3. Basic Concepts
• Degrees of Freedom
• Newton’s Law
• Equation of Motion (external force)
• Equation of Motion (base motion)
• Solutions to Equations of Motion
– Free Vibration
– Natural Period/Frequency
4. Degrees of Freedom
The number of variables required to describe the motion of the
masses is the number of degrees of freedom of the system
Continuous systems – infinite
number of degrees of freedom
Lumped mass systems – masses can be
assumed to be concentrated at specific
locations, and to be connected by massless
elements such as springs. Very useful for
buildings where most of mass is at (or attached
to) floors.
6. Newton’s Law
u
velocity
u
on
accelerati
u
position
Consider a particle with mass, m, moving in
one dimension subjected to an external load,
F(t). The particle has:
According to Newton’s Law:
)
(t
F
u
m
dt
d
If the mass is constant:
)
(t
F
u
m
u
dt
d
m
u
m
dt
d
m
F(t)
7. Equation of Motion (external load)
Mass
Dashpot
Spring
External load
External load
Dashpot force
Spring force
From Newton’s Law, F = mü
Q(t) - fD - fS = mü
8. Equation of Motion (external load)
Elastic resistance
Viscous resistance
)
(t
Q
ku
u
c
u
m
9. Equation of Motion (base motion)
Newton’s law is expressed in terms of absolute velocity and
acceleration, üt(t). The spring and dashpot forces depend on
the relative motion, u(t).
b
b
b
t
u
m
ku
u
c
u
m
ku
u
c
u
u
m
ku
u
c
u
u
m
ku
u
c
u
m
0
)
(
)
(
10. Solutions to Equation of Motion
Four common cases
Free vibration: Q(t) = 0
Undamped: c = 0
Damped: c ≠ 0
Forced vibration: Q(t) ≠ 0
Undamped: c = 0
Damped: c ≠ 0
)
(t
Q
ku
u
c
u
m
11. Solutions to Equation of Motion
Undamped Free Vibration
0
ku
u
m
Solution:
t
b
t
a
t
u o
o
cos
sin
)
(
where
m
k
o
Natural circular frequency
How do we get a and b? From initial conditions
12. Solutions to Equation of Motion
Undamped Free Vibration
t
b
t
a
t
u o
o
cos
sin
)
(
Assume initial displacement (at t = 0) is uo. Then,
b
u
b
a
u
b
a
u
o
o
o
o
o
)
1
(
)
0
(
)
0
(
cos
)
0
(
sin
13. Solutions to Equation of Motion
Assume initial velocity (at t = 0) is uo. Then,
o
o
o
o
o
o
o
o
o
o
o
o
o
o
o
o
u
a
a
u
b
a
u
b
a
u
t
b
t
a
u
)
0
(
)
1
(
)
0
(
sin
)
0
(
cos
sin
cos