A binary encoded signal has a bit-rate of Rb = 28 kbps. An Alternate Mark Inversion line-code is used to encode these bits for baseband transmission over copper wire. What would be the transmission bandwidth required to transmit this signal? B = 112 kHz B = infinity B = 28 kHz B = 56 kHz B = 14 kHz B = 7 kHz Solution Speed or bit rate = nfs = Rb Bandwidth minimum is Rb/2 Bandwidth maximum is Rb Normally bandwidth consider to be half of speed Bandwidth = 28/2 Bandwidth = 14 kbps.