The positron decay of 15O goes directly to the ground state of 15N; n.pdf

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The positron decay of 15O goes directly to the ground state of 15N; no excited states of 15N are populated and no gamma rays follow the beta decay. Yet a source of 15O is found to emit gamma rays of about 0.5 MeV. Explain the origin of these gamma rays. Solution When a nucleus has too many protons, it tends to positron decay. A positron is an antimatter beta particle. When a positron meets with an electron it annihilates it! Both particles disappear and two gamma rays are produced instead. Electron–positron annihilation e + e+ + When a low-energy electron (beta particle) annihilates a low-energy positron (antielectron), they can only produce two or more gamma ray photons, since the electron and positron do not carry enough mass-energy to produce heavier particles, and conservation of energy and linear momentum forbid the creation of only one photon. When an electron and a positron collide to annihilate and create gamma rays, energy is given off. Both particles have a rest energy of 0.511 mega electron volts (MeV). When the mass of the two particles is converted entirely into energy, this rest energy is what is given off. The energy is given off in the form of the aforementioned gamma rays. Each of the gamma rays has energy of 0.511 MeV. This the reason why when rays originates in radioactive decay of Oxygen-15 by positron emission.

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