Given a standardized normal distribution (with a mean of 0 and a standard deviation of 1), complete parts (a) through (d) below. Click here to view page 1 of the cumulative standardized normal distribution table. LOADING... Click here to view page 2 of the cumulative standardized normal distribution table. LOADING... a. What is the probability that Z is between negative 1.551.55 and 1.881.88? The probability that Z is between negative 1.551.55 and 1.881.88 is nothing. (Round to four decimal places as needed.) Solution Normal Distribution Mean ( u ) =0 Standard Deviation ( sd )=1 Normal Distribution = Z= X- u / sd ~ N(0,1) a) To find P(a < = Z < = b) = F(b) - F(a) P(X < -1.55) = (-1.55-0)/1 = -1.55/1 = -1.55 = P ( Z <-1.55) From Standard Normal Table = 0.06057 P(X < 1.88) = (1.88-0)/1 = 1.88/1 = 1.88 = P ( Z <1.88) From Standard Normal Table = 0.96995 P(-1.55 < X < 1.88) = 0.96995-0.06057 = 0.9094.