 7 𝐿𝑜𝑔5 125 = 𝐿𝑜𝑔 125 𝐿𝑜𝑔 5
  • 11. • Find the value of x : • Log 7 (2𝑥 − 5) = 3 • Log (𝑥2) = 4 • Log 5 3𝑥 = 1.6
  • 12. • Find the value of x : • Log 7 (2𝑥 − 5) = 3 ✓ 73 = 2𝑥 − 5 → 343 = 2𝑥 − 5 ∴ 𝑥 = 343 + 5 ÷ 2 = 174 • Log (𝑥2) = 4 ✓ 104 = 𝑥2 → 10000 = 𝑥2 ∴ 𝑥 = ± 10000 = ±100 • Log 5 3𝑥 = 1.6 ✓ 51.6 = 3𝑥 → 13.1 = 3𝑥 ∴ 𝑥 = 13.1 ÷ 3 = 4.37
  • 13. • Find the value of x : • Log (𝑥−3) 5 = 0.5 • Log 2 16 = 7𝑥 − 3
  • 14. • Find the value of x : • Log (𝑥−3) 5 = 0.5 ✓ (𝑥 − 3)0.5 = 5 → 𝑥 − 3 = 5 → 𝑥 − 3 = 52 → 𝑥 − 3 = 25 ∴ 𝑥 = 28 • Log 2 16 = 7𝑥 − 3 ✓ 2(7𝑥−3) = 16 → 2(7𝑥−3) = 24 → 7𝑥 − 3 = 4 ∴ 𝑥 = 1
  • 15. • Log 4 4 = ? ? • Log 3 1 = ? ? • Log 6 ? ? = 1 • Log 5 ? ? = 0 • Log 2 12 = Log 2 3 + Log 2 ? ? • Log 𝑥 (? ? ) = Log 𝑥 5 + Log 𝑥 𝑦 Rules of logs
  • 16. • Log 4 4 = 1 • Log 3 1 = 0 • Log 6 6 = 1 • Log 5 1 = 0 • Log 2 12 = Log 2 3 + Log 2 4 • Log 𝑥 (5𝑦) = Log 𝑥 5 + Log 𝑥 𝑦 Rules of logs
  • 17. • Log 3 25 = ? ? Log 3 5 • 4 Log 7 2 = Log 7 (? ? ) • Log 2 12 = Log 2 36 − Log 2 ? ? • Log ?? ?? = Log 𝑥 − Log 5𝑦 • Log 4 2 10 = −Log 4 (? ? ) • Log 3 25 = Log 𝑥 (??) Log 𝑥 (??) Rules of logs
  • 18. • Log 3 25 = 2 Log 3 5 • 4 Log 7 2 = Log 7 (16) • Log 2 12 = Log 2 36 − Log 2 3 • Log 𝑥 5𝑦 = Log 𝑥 − Log 5𝑦 • Log 4 2 10 = −Log 4 (5) • Log 3 25 = Log 𝑥 (25) Log 𝑥 (3) Rules of logs
  • 19. • Evaluate: • Log 2 1 16 • Log 16 8 = • Log 5 1 Using rules of Logs
  • 20. • Evaluate: • Log 2 1 16 ✓ Log 2 1 16 = −Log 2 16 = −4 • Log 16 8 ✓ Log 16 8 = Log 2 8 Log 2 16 = 3 4 • Log 5 1 = 0 Using rules of Logs
  • 21. • Evaluate: • Log 5 3 − Log 5 75 • 2 Log 2 6 − Log 2 9 • 1 2 Log 10 4 + Log 10 50 Using rules of Logs
  • 22. • Evaluate: • Log 5 3 − Log 5 75 ✓ Log 5 3 75 = Log 5 1 25 = −Log 5 25 = −2 • 2 Log 2 6 − Log 2 9 ✓ Log 2 62 − Log 2 9 = Log 2 36 − Log 2 9 = Log 2 36 9 = Log 2 4 = 2 • 1 2 Log 10 4 + Log 10 50 ✓ Log 10 40.5 + Log 10 50 = Log 10 2 + Log 10 50 = Log 10 2 × 50 = Log 10 100 = 2 Using rules of Logs
  • 23. • Simplify the following logarithms: • Log 10 + Log 2 − Log 4 • 1 2 Log 𝑥 − 3 Log y • 1 3 Log 8 + 2 Log 4 Using rules of Logs
  • 24. • Simplify the following logarithms: • Log 10 + Log 2 − Log 4 ✓ Log 10 × 2 − Log 4 = Log 20 − Log 4 = Log 20 4 = Log 5 • 1 2 Log 𝑥 − 3 Log y ✓ Log 𝑥 Τ1 2 − Log 𝑦3 = Log 𝑥 𝑦3 • 1 3 Log 8 + 2 Log 4 = Log 8 Τ1 3 + Log 42 = Log 2 + Log 16 = Log 2 × 16 = Log 32 Using rules of Logs
  • 25. • The point P on the curve 𝑦 = 9 𝑥 has y-coordinate equal to 150. Use logarithms to find the x-coordinate of P, correct to 3 significant figures. Using rules of Logs
  • 26. • The point P on the curve 𝑦 = 9 𝑥 has y-coordinate equal to 150. Use logarithms to find the x-coordinate of P, correct to 3 significant figures. ✓ 150 = 9 𝑥 Log 150 = Log 9 𝑥 Log 150 = 𝑥 Log 9 ∴ 𝑥 = Log 150 Log 9 = Log9150 = 2.28 Using rules of Logs
  • 27. • Given that Log 𝑥 5𝑦 + 1 − Log 𝑥 3 = 4, express y in terms of x. Using rules of Logs
  • 28. • Given that Log 𝑥 5𝑦 + 1 − Log 𝑥 3 = 4, express y in terms of x. ✓ Log 𝑥 5𝑦+1 3 = 4 𝑥4 = 5𝑦 + 1 3 3𝑥4 = 5𝑦 + 1 ∴ 𝑦 = 3𝑥4 − 1 5 Using rules of Logs
  • 29. • Use logarithms to solve the following equation, giving the value of x correct to 3 s.f: • 7 𝑥 = 2 𝑥+1 Using rules of Logs
  • 30. • Use logarithms to solve the following equation, giving the value of x correct to 3 s.f: • 7 𝑥 = 2 𝑥+1 ✓ Log 7 𝑥 = Log 2 𝑥+1 → 𝑥 Log 7 = 𝑥 + 1 Log 2 𝑥 𝑥+1 = Log 2 Log 7 = 0.356 𝑥 = 𝑥 + 1 0.356 = 0.356𝑥 + 0.356 𝑥 − 0.356𝑥 = 0.356 0.644 𝑥 = 0.356 ∴ 𝑥 = 0.356 ÷ 0.644 = 0.553 Using rules of Logs