overall, what is the net trend of NPP due to climate change Moving t.pdf

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Let X be the mean of a random sample of size n = 12 from the uniform distribution on the interval (0, 1). Approximate P(1/2 X 2/3). Solution as its given that n =12 not infinity we can get the sidtribution of x , the sampling distribution of X N(µ, ²/n) as n 12. by using this we can the sampling distribution N(µ, ²/n) = N(1/2, (1/12)/12) = N(1/2, 1/144) now what we need to find is that x lines in range of 1/2 and 2/3 and we can do this by by dividing the variance and subtract the mean Let Z = (X-bar - µ) / (²/n) = (X-bar - 1/2) / (1/144) = 144(X-bar - 1/2) let it be z variable , which is standard normal and variance = 1 and mean =0 now we have to just it in probability expression and look from the table P(1/2 < X-bar < 2/3) = P{144(1/2 - 1/2) < Z < 144(2/3 - 1/2)} = P{0 < Z < 24} = 0.50000 by normal table.

overall, what is the net trend of NPP due to climate change Moving to another question will save
this response. Overall, what is the net trend of NPP due to climate change? It is decreasing. It is
increasing Decreasing now but expecting to increase shortly it remains unchanged
Solution
Correct answer is :A.It is decreasing
Reason:Climate change due to global warming,heat, drought, expoitation of natural resources all
contribute to the decrease in the net trend of NPP.

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It is hypothesized that when homing pigeons are disoriented in a certain manner, they will exhibit no preference for any direction of flight after takeoff (so that the direction X should be uniformly distributed on the interval from 0o to 360o). To test this, 120 pigeons are disoriented, let loose, and the direction of flight of each is recorded; the resulting data follows. Use the chi- squared test at level 0.10 to see whether the data supports the hypothesis. Direction 10-45° 45- Solution We expect 120/8 = 15 on each direction. Doing an observed/expected value table, O E (O - E)^2/E 11 15 1.066666667 17 15 0.266666667 17 15 0.266666667 15 15 0 13 15 0.266666667 19 15 1.066666667 17 15 0.266666667 11 15 1.066666667 0 0 0 0 Using chi^2 = Sum[(O - E)^2/E], chi^2 = 4.266666667 = 4.27 [ANSWER].

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