Is 53 equivalent to 2 (mod 3), 1(mod 4), 3 (mod 5)? We\'re trying to explain the Chinese remainder theorem in simple words. We got the equations x=60k+53 for any k=0,1,2,3... Is 53 equivalent to 2 (mod 3), 1(mod 4), 3 (mod 5)? We\'re trying to explain the Chinese remainder theorem in simple words. We got the equations x=60k+53 for any k=0,1,2,3... Solution we got x=60k +53 for k=0,1,2,3........... since for k=0, x=60(0)+53 x=0+53 x=53 so 53 equivalent to 2 (mod 3), 1(mod 4), 3 (mod 5).