4) (30 pts) What is pH of (show all your work) A) 0.038 M solution of KOH B) 0.0022 M solution of Ca(OH)2 D C) 0.038 M solution of HF D) 0.0022 M solution of H2S E) 000022 M solution of H2S Solution Answer - A- pOH = -log(OH-) =-log(0.038) = 1.42 We know that, pH +pOH = 14 pH = 14-1.42 = 12.58 B. 1 mol of Ca(OH)2 produce two moles of OH- pOH = -log(2*0.0022) = 2.356 pH = 14-2.356 = 11.644 C- HF produce H+ ions in the solution. pH= -log(H+) = -log( 0.038) = 1.42 D. it gives twom moles of H+ for each mole of H2S pH = -log(2*0.0022) = 2.356 E. SAme as above- pH =-log(0.00022*2) = 3.356 .