Detailed solutions please 1. Let R and S be commutative rings and le.pdf

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Detailed solutions please: 1. Let R and S be commutative rings and let sigma: R right arrow S be a homomorphism. Prove that if sigma is one to one and b in R is a zero divisor of R, then sigma(b) is a zero divisor of S. Solution we are given that R--->S is a homomorphism A homomorphism is a map that preserves selected structure between two algebraic structures, with the structure to be preserved being given by the naming of the homomorphism the set R and S are the same as they form a homomorphic relation. now b E R that is b lies with the set R and since R and S are homomorphic so b will also lie in the ser S since sigma is one to one function threfore the entire domain of sigma will be mapped . its also gven that sigma(b) is a zero divisor of R and since b E S as well so sigma(b) is a zero divisor of S as well hence proved..

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Hilary rode her horse for 8 miles until it was hurt.Then she walked .pdf

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fully comments for my program, thank you will thumb up #include #include #include #include using namespace std; struct book { int ISBN; string Author; string Title; string publisher; int Quantity; double price; }; void choice1(book books[], int& size, int MAX_SIZE) { ifstream inFile; inFile.open(\"inventory.txt\"); if (inFile.fail()) cout <<\"file could not open\"<> books[size].ISBN; cout << \"Enter the author name: \"; cin >> books[size].Author; cout << \"Enter the book tile: \"; cin >> books[size].Title; cin.get(); cout << \"Enter the books quantity: \"; cin >> books[size].Quantity; cout << \"Enter the book price: $\"; cin >> books[size].price; size++; cout << \"You have successfully inserted an entry.\" << endl; } } void choice3(book books[], int& size) { if(size == 0) cout << \"Array is empty. Read the data first.\" << endl; else { int isbn; cout << \"\ Enter the ISBN of the book: \"; cin >> isbn; for(int i = 0; i < size; i++) { if(books[i].ISBN == isbn) { int j = i; while(j < size - 1) { books[j] = books[j + 1]; j++; } size--; break; } } cout << \"You have successfully deleted an entry.\" << endl; } } void choice4(book books[], int size) { if(size == 0) cout << \"Array is empty. Read the data first.\" << endl; else { int isbn; int option; int qty; cout << \"\ Enter the ISBN of the book: \"; cin >> isbn; cout << \"1. Increment\" << endl; cout << \"2. Decrement\" << endl; cout << \"3. Add New\" << endl; cout << \"Enter your option: \"; cin >> option; cout << \"Enter the quantity: \"; cin >> qty; for(int i = 0; i < size; i++) { if(books[i].ISBN == isbn) { if(option == 1) books[i].Quantity += qty; else if(option == 2) { books[i].Quantity -= qty; if(books[i].Quantity) books[i].Quantity = 0; } else if(option == 3) books[i].Quantity = qty; break; } } cout << \"You have successfully updated the array.\" << endl; } } void choice5(book books[], int size) { for(int i = 1; i < size; i++) { book current = books[i]; int j = i; while(j > 0 && (books[j - 1].Title).compare(current.Title) > 0) { books[j] = books[j - 1]; j--; } books[j] = current; } if(size != 0) cout << \"You have successfully sorted the array.\" << endl; else cout << \"Array is empty. Read the data first.\" << endl; } void choice6(book books[], int size) { for(int i = 0; i < size; i++) { cout << endl; cout << \"Book Number: \" << (i + 1) << endl; cout << \"ISBN: \" << books[i].ISBN << endl; cout << \"Author: \" << books[i].Author << endl; cout << \"Title: \" << books[i].Title << endl; cout << \"Quantity: \" << books[i].Quantity << endl; cout << \"Price: $\" << books[i].price << endl; } if(size != 0) cout << \"You have successfully printed the array.\" << endl; else cout << \"Array is empty. Read the file first.\" << endl; } void choice7(book books[], int size) { ofstream outFile; outFile.open(\"finalData.dat\"); for(int i = 0; i < size; i++) { outFile << \"Book Number: \" << (i + 1) << endl; outFile << \"ISBN: \" << books[i].ISBN << endl; outFile << \"Author: \" << books[i].Author << end.

fully comments for my program, thank you will thumb up#include io.pdf

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Find the admittance Yab in the circuit seen in the figure. Take that R1 = 6 , R2 = 6 , R3 = 4 and R4 = 12.8 Part A Express Yab in rectangular form. Express your answer in complex form. The answer is NOT Yab = (4+j3)10^(5) mS Yab = 40+j30 mS 510^(5) e^(j36.86)Yab = 510^(5) e^(j36.86) mS j12.8 n Yab bo 12 j10 n Solution Z3=R3||j10=4*j10/(4+j10) Z2=R2+j12=6+j12 Z1=R1-j2=6-j2 Zequ1=Z1||Z2||Z3=2.1517 +j 0.5793 Z=R4+Zequ1-j12.8=12.8-j12.8+2.1517 + j0.5793=14.9517 -j12.2207 Y=1/Z=1/14.9517 -j12.2207 Y=0.0401 + j0.0328 convert rect to polar a=sqrt((0.0401^2)+(0.0328^2))=0.0518 b=tan-1(-0.0328/0.0401)=- 0.6856 in radins, if conver to degree=-39.2 ans: 0.051806*expj-39.2.

Find the admittance Yab in the circuit seen in the figure. Take that.pdf

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Diversity Paper Each student will complete a diversity research assignment. Students will choose one of the populations below and have the selection approved by the instructor. The assignment explores the resiliency of elders of (African American antic/Latino. Asian American Indian) or the status of older women in society compared to older men. Students will research the economic status, health, social supports, living situations marry of one of the special populations chosen by the student. They will also research specific cultural values and beliefs regarding life, acceptance of help, and death. Students are encouraged to use the text and at least 3 other reliable sources to gather information. Sources should be documented in APA style of referencing Length is 5 pages of content, double-spaced in 12 point font. Paper is due the 7th week of class and is worth so points. No late submissions will be accepted. The due date is Friday, February 24, by 11:00pm Central Start Date Due Date is Friday, February 24, by 11:00 pm central Time. Solution DIVERSITY RESEARCH ASSIGNMENT Age and Socioeconomic Status Socioeconomic status (SES) is often measured as a combination of education, income and occupation. It is commonly conceptualized as the social standing or class of an individual or group. When viewed through a social class lens, privilege, power and control are emphasized. Furthermore, an examination of SES as a gradient or continuous variable reveals inequities in access to and distribution of resources. SES is relevant to all realms of behavioural and social science, including research, practice, education and advocacy. SES Affects Our Society SES affects overall human functioning, including our physical and mental health. Its effects can be observed across the life span. Variance in socioeconomic status such as disparities in the distribution of wealth, income and access to resources mitigate social problems that ultimately affect everyone. All benefit from an increased focus on the foundations of socioeconomic inequalities and efforts to reduce the deep gaps in socioeconomic status observed today in the United States and abroad. While older and retired U.S. residents may enjoy a higher standard of living than their predecessors, older Americans remain among the most economically vulnerable groups. Of major concern is whether older Americans will outlive their financial resources. Psychologists and other social and behavioural science professionals possess the tools necessary to study and identify strategies to alleviate these disparities at both individual and societal levels. SES Impacts the Lives of Older Adults The United States is facing unprecedented increases in the older adult population. Americans age 65 and over comprise nearly 13 percent of the U.S. population, and their proportion is estimated to increase to 20 percent of the population in the next 25 years. As the percentage of older Americans rises, so does concern for their econom.

Diversity Paper Each student will complete a diversity research assig.pdf

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Describe the mechanisms of asexual reproduction in: Prokaryotes Protists Plants- Animals Solution Prokaryotes reprodue asexually by BINARY FISSION mehanism. In this the genetic material is replicated as same as the parent genome the cell devides in two parts and give rise to new progeny so no geneti diversity is formed. protists- they also reprodue asexually through binary fission, BUDDING In this new organism grow from the body of parent. PLANT- VEGETATIVE reproduction is the main asexual reproduction in which a plant part give rise of new plant same as the parent, such as growing tips of RHIZOME. ANIMALS- they also reproduce asexually through budding,fission,fragmentation.In case of stick inset, bees PARTHENOGENESIS our in whih unfertilised egg give rise to new individual it is a type of AGAMOGENESIS..

Describe the mechanisms of asexual reproduction inProkaryotesPr.pdf

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Define intermediate phenotype and then imagine some intermediate phenotypes (e.g. RNA, metabolite, etc) for Down’s Syndrome. Solution intermediate phenotype : it depicts a living being that shows a mix of the phenotypic characteristics that its parents expressed. . In the event that a red blossom cross-pollinates a white bloom, and the subsequent offspring are pink, the posterity portrayed as a intermediate phenotype . It happen when the traits under investigation are neither dominant or recessive. Down disorder (DS or DNS), otherwise called trisomy 21, is a hereditary issue brought about by the nearness of all or some portion of a third duplicate of chromosome 21. It is commonly connected with physical development delays, trademark facial elements and mellow to direct learned incapacity. Down disorder is brought on by having three duplicates of the qualities on chromosome 21, as opposed to the standard two.The guardians of the influenced individual are ordinarily hereditarily ordinary Those who have one tyke with Down disorder have around a 1% danger of having a moment youngster with the disorder, if both guardians are found to have typical karyotypes. The additional chromosome substance can emerge through a few distinctive ways. The most widely recognized cause (around 92–95% of cases) is an entire additional duplicate of chromosome 21, bringing about trisomy 21. In 1.0 to 2.5% of cases, a portion of the phones in the body are typical and others have trisomy 21, known as mosaic Down syndrome. The other basic systems that can offer ascent to Down disorder include: a Robertsonian translocation, isochromosome, or ring chromosome. These contain extra material from chromosome 21 and happen in around 2.5% of cases. An isochromosome comes about when the two long arms of a chromosome isolate together as opposed to the long and short arm isolating together amid egg or sperm improvement. Trisomy 21 is known by the karyotype 47,XX,+21 for females and 47,XY,+21 for guys) is brought about by a disappointment of the 21st chromosome to isolate amid egg or sperm development.As an outcome, a sperm or egg cell is delivered with an additional duplicate of chromosome 21; this cell therefore has 24 chromosomes. At the point when joined with a typical cell from the other parent, the child has 47 chromosomes, with three duplicates of chromosome 21. Around 88% of instances of trisomy 21 result from nonseparation of the chromosomes in the mother, 8% from nonseparation in the father, and 3% after the egg and sperm have combined. Translocation : The additional chromosome 21 material may likewise happen due to a Robertsonian translocation in 2–4% of cases. In this circumstance, the long arm of chromosome 21 is joined to another chromosome, regularly chromosome 14. In a male influenced with Down disorder, it brings about a karyotype of 46XY,t(14q21q). This might be another transformation or already display in one of the guardians. The parent with such a translocation i.

Define intermediate phenotype and then imagine some intermediate phe.pdf

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Consider a population of lizards living on the coast of Africa. A storm creates piles of debris that the lizards use to raft to a faraway uninhabited island. Which evolutionary process is happening? mutation selection balance the founder effect frequency-dependent selection coalescence Solution Answer is. \"Founder effect\". The lizards completely moved to new place where they never I habited before, and hence they found new environment to adjust, which will create some environmental difference. This is known as founder effect..

Consider a population of lizards living on the coast of Africa. A sto.pdf

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Can “discovery science” (for example, the discovery of a new species of fossil, or a new species of organism that is alive today) contribute to our understanding of evolution? Give examples. Solution Scientists seek natural causes for natural phenomena. This is the most basic description of what a scientist aims to do every day. Their focus is limited to what they can physically observe and measure directly, sometimes with the help of tools such as a microscope. They do not seek to explain the supernatural as it is outside the bounds of science, but instead what is all around them. There are basic methods of gaining knowledge that are common to all of science. Biology uses discovery science , and hypothesis-based science . While discovery science is mostly about describing nature, hypothesis-based science attempts to explain nature. The pair of inquiries are widely used together in research. Observations that can be measured and verified are the data of discovery science. In the study of life, discovery science is used to describe both the simplest of life, and the most complex. From the building blocks of atoms and molecules all the way up to the ecosystems and biosphere, discovery science describes it all. Discovery science is based on the logic of inductive reasoning . Inductive reasoning uses numerous specific observations to make a general statement. For example: all living things are made of cells. This comes after the numerous discoveries of cells in every specimen observed by biologists over two centuries. another example we can take \"humans\". today we found most of the fossils of human lives who lived thousands of years back and with help of that fossils we can understand growth and evolution human life..

Can “discovery science” (for example, the discovery of a new species.pdf

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C++ Write a function void headEnqueue(Queue *q, int key) which enqueues the key such that, at function exit, it is positioned at the head of the queue rather than the tail; and the order and integrity of the queue is otherwise maintained. Solution struct node { int data; node* next; }; class Queue //linked_list class { private: node* front; node* rear; public: Queue(); void insert(int); headEnqueue(Queue *q, int key); }; Queue::Queue() { front = rear = NULL; } void Queue::insert(int val) { node* temp = new node; temp->data = val; temp->next = NULL; if (front == NULL) front= rear = temp; else { node* temp1 = front; while (temp1->next) temp1 = temp1->next; temp1->next = temp; } } void Queue::headEnqueue(Queue *q, int key) { node* temp = new node; temp->data = key; temp->next=q->front; q->front=temp; }.

C++Write a function void headEnqueue(Queue q, int key) which enqu.pdf

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All of the following are features or functions of nanobodies except ______________. small, monomeric, lack disulfide bonds, and resistance to denaturation high affinity to the antigen recognize protruding and recessed paratopes cannot be humanized consist of only the VHH domain of heavy chain antibodies Solution d)cannot be humanized because we have many humanized antibodies that are available .example-CyaA-Hly specific humanized antibody.

All of the following are features or functions of nanobodies except _.pdf

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A girl running at a constant speed of 1.4ms in a straight line thro.pdf

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You have a rural dial-up customer who complains that a large number of phone calls have been made to “dangerous” sites on the Internet from his computer but he didn’t make these calls. You investigate his computer and discover what type of malware? A. Adware B. Dialer C. Keystroke logger D. Spim Solution B. Dialers are types of malicious programs installed on computers that cause the dialup modem to call dangerous or pay-per-call locations on the Internet, often resulting in extremely high phone bills for the customer..

You have a rural dial-up customer who complains that a large number .pdf

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You are given a mixed culture containing a anaerobic thermophile, aerobic thermophile and anaerobic hyperthermophile bacteria. How will you separate these into pure cultures? Solution In natural environments, microorganisms usually exist as mixed populations. A pure culture is one by which all organisms are descendants of the exact same organism. A sterile medium is the one which is free of all life forms. It is often sterilized by heating it to a temperature at which all contaminating microorganisms are destroyed. Eventually, in functioning with microorganisms, we ought to have a way of transferring growing organisms from a pure culture to a sterile medium without introducing any undesirable outside contaminants. This approach of stopping unwanted microorganisms from developing accessibility is termed aseptic technique. Microorganisms whose optimal temperature for development is near 0oC are called psychrophiles. The ones that grow optimally between 20oC and 45eC are called mesophiles. These growing most useful at large conditions, 55oC to ~ 70oC and larger, are called thermophiles. Prokaryotes that live at quite high conditions (up to 113oC ) are hyperthermophiles. An organism that will require air for development is called aerobic. An organism whose development can\'t arise in the presence of air is anaerobic. An organism that may grow under either aerobic or anaerobic conditions is a facultative anaerobe. Microaerophilic organisms involve free air but at a limited concentration. Based on this, the plates are incubated at different temperatures with aerobic and anerobic conditions for enhancing the growth of thermophiles and hyperthermophilc bacteria..

You are given a mixed culture containing a anaerobic thermophile, ae.pdf

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Woyld removing phenylethyl alcohol from PEA alter the medium\'s Solution Phenylethyl alcohol agar (PEA) medium is a selective media that inhibit the growth of gram- negative bacteria and allows the growth of gram-positive bacteria only. The phenyl ethyl alcohol is responsible for preventing the growth of gram-negative bacteria. So, removing phenyl ethyl alcohol from PEA alter the medium\'s specificity againstgram positivebacteria..

Woyld removing phenylethyl alcohol from PEA alter the mediumsS.pdf

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Which abstraction uses slates, state transitions, inputs and outputs .pdf

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What is the target cell for the hormone Angiotensionogen? Solution Answer: zona glomerulosa cells of the adrenal cortex in the adrenal gland on kidney Reason: Primarily low blood pressure trigger the release of precursor, angiotensinogen peptide, a serpin family from the liver cells followed by formation of angiotensin I finally to angiotensin II in the presence of angiotensin converting enzyme (ACE). This angiotensin II active form is going to act on the \"zona glomerulosa cells of the adrenal cortex in the adrenal gland on kidney\" to trigger release of aldosterone to act on kidney cells finally to the reabsorption of sodium.

What is the target cell for the hormone AngiotensionogenSolut.pdf

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What is a possible evolutionary advantage of having introns/exons in genes? Give an example of where this usage is observed or may have occurred. Solution Presence of large noncoding sequences such as introns interspersed with exons in the genome lowers the rate mutations from appearing. Introns enable alternative splicing, a mechanism which enables a single gene to encode multiple proteins that perform different functions under different conditions. Small genome but large information stored. Regulatory RNAs such as siRNA encoded by introns are known to regulate gene expression. Adds to biological complexity..

What is a possible evolutionary advantage of having intronsexons in.pdf

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