here is ppt for science subject in Gujarati medium

1. Dharamsinh Rathod
Welcomes You
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2. a[(sD an[ b[ez
a[(sD-b[eztTAY)krN
bfr
a[(sD-b[ezan&mipn
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3. tTAY)krNn) p(kyi
jyir[ a[(sD an[ b[ezmi>a[ksrKi pmiNmi hieD^i[jn aiyn H+
an[ hieD^i[ksieD aiyn OH- B[gi krvimi> aiv[ C[ Ryir[ mLt&>
WivN tTAY hi[y C[.
NaOH (aq) + HCl(aq) NaCl + H2O
b[ez a[(sD xir piN)
Ca(OH)2 + 2 HCl CaCl2 + 2H2O
b[ez a[(sD xir piN)
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4. tTAY)krN
 H3O+ an[ OH- aiyni[B[gi Yen[piN) bniv[C[.
H3O+ + OH-  2 H2O
a[(sD mi>Y) b[ez mi>Y) tTAY
a>(tmaiyn)ksm)krN:
H+ + OH-  H2O
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5. tTAY)krN miT[n& aiyn)ksm)krN
aiynAv$p[ pbLa[(sD,b[ez an[xir lKi[
H+ + Cl- + Na+ + OH- Na+ + Cl- + H2O
a[ksrKiaiyni[n[bid kri[.
H+ + Cl- + Na+ + OH- Na+ + Cl- + H2O
a>(tmaiyn)ksm)krN
H+ + OH- H2O
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6. tTAY)krNni sm)krNn&> s>t&ln
m[³n[S)ym hieD^i[ksieD an[ nieT^)k a[(sD vµc[ Yti tTAY)krN
miT[n&> sm)krN lKi[.
1. a[(sD an[ b[ez ni s*#i[i lKi[.
Mg(OH)2 + HNO3
2. OH- an[ H+ aiynn) s>²yia[ksrK) Yiyt[ r)t[ s>t&(lt kri[
Mg(OH)2 + 2 HNO3
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7. 3. upj lKi[ :
Mg(OH)2 + 2HNO3 Mg(NO3)2 + H2O
xir piN)
(Fit&an[aFit&)
4. upjn[s>t&(ltkri[
Mg(OH)2 + 2 HNO3 Mg(NO3)2 + 2 H2O
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8. udihrN- 1
yi[³yg&Ni>kvD[n)c[ aip[ltTAY)krNnism)krNi[n[ s>t&(ltkri[.
A. __ HCl + __ Al(OH)3 __AlCl3 + __ H2O
1) 1, 3, 3, 1 2) 3, 1, 1, 1 3) 3, 1, 1 3
B.__ Ba(OH)2 + __H3PO4 __Ba3(PO4)2 + __ H2O
1) 3, 2, 2, 2 2) 3, 3, 1, 6 3) 2, 3, 1, 6
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9. uk[l -1
A. 3HCl + 1Al(OH)3 1AlCl3 + 3H2O
B. 3Ba(OH)2 + 2H3PO4 1Ba3(PO4)2 + 6H2O
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10. udihrN- 2
s>t&l)t sm)krN lKi[an[ 50.0 mL ni1.00 M KOH n[ tTAY krvi
miT[k[Tlim)l)l)Tr 2.00 M H2SO4 ji[ea[ t[ gNi[.
___H2SO4 + ___KOH ___K2SO4 + H2O
1) 12.5 mL 2) 50.0 mL 3) 200. mL
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11. uk[l -2
50.0 mL 1.00 M KOH n[ tTAY krvi miT[ k[Tli m)l). 2.00 M
H2SO4 ji[ea[?
H2SO4 + 2KOH K2SO4 + 2H2O
0.0500 L x 1.00 mole KOH x 1 mole H2SO4 x
1 L 2 mole KOH
1 L x 1000 mL = 12.5 mL
2 mole KOH 1 L
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12. udihrN-3
25 mL fi[Afi[r)k a[(sD n[ 40. mL ni 1.5 M NaOH vD[ tTAY
krvimi> aiv[ C[. ti[ fi[Afi[r)k a[(sD niWivNni[ aN&BirSi[Fi[.
3NaOH + H3PO4 Na3PO4 + 3H2O
1) 0.45 M 2) 0.80 M 3) 7.2 M
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13. uk[l -3
0.040 L x 1.5 mole NaOH x 1 mole H3PO4
1 L 3 mole NaOH
x 1 = 0.80 mol/L = 0.80 M
0.025 L
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