If P is a prime and x is a real number such that x^2 = P, then x is .pdf

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If P is a prime and x is a real number such that x^2 = P, then x is irrational. Solution Let, x be rational So, x=r/s ,r,s integers, gcd(r,s)=1 SO, (r/s)^2=P r^2=Ps^2 Henec, P|r^2 P is prime so , P|r Hence, r=kP for some integer k k^2P^2=Ps^2 Pk^2=s^2 So, P|s s=tP for some integer t But, gcd(r,s)=1 HEnce a contradiction HEnce, x is irrational.

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Which of the following items appears on the income statement before income before income taxes? OOther comprehensive income O Discontinued operations. O Comprehensive income. O Other revenues and gains. Solution The following items appear on the income statement before income before income taxes. Other revenues and gains. Explanation:- If the company earns any income from activity other than the main or core operations it is called other revenues and gains. It will be shown in income statement before tax is deducted..

Which of the following items appears on the income statement before i.pdf

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What part of the root is responsible for water and nutrient absorption. Apical meristem root hairs of the epidermis cortex and pith root cap zone of cellular elongation Solution Hi, Answer of your question is : 2.root hairs of the epidermis. Explanation:Because it is responsible for water and nutrients absorption from soil which are important for the plants. I hope my answer is satisfactory. Thanks!!.

What part of the root is responsible for water and nutrient absorptio.pdf

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What is the purpose of the balance sheet? Be sure to discuss the three key elements that make up the balance sheet. URGENT: NEED ANSWER ASAP PLEASE RESPOND WITH COPY AND PASTE, NOT ATTACHMENT USE ORIGINAL CONTENT NOT USED BEFORE ON CHEGG PLEASE ANSWER THROUGHLY TO ALL ANSWER TO BEST ABILITES ORIGINAL SOURCE NEVER USED BEFORE!!! Solution A balance sheet is a financial statement which represents the worth of the company and its business at a given point in time. The Balance sheet details what it owns and to whom it owns to. The purpose of the Balance Sheet is to show the break up of the total assets between the outsider liabilities and owners\' equity at a point of time. The balance sheet of a company has three key elements, which are : (1) Assets, which includes all the current and long-term assets or fixed assets which the company owns, (2) Liabilities, which includes the current and long-term liabilities payable to the outsiders by the company, (3) Shareholders\' equity, it constitutes all that belongs to the Shareholders who are the legal owners of the company, which includes equity capital and retained earnings. The total of its assets is equal to the sum of the Shareholders\' equity alongwith the Liabilities..

What is the purpose of the balance sheet Be sure to discuss the thr.pdf

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What is culture? Why should culture play a role in aiding our understanding of leadership? Solution Culture is the unique characteristics and knowledges or a particular group of people, defined by their lenguage, cuisine, social habits, art, relgion, music etc. Culture play an important role on helping us understand leardership because culture define us as people, depending where you are from will determinate the way you behaive and how you intereact with others. When you are the manager of a group that has huge diversity among its member it is important to understand what motivates each of your employees, you can not assume they all will be motivated the same, it will depend on their culture..

What is culture Why should culture play a role in aiding our unders.pdf

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What are the Federal Reserve\'s major assets and liabilities? What are the relative amounts of each (currently...July 2018)? Solution Federal reserves assets are Gold reserves,Special drwing rights, reserves position in international monetary fund and foreign currencies. Federal reserves liabilities are Federal resrve nbotes, deposits made by depository institutions, the U.S. Treasury, and others hold in accounts at the Federal Reserve Banks. Couldn;t get the data on liabilities. Best of Luck. God BlessAsset in millions of dollars18-AprMay 2018/p1Total1245401228442Gold stock111041110413Special drawing rights2 352402516564Reserve position in International Monetary Fund2 517708175565Foreign Currencies44338942591.

What are the Federal Reserves major assets and liabilities What a.pdf

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Use whichever properties (associative and/or communities) are necessary to simplify each expression. (2+n)+9 (5+x+3)+2 Use whichever properties (associative and/or communities) are necessary to simplify each expression. (2+n)+9 (5+x+3)+2 (2+n)+9 (5+x+3)+2 Solution (2+n) +9 =9+(2+n).... commutative property =(9+2)+n ......associative property =11+n Answer (5+x+3)+2 =2+(5+x+3) commutative property =(2+5) +(x+3) associative property =7+ (x+3) =(7+3)+x associative property =10+x Answer ***********.

Use whichever properties (associative andor communities) are nece.pdf

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Use a 5 significance level unless specified otherwise.Please give.pdf

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two children own two-way radios that have a maximum range of 2 miles.Once leaves a certain point at 1:00 pm. Walking due north at a rate of 4 mi/hr. The other leaves the same point at 1:15 pm. Travling due south at 6 mi/hr. When will they be unable to communicate with each other? Solution Time when the first child leaves (T1) =1:00 pm Speed of first child (S1) = 4 mi/hr Time when second child leaves (T2) = 1:15 pm Speed of second child (S2) = 6 mi/hr Time elapsed until second child leaves=T2-T1=15 minutes Distance travelled by first child in that time=s1*15 minutes =4 mi/hr * (1/4)hr =1 mile Range of radio=2 miles Distance between children at 1.15 pm = 1 mile Remaining range=1 mile first child and second child are moving in opposite directions hence both distances must be considered s=d/t => d=t*s (distanceNorth)+(distanceSouth)=1 mile t(S1)+t(S2)=1 mile t(S1+S2)=1 mile t(4+6)=1 t(10)=1 t=1/10 hour=60/10 minutes=6 minutes Thus,10 minutes later the remaining range of 1 mile would also be passed. Time at that moment = 1.15+6 minutes = 1:21 pm.

two children own two-way radios that have a maximum range of 2 miles.pdf

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The place within an enzyme where a substrate binds is called the ATP site Active site Key hole Transition site If t for two different polypeptides some of their R groups come together to hold both polypeptides together in a certain 3-dimentional shape. Which level of protein structure would this describe? primary structure secondary structure tertiary structure quaternary structure In DNA what nitrogenous base complementanly pairs with T (thymine)? Solution 14. Active site the active site is the region of an enzyme where substrate molecules bind and undergo a chemical reaction. 15. Quaternary structure (quaternary structures arise when a protein is made up of two or more polypeptide chains).

The place within an enzyme where a substrate binds is called the ATP.pdf

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// READ BEFORE YOU START: // Please read the given Word document for the project description with an illustrartive diagram. // You are given a partially completed program that creates a list of dogs for an adoption shelter. // Each dog has the corresponding information: name, breed, and a linked list of checkups. // Please read the instructions above each required function and follow the directions carefully. // If you modify any of the given code, return types, or parameters, you risk failing test cases. // // Note, Textbook Section 2.10 gives a case study on complex linked list operations. // This project is based on that case study. Make sure you read the code in section 2.10. // The following will be accepted as input in the following format: \"name:breed\" // Example Input: \"Spot:Terrier\" or \"Daisy:Poodle\" // Valid name: String containing alphabetical letters beginning with a capital letter // Valid breed: String containing alphabetical letters beginning with a capital letter // Valid date: String in the following format: \"MM/DD/YYYY\" ex: \"01/01/2010\" // All input will be a valid length and no more than the allowed number of dogs will be added to the linked list. #include #include #include #include // included to check for memory leaks #define CRTDBG_MAP_ALLOC #include #pragma warning(disable: 4996) // used to create a linked list of containers, each contaning a \"dog\" struct container { struct dog *dog; struct container *next; } *list = NULL; // used to hold dog information and linked list of \"checkups\" struct dog { char name[30]; char breed[30]; struct checkup *checkups; }; // used to create a linked list of checkups containing \"dates\" struct checkup { char date[30]; struct checkup *next; }; // forward declaration of functions that have already been implemented void flush(); void branching(char); void helper(char); void remove_all(struct container*); void display(struct container*); // the following forward declarations are for functions that require implementation // return type // name and parameters // points void add_dog(char*, char*); // 5 struct dog* search_dog(char*); // 5 void add_checkup(char*, char*); // 10 char* last_checkup(char*); // 15 void remove_one(char*); // 15 // Total: 50 points for hw07 struct container* list_of_breed(char*); // 25 struct container* list_by_name(); // 25 // Total: 50 points for hw08 int main() { char ch = \'i\'; printf(\"Dog Adoption Center\ \ \"); do { printf(\"Please enter your selection:\ \"); printf(\"\\ta: add a new dog to the list\ \"); printf(\"\\ts: search for a dog on the list\ \"); printf(\"\\tr: remove a dog from the list\ \"); printf(\"\\tc: add a checkup date for dog\ \"); printf(\"\\tl: display last checkup for a dog\ \"); printf(\"\\tn: display list of dogs by name\ \"); printf(\"\\tb: display list of dogs of breed\ \"); printf(\"\\tq: quit\ \"); ch = tolower(getchar()); flush(); branching(ch); } while (ch != \'q\'); remove_all(list); list = NULL; _CrtDumpMemoryLeaks(); .

READ BEFORE YOU START Please read the given Word document fo.pdf

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Refer to the table below. A student creates the table above as a study guide. Evaluate the accuracy of the information shown. The information is not accurate because the anterior air sacs push air when they expand and pull air when then contract. The information is not accurate because air sacs expand during exhalation and contract during inhalation. The information shown is accurate. The information is not accurate because air does not flow through the lungs during exhalation. Solution The information shown is accurate. During inhalation, the posterior air sacs expand and the air is filled in posterior air sac and lungs and air fills in the anterior sac. Both the sacs expand during inhalation. During exhalation, both the sacs contracts and pushes air from posterior sac through lungs and from anterior sacs to outside the body..

Refer to the table below. A student creates the table above as a stu.pdf

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prove the followings: 1- every subset of a finite set is finite 2- if s is denumerable, then s is equinumerous with a proper subset of itself Solution Post one more question to get the answer to the second problem. Thanks Proof using induction: 1) Base Case (n=1) There is only one element in the finite set, then we can write it as X \\ a = Phi, since there won\'t be any element in the set if we removing phi, hence the phi is a finite set since it contains only one element and this is an empty element 2) Let us assume that the solution is true for (n=k), i.e. for an finite set with k elements, every subset of that set will be finite 3) Now we need to prove our hypothesis for the set containing (k+1) elements Let us assume that X has (k+1) elements if Y is a subset of X, then it will have atmost k+1 elements, which is equal to X Since X is finite, therefore Y will also be finite Otherwise, there exists an element that belong to X but not to Y a belongs to X\\Y => it implies that Y is a subset of X\\ a This set contain max n elements, hence the Y will be finite.

prove the followings1- every subset of a finite set is finite2-.pdf

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Problem 9-4 Nonconstant growth valuation Hart Enterprises recently paid a dividend, DO of $1.00. It expects to have nonconstant growth of 14% for 2 years followed by a constant rate of 4% thereafter. The m s required return is 16% a. How far away is the horizon date? I. The terminal, or horizon, date is infinity since common stocks do not have a maturity date. II. The terminal, or horizon, date is Year 0 since the value of a common stock is the present value of all future expected dividends at time zero III. The terminal, or horizon, date is the date when the growth rate becomes nonconstant. This occurs at time zero. IV. The terminal, or horizon, date is the date when the growth rate becomes constant. This occurs at the beginning of Year 2. V. The terminal, or horizon, date is the date when the growth rate becomes constant. This occurs at the end of Year 2. Select- b. What is the firm\'s horizon, or continuing, value? Round your answer to two decimal places c. What is the firm\'s intrinsic value today, Po? Round your answer to two decimal places. Solution Answer a. The terminal, or horizon, date is the date when the growth rate becomes constant. This occurs at the end of Year 2. Answer b. D0 = $1.00 Growth rate for next 2 years is 14%, followed by an constant growth rate (g) of 4% D1 = $1.00 * 1.14 = $1.14 D2 = $1.14 * 1.14 = $1.2996 D3 = $1.2996 * 1.04 = $1.3516 Required return, r = 16% Horizon Value of Firm = D3 / (r - g) Horizon Value of Firm = $1.3516 / (0.16 - 0.04) Horizon Value of Firm = $11.26 Answer c. Intrinsic Value of Firm = $1.14/1.16 + $1.2996/1.16^2 + $11.26/1.16^2 Intrinsic Value of Firm = $10.32.

Problem 9-4 Nonconstant growth valuation Hart Enterprises recently pa.pdf

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Please type the answer 4. What government entity is primarily in charge of regulating banks? What government entity regulates mutual funds? (2 points) Solution Bank Regulator (i) Board of Governors of the Federal Reserve System- It regulates state chartered banks and trust companies that belong to the Federal Reserve System. (ii) Federal Deposit Insurance Corporation- It regulates state chartered banks that do not belong to the Federal Reserve System. (iii) Office of the Comptroller of Currency- It regulates banks that have the word \"National\" in or the letters \"N.A.\" after their names Mutual Fund Regulator = U.S. Securities and Exchange Commission.

Please type the answer 4. What government entity is primarily in.pdf

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On the basis of the presence of the appendix, what might you infer about dietary habits of our evolutionary antecedents? Solution The main function of the appendix is to hydrolyze cellulose and indigestible plant material but it is present in mammals that includes rodents and primates which are not eating cellulose as food souce but may be in past they used to eat that so still it is there, Although there is no main function of this organ and known as vestigial organ but there is some report that it having some role in immune system. Some herbivorous animals, such as rabbits, have a terminal vermiform appendix..

On the basis of the presence of the appendix, what might you infer ab.pdf

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Name 4 functions of matrix in composite materials Name 4 functions of matrix in composite materials Name 4 functions of matrix in composite materials Name 4 functions of matrix in composite materials Solution Matrix is binding in nature and homegenoeus material. In compostie materials, it gives the medium for holding, joining different strucutre in composite material. It is continuous. It gives the protection for inner parts from the natural forces..

Name 4 functions of matrix in composite materials .pdf

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Lab 13: Practicing STL Vector Container: 1a. Write a template function(in header file) to search a value stored in a vector and return the position(index) of the item if found; otherwise, return a negative value. Then write a driver to test it. The driver should at least test two different type of vector. Use vector index to do it. 1b. Write a template function(in header file) to search a value stored in a vector and return the position(index) of the item if found; otherwise, return a negative value. Then write a driver to test it. The driver should at least test two different type of vector. Use iterator to do it. Deque Container: 2a. Write a function to add first 6 integers alternately to front and back of a deque. (in header file) 2b. Write a template function to display the content of a deque using iterator (in header file) 2c. Write a template function to change back value to a specified value using iterator (in header file) Then write a driver to test the above three template functions. List Container – see textbook page 605 for basic operations: 3a. Write a template function to read values from an input stream to a list (in header file) 3b. Write a template function to fill in a list with a given vector (in header file) 3c. Write a template function to change a given value in a list to another given value(use find(), insert() and erase()) (in header file) Then write a driver to test the above three template functions. Queue wrapper with list 4. Write a template queue class as defined below: private data member: a STL list public member functions: -empty -size -enqueue -deque -front -back Then write a driver to test the above queue class. Follow our class coding standard to complete this lab, compile and run it, check out for credit Solution Here is the answer for the questions: Please compile using -std=c++11 option example g++ -std=c++11 q3.cpp Q1 files compile : g++ -std=c++11 q1.cpp q1.h #include using std::vector; template int searchUsingIndex(vector values, T item) { for(int i = 0 ; i < values.size(); ++i) { if(values[i] == item) return i; } return -1; } template int searchUsingIterator(vector values, T item) { int i = 0; for(typename vector::iterator it=values.begin(); it != values.end(); ++it, ++i) { if(*it == item) return i; } return -1; } q1.cpp #include #include #include \"q1.h\" using namespace std; int main() { vector num = {3,6,10,1}; vector names = {\"alice\",\"bob\",\"john\" ,\"peter\"}; string search=\"john\"; cout<<\"Index of 2 in num vector using index: \"< #include using namespace std; //we need to pass by reference void addFrontBack(deque &q) { for(int i = 1; i < 7; i ++) { if(i % 2 == 1) q.push_front(i); else q.push_back(i); } } template void print(const deque &q) { for(typename deque::const_iterator it = q.begin(); it != q.end(); ++it) { cout<< *it < void changeBack(deque &q, T newValue) { if(q.empty()) return; typename deque::iterator it = q.end()-1;//get 1 location behind end *(it) = newValue; } q2.cpp #include .

Lab 13 Practicing STLVector Container1a. Write a template func.pdf

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In which generation is a recessive deleterious allele MOST likely to negatively affect the fitness of the individual expressing it? gametophyte equally likely in both sporophyte and gametophyte highly improbable in both generations sporophyte Solution The gametophyte are gamete producing phase which are haploid in nature while sporophytes are spore forming an ddiploid in nature. The haploid games when fuse form zygote and then this forms spores. When we consider recessive alleles, they are expressed only when there is no dominant allele in their zygote because gametes produced will only have one copy of chromosome either dominant or recessive. The fusion of one dominant and one recessive will give a zygote, diploid, and recessive allele won\'t be expressed. Therefore, if gametophyte is equally likely in both sporophyte, the negative affect of recessive allele on the fitness of individual expressing it is more..

In which generation is a recessive deleterious allele MOST likely.pdf

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In a test tube you combine competent E. coli cells with your genetically engineered plasmid that contains the gene for antibiotic resistance. You treat the solution and plate your product on antibiotic containing media overnight. The next day you see growth on your plate. 1)Was there horizontal gene transfer? 2)How do you know? 3)If so, what kind of gene transfer? Solution no what we see next day is only those bacterial colonies on the plate which got transformed previously that is those bacterial colonies in which antibiotic resistance plasmid got sucessfully transformed in them.... because we are growing them on antibiotic contaning medium. SO THERE WAS NOT ANY HORIZONTAL GENE TRANSFER WE CANNOT ASSUME THAT IT WAS BACTERIAL CONJUGATION (HORIZONTAL GENE TRANSFER) AND IN CONJUGATION RESISTANCE GENE GOT EXCHANGED BETWEEN BACTRIUM, BECAUSE RESISTANCE GENE IS ON PLASMID NOT IN BACTERIUM GENOME ... AND IT SEEMS TO BE TRANSIENT TRANSFORMATION RATHER THAN STABLE TRANSFORMATION. THE possibility of horizontal gene transfer is very less compared to sucessful transformation with plasmid because the cells were already competent and could have taken up plasmid easily Hope that answers ..... Regards.

In a test tube you combine competent E. coli cells with your genetic.pdf

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In a certain year, 89% of all Caucasians in the U.S., 74% of all African-Americans, 74% of all Hispanics, and 76% of residents not classified into one of these groups used the Internet for e- mail. At that time, the U.S. population was 65% Caucasian, 10% African-American, and 12% Hispanic. What percentage of U.S. residents who used the Internet for e-mail were Hispanic? (Round your answer to the nearest whole percent.) Solution.

In a certain year, 89 of all Caucasians in the U.S., 74 of all Afr.pdf

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