3. ECE 663
• So far we learned the basics of semiconductor physics, culminating
in the Minority Carrier Diffusion Equation
• We now encounter our simplest electronic device, a diode
• Understanding the principle requires the ability to draw band-
diagrams
• Making this quantitative requires ability to solve MCDE
(only exponentials!)
• Here we only do the equilibrium analysis
5. ECE 663
P-N junction diode
V
I
I = I0(e
qV/kT
-1)
pn v
I
p
0 = q(ni
2/ND) (Lp/p)
6. ECE 663
P-N Junctions - Equilibrium
<= P-type, low EF
- = fixed ionized acceptors
+ = mobile holes, p
What happens when these bandstructures collide?
• Fermi energy must be constant at equilibrium, so bands
must bend near interface
• Far from the interface, bandstructures must revert
7. ECE 663
Time < 0
P-type piece N-type piece
Time < 0: Pieces separated
9. ECE 663
Hole gradient
Jp, diffusion = -qDp dp/dx = current right, holes right
Electron gradient
Jn,diffusion = -qDn dn/dx = current right, electrons right
Gradients drive diffusion
left
11. ECE 663
But charges can’t venture too
far from the interface because
their Coulomb forces pull them back!
++
- -
+
+
+
+
- -
- -
- -
- -
-
+
+
+
++
15. ECE 663
How much is the Built-in Voltage?
Right
i
F
Left
F
i
bi E
E
E
E
qV )
(
)
( −
+
−
=
P side N side
=
−
=
−
i
a
Left
F
i
kT
E
E
i
a
a
n
N
kT
E
E
e
n
N
N
p
F
i
ln
)
(
)
(
=
−
=
−
i
d
Right
i
F
kT
E
E
i
d
d
n
N
kT
E
E
e
n
N
N
n
i
F
ln
)
(
)
(
17. ECE 663
Special case: One-sided Junctions
• One side very heavily doped so that Fermi level is at band edge.
• e.g. p+-n junction (heavy B implant into lightly doped substrate)
+
=
=
−
=
−
−
i
d
G
bi
i
D
Right
i
F
G
V
i
Left
F
i
n
N
q
kT
q
E
V
n
N
kT
E
E
E
E
E
E
E
ln
2
ln
)
(
2
/
)
(
18. ECE 663
How wide is the depletion region?
kT
E
E
i
F
i
e
n
p
)
( −
= kT
E
E
i
i
F
e
n
n
)
( −
=
23. ECE 663
How far does Wd extend into each junction?
Depletion width on the n-side depends on the doping on the p-side
Depletion width on the p-side depends on the doping on the n-side
e.g. if NA>>ND then xn>>xp One-sided junction
+
=
+
=
D
A
A
n
A
D
A
n
N
N
N
W
x
or
N
N
N
x
W
+
=
+
=
+
=
D
A
D
p
A
D
A
D
A
p
A
D
A
n
N
N
N
W
x
or
N
N
N
N
N
x
N
N
N
x
W
27. ECE 663
Reverse Bias
• +Voltage to the n side and –Voltage to the p side:
holes (+) out of P-side
Vapplied is sucking more:
electrons (-) out of N-side
Depletion region will be larger
29. ECE 663
Reverse Bias depletion
( )( )
2
1
0
2
+
+
= rev
bi
A
D
D
A
S
V
V
N
N
N
N
q
K
W
( )
+
=
D
A
A
rev
n
N
N
N
V
W
x ( )
+
=
D
A
D
rev
p
N
N
N
V
W
x
Applied voltage disturbs equilibrium EF no longer constant
Reverse bias adds to the effect of built-in voltage
30. ECE 663
Forward Bias
holes (+) out of P-side
Vapplied is sucking more:
electrons (-) out of N-side
+ -
Negative voltage to n side positive to p side
More electrons supplied to n, more holes to p
Depletion region gets smaller
31. ECE 663
Forward Bias Depletion
( )( )
2
1
0
2
−
+
= fwd
bi
A
D
D
A
S
V
V
N
N
N
N
q
K
W
( )
+
=
D
A
A
fwd
n
N
N
N
V
W
x ( )
+
=
D
A
D
fwd
p
N
N
N
V
W
x
32. ECE 663
General Expression
• Convention = Vappl= + for forward bias
Vappl= - for reverse bias
( )( )
2
1
0
2
−
+
= appl
bi
A
D
D
A
S
V
V
N
N
N
N
q
K
W
( )
+
=
D
A
A
appl
n
N
N
N
V
W
x ( )
+
=
D
A
D
appl
p
N
N
N
V
W
x
33. ECE 663
Bands = plots of electron energy
Voltage = potential energy per (+) charge
Positive voltage pulls bands down- bands are plots of electron energy
Fermi level is not constant Current Flow
Fn
Fp
n = nie(Fn-Ei)/kT
p = nie(Ei-Fp)/kT
34. In summary
A p-n junction at equilibrium sees a depletion width
and a built-in potential barrier. Their values depend on
the individual doping concentrations
Forward biasing the junction shrinks the depletion width
and the barrier, allowing thermionic emission and higher
current. The current is driven by the splitting of the
quasi-Fermi levels
Reverse biasing the junction extends the depletion width
and the barrier, cutting off current and creating a strong
I-V asymmetry
In the next lecture, we’ll make this analysis quantitative
by solving the MCDE with suitable boundary conditions