1. 1NANDA AFIF ASHARI | 1 D4 LJ IT | 2110165028
TUGAS 4 KONSEP JARINGAN
JUDUL : SUBNETTING
PERCOBAAN :
N = sum of borrowed host bit .
n = sum of host bit .
1. How many usable subnets (not theoretical) do you have when using a subnet mask of
255.255.255.240 on Network ID 201.114.168?
Pinjam = 32 – 28 = 4;
Subnet yang digunakan = 24 – 2 = 16-2=14;
2. You are given Network ID 222.72.157, with a subnet mask of 255.255.255.248 to setup.
How many subnets and hosts will you have?
32-3=29;
Network = 222.72.157.0/29
Sum of host in a Subnet = 23 – 2 = 8-2 = 6
Sum of subnet = 25 – 2 = 32 – 2 = 30
30 useable subnets and 6 useable hosts on each subnet
3. You are assigned a Network ID of 198.162.10 and asked to configure the network to
provide at least six useable subnets with at least 25 hosts on each subnet. What is the
BEGINNING IP address of the LAST useable subnet in the network?
Sum of host in a subnet = 25
Sum of subnet = 6
Search borrowed network bit => 6 = 2N - 2
8 = 2N
N = 3
192.168.10 000 0
001 32
010 64
011 96
100 128
101 160
110 192
111 224
first ip for last subnet = 198.162.10.193
4. How many useable hosts are on each subnet when the Network ID is 199.215.210 and the
subnet mask is 255.255.255.252?
Class = C
Network = 199.215.210.0/30
Sum of host in each subnet= 22 – 2 = 4 -2 = 2
2. 2NANDA AFIF ASHARI | 1 D4 LJ IT | 2110165028
5. You are given Network ID 190.90, with a subnet mask of 255.255.192.0 to setup. What are
the high-order bits (Leading Bit Values) for this network?
Binary 10
Class B ,high order bits = Binary “10”,network bit = 14 ,host bit = 16.
6. You are assigned a Network ID of 162.160 and asked to configure the network to provide at
least 60 useable subnets? What would be the subnet mask for this network?
Network = 162.160.0.0
26 – 2 = 64 -2 = 62 , so the sum of borrowed host bit is 6
So the subnetmask is 255.255.252.0
7. How many useable hosts are on each subnet when the Network ID is 150.150 and the
subnet mask is 255.255.192.0?
Network = 150.150.0.0
Borrowed host bit = 18
Sum of host bit = 32 – 18 = 14.
So the sum of host is
2n – 2 = 214 – 2 = 16.382
8. You are assigned a Network ID of 145.19 and asked to configure the network to provide at
least 100 useable subnets with at 500 hosts on each subnet. What is the ENDING IP address
of the EIGHTH useable subnet in the network?
Network = 145.19.0.0
Class = B
Normal mask = 255.255.0.0
Sum of subnet = 2N – 2 =27 – 2
2N = 102
N = 7
So sum of borrowed network bit is 7 .
Range from each subnet is plus 2
8th Subnet
Ip first = 145.19.17.1
Ip last = 145.19.17.254
Ip broadcast = 145.19.17.255
3. 3NANDA AFIF ASHARI | 1 D4 LJ IT | 2110165028
9. You are a private contractor hired by the large company to setup the network for their
enterprise. The Network ID is 33 and you need at least 125 subnets in their large network
with at least 125,000 hosts on each of the subnets. What would be the subnet mask for this
network?
Network = 33.0.0.0
Class = A
Normal subnet = 255.0.0.0
Sum of subnet = 125 ,
Sum of host = 125.000
Sum of subnet = 2N – 2
2N = 125 +2
2N = 127
N = 7.
Subnetmask = 255.254.0.0
10. You are given Network ID 55.0.0.0, with a subnet mask of 255.240.0.0 to setup. How many
subnets and hosts will you have?
Network = 55.0.0.0
Subnetmask = 255.240.0.0
Sum of subnet = 2N – 2 = 24 – 2 = 16 - 2 = 14
Sum of host = 2n – 2 = 220 – 2 = 1.048.576 - 2 = 1.04.,574
14 useable subnets and 1,048,574 useable hosts on each subnet
