2 questions- due in 8-9 hours
Compu
t
e
r O
r
g
a
ni
z
a
t
i
on
a
nd A
rc
hi
t
ec
tu
r
e
AS
S
I
G
N
ME
N
T:
1. The
f
ol
l
owing
M
I
P
S
c
o
d
e
ca
lcu
l
a
tes the
f
loati
n
g
-
point
e
x
p
re
ss
i
on E =A * B+C * D, wh
e
rethe
a
dd
r
e
sses of
A
,
B
, C, D,
a
nd E
a
resto
r
e
d in
R
1, R2, R3, R4,
a
ndR5, r
e
spe
c
t
i
v
e
l
y
:
L
.S
F
0, 0(R1)
L
.S
F
1, 0(R2) M
U
L
.S
F
0,
F
0,
F
1
L
.S
F
2, 0(R3)
L
.S
F
3, 0(R4) M
U
L
.S
F
2,
F
2,
F
3
A
D
D.S
F
0,
F
0,
F
2
S
.S
F
0, 0(R5)
R
e
w
r
i
t
ethe
c
o
d
eseq
ue
n
ce
, but now usi
n
gon
l
y
t
wo
f
loatin
g
-
point
r
e
g
is
t
e
r
s. Optim
iz
e
f
or m
i
ni
m
um run
-
t
i
me.
Y
ou m
a
y
n
ee
d to usetempo
rar
ymem
o
r
yloc
a
t
i
ons to hold in
t
e
rm
e
diatev
a
lues.
L
istthe codeseq
u
e
n
c
e
a
nd
g
i
vethe numb
e
r of
c
y
c
les
t
his
t
a
k
e
s to
e
x
ec
ute.
2. A
5
-
st
a
g
e
pipelined
p
r
o
ce
ssor
h
a
s
I
nstr
u
c
t
i
on
Fe
tch
(
I
F
),
I
nstru
c
t
i
on
D
ec
ode
(
I
D
)
, Op
e
r
a
nd
Fe
tch(
O
F
),
P
e
r
fo
r
mOp
e
r
a
t
i
on(PO)
a
n
d
W
riteOp
e
r
a
nd(WO) sta
g
e
s.T
h
e
I
F
,
I
D
,
O
F
a
nd
W
Ost
a
g
e
s
t
a
ke1
c
lock
c
y
c
l
e
eac
h
f
or
a
n
y ins
t
r
u
c
t
i
on.The
P
Ost
a
g
etak
e
s1
c
lock
c
y
c
l
eforA
D
D
a
n
d
S
UB ins
t
ru
c
t
i
ons,3
c
l
o
c
k
c
y
c
l
e
sfor
MU
L ins
t
ru
c
t
i
on,
a
nd6
c
lock
c
y
c
lesfor
D
I
Vins
t
ru
c
t
i
onr
e
s
p
ec
t
i
v
e
l
y
.Op
e
r
a
ndf
o
r
w
a
rdi
n
g isused
i
nthepipeline.
W
h
a
tisthenumb
e
rof
c
lock
c
y
c
lesn
e
e
d
e
d
t
o
e
x
ec
utethefollowings
e
q
u
e
n
c
eof ins
t
ru
c
t
i
on
s
?
S
how how
y
o
u
a
r
r
ive
a
t
y
o
u
r
a
ns
w
e
r
.
I
nstr
u
c
t
i
on
Me
a
ning ofins
t
ru
c
t
i
on
I
0
:M
U
L
R
2
,
R
0
,
R
1
R
2
←
R
0
*
R
1
I
1
:
D
I
V
R
5
,
R
3
,
R
4
R
5
←
R
3
/
R
4
I
2
: ADD
R
2
,
R
5
,
R
2
R
2
←
R
5
+
R
2
I
3
:
S
UB
R
5
,
R
2
,
R
6
R
5
←
R
2
-
R
6
See the attached for clarity
.
