3 Suppose V is finite-dimensional and v element of V with v is not equals to 0. Prove that there exists phi element of V? such that phi(v) = 1. Solution As V is finite dimensional, and non zero there exists v\' such that v *v\' =1 (since non zero elements in finite dimensional vector space have multiplicative inverse.) Hence there exists phi in V\' such that phi(v) =1.