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The population distribution is normal.Solution The population.pdf
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Yes, it\'s true that most mutations are deleterious however there are a few mutations that are beneficial and provide for differential propagation of the variation which is the basis for evolution Solution Yes, it\'s true that most mutations are deleterious however there are a few mutations that are beneficial and provide for differential propagation of the variation which is the basis for evolution.
Yes, its true that most mutations are deleterious however there ar.pdf
Yes, its true that most mutations are deleterious however there ar.pdf
apexelectronices01
we found sp3 hybrid orbitals on the central atom in NH3 Solution we found sp3 hybrid orbitals on the central atom in NH3.
we found sp3 hybrid orbitals on the central atom in NH3Solution.pdf
we found sp3 hybrid orbitals on the central atom in NH3Solution.pdf
apexelectronices01
The definitions of process just given could just as easily apply to activities wearing the labels function, task, step, or operation. Indeed, if you accept the notion that a process is a set of related activities, then any set of related activities, regardless of scope or scale, constitutes a process, and any label for activity is also a legitimate synonym for process. In the end, words fail us. As a result, the meaning of process eludes us. This lack of meaning creates much of the difficulty in defining an organization’s business processes. An organization’s transformational processes (the conversion of inputs to outputs) and its transactional processes (the exchange of outputs for inputs) define the organization from the process perspective. The transformational-transactional view of organizations shown in Figure 1 suggests that all organizations have only a few basic processes. Some basic processes clearly implied by Figure 1 are listed below. Process 1 Converting products, and services coming in to products and services going out. Process 2 Getting products and services from the producer to the customer or the marketplace. Process 3 Influencing customers’ decisions to buy and to pay, that is, obtaining orders and payments. Process 4 Managing the money coming in, the money going out, and any surplus. Process 5 Obtaining from suppliers the inputs necessary to sustain the functioning of the organization. [ Although Figure 1 emphasizes products and services as the major inputs, capital in the form of loans from lenders and investments from investors is another major input, as is information.] These basic processes are themselves parts of larger loops of activity, some of which are transformational and some of which are transactional in nature. An organization’s processes, that is, the flow of inputs and outputs through its transformational and transactional loops, are typically divided up into some commonly accepted business functions. With additional thought, other functions can be added to those above: The precise form these functions take, the labels they wear, and their distribution among a firm’s functional structures vary with the industry, the technology, and the history of the firm in question. That aside, the basic lesson is plain to see: There are only about a dozen or so basic business functions in any organization, and even fewer business processes. Examples at ETS Consider the case at my company, Educational Testing Service (ETS), home to a host of tests recognizable by their initials: for example, SAT, GRE, and GMAT. Ask almost anyone at ETS to generate a list of ETS’s key processes and, chances are, the list will include the following: Press for a longer list and you’ll probably see some of the following—plus others: Pose any of the items above as examples of processes, however, and they will be immediately disputed. The primary reason for this contentiousness is that most analyses of processes are \"floating,\" adrift in a sea.
The definitions of process just given could just as easily apply to .pdf
The definitions of process just given could just as easily apply to .pdf
apexelectronices01
Solution : The string which has two different syntax trees is -id-id. The leftmost derivation for each of the trees is same and it is given below: A-> -A A -> -A-id A-> -id-id.
SolutionThe string which has two different syntax trees is -id-id.pdf
SolutionThe string which has two different syntax trees is -id-id.pdf
apexelectronices01
Rhizopus Rhizopus is a genus of common saprophytic fungi on plants and specialized parasites on animals. They are found on a wide variety of organic substrates, including \"mature fruits and vegetables. jellies, syrups, leather, bread, peanuts, and tobacco. Some Rhizopusspecies are opportunistic agents of human zygomycosis (fungal infection) and can be fatal. Rhizopus infections may also be a complication of diabetic ketoacidosis. This widespread genus includes at least eight species. Rhizopus species grow as filamentous, branching hyphae that generally lack cross-walls (i.e., they are coenocytic). They reproduce by forming asexual and sexual spores. In asexual reproduction, sporangiospores are produced inside a spherical structure, the sporangium. Sporangia are supported by a large apophysate columella atop a long stalk, the sporangiophore. Sporangiophores arise among distinctive, root-like rhizoids. In sexual reproduction, a dark zygospore is produced at the point where two compatible myceliafuse. Upon germination, a zygospore produces colonies that are genetically different from either parent. · R. microsporus var. oligosporus is used to make tempeh, a fermented food derived from soybeans. · R. oryzae is used in the production of alcoholic beverages in parts of Asia and Africa. · Rhizopus stolonifer (black bread mold) causes fruit rot on strawberry, tomato, and sweet potato and used in commercial production of fumaric acid and cortisone. Various species, including R. stolonifer, may cause soft rot in sweet potatoes and Narcissus. Penicillium chrysogenum Penicillium chrysogenum or Notatum (formerly) is a species of fungus in the family Trichocomaceae. It is common in temperate and subtropical regions and can be found on salted food products,[1] but it is mostly found in indoor environments, especially in damp or water-damaged buildings.[2] It was previously known as Penicillium notatum. It has rarely been reported as a cause of human disease.[. It is the source of several -lactam antibiotics, most significantly penicillin. Other secondary metabolites of P. chrysogenum include roquefortine C, meleagrin, chrysogine, xanthocillins, secalonic acids, sorrentanone, sorbicillin, and PR-toxin. Like the many other species of the genus Penicillium, P. chrysogenum usually reproduces by forming dry chains of spores (or conidia) from brush-shaped conidiophores. The conidia are typically carried by air currents to new colonisation sites. In P. chrysogenum the conidia are blue to blue-green, and the mold sometimes exudes a yellow pigment. However, P. chrysogenum cannot be identified based on colour alone. Observations of morphology and microscopic features are needed to confirm its identity and DNA sequencing is essential to distinguish it from closely related species such as Penicillium rubens. The sexual stage of P. chrysogenum was discovered in 2013 by mating cultures in the dark on oatmeal agar supplemented with biotin, after the mating types (MAT1-1 .
RhizopusRhizopus is a genus of common saprophytic fungi on plants .pdf
RhizopusRhizopus is a genus of common saprophytic fungi on plants .pdf
apexelectronices01
Small interfering RNA (siRNA) and microRNA silence genes at the transcriptional, posttranscriptional, and/or translational level. Using human tissue culture cells, we show that promoter-directed siRNA inhibits transcription of an integrated, proviral, elongation factor 1alpha (EF1A) promoter–green fluorescent protein reporter gene and of endogenous EF1A. Silencing was associated with DNA methylation of the targeted sequence, and it required either active transport of siRNA into the nucleus or permeabilization of the nuclear envelope by lentiviral transduction. These results demonstrate that siRNA-directed transcriptional silencing is conserved in mammals, providing a means to inhibit mammalian gene function. The ‘nuclear side’ of RNA interference (RNAi) is increasingly recognized as an integral part of RNA-mediated gene silencing networks. Current data are consistent with the idea that epigenetic changes, such as DNA (cytosine-5) methylation and histone modifications, can be targeted to identical DNA sequences by short RNAs derived via Dicer cleavage of double-stranded RNA (dsRNA). To determine the relationships among RNA signals, DNA methylation and chromatin structure, we are carrying out a genetic analysis of RNA-mediated transcriptional gene silencing (TGS) in Arabidopsis. Results obtained so far indicate that in response to RNA signals, different site-specific DNA methyltransferases (DMTases) cooperate with each other and eventually with histone-modifying enzymes to establish and maintain a transcriptionally inactive state at a homologous target promoter. Processing of dsRNA in Arabidopsis occurs in the nucleus and in the cytoplasm, where distinct Dicer-like (DCL) activities are thought to generate functionally distinct classes of short RNAs. RNA silencing pathways thus operate throughout the cell to defend against invasive nucleic acids and to regulate genome structure and function. Solution Small interfering RNA (siRNA) and microRNA silence genes at the transcriptional, posttranscriptional, and/or translational level. Using human tissue culture cells, we show that promoter-directed siRNA inhibits transcription of an integrated, proviral, elongation factor 1alpha (EF1A) promoter–green fluorescent protein reporter gene and of endogenous EF1A. Silencing was associated with DNA methylation of the targeted sequence, and it required either active transport of siRNA into the nucleus or permeabilization of the nuclear envelope by lentiviral transduction. These results demonstrate that siRNA-directed transcriptional silencing is conserved in mammals, providing a means to inhibit mammalian gene function. The ‘nuclear side’ of RNA interference (RNAi) is increasingly recognized as an integral part of RNA-mediated gene silencing networks. Current data are consistent with the idea that epigenetic changes, such as DNA (cytosine-5) methylation and histone modifications, can be targeted to identical DNA sequences by short RNAs derived via Dicer cleavag.
Small interfering RNA (siRNA) and microRNA silence genes at the tran.pdf
Small interfering RNA (siRNA) and microRNA silence genes at the tran.pdf
apexelectronices01
private int func(int m, int n) { if(m Solution private int func(int m, int n) { if(m.
private int func(int m, int n){if(mn)return 0;else return1+.pdf
private int func(int m, int n){if(mn)return 0;else return1+.pdf
apexelectronices01
Questions has 4 parts. 1st part: Program to implement sorting algorithms: #include #include #include using namespace std; void swap(std::vector & data, int i, int j) { int tmp = data[i]; data[i] = data[j]; data[j] = tmp; } void print(std::vector const & data) { std::vector::const_iterator iter = data.begin(); for (; iter != data.end(); ++iter) { cout << *iter << \" \"; } if (data.size() > 0) { cout << endl; } } int generateRandom(int low, int high); void Shuffle(std::vector & data) { int length = data.size(); for (int i = 0; i < length-1; ++i) { swap(data, i, generateRandom(i+1, length-1)); } print(data); } int generateRandom(int low, int high) { srand(low); int gen = 0; gen = rand() % (high - low + 1) + low; return gen; } //useful for small lists, and for large lists where data is //already sorted void BubbleSort(std::vector & data) { int length = data.size(); for (int i = 0; i < length; ++i) { bool swapped = false; for (int j = 0; j < length - (i+1); ++j) { if (data[j] > data[j+1]) { swap(data, j, j+1); swapped = true; } } if (!swapped) break; } } //useful for small lists and where swapping is expensive // does at most n swaps void SelectionSort(std::vector & data) { int length = data.size(); for (int i = 0; i < length; ++i) { int min = i; for (int j = i+1; j < length; ++j) { if (data[j] < data[min]) { min = j; } } if (min != i) { swap(data, i, min); } } } //useful for small and mostly sorted lists //expensive to move array elements void InsertionSort(std::vector & data) { int length = data.size(); for (int i = 1; i < length; ++i) { bool inplace = true; int j = 0; for (; j < i; ++j) { if (data[i] < data[j]) { inplace = false; break; } } if (!inplace) { int save = data[i]; for (int k = i; k > j; --k) { data[k] = data[k-1]; } data[j] = save; } } } void Merge(std::vector & data, int lowl, int highl, int lowr, int highr); void MergeSort(std::vector & data, int low, int high) { if (low >= high) { return; } int mid = low + (high-low)/2; MergeSort(data, low, mid); MergeSort(data, mid+1, high); Merge(data, low, mid, mid+1, high); } void Merge(std::vector & data, int lowl, int highl, int lowr, int highr) { int tmp_low = lowl; std::vector tmp; while (lowl <= highl && lowr <= highr) { if (data[lowl] < data[lowr]) { tmp.push_back(data[lowl++]); } else if (data[lowr] < data[lowl]) { tmp.push_back(data[lowr++]); } else { tmp.push_back(data[lowl++]); tmp.push_back(data[lowr++]); } } while (lowl <= highl) { tmp.push_back(data[lowl++]); } while (lowr <= highr) { tmp.push_back(data[lowr++]); } std::vector::const_iterator iter = tmp.begin(); for(; iter != tmp.end(); ++iter) { data[tmp_low++] = *iter; } } int Partition(std::vector & data, int low, int high); void QuickSort(std::vector & data, int low, int high) { if (low >= high) return; int p = Partition(data, low, high); QuickSort(data, low, p-1); QuickSort(data, p+1, high); } int Partition(std::vector & data, int low, int high) { int p = low; for (int i = p+1; i <= high; ++i) { if (data[i] < data[p]) { swap.
Questions has 4 parts.1st part Program to implement sorting algor.pdf
Questions has 4 parts.1st part Program to implement sorting algor.pdf
apexelectronices01
Recommended
Yes, it\'s true that most mutations are deleterious however there are a few mutations that are beneficial and provide for differential propagation of the variation which is the basis for evolution Solution Yes, it\'s true that most mutations are deleterious however there are a few mutations that are beneficial and provide for differential propagation of the variation which is the basis for evolution.
Yes, its true that most mutations are deleterious however there ar.pdf
Yes, its true that most mutations are deleterious however there ar.pdf
apexelectronices01
we found sp3 hybrid orbitals on the central atom in NH3 Solution we found sp3 hybrid orbitals on the central atom in NH3.
we found sp3 hybrid orbitals on the central atom in NH3Solution.pdf
we found sp3 hybrid orbitals on the central atom in NH3Solution.pdf
apexelectronices01
The definitions of process just given could just as easily apply to activities wearing the labels function, task, step, or operation. Indeed, if you accept the notion that a process is a set of related activities, then any set of related activities, regardless of scope or scale, constitutes a process, and any label for activity is also a legitimate synonym for process. In the end, words fail us. As a result, the meaning of process eludes us. This lack of meaning creates much of the difficulty in defining an organization’s business processes. An organization’s transformational processes (the conversion of inputs to outputs) and its transactional processes (the exchange of outputs for inputs) define the organization from the process perspective. The transformational-transactional view of organizations shown in Figure 1 suggests that all organizations have only a few basic processes. Some basic processes clearly implied by Figure 1 are listed below. Process 1 Converting products, and services coming in to products and services going out. Process 2 Getting products and services from the producer to the customer or the marketplace. Process 3 Influencing customers’ decisions to buy and to pay, that is, obtaining orders and payments. Process 4 Managing the money coming in, the money going out, and any surplus. Process 5 Obtaining from suppliers the inputs necessary to sustain the functioning of the organization. [ Although Figure 1 emphasizes products and services as the major inputs, capital in the form of loans from lenders and investments from investors is another major input, as is information.] These basic processes are themselves parts of larger loops of activity, some of which are transformational and some of which are transactional in nature. An organization’s processes, that is, the flow of inputs and outputs through its transformational and transactional loops, are typically divided up into some commonly accepted business functions. With additional thought, other functions can be added to those above: The precise form these functions take, the labels they wear, and their distribution among a firm’s functional structures vary with the industry, the technology, and the history of the firm in question. That aside, the basic lesson is plain to see: There are only about a dozen or so basic business functions in any organization, and even fewer business processes. Examples at ETS Consider the case at my company, Educational Testing Service (ETS), home to a host of tests recognizable by their initials: for example, SAT, GRE, and GMAT. Ask almost anyone at ETS to generate a list of ETS’s key processes and, chances are, the list will include the following: Press for a longer list and you’ll probably see some of the following—plus others: Pose any of the items above as examples of processes, however, and they will be immediately disputed. The primary reason for this contentiousness is that most analyses of processes are \"floating,\" adrift in a sea.
The definitions of process just given could just as easily apply to .pdf
The definitions of process just given could just as easily apply to .pdf
apexelectronices01
Solution : The string which has two different syntax trees is -id-id. The leftmost derivation for each of the trees is same and it is given below: A-> -A A -> -A-id A-> -id-id.
SolutionThe string which has two different syntax trees is -id-id.pdf
SolutionThe string which has two different syntax trees is -id-id.pdf
apexelectronices01
Rhizopus Rhizopus is a genus of common saprophytic fungi on plants and specialized parasites on animals. They are found on a wide variety of organic substrates, including \"mature fruits and vegetables. jellies, syrups, leather, bread, peanuts, and tobacco. Some Rhizopusspecies are opportunistic agents of human zygomycosis (fungal infection) and can be fatal. Rhizopus infections may also be a complication of diabetic ketoacidosis. This widespread genus includes at least eight species. Rhizopus species grow as filamentous, branching hyphae that generally lack cross-walls (i.e., they are coenocytic). They reproduce by forming asexual and sexual spores. In asexual reproduction, sporangiospores are produced inside a spherical structure, the sporangium. Sporangia are supported by a large apophysate columella atop a long stalk, the sporangiophore. Sporangiophores arise among distinctive, root-like rhizoids. In sexual reproduction, a dark zygospore is produced at the point where two compatible myceliafuse. Upon germination, a zygospore produces colonies that are genetically different from either parent. · R. microsporus var. oligosporus is used to make tempeh, a fermented food derived from soybeans. · R. oryzae is used in the production of alcoholic beverages in parts of Asia and Africa. · Rhizopus stolonifer (black bread mold) causes fruit rot on strawberry, tomato, and sweet potato and used in commercial production of fumaric acid and cortisone. Various species, including R. stolonifer, may cause soft rot in sweet potatoes and Narcissus. Penicillium chrysogenum Penicillium chrysogenum or Notatum (formerly) is a species of fungus in the family Trichocomaceae. It is common in temperate and subtropical regions and can be found on salted food products,[1] but it is mostly found in indoor environments, especially in damp or water-damaged buildings.[2] It was previously known as Penicillium notatum. It has rarely been reported as a cause of human disease.[. It is the source of several -lactam antibiotics, most significantly penicillin. Other secondary metabolites of P. chrysogenum include roquefortine C, meleagrin, chrysogine, xanthocillins, secalonic acids, sorrentanone, sorbicillin, and PR-toxin. Like the many other species of the genus Penicillium, P. chrysogenum usually reproduces by forming dry chains of spores (or conidia) from brush-shaped conidiophores. The conidia are typically carried by air currents to new colonisation sites. In P. chrysogenum the conidia are blue to blue-green, and the mold sometimes exudes a yellow pigment. However, P. chrysogenum cannot be identified based on colour alone. Observations of morphology and microscopic features are needed to confirm its identity and DNA sequencing is essential to distinguish it from closely related species such as Penicillium rubens. The sexual stage of P. chrysogenum was discovered in 2013 by mating cultures in the dark on oatmeal agar supplemented with biotin, after the mating types (MAT1-1 .
RhizopusRhizopus is a genus of common saprophytic fungi on plants .pdf
RhizopusRhizopus is a genus of common saprophytic fungi on plants .pdf
apexelectronices01
Small interfering RNA (siRNA) and microRNA silence genes at the transcriptional, posttranscriptional, and/or translational level. Using human tissue culture cells, we show that promoter-directed siRNA inhibits transcription of an integrated, proviral, elongation factor 1alpha (EF1A) promoter–green fluorescent protein reporter gene and of endogenous EF1A. Silencing was associated with DNA methylation of the targeted sequence, and it required either active transport of siRNA into the nucleus or permeabilization of the nuclear envelope by lentiviral transduction. These results demonstrate that siRNA-directed transcriptional silencing is conserved in mammals, providing a means to inhibit mammalian gene function. The ‘nuclear side’ of RNA interference (RNAi) is increasingly recognized as an integral part of RNA-mediated gene silencing networks. Current data are consistent with the idea that epigenetic changes, such as DNA (cytosine-5) methylation and histone modifications, can be targeted to identical DNA sequences by short RNAs derived via Dicer cleavage of double-stranded RNA (dsRNA). To determine the relationships among RNA signals, DNA methylation and chromatin structure, we are carrying out a genetic analysis of RNA-mediated transcriptional gene silencing (TGS) in Arabidopsis. Results obtained so far indicate that in response to RNA signals, different site-specific DNA methyltransferases (DMTases) cooperate with each other and eventually with histone-modifying enzymes to establish and maintain a transcriptionally inactive state at a homologous target promoter. Processing of dsRNA in Arabidopsis occurs in the nucleus and in the cytoplasm, where distinct Dicer-like (DCL) activities are thought to generate functionally distinct classes of short RNAs. RNA silencing pathways thus operate throughout the cell to defend against invasive nucleic acids and to regulate genome structure and function. Solution Small interfering RNA (siRNA) and microRNA silence genes at the transcriptional, posttranscriptional, and/or translational level. Using human tissue culture cells, we show that promoter-directed siRNA inhibits transcription of an integrated, proviral, elongation factor 1alpha (EF1A) promoter–green fluorescent protein reporter gene and of endogenous EF1A. Silencing was associated with DNA methylation of the targeted sequence, and it required either active transport of siRNA into the nucleus or permeabilization of the nuclear envelope by lentiviral transduction. These results demonstrate that siRNA-directed transcriptional silencing is conserved in mammals, providing a means to inhibit mammalian gene function. The ‘nuclear side’ of RNA interference (RNAi) is increasingly recognized as an integral part of RNA-mediated gene silencing networks. Current data are consistent with the idea that epigenetic changes, such as DNA (cytosine-5) methylation and histone modifications, can be targeted to identical DNA sequences by short RNAs derived via Dicer cleavag.
Small interfering RNA (siRNA) and microRNA silence genes at the tran.pdf
Small interfering RNA (siRNA) and microRNA silence genes at the tran.pdf
apexelectronices01
private int func(int m, int n) { if(m Solution private int func(int m, int n) { if(m.
private int func(int m, int n){if(mn)return 0;else return1+.pdf
private int func(int m, int n){if(mn)return 0;else return1+.pdf
apexelectronices01
Questions has 4 parts. 1st part: Program to implement sorting algorithms: #include #include #include using namespace std; void swap(std::vector & data, int i, int j) { int tmp = data[i]; data[i] = data[j]; data[j] = tmp; } void print(std::vector const & data) { std::vector::const_iterator iter = data.begin(); for (; iter != data.end(); ++iter) { cout << *iter << \" \"; } if (data.size() > 0) { cout << endl; } } int generateRandom(int low, int high); void Shuffle(std::vector & data) { int length = data.size(); for (int i = 0; i < length-1; ++i) { swap(data, i, generateRandom(i+1, length-1)); } print(data); } int generateRandom(int low, int high) { srand(low); int gen = 0; gen = rand() % (high - low + 1) + low; return gen; } //useful for small lists, and for large lists where data is //already sorted void BubbleSort(std::vector & data) { int length = data.size(); for (int i = 0; i < length; ++i) { bool swapped = false; for (int j = 0; j < length - (i+1); ++j) { if (data[j] > data[j+1]) { swap(data, j, j+1); swapped = true; } } if (!swapped) break; } } //useful for small lists and where swapping is expensive // does at most n swaps void SelectionSort(std::vector & data) { int length = data.size(); for (int i = 0; i < length; ++i) { int min = i; for (int j = i+1; j < length; ++j) { if (data[j] < data[min]) { min = j; } } if (min != i) { swap(data, i, min); } } } //useful for small and mostly sorted lists //expensive to move array elements void InsertionSort(std::vector & data) { int length = data.size(); for (int i = 1; i < length; ++i) { bool inplace = true; int j = 0; for (; j < i; ++j) { if (data[i] < data[j]) { inplace = false; break; } } if (!inplace) { int save = data[i]; for (int k = i; k > j; --k) { data[k] = data[k-1]; } data[j] = save; } } } void Merge(std::vector & data, int lowl, int highl, int lowr, int highr); void MergeSort(std::vector & data, int low, int high) { if (low >= high) { return; } int mid = low + (high-low)/2; MergeSort(data, low, mid); MergeSort(data, mid+1, high); Merge(data, low, mid, mid+1, high); } void Merge(std::vector & data, int lowl, int highl, int lowr, int highr) { int tmp_low = lowl; std::vector tmp; while (lowl <= highl && lowr <= highr) { if (data[lowl] < data[lowr]) { tmp.push_back(data[lowl++]); } else if (data[lowr] < data[lowl]) { tmp.push_back(data[lowr++]); } else { tmp.push_back(data[lowl++]); tmp.push_back(data[lowr++]); } } while (lowl <= highl) { tmp.push_back(data[lowl++]); } while (lowr <= highr) { tmp.push_back(data[lowr++]); } std::vector::const_iterator iter = tmp.begin(); for(; iter != tmp.end(); ++iter) { data[tmp_low++] = *iter; } } int Partition(std::vector & data, int low, int high); void QuickSort(std::vector & data, int low, int high) { if (low >= high) return; int p = Partition(data, low, high); QuickSort(data, low, p-1); QuickSort(data, p+1, high); } int Partition(std::vector & data, int low, int high) { int p = low; for (int i = p+1; i <= high; ++i) { if (data[i] < data[p]) { swap.
Questions has 4 parts.1st part Program to implement sorting algor.pdf
Questions has 4 parts.1st part Program to implement sorting algor.pdf
apexelectronices01
Ques-1: How would agriculture be impacted in this country if the soils were lacking in microbes? Can you imagine a time in the future when we will have eliminated all of the fatal diseases caused by microbes? If you could cure just one microbial disease which one would it be and why? Which disease would be the easiest and cheapest to prevent and why? Answer: Microbes are natural scavangers and they are essential to convert disposing waste sludge into final product as an organic fertilizer through the anaerobic digestion, pasteurization and compost preparation. In order to minimize the error and to enable efficient growth of plant, it is better to supply plant with equal ratios at which plant can survive followed by supplying soil worms to enable proper nitrate and phosphorous fixation. These soil worms also should be in a proper ratio. In order to get better yield, fertilizers, which have the properties of not inhibiting the growth of soil microbes, are crucial. Providing plants with sufficient mineral supply is also important. The above methods of waste sludge treatment produces ----> organic manure or organic natural fertilizer for plant growth. Therefore, absence of microbes is leading to lack of leaf, shoot and root systems for plants result in no adequate mineral supplement to plants. This is leading to imbalance of ecosystem equilibrium. Plant growth was observed only in plants with soil and soil with worms. The major reason behind this is aerobic decomposition of soil microbes and worms supplying sufficient amount of nutrient such as nitrogen, phosphorous in the form of nitrates, phosphates. Soil worms efficiently performing nitrate fixation and phosphate fixation followed by carbon fixation. Soil worms are major symbiotic parasites, which can fix these complex phosphates, nitrates to supply to the plant efficiently as plant cannot fix nitrate and phosphates straightaway. Soil worms are natural scavengers. But in the treatments \"fertilizers with no worms and also fertilizers with worms, plant growth did not observed considerably as in which organophosphorous nitrate and phosphate fertilizers may have properties to act on soil microbes to inhibit their growth and reproduction. Thereby excess fertilizers may lead to excessive concentration inside the plant root cells (endoderm) followed by hyperosmotic cell death finally result in plant roots inability to supply minerals and water to the plant. Growth is going to be inhibited by excessive amount of fertilizers or even in the absence of soil worms. No, it is not possible to eliminate all the communicable diseases caused by microbes in future because microbes do exist antibiotic resistant and they have a property of transferring genes (transformation, conjugation and transduction) to other microbe of same genus result in acquiring resistance to host defense system. Sometimes some viral species have ability to undergo phage variation through mutated genome in the host cells. Curing a micro.
Ques-1 How would agriculture be impacted in this country if the soi.pdf
Ques-1 How would agriculture be impacted in this country if the soi.pdf
apexelectronices01
Percentile Ranks Standard Scores and Scaled Scores Solution Percentile Ranks Standard Scores and Scaled Scores.
Percentile RanksStandard Scores and Scaled ScoresSolutionPer.pdf
Percentile RanksStandard Scores and Scaled ScoresSolutionPer.pdf
apexelectronices01
import java.util.Scanner; public class Digits { public static void main(String[] args) { int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters int value, digit; //stores input value and digit respectively int copy; //stores copy of entry Scanner scan = new Scanner(System.in); //Get value from user System.out.println(\"enter number :\"); int value=scan.nextInt(); copy=value; //Make the value positive value=Math.abs(value); //What if the value is actually zero? if(value==0) zeroCount++; while(value>0) { digit=value10; if(digit==0) zerocount++; if(digit%2==0) evenCount++; else oddCount++; value=value/10; } System.out.println(\"original value:\"+copy); System.out.println(\"zero digits :\"+zeroCount); System.out.println(\"odd digits :\"+oddCount); System.out.println(\"even digits :\"+evenCount) } } Solution import java.util.Scanner; public class Digits { public static void main(String[] args) { int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters int value, digit; //stores input value and digit respectively int copy; //stores copy of entry Scanner scan = new Scanner(System.in); //Get value from user System.out.println(\"enter number :\"); int value=scan.nextInt(); copy=value; //Make the value positive value=Math.abs(value); //What if the value is actually zero? if(value==0) zeroCount++; while(value>0) { digit=value10; if(digit==0) zerocount++; if(digit%2==0) evenCount++; else oddCount++; value=value/10; } System.out.println(\"original value:\"+copy); System.out.println(\"zero digits :\"+zeroCount); System.out.println(\"odd digits :\"+oddCount); System.out.println(\"even digits :\"+evenCount) } }.
import java.util.Scanner;public class Digits { public static v.pdf
import java.util.Scanner;public class Digits { public static v.pdf
apexelectronices01
I hope the below code is helpful to you, please give me rewards. import java.awt.*; import java.awt.event.*; import java.text.DecimalFormat; import javax.swing.*; import javax.swing.border.*; public class MicrowaveOven extends JFrame { // JPanel for microwave window private JPanel windowJPanel; // JPanel for microwave controls private JPanel controlJPanel; // JTextField for cooking time private JTextField displayJTextField; // JButtons to set cooking time private JButton oneJButton; private JButton twoJButton; private JButton threeJButton; private JButton fourJButton; private JButton fiveJButton; private JButton sixJButton; private JButton sevenJButton; private JButton eightJButton; private JButton nineJButton; private JButton zeroJButton; // JButtons to start and clear timer private JButton startJButton; private JButton clearJButton; // Timer to count down seconds private Timer clockTimer; // String for storing digits entered by user private String timeToDisplay = \"\"; // Time instance for storing the current time private CookingTime microwaveTime = new CookingTime( 0, 0 ); // DecimalFormat to format time output private DecimalFormat timeFormat = new DecimalFormat( \"00\" ); // no-argument constructor public MicrowaveOven() { createUserInterface(); } // create and position GUI components; register event handlers private void createUserInterface() { // get content pane for attaching GUI components Container contentPane = getContentPane(); // enable explicit positioning of GUI components contentPane.setLayout( null ); // set up windowJPanel windowJPanel = new JPanel(); windowJPanel.setBounds( 16, 16, 328, 205 ); windowJPanel.setBorder( new LineBorder( Color.BLACK ) ); contentPane.add( windowJPanel ); // set up controlJPanel controlJPanel = new JPanel(); controlJPanel.setBounds( 368, 16, 149, 205 ); controlJPanel.setBorder( new LineBorder( Color.BLACK ) ); controlJPanel.setLayout( null ); contentPane.add( controlJPanel ); // set up displayJTextField displayJTextField = new JTextField(); displayJTextField.setBounds( 7, 5, 135, 42 ); displayJTextField.setText( \"Microwave Oven\" ); displayJTextField.setHorizontalAlignment( JTextField.CENTER ); displayJTextField.setEditable( false ); controlJPanel.add( displayJTextField ); // set up oneJButton oneJButton = new JButton(); oneJButton.setBounds( 13, 59, 41, 24 ); oneJButton.setText( \"1\" ); controlJPanel.add( oneJButton ); oneJButton.addActionListener( new ActionListener() // anonymous inner class { // event handler called when oneJButton is pressed public void actionPerformed( ActionEvent event ) { oneJButtonActionPerformed( event ); } } // end anonymous inner class ); // end call to addActionListener // set up twoJButton twoJButton = new JButton(); twoJButton.setBounds( 54, 59, 41, 24 ); twoJButton.setText( \"2\" ); controlJPanel.add( twoJButton ); twoJButton.addActionListener( new ActionListener() // anonymous inner class { // event handler called when twoJButton is pressed public void actionPer.
I hope the below code is helpful to you, please give me rewards.im.pdf
I hope the below code is helpful to you, please give me rewards.im.pdf
apexelectronices01
H3PO4(aq) + NaOH(aq) --> H2O(aq) + H2PO4(2-)(aq) + Na+ (aq) Hl(aq) + LiOH(aq) ---> H2O(aq) + I+ (aq) + Li+ (aq) HNO3(aq) + Ca(OH)2(aq) --> H2O(aq) + NO3(-)(aq) + Ca+(aq) + OH-(aq) Solution H3PO4(aq) + NaOH(aq) --> H2O(aq) + H2PO4(2-)(aq) + Na+ (aq) Hl(aq) + LiOH(aq) ---> H2O(aq) + I+ (aq) + Li+ (aq) HNO3(aq) + Ca(OH)2(aq) --> H2O(aq) + NO3(-)(aq) + Ca+(aq) + OH-(aq).
H3PO4(aq) + NaOH(aq) -- H2O(aq) + H2PO4(2-)(aq) + Na+ (aq) Hl(aq).pdf
H3PO4(aq) + NaOH(aq) -- H2O(aq) + H2PO4(2-)(aq) + Na+ (aq) Hl(aq).pdf
apexelectronices01
(a) tetrabromocuprate(II) [Cu(Br)4]2- (b) potassiumtrioxalatochromate(III) K3[Cr(C2O4)3] (c) aquocyanobis(ethylenediamine)cobalt(III) [Co(en)2CN(H2O)]2+ (d) Potassium tetracyanonickelate(II) K2[Ni(CN)4] (d) Potassium tetracyanonickelate(II) K2[Ni(CN)4] Solution (a) tetrabromocuprate(II) [Cu(Br)4]2- (b) potassiumtrioxalatochromate(III) K3[Cr(C2O4)3] (c) aquocyanobis(ethylenediamine)cobalt(III) [Co(en)2CN(H2O)]2+ (d) Potassium tetracyanonickelate(II) K2[Ni(CN)4] (d) Potassium tetracyanonickelate(II) K2[Ni(CN)4].
(a) tetrabromocuprate(II)[Cu(Br)4]2-(b) potassiumtrioxalatochrom.pdf
(a) tetrabromocuprate(II)[Cu(Br)4]2-(b) potassiumtrioxalatochrom.pdf
apexelectronices01
Consuming both E.coli and Salmonella are risky. But Salmonella is much more pathogenic and cause deliterious effects on human beings than E.coli. E.coli causes diarrhea, in most cases the diarrhea subsides without any medical intervention. Some strains of E.coli are not pathogenic and do not cause any pathogenic effect. But some strains can damage intestinal epithelium and cause ulcers in the intestine. Enteropathogenic E.coli, Enterohaemmorhagic E.coli are dangerous. Whereas in case of Salmonella, all the strains are pathogenic and can cause Typhoid, gastroenteritis based on the species. Typhoid or enteric fever and salmonella gastroenteritis are complicated without medical intervention. The person who consumed may also become carrier. The number of Salmonella bacteria required to cause infection is less than the number of E.coli required to cause infection. In other terms, the infectivity of Salmonella is higher than E.coli. Solution Consuming both E.coli and Salmonella are risky. But Salmonella is much more pathogenic and cause deliterious effects on human beings than E.coli. E.coli causes diarrhea, in most cases the diarrhea subsides without any medical intervention. Some strains of E.coli are not pathogenic and do not cause any pathogenic effect. But some strains can damage intestinal epithelium and cause ulcers in the intestine. Enteropathogenic E.coli, Enterohaemmorhagic E.coli are dangerous. Whereas in case of Salmonella, all the strains are pathogenic and can cause Typhoid, gastroenteritis based on the species. Typhoid or enteric fever and salmonella gastroenteritis are complicated without medical intervention. The person who consumed may also become carrier. The number of Salmonella bacteria required to cause infection is less than the number of E.coli required to cause infection. In other terms, the infectivity of Salmonella is higher than E.coli..
Consuming both E.coli and Salmonella are risky. But Salmonella is mu.pdf
Consuming both E.coli and Salmonella are risky. But Salmonella is mu.pdf
apexelectronices01
Debt-equity ratio=Debt/equity Hence debt=0.65equity Let equity be $x Hence debt=$0.65x Total=debt+equity =(x+0.65x)=$1.65x After tax cost of debt=9(1-0.4)=5.4% WACC=Respective costs*Respective investment weights =(5.4*0.65x/1.65x)+(x/1.65x*13) which is equal to =10.01%(Approx). Solution Debt-equity ratio=Debt/equity Hence debt=0.65equity Let equity be $x Hence debt=$0.65x Total=debt+equity =(x+0.65x)=$1.65x After tax cost of debt=9(1-0.4)=5.4% WACC=Respective costs*Respective investment weights =(5.4*0.65x/1.65x)+(x/1.65x*13) which is equal to =10.01%(Approx)..
Debt-equity ratio=DebtequityHence debt=0.65equityLet equity be .pdf
Debt-equity ratio=DebtequityHence debt=0.65equityLet equity be .pdf
apexelectronices01
As we move from left to right in a period the E.N valuesincreases & as we move from top to bottom in a group the E.Nvalue decreases . Part (A) P having more E.N value Part (B) K has more E.N value Part (c) C is having more E.N value Part (d) I having more E.N value a Solution As we move from left to right in a period the E.N valuesincreases & as we move from top to bottom in a group the E.Nvalue decreases . Part (A) P having more E.N value Part (B) K has more E.N value Part (c) C is having more E.N value Part (d) I having more E.N value a.
As we move from left to right in a period the E.N valuesincreases & .pdf
As we move from left to right in a period the E.N valuesincreases & .pdf
apexelectronices01
Answer nondiversifiable risk meaning Risk of an investment asset that cannot be reduced or eliminated by adding that asset to a diversified investment portfolio. Market or systemic risks are non-diversifiable risks The amount of investment might decrease over a period of time only due to economic changes or other events which affect high varities of the market. However, investment diversification and asset allocation can provide protection against non-diversifiable risk as different sections of the market have a tendency to underperform at different times. Solution Answer nondiversifiable risk meaning Risk of an investment asset that cannot be reduced or eliminated by adding that asset to a diversified investment portfolio. Market or systemic risks are non-diversifiable risks The amount of investment might decrease over a period of time only due to economic changes or other events which affect high varities of the market. However, investment diversification and asset allocation can provide protection against non-diversifiable risk as different sections of the market have a tendency to underperform at different times..
Answernondiversifiable riskmeaningRisk of an investment asset .pdf
Answernondiversifiable riskmeaningRisk of an investment asset .pdf
apexelectronices01
// PrintDiamond.java import java.util.Scanner; class PrintDiamond { public static void main(String[] args) { Scanner scan=new Scanner(System.in); System.out.println(\"Enter an integer: \"); int n = scan.nextInt(); int tab = n - 1; for (int i = 1; i<=n; i++) { for (int j = 1; j<=tab; j++) System.out.print(\" \"); tab--; for (int j = 1; j<= 2*i-1; j++) System.out.print(\"*\"); System.out.print(\"\ \"); } tab = 1; for (int i = 1; i<= n - 1; i++) { for (int j = 1; j<= tab; j++) System.out.print(\" \"); tab++; for (int j = 1 ; j<= 2*(n-i)-1; j++) System.out.print(\"*\"); System.out.println(\"\"); } } } /* output: Enter an integer: 4 * *** ***** ******* ***** *** * */ Solution // PrintDiamond.java import java.util.Scanner; class PrintDiamond { public static void main(String[] args) { Scanner scan=new Scanner(System.in); System.out.println(\"Enter an integer: \"); int n = scan.nextInt(); int tab = n - 1; for (int i = 1; i<=n; i++) { for (int j = 1; j<=tab; j++) System.out.print(\" \"); tab--; for (int j = 1; j<= 2*i-1; j++) System.out.print(\"*\"); System.out.print(\"\ \"); } tab = 1; for (int i = 1; i<= n - 1; i++) { for (int j = 1; j<= tab; j++) System.out.print(\" \"); tab++; for (int j = 1 ; j<= 2*(n-i)-1; j++) System.out.print(\"*\"); System.out.println(\"\"); } } } /* output: Enter an integer: 4 * *** ***** ******* ***** *** * */.
PrintDiamond.javaimport java.util.Scanner;class PrintDiamond.pdf
PrintDiamond.javaimport java.util.Scanner;class PrintDiamond.pdf
apexelectronices01
Let v be the number of vertices. Then Euler\'s formula tells, v + 16 - 28 = 2 Hence, v = 14 vertices Solution Let v be the number of vertices. Then Euler\'s formula tells, v + 16 - 28 = 2 Hence, v = 14 vertices.
Let v be the number of vertices. Then Eulers formula tells,.pdf
Let v be the number of vertices. Then Eulers formula tells,.pdf
apexelectronices01
ultraviolet light is the highest energy radiation Solution ultraviolet light is the highest energy radiation.
ultraviolet light is the highest energy radiation.pdf
ultraviolet light is the highest energy radiation.pdf
apexelectronices01
There\'s a proportionality constant (the rate constant) and the effect of concentration in a rate-law expression. Since the concentration of CO has no effect, I\'ll leave it out. Rate = - d[NO2]/dt = k[NO2]^2 Solution There\'s a proportionality constant (the rate constant) and the effect of concentration in a rate-law expression. Since the concentration of CO has no effect, I\'ll leave it out. Rate = - d[NO2]/dt = k[NO2]^2.
Theres a proportionality constant (the rate con.pdf
Theres a proportionality constant (the rate con.pdf
apexelectronices01
The only one I might change is #2. Oxygen is more electronegativethan N so it might overcome the fact that N has two hydrogens. Sorry if I got that wrong. Steve Solution The only one I might change is #2. Oxygen is more electronegativethan N so it might overcome the fact that N has two hydrogens. Sorry if I got that wrong. Steve.
The only one I might change is #2. Oxygen is more.pdf
The only one I might change is #2. Oxygen is more.pdf
apexelectronices01
the total volume (in mL) of Naoh solution added to reach the endpoint = 14.16 - 0.52 ml = 13.64 ml Solution the total volume (in mL) of Naoh solution added to reach the endpoint = 14.16 - 0.52 ml = 13.64 ml.
the total volume (in mL) of Naoh solution added t.pdf
the total volume (in mL) of Naoh solution added t.pdf
apexelectronices01
The balanced Equations are : 1. 3Mg + N2 --> Mg3N2 2. 2H2O2 --> 2H2O + O2 3. 2C6H6 + 15 O2 --> 12 CO2 + 6 H2O 4. 2Al + 3H2SO4 --> Al2(SO4)3 + 3 H2 5. Al4C3 + 12 H2O --> 4Al(OH)3 + 3CH4 Solution The balanced Equations are : 1. 3Mg + N2 --> Mg3N2 2. 2H2O2 --> 2H2O + O2 3. 2C6H6 + 15 O2 --> 12 CO2 + 6 H2O 4. 2Al + 3H2SO4 --> Al2(SO4)3 + 3 H2 5. Al4C3 + 12 H2O --> 4Al(OH)3 + 3CH4.
The balanced Equations are 1. 3Mg + N2 -- Mg3N.pdf
The balanced Equations are 1. 3Mg + N2 -- Mg3N.pdf
apexelectronices01
proline disturbs alpha helical structure but doesnot create problems when finding the sequence Solution proline disturbs alpha helical structure but doesnot create problems when finding the sequence.
proline disturbs alpha helical structure but does.pdf
proline disturbs alpha helical structure but does.pdf
apexelectronices01
ln( Ae^dH/RT) = ln A + dh/RT Solution ln( Ae^dH/RT) = ln A + dh/RT.
ln( Ae^dHRT) = ln A + dhRT .pdf
ln( Ae^dHRT) = ln A + dhRT .pdf
apexelectronices01
mainly the halogens (group 17) though nitrogen and oxygen also makediatomic molecules Solution mainly the halogens (group 17) though nitrogen and oxygen also makediatomic molecules.
mainly the halogens (group 17) though nitrogen an.pdf
mainly the halogens (group 17) though nitrogen an.pdf
apexelectronices01
Pie
The basics of sentences session 2pptx copy.pptx
The basics of sentences session 2pptx copy.pptx
heathfieldcps1
Código Creativo y Arte de Software | Unidad 1
Código Creativo y Arte de Software | Unidad 1
Código Creativo y Arte de Software | Unidad 1
Maestría en Comunicación Digital Interactiva - UNR
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Ques-1: How would agriculture be impacted in this country if the soils were lacking in microbes? Can you imagine a time in the future when we will have eliminated all of the fatal diseases caused by microbes? If you could cure just one microbial disease which one would it be and why? Which disease would be the easiest and cheapest to prevent and why? Answer: Microbes are natural scavangers and they are essential to convert disposing waste sludge into final product as an organic fertilizer through the anaerobic digestion, pasteurization and compost preparation. In order to minimize the error and to enable efficient growth of plant, it is better to supply plant with equal ratios at which plant can survive followed by supplying soil worms to enable proper nitrate and phosphorous fixation. These soil worms also should be in a proper ratio. In order to get better yield, fertilizers, which have the properties of not inhibiting the growth of soil microbes, are crucial. Providing plants with sufficient mineral supply is also important. The above methods of waste sludge treatment produces ----> organic manure or organic natural fertilizer for plant growth. Therefore, absence of microbes is leading to lack of leaf, shoot and root systems for plants result in no adequate mineral supplement to plants. This is leading to imbalance of ecosystem equilibrium. Plant growth was observed only in plants with soil and soil with worms. The major reason behind this is aerobic decomposition of soil microbes and worms supplying sufficient amount of nutrient such as nitrogen, phosphorous in the form of nitrates, phosphates. Soil worms efficiently performing nitrate fixation and phosphate fixation followed by carbon fixation. Soil worms are major symbiotic parasites, which can fix these complex phosphates, nitrates to supply to the plant efficiently as plant cannot fix nitrate and phosphates straightaway. Soil worms are natural scavengers. But in the treatments \"fertilizers with no worms and also fertilizers with worms, plant growth did not observed considerably as in which organophosphorous nitrate and phosphate fertilizers may have properties to act on soil microbes to inhibit their growth and reproduction. Thereby excess fertilizers may lead to excessive concentration inside the plant root cells (endoderm) followed by hyperosmotic cell death finally result in plant roots inability to supply minerals and water to the plant. Growth is going to be inhibited by excessive amount of fertilizers or even in the absence of soil worms. No, it is not possible to eliminate all the communicable diseases caused by microbes in future because microbes do exist antibiotic resistant and they have a property of transferring genes (transformation, conjugation and transduction) to other microbe of same genus result in acquiring resistance to host defense system. Sometimes some viral species have ability to undergo phage variation through mutated genome in the host cells. Curing a micro.
Ques-1 How would agriculture be impacted in this country if the soi.pdf
Ques-1 How would agriculture be impacted in this country if the soi.pdf
apexelectronices01
Percentile Ranks Standard Scores and Scaled Scores Solution Percentile Ranks Standard Scores and Scaled Scores.
Percentile RanksStandard Scores and Scaled ScoresSolutionPer.pdf
Percentile RanksStandard Scores and Scaled ScoresSolutionPer.pdf
apexelectronices01
import java.util.Scanner; public class Digits { public static void main(String[] args) { int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters int value, digit; //stores input value and digit respectively int copy; //stores copy of entry Scanner scan = new Scanner(System.in); //Get value from user System.out.println(\"enter number :\"); int value=scan.nextInt(); copy=value; //Make the value positive value=Math.abs(value); //What if the value is actually zero? if(value==0) zeroCount++; while(value>0) { digit=value10; if(digit==0) zerocount++; if(digit%2==0) evenCount++; else oddCount++; value=value/10; } System.out.println(\"original value:\"+copy); System.out.println(\"zero digits :\"+zeroCount); System.out.println(\"odd digits :\"+oddCount); System.out.println(\"even digits :\"+evenCount) } } Solution import java.util.Scanner; public class Digits { public static void main(String[] args) { int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters int value, digit; //stores input value and digit respectively int copy; //stores copy of entry Scanner scan = new Scanner(System.in); //Get value from user System.out.println(\"enter number :\"); int value=scan.nextInt(); copy=value; //Make the value positive value=Math.abs(value); //What if the value is actually zero? if(value==0) zeroCount++; while(value>0) { digit=value10; if(digit==0) zerocount++; if(digit%2==0) evenCount++; else oddCount++; value=value/10; } System.out.println(\"original value:\"+copy); System.out.println(\"zero digits :\"+zeroCount); System.out.println(\"odd digits :\"+oddCount); System.out.println(\"even digits :\"+evenCount) } }.
import java.util.Scanner;public class Digits { public static v.pdf
import java.util.Scanner;public class Digits { public static v.pdf
apexelectronices01
I hope the below code is helpful to you, please give me rewards. import java.awt.*; import java.awt.event.*; import java.text.DecimalFormat; import javax.swing.*; import javax.swing.border.*; public class MicrowaveOven extends JFrame { // JPanel for microwave window private JPanel windowJPanel; // JPanel for microwave controls private JPanel controlJPanel; // JTextField for cooking time private JTextField displayJTextField; // JButtons to set cooking time private JButton oneJButton; private JButton twoJButton; private JButton threeJButton; private JButton fourJButton; private JButton fiveJButton; private JButton sixJButton; private JButton sevenJButton; private JButton eightJButton; private JButton nineJButton; private JButton zeroJButton; // JButtons to start and clear timer private JButton startJButton; private JButton clearJButton; // Timer to count down seconds private Timer clockTimer; // String for storing digits entered by user private String timeToDisplay = \"\"; // Time instance for storing the current time private CookingTime microwaveTime = new CookingTime( 0, 0 ); // DecimalFormat to format time output private DecimalFormat timeFormat = new DecimalFormat( \"00\" ); // no-argument constructor public MicrowaveOven() { createUserInterface(); } // create and position GUI components; register event handlers private void createUserInterface() { // get content pane for attaching GUI components Container contentPane = getContentPane(); // enable explicit positioning of GUI components contentPane.setLayout( null ); // set up windowJPanel windowJPanel = new JPanel(); windowJPanel.setBounds( 16, 16, 328, 205 ); windowJPanel.setBorder( new LineBorder( Color.BLACK ) ); contentPane.add( windowJPanel ); // set up controlJPanel controlJPanel = new JPanel(); controlJPanel.setBounds( 368, 16, 149, 205 ); controlJPanel.setBorder( new LineBorder( Color.BLACK ) ); controlJPanel.setLayout( null ); contentPane.add( controlJPanel ); // set up displayJTextField displayJTextField = new JTextField(); displayJTextField.setBounds( 7, 5, 135, 42 ); displayJTextField.setText( \"Microwave Oven\" ); displayJTextField.setHorizontalAlignment( JTextField.CENTER ); displayJTextField.setEditable( false ); controlJPanel.add( displayJTextField ); // set up oneJButton oneJButton = new JButton(); oneJButton.setBounds( 13, 59, 41, 24 ); oneJButton.setText( \"1\" ); controlJPanel.add( oneJButton ); oneJButton.addActionListener( new ActionListener() // anonymous inner class { // event handler called when oneJButton is pressed public void actionPerformed( ActionEvent event ) { oneJButtonActionPerformed( event ); } } // end anonymous inner class ); // end call to addActionListener // set up twoJButton twoJButton = new JButton(); twoJButton.setBounds( 54, 59, 41, 24 ); twoJButton.setText( \"2\" ); controlJPanel.add( twoJButton ); twoJButton.addActionListener( new ActionListener() // anonymous inner class { // event handler called when twoJButton is pressed public void actionPer.
I hope the below code is helpful to you, please give me rewards.im.pdf
I hope the below code is helpful to you, please give me rewards.im.pdf
apexelectronices01
H3PO4(aq) + NaOH(aq) --> H2O(aq) + H2PO4(2-)(aq) + Na+ (aq) Hl(aq) + LiOH(aq) ---> H2O(aq) + I+ (aq) + Li+ (aq) HNO3(aq) + Ca(OH)2(aq) --> H2O(aq) + NO3(-)(aq) + Ca+(aq) + OH-(aq) Solution H3PO4(aq) + NaOH(aq) --> H2O(aq) + H2PO4(2-)(aq) + Na+ (aq) Hl(aq) + LiOH(aq) ---> H2O(aq) + I+ (aq) + Li+ (aq) HNO3(aq) + Ca(OH)2(aq) --> H2O(aq) + NO3(-)(aq) + Ca+(aq) + OH-(aq).
H3PO4(aq) + NaOH(aq) -- H2O(aq) + H2PO4(2-)(aq) + Na+ (aq) Hl(aq).pdf
H3PO4(aq) + NaOH(aq) -- H2O(aq) + H2PO4(2-)(aq) + Na+ (aq) Hl(aq).pdf
apexelectronices01
(a) tetrabromocuprate(II) [Cu(Br)4]2- (b) potassiumtrioxalatochromate(III) K3[Cr(C2O4)3] (c) aquocyanobis(ethylenediamine)cobalt(III) [Co(en)2CN(H2O)]2+ (d) Potassium tetracyanonickelate(II) K2[Ni(CN)4] (d) Potassium tetracyanonickelate(II) K2[Ni(CN)4] Solution (a) tetrabromocuprate(II) [Cu(Br)4]2- (b) potassiumtrioxalatochromate(III) K3[Cr(C2O4)3] (c) aquocyanobis(ethylenediamine)cobalt(III) [Co(en)2CN(H2O)]2+ (d) Potassium tetracyanonickelate(II) K2[Ni(CN)4] (d) Potassium tetracyanonickelate(II) K2[Ni(CN)4].
(a) tetrabromocuprate(II)[Cu(Br)4]2-(b) potassiumtrioxalatochrom.pdf
(a) tetrabromocuprate(II)[Cu(Br)4]2-(b) potassiumtrioxalatochrom.pdf
apexelectronices01
Consuming both E.coli and Salmonella are risky. But Salmonella is much more pathogenic and cause deliterious effects on human beings than E.coli. E.coli causes diarrhea, in most cases the diarrhea subsides without any medical intervention. Some strains of E.coli are not pathogenic and do not cause any pathogenic effect. But some strains can damage intestinal epithelium and cause ulcers in the intestine. Enteropathogenic E.coli, Enterohaemmorhagic E.coli are dangerous. Whereas in case of Salmonella, all the strains are pathogenic and can cause Typhoid, gastroenteritis based on the species. Typhoid or enteric fever and salmonella gastroenteritis are complicated without medical intervention. The person who consumed may also become carrier. The number of Salmonella bacteria required to cause infection is less than the number of E.coli required to cause infection. In other terms, the infectivity of Salmonella is higher than E.coli. Solution Consuming both E.coli and Salmonella are risky. But Salmonella is much more pathogenic and cause deliterious effects on human beings than E.coli. E.coli causes diarrhea, in most cases the diarrhea subsides without any medical intervention. Some strains of E.coli are not pathogenic and do not cause any pathogenic effect. But some strains can damage intestinal epithelium and cause ulcers in the intestine. Enteropathogenic E.coli, Enterohaemmorhagic E.coli are dangerous. Whereas in case of Salmonella, all the strains are pathogenic and can cause Typhoid, gastroenteritis based on the species. Typhoid or enteric fever and salmonella gastroenteritis are complicated without medical intervention. The person who consumed may also become carrier. The number of Salmonella bacteria required to cause infection is less than the number of E.coli required to cause infection. In other terms, the infectivity of Salmonella is higher than E.coli..
Consuming both E.coli and Salmonella are risky. But Salmonella is mu.pdf
Consuming both E.coli and Salmonella are risky. But Salmonella is mu.pdf
apexelectronices01
Debt-equity ratio=Debt/equity Hence debt=0.65equity Let equity be $x Hence debt=$0.65x Total=debt+equity =(x+0.65x)=$1.65x After tax cost of debt=9(1-0.4)=5.4% WACC=Respective costs*Respective investment weights =(5.4*0.65x/1.65x)+(x/1.65x*13) which is equal to =10.01%(Approx). Solution Debt-equity ratio=Debt/equity Hence debt=0.65equity Let equity be $x Hence debt=$0.65x Total=debt+equity =(x+0.65x)=$1.65x After tax cost of debt=9(1-0.4)=5.4% WACC=Respective costs*Respective investment weights =(5.4*0.65x/1.65x)+(x/1.65x*13) which is equal to =10.01%(Approx)..
Debt-equity ratio=DebtequityHence debt=0.65equityLet equity be .pdf
Debt-equity ratio=DebtequityHence debt=0.65equityLet equity be .pdf
apexelectronices01
As we move from left to right in a period the E.N valuesincreases & as we move from top to bottom in a group the E.Nvalue decreases . Part (A) P having more E.N value Part (B) K has more E.N value Part (c) C is having more E.N value Part (d) I having more E.N value a Solution As we move from left to right in a period the E.N valuesincreases & as we move from top to bottom in a group the E.Nvalue decreases . Part (A) P having more E.N value Part (B) K has more E.N value Part (c) C is having more E.N value Part (d) I having more E.N value a.
As we move from left to right in a period the E.N valuesincreases & .pdf
As we move from left to right in a period the E.N valuesincreases & .pdf
apexelectronices01
Answer nondiversifiable risk meaning Risk of an investment asset that cannot be reduced or eliminated by adding that asset to a diversified investment portfolio. Market or systemic risks are non-diversifiable risks The amount of investment might decrease over a period of time only due to economic changes or other events which affect high varities of the market. However, investment diversification and asset allocation can provide protection against non-diversifiable risk as different sections of the market have a tendency to underperform at different times. Solution Answer nondiversifiable risk meaning Risk of an investment asset that cannot be reduced or eliminated by adding that asset to a diversified investment portfolio. Market or systemic risks are non-diversifiable risks The amount of investment might decrease over a period of time only due to economic changes or other events which affect high varities of the market. However, investment diversification and asset allocation can provide protection against non-diversifiable risk as different sections of the market have a tendency to underperform at different times..
Answernondiversifiable riskmeaningRisk of an investment asset .pdf
Answernondiversifiable riskmeaningRisk of an investment asset .pdf
apexelectronices01
// PrintDiamond.java import java.util.Scanner; class PrintDiamond { public static void main(String[] args) { Scanner scan=new Scanner(System.in); System.out.println(\"Enter an integer: \"); int n = scan.nextInt(); int tab = n - 1; for (int i = 1; i<=n; i++) { for (int j = 1; j<=tab; j++) System.out.print(\" \"); tab--; for (int j = 1; j<= 2*i-1; j++) System.out.print(\"*\"); System.out.print(\"\ \"); } tab = 1; for (int i = 1; i<= n - 1; i++) { for (int j = 1; j<= tab; j++) System.out.print(\" \"); tab++; for (int j = 1 ; j<= 2*(n-i)-1; j++) System.out.print(\"*\"); System.out.println(\"\"); } } } /* output: Enter an integer: 4 * *** ***** ******* ***** *** * */ Solution // PrintDiamond.java import java.util.Scanner; class PrintDiamond { public static void main(String[] args) { Scanner scan=new Scanner(System.in); System.out.println(\"Enter an integer: \"); int n = scan.nextInt(); int tab = n - 1; for (int i = 1; i<=n; i++) { for (int j = 1; j<=tab; j++) System.out.print(\" \"); tab--; for (int j = 1; j<= 2*i-1; j++) System.out.print(\"*\"); System.out.print(\"\ \"); } tab = 1; for (int i = 1; i<= n - 1; i++) { for (int j = 1; j<= tab; j++) System.out.print(\" \"); tab++; for (int j = 1 ; j<= 2*(n-i)-1; j++) System.out.print(\"*\"); System.out.println(\"\"); } } } /* output: Enter an integer: 4 * *** ***** ******* ***** *** * */.
PrintDiamond.javaimport java.util.Scanner;class PrintDiamond.pdf
PrintDiamond.javaimport java.util.Scanner;class PrintDiamond.pdf
apexelectronices01
Let v be the number of vertices. Then Euler\'s formula tells, v + 16 - 28 = 2 Hence, v = 14 vertices Solution Let v be the number of vertices. Then Euler\'s formula tells, v + 16 - 28 = 2 Hence, v = 14 vertices.
Let v be the number of vertices. Then Eulers formula tells,.pdf
Let v be the number of vertices. Then Eulers formula tells,.pdf
apexelectronices01
ultraviolet light is the highest energy radiation Solution ultraviolet light is the highest energy radiation.
ultraviolet light is the highest energy radiation.pdf
ultraviolet light is the highest energy radiation.pdf
apexelectronices01
There\'s a proportionality constant (the rate constant) and the effect of concentration in a rate-law expression. Since the concentration of CO has no effect, I\'ll leave it out. Rate = - d[NO2]/dt = k[NO2]^2 Solution There\'s a proportionality constant (the rate constant) and the effect of concentration in a rate-law expression. Since the concentration of CO has no effect, I\'ll leave it out. Rate = - d[NO2]/dt = k[NO2]^2.
Theres a proportionality constant (the rate con.pdf
Theres a proportionality constant (the rate con.pdf
apexelectronices01
The only one I might change is #2. Oxygen is more electronegativethan N so it might overcome the fact that N has two hydrogens. Sorry if I got that wrong. Steve Solution The only one I might change is #2. Oxygen is more electronegativethan N so it might overcome the fact that N has two hydrogens. Sorry if I got that wrong. Steve.
The only one I might change is #2. Oxygen is more.pdf
The only one I might change is #2. Oxygen is more.pdf
apexelectronices01
the total volume (in mL) of Naoh solution added to reach the endpoint = 14.16 - 0.52 ml = 13.64 ml Solution the total volume (in mL) of Naoh solution added to reach the endpoint = 14.16 - 0.52 ml = 13.64 ml.
the total volume (in mL) of Naoh solution added t.pdf
the total volume (in mL) of Naoh solution added t.pdf
apexelectronices01
The balanced Equations are : 1. 3Mg + N2 --> Mg3N2 2. 2H2O2 --> 2H2O + O2 3. 2C6H6 + 15 O2 --> 12 CO2 + 6 H2O 4. 2Al + 3H2SO4 --> Al2(SO4)3 + 3 H2 5. Al4C3 + 12 H2O --> 4Al(OH)3 + 3CH4 Solution The balanced Equations are : 1. 3Mg + N2 --> Mg3N2 2. 2H2O2 --> 2H2O + O2 3. 2C6H6 + 15 O2 --> 12 CO2 + 6 H2O 4. 2Al + 3H2SO4 --> Al2(SO4)3 + 3 H2 5. Al4C3 + 12 H2O --> 4Al(OH)3 + 3CH4.
The balanced Equations are 1. 3Mg + N2 -- Mg3N.pdf
The balanced Equations are 1. 3Mg + N2 -- Mg3N.pdf
apexelectronices01
proline disturbs alpha helical structure but doesnot create problems when finding the sequence Solution proline disturbs alpha helical structure but doesnot create problems when finding the sequence.
proline disturbs alpha helical structure but does.pdf
proline disturbs alpha helical structure but does.pdf
apexelectronices01
ln( Ae^dH/RT) = ln A + dh/RT Solution ln( Ae^dH/RT) = ln A + dh/RT.
ln( Ae^dHRT) = ln A + dhRT .pdf
ln( Ae^dHRT) = ln A + dhRT .pdf
apexelectronices01
mainly the halogens (group 17) though nitrogen and oxygen also makediatomic molecules Solution mainly the halogens (group 17) though nitrogen and oxygen also makediatomic molecules.
mainly the halogens (group 17) though nitrogen an.pdf
mainly the halogens (group 17) though nitrogen an.pdf
apexelectronices01
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