Use whichever properties (associative andor communities) are nece.pdf
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Use whichever properties (associative and/or communities) are necessary to simplify each expression. (2+n)+9 (5+x+3)+2 Use whichever properties (associative and/or communities) are necessary to simplify each expression. (2+n)+9 (5+x+3)+2 (2+n)+9 (5+x+3)+2 Solution (2+n) +9 =9+(2+n).... commutative property =(9+2)+n ......associative property =11+n Answer (5+x+3)+2 =2+(5+x+3) commutative property =(2+5) +(x+3) associative property =7+ (x+3) =(7+3)+x associative property =10+x Answer ***********.
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Firms HL and LL are identical except for their leverage ratios and t.pdf
Firms HL and LL are identical except for their leverage ratios and the interest rates they pay on
debt. Each has $30 million in invested capital, has $4.5 million of EBIT, and is in the 40%
federal-plus-state tax bracket. Firm HL, however, has a debt-to-capital ratio of 60% and pays
12% interest on its debt, whereas LL has a 40% debt-to-capital ratio and pays only 9% interest
on its debt. Neither firm uses preferred stock in its capital structure.
Calculate the return on invested capital (ROIC) for each firm. Round your answers to two
decimal places.
ROIC for firm LL is ________ %
ROIC for firm HL is ________ %
Calculate the rate of return on equity (ROE) for each firm. Round your answers to two decimal
places.
ROE for firm LL is ________ %
ROE for firm HL is ________ %
Observing that HL has a higher ROE, LL\'s treasurer is thinking of raising the debt-to-capital
ratio from 40% to 60%, even though that would increase LL\'s interest rate on all debt to 15%.
Calculate the new ROE for LL. Round your answer to two decimal places.
________ %
Solution
Answer a.
Firm LL:
Invested Capital = $30,000,000
EBIT = $4,500,000
Tax Rate = 40%
ROIC = EBIT * (1 - tax)/ Invested Capital
ROIC = $4,500,000 * (1 - 0.40) / $30,000,000
ROIC = 9%
Firm HL:
Invested Capital = $30,000,000
EBIT = $4,500,000
Tax Rate = 40%
ROIC = EBIT * (1 - tax)/ Invested Capital
ROIC = $4,500,000 * (1 - 0.40) / $30,000,000
ROIC = 9%
Answer b.
Firm LL:
Invested Capital = $30,000,000
Debt = 40% * $30,000,000
Debt = $12,000,000
Interest Expense = 9% * $12,000,000
Interest Expense = $1,080,000
Equity = 60% * $30,000,000
Equity = $18,000,000
Net Income = (EBIT - Interest Expense) * (1 - tax)
Net Income = ($4,500,000 - $1,080,000) * (1 - 0.40)
Net Income = $2,052,000
ROE = Net Income / Equity
ROE = $2,052,000 / $18,000,000
ROE = 11.4%
Firm HL:
Invested Capital = $30,000,000
Debt = 60% * $30,000,000
Debt = $18,000,000
Interest Expense = 12% * $18,000,000
Interest Expense = $2,160,000
Equity = 40% * $30,000,000
Equity = $12,000,000
Net Income = (EBIT - Interest Expense) * (1 - tax)
Net Income = ($4,500,000 - $2,160,000) * (1 - 0.40)
Net Income = $1,404,000
ROE = Net Income / Equity
ROE = $1,404,000 / $12,000,000
ROE = 11.7%
Answer c.
Firm LL:
Invested Capital = $30,000,000
Debt = 60% * $30,000,000
Debt = $18,000,000
Interest Expense = 15% * $18,000,000
Interest Expense = $2,700,000
Equity = 40% * $30,000,000
Equity = $12,000,000
Net Income = (EBIT - Interest Expense) * (1 - tax)
Net Income = ($4,500,000 - $2,700,000) * (1 - 0.40)
Net Income = $1,080,000
ROE = Net Income / Equity
ROE = $1,080,000 / $12,000,000
ROE = 9.00%.
Find the domain of the composite function fog. 1 The domain contains .pdf
Find the domain of the composite function fog. 1 The domain contains all real numbers except
for which two values? (smaller value) (larger value)
Solution
g(x)=-8/x
domain of g does not contain 0
fog
=f(g(x))
=1/((-8/x)+9)
=1/((-8+9x)/x)
=x/(9x -8)
function is undefined if 9x -8=0
=>x =8/9
so domain is all real numbers except 0, 8/9.
Do the following two problems1. Any algorithm that solves the sea.pdf
Do the following two problems:
1. Any algorithm that solves the search problem for a 7654 element list by comparing the target
element x to the list items must do at least __________ comparisons in the worst case.
2. Any algorithm that sorts a 7 element list by comparing pairs of items from the list must do at
least __________ comparisons in the worst case.
Solution
If the element is not in the list, the only way to know it is to compare it against every item
present in the list. If there are n elements, then the sequential search requires n comparisons to
discover that the item is not there. In the case where the item is in the list, the analysis is not so
straightforward. There are actually three different scenarios that can occur. In the best case we
will find the item in the first place we look, at the beginning of the list. We will need only one
comparison. In the worst case, we will not discover the element until the very last comparison,
the nth comparison.
So, Any algorithm that solves the search problem for a 7654 element list by comparing the target
element x to the list items must do at least __7654__ comparisons in the worst case.
Next,the algorithm for bubble sort or pair sort requires a pair of nested loops. The outer loop
must iterate once for each element in the data set (of size n) while the inner loop iterates n times
the first time it is entered, n-1 times the second, and so on. Consider the purpose of each loop.
Bubble sort is structured so that on each pass through the list the next largest element of the data
is moved to its proper place. Therefore, to get all n elements in their correct places, the outer
loop must be executed n times.
And on the first iteration of the outer loop, while trying to place the largest element, there have to
be n - 1 comparisons: the first comparison is made between the 1st and 2nd elements, the second
is made between the second and third elements, and so on until the (n-1)th comparison is made
between the (n-1)th and the nth element. On the second iteration of the outer loop, there is no
need to compare the against the last element of the list, because it was put in the correct place on
the previous pass. Therefore, the second iteration requires only n-2 comparisons. This pattern
continues until the second-to-last iteration of the outer loop when only the first two elements of
the list are unsorted so, only one comparison is necessary. The total number of comparisons,
therefore, is (n- 1) + (n- 2)...(2) + (1)
=n(n- 1)/2 orO(n2).
So, any algorithm that sorts a 7 element list by comparing pairs of items from the list must do at
least __21________ comparisons in the worst case..
Describe two traits that represent a sustainable societyand two tr.pdf
Describe two traits that represent a sustainable society
and two traits of a nonsustainable society.
Solution
The 2 traits that mainly represent a sustainable society is a meticulous emphasis on
“egalitarianism”. This egalitarianism is mainly depicts that the implementation society of formal
equality in distribution of wealth and resources as explained below so that another trait is attain a
capitalism economic structure & utilitarianism for economic growth in the society. So that, moral
equality can be attained with moral values, and ethical based decisions must be implemented
within the communities to establish social justice with equality and responsibility.
A non-sustainable society is represented by the traits such as use of high amount to non-
renewable resources with unequal distribution of resources and possessing ever-cumulative
productions of products.
Compare Windows Assembly to that of a UNIX system.SolutionTher.pdf
Compare Windows Assembly to that of a UNIX system.
Solution
There is no difference. The assembly code is the same if the processor is the same. x86 code
compiled on Windows is binary compatible with x86 code on Linux. The compiler does not
produce OS-dependent binary code, but it may package the code in a different format (e.g. PE vs.
ELF).
The difference is in which libraries are used. In order to use OS stuff (I/O for example) you must
link against the operating system\'s libraries. Unsurprisingly, Windows system libraries are not
available on a Linux machine (unless you have Wine of course) and vice-versa..
Below is the assignment description and the file I have written..pdf
Below is the assignment description and the file I have written. I would love to test this file to
make sure that everything is satisfied (vector with all modes in ascending order). I\'m having a
really hard time constructing a main method to test it. Help!!
-------------------------------------------------------
The mode is the value that appears most often in a set of data. Write a function named findMode
that takes as parameters an array of int and the size of the array, and returns a vector containing
the mode(s). If there is just a single most frequent value, the vector will only contain that one
value, but if multiple values tie for maximum frequency, the vector will need to contain all such
values. This includes the case where every number in the array appears only once. Each mode
should appear only once in the vector. The values in the vector that is returned must be in
ascending order. If you need to sort a vector, it\'s similar to sorting an array, but specifying the
beginning and end of the vector look a little bit different. If your vector is named result, then it
would look like this: \"std::sort(result.begin(), result.end());\".
-------------------------------------------------------
#include // needed for the sort() function
#include // needed to use the vector type
#include // needed for the main function
using std::vector;
using std::sort;
vector findMode(int array[], int size)
{
int maxFreq = 1; // initalizing the largest frequency to be 1
vector result; // results is an empty vector
//Initializing the loop through the integer array
for (int i = 0; i < size; i++)
{
int count = 1; //started the counter at 1
//started the the loop after the 1st entry, looking for matches with the value at index i.
for (int j = i + 1; j < size; j++)
{
//if an entry matches another, then add one to the counter
if (array[i] == array[j])
{
count++;
}
}
//when the counter is equal to the max frequency, the integer is added to the result vector.
if (count == maxFreq)
{
result.push_back(array[i]);
}
//when the counter for i is greater than the max frequency, updates the maxFreq, clear the values
stored in the result vector, and push the value to the empty vector.
if (count > maxFreq)
{
maxFreq = count;
result.clear();
result.push_back(array[i]);
}
}
//sort the modes in ascending order
sort(result.begin(), result.end());
return result;
Below is the assignment description and the file I have written. I would love to test this file to
make sure that everything is satisfied (vector with all modes in ascending order). I\'m having a
really hard time constructing a main method to test it. Help!!
-------------------------------------------------------
The mode is the value that appears most often in a set of data. Write a function named findMode
that takes as parameters an array of int and the size of the array, and returns a vector containing
the mode(s). If there is just a single most frequent value, the vector will only contain that one
value, but if mult.
You have prepared the spread plates below using 0.1 mL from a liquid .pdf
You have prepared the spread plates below using 0.1 mL from a liquid culture of E. coli at an
unknown concentration. Count the colonies that have grown and use the information, together
with the TDF for the corresponding plate, to calculate the average original concentration of your
E. coli suspension.
Solution
to calculate the average original concentration of e.coli suspension,
first we need to find out CFU/ML by formula-
no. of colonies x dilution factor / volume of culture plate
for plate first- TDF-2 x 105, so total number of colony is 12 x ( 2x105) / 0.1 ml = 24x106
second plate TDF is 1 x 106, so CFU/ml is = 6 x 107
so overall average CFU/ml is = 1.5 x 1014 by taking average of both plate sample add both value
than divide by 2 so the final outcome is 1.5 x 1014, the final concentration of E.coli suspension
is 1.5 x 1014 u/ml..
While bacteria exhibit simple cell division where the quantity o.pdf
While bacteria exhibit \"simple cell division\" where the quantity of DNA remains constant
following cell production, why would it be incorrect to say they undergo mitosis?
Solution
The mechanics and sequence of bacterial cell division and mitosis are fairly different.When cells
divide by mitosis in an multicellular organism,it causes the organism to grow bigger and replace
old cells with new ones.However in case of bacteria,cell division is not just a means of producing
new cells instead it is a mechanism of bacerial reproduction.In case of binary fission,the
prokaryotc chromosome repicates, then attaches each copy to a different part of the cell
membrane. When the cell pulls apart,replicated and original chromosomes are
seperated.Cytokinesis then produces two seperate cells.
mitosis is a more complex process and takes place in 5 stages:
prophase,anaphase,metaphase,telophase,cytokinesis.
in binary fission no mitotic spindles are formed. DNA replication takes place at the same time as
DNA seperation.Whereas in mitosis DNA is copied during S phase,whereas it is seperated in M
phase.
Therefore it would be incorrect to say binary fission and mitosis as same..
Recommended
Firms HL and LL are identical except for their leverage ratios and t.pdf
Firms HL and LL are identical except for their leverage ratios and the interest rates they pay on
debt. Each has $30 million in invested capital, has $4.5 million of EBIT, and is in the 40%
federal-plus-state tax bracket. Firm HL, however, has a debt-to-capital ratio of 60% and pays
12% interest on its debt, whereas LL has a 40% debt-to-capital ratio and pays only 9% interest
on its debt. Neither firm uses preferred stock in its capital structure.
Calculate the return on invested capital (ROIC) for each firm. Round your answers to two
decimal places.
ROIC for firm LL is ________ %
ROIC for firm HL is ________ %
Calculate the rate of return on equity (ROE) for each firm. Round your answers to two decimal
places.
ROE for firm LL is ________ %
ROE for firm HL is ________ %
Observing that HL has a higher ROE, LL\'s treasurer is thinking of raising the debt-to-capital
ratio from 40% to 60%, even though that would increase LL\'s interest rate on all debt to 15%.
Calculate the new ROE for LL. Round your answer to two decimal places.
________ %
Solution
Answer a.
Firm LL:
Invested Capital = $30,000,000
EBIT = $4,500,000
Tax Rate = 40%
ROIC = EBIT * (1 - tax)/ Invested Capital
ROIC = $4,500,000 * (1 - 0.40) / $30,000,000
ROIC = 9%
Firm HL:
Invested Capital = $30,000,000
EBIT = $4,500,000
Tax Rate = 40%
ROIC = EBIT * (1 - tax)/ Invested Capital
ROIC = $4,500,000 * (1 - 0.40) / $30,000,000
ROIC = 9%
Answer b.
Firm LL:
Invested Capital = $30,000,000
Debt = 40% * $30,000,000
Debt = $12,000,000
Interest Expense = 9% * $12,000,000
Interest Expense = $1,080,000
Equity = 60% * $30,000,000
Equity = $18,000,000
Net Income = (EBIT - Interest Expense) * (1 - tax)
Net Income = ($4,500,000 - $1,080,000) * (1 - 0.40)
Net Income = $2,052,000
ROE = Net Income / Equity
ROE = $2,052,000 / $18,000,000
ROE = 11.4%
Firm HL:
Invested Capital = $30,000,000
Debt = 60% * $30,000,000
Debt = $18,000,000
Interest Expense = 12% * $18,000,000
Interest Expense = $2,160,000
Equity = 40% * $30,000,000
Equity = $12,000,000
Net Income = (EBIT - Interest Expense) * (1 - tax)
Net Income = ($4,500,000 - $2,160,000) * (1 - 0.40)
Net Income = $1,404,000
ROE = Net Income / Equity
ROE = $1,404,000 / $12,000,000
ROE = 11.7%
Answer c.
Firm LL:
Invested Capital = $30,000,000
Debt = 60% * $30,000,000
Debt = $18,000,000
Interest Expense = 15% * $18,000,000
Interest Expense = $2,700,000
Equity = 40% * $30,000,000
Equity = $12,000,000
Net Income = (EBIT - Interest Expense) * (1 - tax)
Net Income = ($4,500,000 - $2,700,000) * (1 - 0.40)
Net Income = $1,080,000
ROE = Net Income / Equity
ROE = $1,080,000 / $12,000,000
ROE = 9.00%.
Find the domain of the composite function fog. 1 The domain contains .pdf
Find the domain of the composite function fog. 1 The domain contains all real numbers except
for which two values? (smaller value) (larger value)
Solution
g(x)=-8/x
domain of g does not contain 0
fog
=f(g(x))
=1/((-8/x)+9)
=1/((-8+9x)/x)
=x/(9x -8)
function is undefined if 9x -8=0
=>x =8/9
so domain is all real numbers except 0, 8/9.
Do the following two problems1. Any algorithm that solves the sea.pdf
Do the following two problems:
1. Any algorithm that solves the search problem for a 7654 element list by comparing the target
element x to the list items must do at least __________ comparisons in the worst case.
2. Any algorithm that sorts a 7 element list by comparing pairs of items from the list must do at
least __________ comparisons in the worst case.
Solution
If the element is not in the list, the only way to know it is to compare it against every item
present in the list. If there are n elements, then the sequential search requires n comparisons to
discover that the item is not there. In the case where the item is in the list, the analysis is not so
straightforward. There are actually three different scenarios that can occur. In the best case we
will find the item in the first place we look, at the beginning of the list. We will need only one
comparison. In the worst case, we will not discover the element until the very last comparison,
the nth comparison.
So, Any algorithm that solves the search problem for a 7654 element list by comparing the target
element x to the list items must do at least __7654__ comparisons in the worst case.
Next,the algorithm for bubble sort or pair sort requires a pair of nested loops. The outer loop
must iterate once for each element in the data set (of size n) while the inner loop iterates n times
the first time it is entered, n-1 times the second, and so on. Consider the purpose of each loop.
Bubble sort is structured so that on each pass through the list the next largest element of the data
is moved to its proper place. Therefore, to get all n elements in their correct places, the outer
loop must be executed n times.
And on the first iteration of the outer loop, while trying to place the largest element, there have to
be n - 1 comparisons: the first comparison is made between the 1st and 2nd elements, the second
is made between the second and third elements, and so on until the (n-1)th comparison is made
between the (n-1)th and the nth element. On the second iteration of the outer loop, there is no
need to compare the against the last element of the list, because it was put in the correct place on
the previous pass. Therefore, the second iteration requires only n-2 comparisons. This pattern
continues until the second-to-last iteration of the outer loop when only the first two elements of
the list are unsorted so, only one comparison is necessary. The total number of comparisons,
therefore, is (n- 1) + (n- 2)...(2) + (1)
=n(n- 1)/2 orO(n2).
So, any algorithm that sorts a 7 element list by comparing pairs of items from the list must do at
least __21________ comparisons in the worst case..
Describe two traits that represent a sustainable societyand two tr.pdf
Describe two traits that represent a sustainable society
and two traits of a nonsustainable society.
Solution
The 2 traits that mainly represent a sustainable society is a meticulous emphasis on
“egalitarianism”. This egalitarianism is mainly depicts that the implementation society of formal
equality in distribution of wealth and resources as explained below so that another trait is attain a
capitalism economic structure & utilitarianism for economic growth in the society. So that, moral
equality can be attained with moral values, and ethical based decisions must be implemented
within the communities to establish social justice with equality and responsibility.
A non-sustainable society is represented by the traits such as use of high amount to non-
renewable resources with unequal distribution of resources and possessing ever-cumulative
productions of products.
Compare Windows Assembly to that of a UNIX system.SolutionTher.pdf
Compare Windows Assembly to that of a UNIX system.
Solution
There is no difference. The assembly code is the same if the processor is the same. x86 code
compiled on Windows is binary compatible with x86 code on Linux. The compiler does not
produce OS-dependent binary code, but it may package the code in a different format (e.g. PE vs.
ELF).
The difference is in which libraries are used. In order to use OS stuff (I/O for example) you must
link against the operating system\'s libraries. Unsurprisingly, Windows system libraries are not
available on a Linux machine (unless you have Wine of course) and vice-versa..
Below is the assignment description and the file I have written..pdf
Below is the assignment description and the file I have written. I would love to test this file to
make sure that everything is satisfied (vector with all modes in ascending order). I\'m having a
really hard time constructing a main method to test it. Help!!
-------------------------------------------------------
The mode is the value that appears most often in a set of data. Write a function named findMode
that takes as parameters an array of int and the size of the array, and returns a vector containing
the mode(s). If there is just a single most frequent value, the vector will only contain that one
value, but if multiple values tie for maximum frequency, the vector will need to contain all such
values. This includes the case where every number in the array appears only once. Each mode
should appear only once in the vector. The values in the vector that is returned must be in
ascending order. If you need to sort a vector, it\'s similar to sorting an array, but specifying the
beginning and end of the vector look a little bit different. If your vector is named result, then it
would look like this: \"std::sort(result.begin(), result.end());\".
-------------------------------------------------------
#include // needed for the sort() function
#include // needed to use the vector type
#include // needed for the main function
using std::vector;
using std::sort;
vector findMode(int array[], int size)
{
int maxFreq = 1; // initalizing the largest frequency to be 1
vector result; // results is an empty vector
//Initializing the loop through the integer array
for (int i = 0; i < size; i++)
{
int count = 1; //started the counter at 1
//started the the loop after the 1st entry, looking for matches with the value at index i.
for (int j = i + 1; j < size; j++)
{
//if an entry matches another, then add one to the counter
if (array[i] == array[j])
{
count++;
}
}
//when the counter is equal to the max frequency, the integer is added to the result vector.
if (count == maxFreq)
{
result.push_back(array[i]);
}
//when the counter for i is greater than the max frequency, updates the maxFreq, clear the values
stored in the result vector, and push the value to the empty vector.
if (count > maxFreq)
{
maxFreq = count;
result.clear();
result.push_back(array[i]);
}
}
//sort the modes in ascending order
sort(result.begin(), result.end());
return result;
Below is the assignment description and the file I have written. I would love to test this file to
make sure that everything is satisfied (vector with all modes in ascending order). I\'m having a
really hard time constructing a main method to test it. Help!!
-------------------------------------------------------
The mode is the value that appears most often in a set of data. Write a function named findMode
that takes as parameters an array of int and the size of the array, and returns a vector containing
the mode(s). If there is just a single most frequent value, the vector will only contain that one
value, but if mult.
You have prepared the spread plates below using 0.1 mL from a liquid .pdf
You have prepared the spread plates below using 0.1 mL from a liquid culture of E. coli at an
unknown concentration. Count the colonies that have grown and use the information, together
with the TDF for the corresponding plate, to calculate the average original concentration of your
E. coli suspension.
Solution
to calculate the average original concentration of e.coli suspension,
first we need to find out CFU/ML by formula-
no. of colonies x dilution factor / volume of culture plate
for plate first- TDF-2 x 105, so total number of colony is 12 x ( 2x105) / 0.1 ml = 24x106
second plate TDF is 1 x 106, so CFU/ml is = 6 x 107
so overall average CFU/ml is = 1.5 x 1014 by taking average of both plate sample add both value
than divide by 2 so the final outcome is 1.5 x 1014, the final concentration of E.coli suspension
is 1.5 x 1014 u/ml..
While bacteria exhibit simple cell division where the quantity o.pdf
While bacteria exhibit \"simple cell division\" where the quantity of DNA remains constant
following cell production, why would it be incorrect to say they undergo mitosis?
Solution
The mechanics and sequence of bacterial cell division and mitosis are fairly different.When cells
divide by mitosis in an multicellular organism,it causes the organism to grow bigger and replace
old cells with new ones.However in case of bacteria,cell division is not just a means of producing
new cells instead it is a mechanism of bacerial reproduction.In case of binary fission,the
prokaryotc chromosome repicates, then attaches each copy to a different part of the cell
membrane. When the cell pulls apart,replicated and original chromosomes are
seperated.Cytokinesis then produces two seperate cells.
mitosis is a more complex process and takes place in 5 stages:
prophase,anaphase,metaphase,telophase,cytokinesis.
in binary fission no mitotic spindles are formed. DNA replication takes place at the same time as
DNA seperation.Whereas in mitosis DNA is copied during S phase,whereas it is seperated in M
phase.
Therefore it would be incorrect to say binary fission and mitosis as same..
Which of the following items appears on the income statement before i.pdf
Which of the following items appears on the income statement before income before income
taxes? OOther comprehensive income O Discontinued operations. O Comprehensive income. O
Other revenues and gains.
Solution
The following items appear on the income statement before income before income taxes.
Other revenues and gains.
Explanation:-
If the company earns any income from activity other than the main or core operations it is called
other revenues and gains. It will be shown in income statement before tax is deducted..
What part of the root is responsible for water and nutrient absorptio.pdf
What part of the root is responsible for water and nutrient absorption. Apical meristem root
hairs of the epidermis cortex and pith root cap zone of cellular elongation
Solution
Hi,
Answer of your question is :
2.root hairs of the epidermis.
Explanation:Because it is responsible for water and nutrients absorption from soil which are
important for the plants.
I hope my answer is satisfactory.
Thanks!!.
What is the purpose of the balance sheet Be sure to discuss the thr.pdf
What is the purpose of the balance sheet? Be sure to discuss the three key elements that make up
the balance sheet.
URGENT: NEED ANSWER ASAP
PLEASE RESPOND WITH COPY AND PASTE, NOT ATTACHMENT USE ORIGINAL
CONTENT NOT USED BEFORE ON CHEGG
PLEASE ANSWER THROUGHLY TO ALL ANSWER TO BEST ABILITES ORIGINAL
SOURCE NEVER USED BEFORE!!!
Solution
A balance sheet is a financial statement which represents the worth of the company and its
business at a given point in time. The Balance sheet details what it owns and to whom it owns to.
The purpose of the Balance Sheet is to show the break up of the total assets between the outsider
liabilities and owners\' equity at a point of time.
The balance sheet of a company has three key elements, which are : (1) Assets, which includes
all the current and long-term assets or fixed assets which the company owns, (2) Liabilities,
which includes the current and long-term liabilities payable to the outsiders by the company, (3)
Shareholders\' equity, it constitutes all that belongs to the Shareholders who are the legal owners
of the company, which includes equity capital and retained earnings. The total of its assets is
equal to the sum of the Shareholders\' equity alongwith the Liabilities..
What is culture Why should culture play a role in aiding our unders.pdf
What is culture? Why should culture play a role in aiding our understanding of leadership?
Solution
Culture is the unique characteristics and knowledges or a particular group of people, defined by
their lenguage, cuisine, social habits, art, relgion, music etc.
Culture play an important role on helping us understand leardership because culture define us as
people, depending where you are from will determinate the way you behaive and how you
intereact with others.
When you are the manager of a group that has huge diversity among its member it is important to
understand what motivates each of your employees, you can not assume they all will be
motivated the same, it will depend on their culture..
What are the Federal Reserves major assets and liabilities What a.pdf
What are the Federal Reserve\'s major assets and liabilities? What are the relative amounts of
each (currently...July 2018)?
Solution
Federal reserves assets are Gold reserves,Special drwing rights, reserves position in international
monetary fund and foreign currencies.
Federal reserves liabilities are Federal resrve nbotes, deposits made by depository institutions,
the U.S. Treasury, and others hold in accounts at the Federal Reserve Banks.
Couldn;t get the data on liabilities.
Best of Luck. God BlessAsset in millions of dollars18-AprMay
2018/p1Total1245401228442Gold stock111041110413Special drawing rights2
352402516564Reserve position in International Monetary Fund2 517708175565Foreign
Currencies44338942591.
Use a 5 significance level unless specified otherwise.Please give.pdf
Use a 5% significance level unless specified otherwise.
Please give the answers to two decimal places.
x^2=______________?
Solution
H0: the number of absentees is equally distributed
H1: the number of absentees is more on some days
Here we use
chi-square=Sum((observed-expected)2/expected)Goodness of Fit TestobservedexpectedO - E(O
- E).
two children own two-way radios that have a maximum range of 2 miles.pdf
two children own two-way radios that have a maximum range of 2 miles.Once leaves a certain
point at 1:00 pm. Walking due north at a rate of 4 mi/hr. The other leaves the same point at 1:15
pm. Travling due south at 6 mi/hr. When will they be unable to communicate with each other?
Solution
Time when the first child leaves (T1) =1:00 pm
Speed of first child (S1) = 4 mi/hr
Time when second child leaves (T2) = 1:15 pm
Speed of second child (S2) = 6 mi/hr
Time elapsed until second child leaves=T2-T1=15 minutes
Distance travelled by first child in that time=s1*15 minutes
=4 mi/hr * (1/4)hr
=1 mile
Range of radio=2 miles
Distance between children at 1.15 pm = 1 mile
Remaining range=1 mile
first child and second child are moving in opposite directions hence both distances must be
considered
s=d/t => d=t*s
(distanceNorth)+(distanceSouth)=1 mile
t(S1)+t(S2)=1 mile
t(S1+S2)=1 mile
t(4+6)=1
t(10)=1
t=1/10 hour=60/10 minutes=6 minutes
Thus,10 minutes later the remaining range of 1 mile would also be passed.
Time at that moment = 1.15+6 minutes = 1:21 pm.
The place within an enzyme where a substrate binds is called the ATP.pdf
The place within an enzyme where a substrate binds is called the ATP site Active site Key
hole Transition site If t for two different polypeptides some of their R groups come together to
hold both polypeptides together in a certain 3-dimentional shape. Which level of protein
structure would this describe? primary structure secondary structure tertiary structure
quaternary structure In DNA what nitrogenous base complementanly pairs with T (thymine)?
Solution
14. Active site
the active site is the region of an enzyme where substrate molecules bind and undergo a chemical
reaction.
15. Quaternary structure (quaternary structures arise when a protein is made up of two or more
polypeptide chains).
READ BEFORE YOU START Please read the given Word document fo.pdf
// READ BEFORE YOU START: // Please read the given Word document for the project
description with an illustrartive diagram. // You are given a partially completed program that
creates a list of dogs for an adoption shelter. // Each dog has the corresponding information:
name, breed, and a linked list of checkups. // Please read the instructions above each required
function and follow the directions carefully. // If you modify any of the given code, return types,
or parameters, you risk failing test cases. // // Note, Textbook Section 2.10 gives a case study on
complex linked list operations. // This project is based on that case study. Make sure you read
the code in section 2.10. // The following will be accepted as input in the following format:
\"name:breed\" // Example Input: \"Spot:Terrier\" or \"Daisy:Poodle\" // Valid name:
String containing alphabetical letters beginning with a capital letter // Valid breed: String
containing alphabetical letters beginning with a capital letter // Valid date: String in the
following format: \"MM/DD/YYYY\" ex: \"01/01/2010\" // All input will be a valid length and
no more than the allowed number of dogs will be added to the linked list. #include #include
#include #include // included to check for memory leaks #define CRTDBG_MAP_ALLOC
#include #pragma warning(disable: 4996) // used to create a linked list of containers, each
contaning a \"dog\" struct container { struct dog *dog; struct container *next; } *list =
NULL; // used to hold dog information and linked list of \"checkups\" struct dog { char
name[30]; char breed[30]; struct checkup *checkups; }; // used to create a linked list
of checkups containing \"dates\" struct checkup { char date[30]; struct checkup *next;
}; // forward declaration of functions that have already been implemented void flush(); void
branching(char); void helper(char); void remove_all(struct container*); void display(struct
container*); // the following forward declarations are for functions that require implementation
// return type // name and parameters // points void
add_dog(char*, char*); // 5 struct dog* search_dog(char*);
// 5 void add_checkup(char*, char*); // 10 char*
last_checkup(char*); // 15 void remove_one(char*);
// 15 //
Total: 50 points for hw07 struct container* list_of_breed(char*); // 25 struct
container* list_by_name(); // 25 //
Total: 50 points for hw08 int main() { char ch = \'i\';
printf(\"Dog Adoption Center\ \ \"); do { printf(\"Please enter your
selection:\ \"); printf(\"\\ta: add a new dog to the list\ \"); printf(\"\\ts: search
for a dog on the list\ \"); printf(\"\\tr: remove a dog from the list\ \");
printf(\"\\tc: add a checkup date for dog\ \"); printf(\"\\tl: display last checkup for a
dog\ \"); printf(\"\\tn: display list of dogs by name\ \"); printf(\"\\tb: display
list of dogs of breed\ \"); printf(\"\\tq: quit\ \"); ch = tolower(getchar());
flush(); branching(ch); } while (ch != \'q\'); remove_all(list); list =
NULL; _CrtDumpMemoryLeaks(); .
Refer to the table below. A student creates the table above as a stu.pdf
Refer to the table below. A student creates the table above as a study guide. Evaluate the
accuracy of the information shown. The information is not accurate because the anterior air sacs
push air when they expand and pull air when then contract. The information is not accurate
because air sacs expand during exhalation and contract during inhalation. The information
shown is accurate. The information is not accurate because air does not flow through the lungs
during exhalation.
Solution
The information shown is accurate.
During inhalation, the posterior air sacs expand and the air is filled in posterior air sac and lungs
and air fills in the anterior sac. Both the sacs expand during inhalation. During exhalation, both
the sacs contracts and pushes air from posterior sac through lungs and from anterior sacs to
outside the body..
prove the followings1- every subset of a finite set is finite2-.pdf
prove the followings:
1- every subset of a finite set is finite
2- if s is denumerable, then s is equinumerous with a proper subset of itself
Solution
Post one more question to get the answer to the second problem. Thanks
Proof using induction:
1) Base Case (n=1)
There is only one element in the finite set, then we can write it as
X \\ a = Phi, since there won\'t be any element in the set if we removing phi, hence the phi is a
finite set since it contains only one element and this is an empty element
2) Let us assume that the solution is true for (n=k), i.e. for an finite set with k elements, every
subset of that set will be finite
3) Now we need to prove our hypothesis for the set containing (k+1) elements
Let us assume that X has (k+1) elements if Y is a subset of X, then it will have atmost k+1
elements, which is equal to X
Since X is finite, therefore Y will also be finite
Otherwise, there exists an element that belong to X but not to Y
a belongs to X\\Y
=> it implies that Y is a subset of X\\ a
This set contain max n elements, hence the Y will be finite.
Problem 9-4 Nonconstant growth valuation Hart Enterprises recently pa.pdf
Problem 9-4 Nonconstant growth valuation Hart Enterprises recently paid a dividend, DO of
$1.00. It expects to have nonconstant growth of 14% for 2 years followed by a constant rate of
4% thereafter. The m s required return is 16% a. How far away is the horizon date? I. The
terminal, or horizon, date is infinity since common stocks do not have a maturity date. II. The
terminal, or horizon, date is Year 0 since the value of a common stock is the present value of all
future expected dividends at time zero III. The terminal, or horizon, date is the date when the
growth rate becomes nonconstant. This occurs at time zero. IV. The terminal, or horizon, date is
the date when the growth rate becomes constant. This occurs at the beginning of Year 2. V. The
terminal, or horizon, date is the date when the growth rate becomes constant. This occurs at the
end of Year 2. Select- b. What is the firm\'s horizon, or continuing, value? Round your answer to
two decimal places c. What is the firm\'s intrinsic value today, Po? Round your answer to two
decimal places.
Solution
Answer a.
The terminal, or horizon, date is the date when the growth rate becomes constant. This occurs at
the end of Year 2.
Answer b.
D0 = $1.00
Growth rate for next 2 years is 14%, followed by an constant growth rate (g) of 4%
D1 = $1.00 * 1.14 = $1.14
D2 = $1.14 * 1.14 = $1.2996
D3 = $1.2996 * 1.04 = $1.3516
Required return, r = 16%
Horizon Value of Firm = D3 / (r - g)
Horizon Value of Firm = $1.3516 / (0.16 - 0.04)
Horizon Value of Firm = $11.26
Answer c.
Intrinsic Value of Firm = $1.14/1.16 + $1.2996/1.16^2 + $11.26/1.16^2
Intrinsic Value of Firm = $10.32.
Please type the answer 4. What government entity is primarily in.pdf
Please type the answer 4. What government entity is primarily in charge of regulating banks?
What government entity regulates mutual funds? (2 points)
Solution
Bank Regulator
(i) Board of Governors of the Federal Reserve System- It regulates state chartered banks and
trust companies that belong to the Federal Reserve System.
(ii) Federal Deposit Insurance Corporation- It regulates state chartered banks that do not belong
to the Federal Reserve System.
(iii) Office of the Comptroller of Currency- It regulates banks that have the word \"National\" in
or the letters \"N.A.\" after their names
Mutual Fund Regulator = U.S. Securities and Exchange Commission.
On the basis of the presence of the appendix, what might you infer ab.pdf
On the basis of the presence of the appendix, what might you infer about dietary habits of our
evolutionary antecedents?
Solution
The main function of the appendix is to hydrolyze cellulose and indigestible plant material but it
is present in mammals that includes rodents and primates which are not eating cellulose as food
souce but may be in past they used to eat that so still it is there, Although there is no main
function of this organ and known as vestigial organ but there is some report that it having some
role in immune system. Some herbivorous animals, such as rabbits, have a terminal vermiform
appendix..
Name 4 functions of matrix in composite materials .pdf
Name 4 functions of matrix in composite materials
Name 4 functions of matrix in composite materials
Name 4 functions of matrix in composite materials
Name 4 functions of matrix in composite materials
Solution
Matrix is binding in nature and homegenoeus material.
In compostie materials, it gives the medium for holding, joining different strucutre in composite
material.
It is continuous.
It gives the protection for inner parts from the natural forces..
Lab 13 Practicing STLVector Container1a. Write a template func.pdf
Lab 13: Practicing STL
Vector Container:
1a. Write a template function(in header file) to search a value stored in a vector and return the
position(index) of the item if found; otherwise, return a negative value. Then write a driver to
test it. The driver should at least test two different type of vector. Use vector index to do it.
1b. Write a template function(in header file) to search a value stored in a vector and return the
position(index) of the item if found; otherwise, return a negative value. Then write a driver to
test it. The driver should at least test two different type of vector. Use iterator to do it.
Deque Container:
2a. Write a function to add first 6 integers alternately to front and back of a deque. (in header
file)
2b. Write a template function to display the content of a deque using iterator (in header file)
2c. Write a template function to change back value to a specified value using iterator (in header
file)
Then write a driver to test the above three template functions.
List Container – see textbook page 605 for basic operations:
3a. Write a template function to read values from an input stream to a list (in header file)
3b. Write a template function to fill in a list with a given vector (in header file)
3c. Write a template function to change a given value in a list to another given value(use find(),
insert() and erase()) (in header file)
Then write a driver to test the above three template functions.
Queue wrapper with list
4. Write a template queue class as defined below:
private data member: a STL list
public member functions:
-empty
-size
-enqueue
-deque
-front
-back
Then write a driver to test the above queue class.
Follow our class coding standard to complete this lab, compile and run it, check out for credit
Solution
Here is the answer for the questions:
Please compile using -std=c++11 option
example g++ -std=c++11 q3.cpp
Q1 files
compile : g++ -std=c++11 q1.cpp
q1.h
#include
using std::vector;
template
int searchUsingIndex(vector values, T item)
{
for(int i = 0 ; i < values.size(); ++i)
{
if(values[i] == item)
return i;
}
return -1;
}
template
int searchUsingIterator(vector values, T item)
{
int i = 0;
for(typename vector::iterator it=values.begin(); it != values.end(); ++it, ++i)
{
if(*it == item)
return i;
}
return -1;
}
q1.cpp
#include
#include
#include \"q1.h\"
using namespace std;
int main()
{
vector num = {3,6,10,1};
vector names = {\"alice\",\"bob\",\"john\" ,\"peter\"};
string search=\"john\";
cout<<\"Index of 2 in num vector using index: \"<
#include
using namespace std;
//we need to pass by reference
void addFrontBack(deque &q)
{
for(int i = 1; i < 7; i ++)
{
if(i % 2 == 1)
q.push_front(i);
else
q.push_back(i);
}
}
template
void print(const deque &q)
{
for(typename deque::const_iterator it = q.begin(); it != q.end(); ++it)
{
cout<< *it <
void changeBack(deque &q, T newValue)
{
if(q.empty())
return;
typename deque::iterator it = q.end()-1;//get 1 location behind end
*(it) = newValue;
}
q2.cpp
#include .
In which generation is a recessive deleterious allele MOST likely.pdf
In which generation is a recessive deleterious allele MOST likely to negatively affect the
fitness of the individual expressing it?
gametophyte
equally likely in both sporophyte and gametophyte
highly improbable in both generations
sporophyte
Solution
The gametophyte are gamete producing phase which are haploid in nature while sporophytes are
spore forming an ddiploid in nature. The haploid games when fuse form zygote and then this
forms spores. When we consider recessive alleles, they are expressed only when there is no
dominant allele in their zygote because gametes produced will only have one copy of
chromosome either dominant or recessive. The fusion of one dominant and one recessive will
give a zygote, diploid, and recessive allele won\'t be expressed. Therefore, if gametophyte is
equally likely in both sporophyte, the negative affect of recessive allele on the fitness of
individual expressing it is more..
In a test tube you combine competent E. coli cells with your genetic.pdf
In a test tube you combine competent E. coli cells with your genetically engineered plasmid that
contains the gene for antibiotic resistance. You treat the solution and plate your product on
antibiotic containing media overnight. The next day you see growth on your plate.
1)Was there horizontal gene transfer?
2)How do you know?
3)If so, what kind of gene transfer?
Solution
no what we see next day is only those bacterial colonies on the plate which got transformed
previously that is those bacterial colonies in which antibiotic resistance plasmid got sucessfully
transformed in them.... because we are growing them on antibiotic contaning medium.
SO THERE WAS NOT ANY HORIZONTAL GENE TRANSFER
WE CANNOT ASSUME THAT IT WAS BACTERIAL CONJUGATION (HORIZONTAL
GENE TRANSFER) AND IN CONJUGATION RESISTANCE GENE GOT EXCHANGED
BETWEEN BACTRIUM, BECAUSE RESISTANCE GENE IS ON PLASMID NOT IN
BACTERIUM GENOME ... AND IT SEEMS TO BE TRANSIENT TRANSFORMATION
RATHER THAN STABLE TRANSFORMATION. THE possibility of horizontal gene transfer
is very less compared to sucessful transformation with plasmid because the cells were already
competent and could have taken up plasmid easily
Hope that answers ..... Regards.
In a certain year, 89 of all Caucasians in the U.S., 74 of all Afr.pdf
In a certain year, 89% of all Caucasians in the U.S., 74% of all African-Americans, 74% of all
Hispanics, and 76% of residents not classified into one of these groups used the Internet for e-
mail. At that time, the U.S. population was 65% Caucasian, 10% African-American, and 12%
Hispanic. What percentage of U.S. residents who used the Internet for e-mail were Hispanic?
(Round your answer to the nearest whole percent.)
Solution.
Immune cells that operate by phagocytizing harmful bacteria, rely on.pdf
Immune cells that operate by phagocytizing harmful bacteria, rely on their cytoskeleton for their
ability to move and for their ability release molecules that attract other immune cells.Explain
which parts of the cytoskeleton are involved in these two processes and how cytoskeletal
proteins are able to help the cell move, and also release signaling molecules.
Solution
Leucocytes ie..Macrophages are the primary cells invovled in phagocytosis, the engulfment of
the harmful bacterial cells for this lysosomes are the organelles invovled in the formation of
phagolysosome complex which release hydrolytic acid hydrolases so that it digested the
pathogenic bacteria, for the movement of the vesicles in the phagolysosome the cytoskeleton
microfilaments invovled in the movement of the lysosomes.
In signalling pathways the activation of the T cells occurs due to the cytoskeleton actin filaments
which triggers for the the formation of T cells,shape development , movement, formation of the
synapses.thus it plays a major role in the immune response.
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A Strategic Approach: GenAI in Education
Artificial Intelligence (AI) technologies such as Generative AI, Image Generators and Large Language Models have had a dramatic impact on teaching, learning and assessment over the past 18 months. The most immediate threat AI posed was to Academic Integrity with Higher Education Institutes (HEIs) focusing their efforts on combating the use of GenAI in assessment. Guidelines were developed for staff and students, policies put in place too. Innovative educators have forged paths in the use of Generative AI for teaching, learning and assessments leading to pockets of transformation springing up across HEIs, often with little or no top-down guidance, support or direction.
This Gasta posits a strategic approach to integrating AI into HEIs to prepare staff, students and the curriculum for an evolving world and workplace. We will highlight the advantages of working with these technologies beyond the realm of teaching, learning and assessment by considering prompt engineering skills, industry impact, curriculum changes, and the need for staff upskilling. In contrast, not engaging strategically with Generative AI poses risks, including falling behind peers, missed opportunities and failing to ensure our graduates remain employable. The rapid evolution of AI technologies necessitates a proactive and strategic approach if we are to remain relevant.
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Which of the following items appears on the income statement before i.pdf
Which of the following items appears on the income statement before income before income
taxes? OOther comprehensive income O Discontinued operations. O Comprehensive income. O
Other revenues and gains.
Solution
The following items appear on the income statement before income before income taxes.
Other revenues and gains.
Explanation:-
If the company earns any income from activity other than the main or core operations it is called
other revenues and gains. It will be shown in income statement before tax is deducted..
What part of the root is responsible for water and nutrient absorptio.pdf
What part of the root is responsible for water and nutrient absorption. Apical meristem root
hairs of the epidermis cortex and pith root cap zone of cellular elongation
Solution
Hi,
Answer of your question is :
2.root hairs of the epidermis.
Explanation:Because it is responsible for water and nutrients absorption from soil which are
important for the plants.
I hope my answer is satisfactory.
Thanks!!.
What is the purpose of the balance sheet Be sure to discuss the thr.pdf
What is the purpose of the balance sheet? Be sure to discuss the three key elements that make up
the balance sheet.
URGENT: NEED ANSWER ASAP
PLEASE RESPOND WITH COPY AND PASTE, NOT ATTACHMENT USE ORIGINAL
CONTENT NOT USED BEFORE ON CHEGG
PLEASE ANSWER THROUGHLY TO ALL ANSWER TO BEST ABILITES ORIGINAL
SOURCE NEVER USED BEFORE!!!
Solution
A balance sheet is a financial statement which represents the worth of the company and its
business at a given point in time. The Balance sheet details what it owns and to whom it owns to.
The purpose of the Balance Sheet is to show the break up of the total assets between the outsider
liabilities and owners\' equity at a point of time.
The balance sheet of a company has three key elements, which are : (1) Assets, which includes
all the current and long-term assets or fixed assets which the company owns, (2) Liabilities,
which includes the current and long-term liabilities payable to the outsiders by the company, (3)
Shareholders\' equity, it constitutes all that belongs to the Shareholders who are the legal owners
of the company, which includes equity capital and retained earnings. The total of its assets is
equal to the sum of the Shareholders\' equity alongwith the Liabilities..
What is culture Why should culture play a role in aiding our unders.pdf
What is culture? Why should culture play a role in aiding our understanding of leadership?
Solution
Culture is the unique characteristics and knowledges or a particular group of people, defined by
their lenguage, cuisine, social habits, art, relgion, music etc.
Culture play an important role on helping us understand leardership because culture define us as
people, depending where you are from will determinate the way you behaive and how you
intereact with others.
When you are the manager of a group that has huge diversity among its member it is important to
understand what motivates each of your employees, you can not assume they all will be
motivated the same, it will depend on their culture..
What are the Federal Reserves major assets and liabilities What a.pdf
What are the Federal Reserve\'s major assets and liabilities? What are the relative amounts of
each (currently...July 2018)?
Solution
Federal reserves assets are Gold reserves,Special drwing rights, reserves position in international
monetary fund and foreign currencies.
Federal reserves liabilities are Federal resrve nbotes, deposits made by depository institutions,
the U.S. Treasury, and others hold in accounts at the Federal Reserve Banks.
Couldn;t get the data on liabilities.
Best of Luck. God BlessAsset in millions of dollars18-AprMay
2018/p1Total1245401228442Gold stock111041110413Special drawing rights2
352402516564Reserve position in International Monetary Fund2 517708175565Foreign
Currencies44338942591.
Use a 5 significance level unless specified otherwise.Please give.pdf
Use a 5% significance level unless specified otherwise.
Please give the answers to two decimal places.
x^2=______________?
Solution
H0: the number of absentees is equally distributed
H1: the number of absentees is more on some days
Here we use
chi-square=Sum((observed-expected)2/expected)Goodness of Fit TestobservedexpectedO - E(O
- E).
two children own two-way radios that have a maximum range of 2 miles.pdf
two children own two-way radios that have a maximum range of 2 miles.Once leaves a certain
point at 1:00 pm. Walking due north at a rate of 4 mi/hr. The other leaves the same point at 1:15
pm. Travling due south at 6 mi/hr. When will they be unable to communicate with each other?
Solution
Time when the first child leaves (T1) =1:00 pm
Speed of first child (S1) = 4 mi/hr
Time when second child leaves (T2) = 1:15 pm
Speed of second child (S2) = 6 mi/hr
Time elapsed until second child leaves=T2-T1=15 minutes
Distance travelled by first child in that time=s1*15 minutes
=4 mi/hr * (1/4)hr
=1 mile
Range of radio=2 miles
Distance between children at 1.15 pm = 1 mile
Remaining range=1 mile
first child and second child are moving in opposite directions hence both distances must be
considered
s=d/t => d=t*s
(distanceNorth)+(distanceSouth)=1 mile
t(S1)+t(S2)=1 mile
t(S1+S2)=1 mile
t(4+6)=1
t(10)=1
t=1/10 hour=60/10 minutes=6 minutes
Thus,10 minutes later the remaining range of 1 mile would also be passed.
Time at that moment = 1.15+6 minutes = 1:21 pm.
The place within an enzyme where a substrate binds is called the ATP.pdf
The place within an enzyme where a substrate binds is called the ATP site Active site Key
hole Transition site If t for two different polypeptides some of their R groups come together to
hold both polypeptides together in a certain 3-dimentional shape. Which level of protein
structure would this describe? primary structure secondary structure tertiary structure
quaternary structure In DNA what nitrogenous base complementanly pairs with T (thymine)?
Solution
14. Active site
the active site is the region of an enzyme where substrate molecules bind and undergo a chemical
reaction.
15. Quaternary structure (quaternary structures arise when a protein is made up of two or more
polypeptide chains).
READ BEFORE YOU START Please read the given Word document fo.pdf
// READ BEFORE YOU START: // Please read the given Word document for the project
description with an illustrartive diagram. // You are given a partially completed program that
creates a list of dogs for an adoption shelter. // Each dog has the corresponding information:
name, breed, and a linked list of checkups. // Please read the instructions above each required
function and follow the directions carefully. // If you modify any of the given code, return types,
or parameters, you risk failing test cases. // // Note, Textbook Section 2.10 gives a case study on
complex linked list operations. // This project is based on that case study. Make sure you read
the code in section 2.10. // The following will be accepted as input in the following format:
\"name:breed\" // Example Input: \"Spot:Terrier\" or \"Daisy:Poodle\" // Valid name:
String containing alphabetical letters beginning with a capital letter // Valid breed: String
containing alphabetical letters beginning with a capital letter // Valid date: String in the
following format: \"MM/DD/YYYY\" ex: \"01/01/2010\" // All input will be a valid length and
no more than the allowed number of dogs will be added to the linked list. #include #include
#include #include // included to check for memory leaks #define CRTDBG_MAP_ALLOC
#include #pragma warning(disable: 4996) // used to create a linked list of containers, each
contaning a \"dog\" struct container { struct dog *dog; struct container *next; } *list =
NULL; // used to hold dog information and linked list of \"checkups\" struct dog { char
name[30]; char breed[30]; struct checkup *checkups; }; // used to create a linked list
of checkups containing \"dates\" struct checkup { char date[30]; struct checkup *next;
}; // forward declaration of functions that have already been implemented void flush(); void
branching(char); void helper(char); void remove_all(struct container*); void display(struct
container*); // the following forward declarations are for functions that require implementation
// return type // name and parameters // points void
add_dog(char*, char*); // 5 struct dog* search_dog(char*);
// 5 void add_checkup(char*, char*); // 10 char*
last_checkup(char*); // 15 void remove_one(char*);
// 15 //
Total: 50 points for hw07 struct container* list_of_breed(char*); // 25 struct
container* list_by_name(); // 25 //
Total: 50 points for hw08 int main() { char ch = \'i\';
printf(\"Dog Adoption Center\ \ \"); do { printf(\"Please enter your
selection:\ \"); printf(\"\\ta: add a new dog to the list\ \"); printf(\"\\ts: search
for a dog on the list\ \"); printf(\"\\tr: remove a dog from the list\ \");
printf(\"\\tc: add a checkup date for dog\ \"); printf(\"\\tl: display last checkup for a
dog\ \"); printf(\"\\tn: display list of dogs by name\ \"); printf(\"\\tb: display
list of dogs of breed\ \"); printf(\"\\tq: quit\ \"); ch = tolower(getchar());
flush(); branching(ch); } while (ch != \'q\'); remove_all(list); list =
NULL; _CrtDumpMemoryLeaks(); .
Refer to the table below. A student creates the table above as a stu.pdf
Refer to the table below. A student creates the table above as a study guide. Evaluate the
accuracy of the information shown. The information is not accurate because the anterior air sacs
push air when they expand and pull air when then contract. The information is not accurate
because air sacs expand during exhalation and contract during inhalation. The information
shown is accurate. The information is not accurate because air does not flow through the lungs
during exhalation.
Solution
The information shown is accurate.
During inhalation, the posterior air sacs expand and the air is filled in posterior air sac and lungs
and air fills in the anterior sac. Both the sacs expand during inhalation. During exhalation, both
the sacs contracts and pushes air from posterior sac through lungs and from anterior sacs to
outside the body..
prove the followings1- every subset of a finite set is finite2-.pdf
prove the followings:
1- every subset of a finite set is finite
2- if s is denumerable, then s is equinumerous with a proper subset of itself
Solution
Post one more question to get the answer to the second problem. Thanks
Proof using induction:
1) Base Case (n=1)
There is only one element in the finite set, then we can write it as
X \\ a = Phi, since there won\'t be any element in the set if we removing phi, hence the phi is a
finite set since it contains only one element and this is an empty element
2) Let us assume that the solution is true for (n=k), i.e. for an finite set with k elements, every
subset of that set will be finite
3) Now we need to prove our hypothesis for the set containing (k+1) elements
Let us assume that X has (k+1) elements if Y is a subset of X, then it will have atmost k+1
elements, which is equal to X
Since X is finite, therefore Y will also be finite
Otherwise, there exists an element that belong to X but not to Y
a belongs to X\\Y
=> it implies that Y is a subset of X\\ a
This set contain max n elements, hence the Y will be finite.
Problem 9-4 Nonconstant growth valuation Hart Enterprises recently pa.pdf
Problem 9-4 Nonconstant growth valuation Hart Enterprises recently paid a dividend, DO of
$1.00. It expects to have nonconstant growth of 14% for 2 years followed by a constant rate of
4% thereafter. The m s required return is 16% a. How far away is the horizon date? I. The
terminal, or horizon, date is infinity since common stocks do not have a maturity date. II. The
terminal, or horizon, date is Year 0 since the value of a common stock is the present value of all
future expected dividends at time zero III. The terminal, or horizon, date is the date when the
growth rate becomes nonconstant. This occurs at time zero. IV. The terminal, or horizon, date is
the date when the growth rate becomes constant. This occurs at the beginning of Year 2. V. The
terminal, or horizon, date is the date when the growth rate becomes constant. This occurs at the
end of Year 2. Select- b. What is the firm\'s horizon, or continuing, value? Round your answer to
two decimal places c. What is the firm\'s intrinsic value today, Po? Round your answer to two
decimal places.
Solution
Answer a.
The terminal, or horizon, date is the date when the growth rate becomes constant. This occurs at
the end of Year 2.
Answer b.
D0 = $1.00
Growth rate for next 2 years is 14%, followed by an constant growth rate (g) of 4%
D1 = $1.00 * 1.14 = $1.14
D2 = $1.14 * 1.14 = $1.2996
D3 = $1.2996 * 1.04 = $1.3516
Required return, r = 16%
Horizon Value of Firm = D3 / (r - g)
Horizon Value of Firm = $1.3516 / (0.16 - 0.04)
Horizon Value of Firm = $11.26
Answer c.
Intrinsic Value of Firm = $1.14/1.16 + $1.2996/1.16^2 + $11.26/1.16^2
Intrinsic Value of Firm = $10.32.
Please type the answer 4. What government entity is primarily in.pdf
Please type the answer 4. What government entity is primarily in charge of regulating banks?
What government entity regulates mutual funds? (2 points)
Solution
Bank Regulator
(i) Board of Governors of the Federal Reserve System- It regulates state chartered banks and
trust companies that belong to the Federal Reserve System.
(ii) Federal Deposit Insurance Corporation- It regulates state chartered banks that do not belong
to the Federal Reserve System.
(iii) Office of the Comptroller of Currency- It regulates banks that have the word \"National\" in
or the letters \"N.A.\" after their names
Mutual Fund Regulator = U.S. Securities and Exchange Commission.
On the basis of the presence of the appendix, what might you infer ab.pdf
On the basis of the presence of the appendix, what might you infer about dietary habits of our
evolutionary antecedents?
Solution
The main function of the appendix is to hydrolyze cellulose and indigestible plant material but it
is present in mammals that includes rodents and primates which are not eating cellulose as food
souce but may be in past they used to eat that so still it is there, Although there is no main
function of this organ and known as vestigial organ but there is some report that it having some
role in immune system. Some herbivorous animals, such as rabbits, have a terminal vermiform
appendix..
Name 4 functions of matrix in composite materials .pdf
Name 4 functions of matrix in composite materials
Name 4 functions of matrix in composite materials
Name 4 functions of matrix in composite materials
Name 4 functions of matrix in composite materials
Solution
Matrix is binding in nature and homegenoeus material.
In compostie materials, it gives the medium for holding, joining different strucutre in composite
material.
It is continuous.
It gives the protection for inner parts from the natural forces..
Lab 13 Practicing STLVector Container1a. Write a template func.pdf
Lab 13: Practicing STL
Vector Container:
1a. Write a template function(in header file) to search a value stored in a vector and return the
position(index) of the item if found; otherwise, return a negative value. Then write a driver to
test it. The driver should at least test two different type of vector. Use vector index to do it.
1b. Write a template function(in header file) to search a value stored in a vector and return the
position(index) of the item if found; otherwise, return a negative value. Then write a driver to
test it. The driver should at least test two different type of vector. Use iterator to do it.
Deque Container:
2a. Write a function to add first 6 integers alternately to front and back of a deque. (in header
file)
2b. Write a template function to display the content of a deque using iterator (in header file)
2c. Write a template function to change back value to a specified value using iterator (in header
file)
Then write a driver to test the above three template functions.
List Container – see textbook page 605 for basic operations:
3a. Write a template function to read values from an input stream to a list (in header file)
3b. Write a template function to fill in a list with a given vector (in header file)
3c. Write a template function to change a given value in a list to another given value(use find(),
insert() and erase()) (in header file)
Then write a driver to test the above three template functions.
Queue wrapper with list
4. Write a template queue class as defined below:
private data member: a STL list
public member functions:
-empty
-size
-enqueue
-deque
-front
-back
Then write a driver to test the above queue class.
Follow our class coding standard to complete this lab, compile and run it, check out for credit
Solution
Here is the answer for the questions:
Please compile using -std=c++11 option
example g++ -std=c++11 q3.cpp
Q1 files
compile : g++ -std=c++11 q1.cpp
q1.h
#include
using std::vector;
template
int searchUsingIndex(vector values, T item)
{
for(int i = 0 ; i < values.size(); ++i)
{
if(values[i] == item)
return i;
}
return -1;
}
template
int searchUsingIterator(vector values, T item)
{
int i = 0;
for(typename vector::iterator it=values.begin(); it != values.end(); ++it, ++i)
{
if(*it == item)
return i;
}
return -1;
}
q1.cpp
#include
#include
#include \"q1.h\"
using namespace std;
int main()
{
vector num = {3,6,10,1};
vector names = {\"alice\",\"bob\",\"john\" ,\"peter\"};
string search=\"john\";
cout<<\"Index of 2 in num vector using index: \"<
#include
using namespace std;
//we need to pass by reference
void addFrontBack(deque &q)
{
for(int i = 1; i < 7; i ++)
{
if(i % 2 == 1)
q.push_front(i);
else
q.push_back(i);
}
}
template
void print(const deque &q)
{
for(typename deque::const_iterator it = q.begin(); it != q.end(); ++it)
{
cout<< *it <
void changeBack(deque &q, T newValue)
{
if(q.empty())
return;
typename deque::iterator it = q.end()-1;//get 1 location behind end
*(it) = newValue;
}
q2.cpp
#include .
In which generation is a recessive deleterious allele MOST likely.pdf
In which generation is a recessive deleterious allele MOST likely to negatively affect the
fitness of the individual expressing it?
gametophyte
equally likely in both sporophyte and gametophyte
highly improbable in both generations
sporophyte
Solution
The gametophyte are gamete producing phase which are haploid in nature while sporophytes are
spore forming an ddiploid in nature. The haploid games when fuse form zygote and then this
forms spores. When we consider recessive alleles, they are expressed only when there is no
dominant allele in their zygote because gametes produced will only have one copy of
chromosome either dominant or recessive. The fusion of one dominant and one recessive will
give a zygote, diploid, and recessive allele won\'t be expressed. Therefore, if gametophyte is
equally likely in both sporophyte, the negative affect of recessive allele on the fitness of
individual expressing it is more..
In a test tube you combine competent E. coli cells with your genetic.pdf
In a test tube you combine competent E. coli cells with your genetically engineered plasmid that
contains the gene for antibiotic resistance. You treat the solution and plate your product on
antibiotic containing media overnight. The next day you see growth on your plate.
1)Was there horizontal gene transfer?
2)How do you know?
3)If so, what kind of gene transfer?
Solution
no what we see next day is only those bacterial colonies on the plate which got transformed
previously that is those bacterial colonies in which antibiotic resistance plasmid got sucessfully
transformed in them.... because we are growing them on antibiotic contaning medium.
SO THERE WAS NOT ANY HORIZONTAL GENE TRANSFER
WE CANNOT ASSUME THAT IT WAS BACTERIAL CONJUGATION (HORIZONTAL
GENE TRANSFER) AND IN CONJUGATION RESISTANCE GENE GOT EXCHANGED
BETWEEN BACTRIUM, BECAUSE RESISTANCE GENE IS ON PLASMID NOT IN
BACTERIUM GENOME ... AND IT SEEMS TO BE TRANSIENT TRANSFORMATION
RATHER THAN STABLE TRANSFORMATION. THE possibility of horizontal gene transfer
is very less compared to sucessful transformation with plasmid because the cells were already
competent and could have taken up plasmid easily
Hope that answers ..... Regards.
In a certain year, 89 of all Caucasians in the U.S., 74 of all Afr.pdf
In a certain year, 89% of all Caucasians in the U.S., 74% of all African-Americans, 74% of all
Hispanics, and 76% of residents not classified into one of these groups used the Internet for e-
mail. At that time, the U.S. population was 65% Caucasian, 10% African-American, and 12%
Hispanic. What percentage of U.S. residents who used the Internet for e-mail were Hispanic?
(Round your answer to the nearest whole percent.)
Solution.
Immune cells that operate by phagocytizing harmful bacteria, rely on.pdf
Immune cells that operate by phagocytizing harmful bacteria, rely on their cytoskeleton for their
ability to move and for their ability release molecules that attract other immune cells.Explain
which parts of the cytoskeleton are involved in these two processes and how cytoskeletal
proteins are able to help the cell move, and also release signaling molecules.
Solution
Leucocytes ie..Macrophages are the primary cells invovled in phagocytosis, the engulfment of
the harmful bacterial cells for this lysosomes are the organelles invovled in the formation of
phagolysosome complex which release hydrolytic acid hydrolases so that it digested the
pathogenic bacteria, for the movement of the vesicles in the phagolysosome the cytoskeleton
microfilaments invovled in the movement of the lysosomes.
In signalling pathways the activation of the T cells occurs due to the cytoskeleton actin filaments
which triggers for the the formation of T cells,shape development , movement, formation of the
synapses.thus it plays a major role in the immune response.
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