The balanced Equations are 1. 3Mg + N2 -- Mg3N.pdf

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The balanced Equations are : 1. 3Mg + N2 --> Mg3N2 2. 2H2O2 --> 2H2O + O2 3. 2C6H6 + 15 O2 --> 12 CO2 + 6 H2O 4. 2Al + 3H2SO4 --> Al2(SO4)3 + 3 H2 5. Al4C3 + 12 H2O --> 4Al(OH)3 + 3CH4 Solution The balanced Equations are : 1. 3Mg + N2 --> Mg3N2 2. 2H2O2 --> 2H2O + O2 3. 2C6H6 + 15 O2 --> 12 CO2 + 6 H2O 4. 2Al + 3H2SO4 --> Al2(SO4)3 + 3 H2 5. Al4C3 + 12 H2O --> 4Al(OH)3 + 3CH4.

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Ques-1: How would agriculture be impacted in this country if the soils were lacking in microbes? Can you imagine a time in the future when we will have eliminated all of the fatal diseases caused by microbes? If you could cure just one microbial disease which one would it be and why? Which disease would be the easiest and cheapest to prevent and why? Answer: Microbes are natural scavangers and they are essential to convert disposing waste sludge into final product as an organic fertilizer through the anaerobic digestion, pasteurization and compost preparation. In order to minimize the error and to enable efficient growth of plant, it is better to supply plant with equal ratios at which plant can survive followed by supplying soil worms to enable proper nitrate and phosphorous fixation. These soil worms also should be in a proper ratio. In order to get better yield, fertilizers, which have the properties of not inhibiting the growth of soil microbes, are crucial. Providing plants with sufficient mineral supply is also important. The above methods of waste sludge treatment produces ----> organic manure or organic natural fertilizer for plant growth. Therefore, absence of microbes is leading to lack of leaf, shoot and root systems for plants result in no adequate mineral supplement to plants. This is leading to imbalance of ecosystem equilibrium. Plant growth was observed only in plants with soil and soil with worms. The major reason behind this is aerobic decomposition of soil microbes and worms supplying sufficient amount of nutrient such as nitrogen, phosphorous in the form of nitrates, phosphates. Soil worms efficiently performing nitrate fixation and phosphate fixation followed by carbon fixation. Soil worms are major symbiotic parasites, which can fix these complex phosphates, nitrates to supply to the plant efficiently as plant cannot fix nitrate and phosphates straightaway. Soil worms are natural scavengers. But in the treatments \"fertilizers with no worms and also fertilizers with worms, plant growth did not observed considerably as in which organophosphorous nitrate and phosphate fertilizers may have properties to act on soil microbes to inhibit their growth and reproduction. Thereby excess fertilizers may lead to excessive concentration inside the plant root cells (endoderm) followed by hyperosmotic cell death finally result in plant roots inability to supply minerals and water to the plant. Growth is going to be inhibited by excessive amount of fertilizers or even in the absence of soil worms. No, it is not possible to eliminate all the communicable diseases caused by microbes in future because microbes do exist antibiotic resistant and they have a property of transferring genes (transformation, conjugation and transduction) to other microbe of same genus result in acquiring resistance to host defense system. Sometimes some viral species have ability to undergo phage variation through mutated genome in the host cells. Curing a micro.

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Percentile RanksStandard Scores and Scaled ScoresSolutionPer.pdf

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import java.util.Scanner; public class Digits { public static void main(String[] args) { int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters int value, digit; //stores input value and digit respectively int copy; //stores copy of entry Scanner scan = new Scanner(System.in); //Get value from user System.out.println(\"enter number :\"); int value=scan.nextInt(); copy=value; //Make the value positive value=Math.abs(value); //What if the value is actually zero? if(value==0) zeroCount++; while(value>0) { digit=value10; if(digit==0) zerocount++; if(digit%2==0) evenCount++; else oddCount++; value=value/10; } System.out.println(\"original value:\"+copy); System.out.println(\"zero digits :\"+zeroCount); System.out.println(\"odd digits :\"+oddCount); System.out.println(\"even digits :\"+evenCount) } } Solution import java.util.Scanner; public class Digits { public static void main(String[] args) { int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters int value, digit; //stores input value and digit respectively int copy; //stores copy of entry Scanner scan = new Scanner(System.in); //Get value from user System.out.println(\"enter number :\"); int value=scan.nextInt(); copy=value; //Make the value positive value=Math.abs(value); //What if the value is actually zero? if(value==0) zeroCount++; while(value>0) { digit=value10; if(digit==0) zerocount++; if(digit%2==0) evenCount++; else oddCount++; value=value/10; } System.out.println(\"original value:\"+copy); System.out.println(\"zero digits :\"+zeroCount); System.out.println(\"odd digits :\"+oddCount); System.out.println(\"even digits :\"+evenCount) } }.

import java.util.Scanner;public class Digits { public static v.pdf

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I hope the below code is helpful to you, please give me rewards.im.pdf

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H3PO4(aq) + NaOH(aq) -- H2O(aq) + H2PO4(2-)(aq) + Na+ (aq) Hl(aq).pdf

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(a) tetrabromocuprate(II) [Cu(Br)4]2- (b) potassiumtrioxalatochromate(III) K3[Cr(C2O4)3] (c) aquocyanobis(ethylenediamine)cobalt(III) [Co(en)2CN(H2O)]2+ (d) Potassium tetracyanonickelate(II) K2[Ni(CN)4] (d) Potassium tetracyanonickelate(II) K2[Ni(CN)4] Solution (a) tetrabromocuprate(II) [Cu(Br)4]2- (b) potassiumtrioxalatochromate(III) K3[Cr(C2O4)3] (c) aquocyanobis(ethylenediamine)cobalt(III) [Co(en)2CN(H2O)]2+ (d) Potassium tetracyanonickelate(II) K2[Ni(CN)4] (d) Potassium tetracyanonickelate(II) K2[Ni(CN)4].

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Consuming both E.coli and Salmonella are risky. But Salmonella is much more pathogenic and cause deliterious effects on human beings than E.coli. E.coli causes diarrhea, in most cases the diarrhea subsides without any medical intervention. Some strains of E.coli are not pathogenic and do not cause any pathogenic effect. But some strains can damage intestinal epithelium and cause ulcers in the intestine. Enteropathogenic E.coli, Enterohaemmorhagic E.coli are dangerous. Whereas in case of Salmonella, all the strains are pathogenic and can cause Typhoid, gastroenteritis based on the species. Typhoid or enteric fever and salmonella gastroenteritis are complicated without medical intervention. The person who consumed may also become carrier. The number of Salmonella bacteria required to cause infection is less than the number of E.coli required to cause infection. In other terms, the infectivity of Salmonella is higher than E.coli. Solution Consuming both E.coli and Salmonella are risky. But Salmonella is much more pathogenic and cause deliterious effects on human beings than E.coli. E.coli causes diarrhea, in most cases the diarrhea subsides without any medical intervention. Some strains of E.coli are not pathogenic and do not cause any pathogenic effect. But some strains can damage intestinal epithelium and cause ulcers in the intestine. Enteropathogenic E.coli, Enterohaemmorhagic E.coli are dangerous. Whereas in case of Salmonella, all the strains are pathogenic and can cause Typhoid, gastroenteritis based on the species. Typhoid or enteric fever and salmonella gastroenteritis are complicated without medical intervention. The person who consumed may also become carrier. The number of Salmonella bacteria required to cause infection is less than the number of E.coli required to cause infection. In other terms, the infectivity of Salmonella is higher than E.coli..

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Debt-equity ratio=Debt/equity Hence debt=0.65equity Let equity be $x Hence debt=$0.65x Total=debt+equity =(x+0.65x)=$1.65x After tax cost of debt=9(1-0.4)=5.4% WACC=Respective costs*Respective investment weights =(5.4*0.65x/1.65x)+(x/1.65x*13) which is equal to =10.01%(Approx). Solution Debt-equity ratio=Debt/equity Hence debt=0.65equity Let equity be $x Hence debt=$0.65x Total=debt+equity =(x+0.65x)=$1.65x After tax cost of debt=9(1-0.4)=5.4% WACC=Respective costs*Respective investment weights =(5.4*0.65x/1.65x)+(x/1.65x*13) which is equal to =10.01%(Approx)..

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As we move from left to right in a period the E.N valuesincreases & as we move from top to bottom in a group the E.Nvalue decreases . Part (A) P having more E.N value Part (B) K has more E.N value Part (c) C is having more E.N value Part (d) I having more E.N value a Solution As we move from left to right in a period the E.N valuesincreases & as we move from top to bottom in a group the E.Nvalue decreases . Part (A) P having more E.N value Part (B) K has more E.N value Part (c) C is having more E.N value Part (d) I having more E.N value a.

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Answer nondiversifiable risk meaning Risk of an investment asset that cannot be reduced or eliminated by adding that asset to a diversified investment portfolio. Market or systemic risks are non-diversifiable risks The amount of investment might decrease over a period of time only due to economic changes or other events which affect high varities of the market. However, investment diversification and asset allocation can provide protection against non-diversifiable risk as different sections of the market have a tendency to underperform at different times. Solution Answer nondiversifiable risk meaning Risk of an investment asset that cannot be reduced or eliminated by adding that asset to a diversified investment portfolio. Market or systemic risks are non-diversifiable risks The amount of investment might decrease over a period of time only due to economic changes or other events which affect high varities of the market. However, investment diversification and asset allocation can provide protection against non-diversifiable risk as different sections of the market have a tendency to underperform at different times..

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There\'s a proportionality constant (the rate constant) and the effect of concentration in a rate-law expression. Since the concentration of CO has no effect, I\'ll leave it out. Rate = - d[NO2]/dt = k[NO2]^2 Solution There\'s a proportionality constant (the rate constant) and the effect of concentration in a rate-law expression. Since the concentration of CO has no effect, I\'ll leave it out. Rate = - d[NO2]/dt = k[NO2]^2.

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