Now a normal O2 molecule has 12 electrons in the valence shell so, O2+ has 11 electrons in its
valence shell. The first two go in the s2s and the next two go in the s*2s. Now two go in the s2p.
Now thats 6 of the electrons. 4 electrons go in the p2p level and the remaining one goes in the
p*2p level. Now count that up and the bond order is 1/2 the number of bonding electrons minus
antibonding electrons:
Order = 1/2 (8 - 3) = 5/2
Solution
Now a normal O2 molecule has 12 electrons in the valence shell so, O2+ has 11 electrons in its
valence shell. The first two go in the s2s and the next two go in the s*2s. Now two go in the s2p.
Now thats 6 of the electrons. 4 electrons go in the p2p level and the remaining one goes in the
p*2p level. Now count that up and the bond order is 1/2 the number of bonding electrons minus
antibonding electrons:
Order = 1/2 (8 - 3) = 5/2.
Now a normal O2 molecule has 12 electrons in the valence shell so, O.pdf
1. Now a normal O2 molecule has 12 electrons in the valence shell so, O2+ has 11 electrons in its
valence shell. The first two go in the s2s and the next two go in the s*2s. Now two go in the s2p.
Now thats 6 of the electrons. 4 electrons go in the p2p level and the remaining one goes in the
p*2p level. Now count that up and the bond order is 1/2 the number of bonding electrons minus
antibonding electrons:
Order = 1/2 (8 - 3) = 5/2
Solution
Now a normal O2 molecule has 12 electrons in the valence shell so, O2+ has 11 electrons in its
valence shell. The first two go in the s2s and the next two go in the s*2s. Now two go in the s2p.
Now thats 6 of the electrons. 4 electrons go in the p2p level and the remaining one goes in the
p*2p level. Now count that up and the bond order is 1/2 the number of bonding electrons minus
antibonding electrons:
Order = 1/2 (8 - 3) = 5/2
